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Topic S2.4 · SL and HL

From models to materials: notes and practice questions

Summary
  • This topic explores how bonding and structure influence material properties, using models to explain them.
  • Bonding is best described as a continuum between ionic, covalent, and metallic models, represented by a bonding triangle.
  • The position of a compound in the bonding triangle is determined by the relative contributions of the three bonding types.
  • Properties of a compound can be predicted based on its position in the bonding triangle.
  • Alloys are mixtures of metals or metals and non-metals, with enhanced properties due to non-directional bonding.
  • Polymers are large molecules (macromolecules) made from repeating monomer subunits.
  • Addition polymers form by breaking double bonds in monomers, while condensation polymers form by reactions between functional groups with the release of a small molecule.

How it is examined

Bonding triangle questions give the electronegativity data and ask for a position or a predicted property, 1 to 2 marks. Polymer questions run both ways: draw the repeating unit from monomers, or deduce the monomer from a drawn polymer. May 2025 HL Paper 2 TZ