Energy cycles in reactions: notes and practice questions
- This topic covers how the law of conservation of energy helps predict energy changes in chemical reactions.
- Bond breaking is an endothermic process, absorbing energy.
- Bond forming is an exothermic process, releasing energy.
- The enthalpy change of a reaction can be calculated from average bond enthalpy data.
- Hess's law states that the enthalpy change for a reaction is independent of the pathway between initial and final states.
- Hess's law is applied to calculate enthalpy changes in multistep reactions.
How it is examined
Bond enthalpy calculations are 2 to 3 marks: bonds broken, bonds formed, difference. Only average bond enthalpies work for gaseous species, which is a standard "explain why the calculated value differs" follow-up worth 1 mark. May 2025 HL Paper 2 TZ1 gave a partly filled Born-Haber-style cycle and asked candidates to complete boxes with names of processes and formulas of species including state symbols for [3], with a Notes line refusing "ionization energy" singular where "ionization energies" was needed. It also ran a paired part asking for the enthalpy of a reaction from bond enthalpies [3] and then from ΔHf⦵ data [2], then why the two answers differ [1].
Average bond enthalpies. HL: standard enthalpies of formation and combustion, the two Hess's law summation equations, ionization energies, electron affinities and lattice enthalpies. What is recall: the direction of the two summation equations, which is the part students reverse. Products minus reactants for formation, reactants minus products for combustion.
- 1.2.1 Bond-breaking absorbs and bond-forming releases energy. Students calculate the enthalpy change of a reaction from given average bond enthalpy data.
- 1.2.2 Hess's law states that the enthalpy change for a reaction is independent of the pathway between the initial and final states. Students apply Hess's law to calculate enthalpy changes in multistep reactions.
HL: the construction of a complete Born-Haber cycle will not be assessed. Students interpret a given cycle or fill in parts of one. Do not generate a question that asks a student to build the whole cycle from nothing.
- 1.2.3 Standard enthalpy changes of combustion, ΔHc⦵, and formation, ΔHf⦵, data are used in thermodynamic calculations. Students deduce equations and solutions to problems involving these terms.
- 1.2.4 An application of Hess's law uses enthalpy of formation data or enthalpy of combustion data to calculate the enthalpy change of a reaction. Students calculate enthalpy changes using `ΔH⦵ = Σ ΔHf⦵(products) − Σ ΔHf⦵(reactants)` and `ΔH⦵ = Σ ΔHc⦵(reactants) − Σ ΔHc⦵(products)`.
- 1.2.5 A Born-Haber cycle is an application of Hess's law, used to show energy changes in the formation of an ionic compound. Students interpret and determine values from a Born-Haber cycle for compounds composed of univalent and divalent ions.
Guiding questions
- How does application of the law of conservation of energy help us to predict energy changes during reactions?
Linking questions
- Structure 2.2 How would you expect bond enthalpy data to relate to bond length and polarity? (HL) Would you expect allotropes of an element, such as diamond and graphite, to have different ΔHf⦵ values?
- Reactivity 3.4 How does the strength of a carbon-halogen bond affect the rate of a nucleophilic substitution reaction?
- Structure 2.1 (HL) What are the factors that influence the strength of lattice enthalpy in an ionic compound?
Practice questions
8 questions · 1 easy · 6 medium · 1 hardQuestion 1
EasyPaper 1A · calculator1 markFor which reactions can the enthalpy change be calculated using only average bond enthalpy data?
I.
II.
III.
A. I and II only
B. I and III only
C. II and III only
D. I, II and III
Recall the definition of average bond enthalpy. In which state of matter must the substances be for this definition to apply?
Question 2
MediumPaper 1A · calculator1 markThe standard enthalpy of hydrogenation of cyclohexene is .
Based on this value, what would be the predicted standard enthalpy of hydrogenation for the Kekulé structure of benzene, and what does the experimental value being significantly less exothermic indicate about the stability of benzene?
A. Predicted ; Benzene is less stable than the Kekulé structure.
B. Predicted ; Benzene is more stable than the Kekulé structure.
C. Predicted ; Benzene is less stable than the Kekulé structure.
D. Predicted ; Benzene is more stable than the Kekulé structure.
The Kekulé structure for benzene contains three alternating C=C double bonds. First, calculate the expected enthalpy change for hydrogenating these three bonds using the data for cyclohexene. Then, consider the meaning of 'less exothermic' in terms of energy levels and stability. A more stable compound has a lower enthalpy.
Question 3
HardPaper 2 · calculator7 marksThe thermal decomposition of calcium carbonate is an important industrial process used in the production of cement. The equation for the reaction is:
(a) The standard enthalpy of formation, , for the substances involved are given in the table.
| Substance | / kJ mol⁻¹ |
|---|---|
| -1207 | |
| -635 | |
| -394 |
Calculate the standard enthalpy change, , for the decomposition of calcium carbonate.
(b) Predict, with a reason, the sign of the standard entropy change, , for this reaction.
(c) Using the value J K⁻¹ mol⁻¹, and your answer from part (a), calculate the temperature, in K, above which this reaction is spontaneous.
Use the formula .
Compare the states of the reactants and products. How does the production of a gas affect the overall disorder of the system?
The boundary between spontaneous and non-spontaneous occurs when . Use this to find the temperature. Remember to ensure your units for enthalpy and entropy are consistent (e.g., both in kJ or both in J).
Question 4
MediumPaper 1A · calculator1 markWhich equation represents the standard enthalpy change of atomisation, , of phosphorus?
A.
B.
C.
D.
Recall the definition of standard enthalpy change of atomisation. It is the enthalpy change when one mole of gaseous atoms is formed from the element in its standard state. What is the standard state of phosphorus, and how many moles of it are needed to form one mole of P(g) atoms?
Question 5
MediumPaper 1A · calculator1 markConsider the following thermochemical equations related to the formation of nitrogen oxides:
kJ mol⁻¹
kJ mol⁻¹
What is the standard enthalpy change, , in kJ, for the dimerization of nitrogen dioxide?
A.
B.
C.
D.
Apply Hess's Law. You will need to manipulate the given equations (by reversing and/or multiplying) so that they add up to the target equation. Remember to apply the same manipulations to the enthalpy change values.
Question 6
MediumPaper 1A · calculator1 markThe hydrogenation of ethene is an important industrial process to produce ethane. Use the provided standard enthalpy of combustion data to calculate the enthalpy change for the hydrogenation of ethene in .
Given standard enthalpy of combustion values:
I.
II.
III.
A.
B.
C.
D.
Apply Hess's Law. Manipulate the given equations (reverse, multiply) so that when added, they yield the target equation. Remember to apply the same manipulations to their corresponding enthalpy changes.
Question 7
MediumPaper 1A · calculator1 markThe Contact Process is a key industrial method for producing sulfuric acid. One crucial step involves the oxidation of sulfur dioxide to sulfur trioxide. Consider the following enthalpy changes related to the formation of sulfur trioxide:
What is the enthalpy change, , in , for the direct formation of sulfur trioxide from its elements, ?
A.
B.
C.
D.
Recall Hess's Law, which states that the total enthalpy change for a reaction is independent of the pathway taken. Consider how the given reactions can be combined to form the target reaction.
Question 8
MediumPaper 1A · calculator1 markConsider the following thermochemical equations:
What is the value of , in , for the following reaction?
A.
B.
C.
D.
Apply Hess's Law. The target equation requires as a reactant and as a product. You will need to manipulate the given equations to match the target equation. Remember that if you reverse an equation, you must change the sign of its value, and if you multiply an equation by a factor, you must do the same to its value.
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Where marks are lost
- Reaching for "human error" or "only one trial." A source of error has to be a specific step in the method, not a general apology for the result.
- Joining the dots instead of drawing a curve.
- Naming a chemical instead of the property that distinguishes it, or vice versa. Answering with the nearest fact that comes to mind rather than the fact the command term and stem jointly ask for is a recurring way to answer a question that was not, quite, the one asked.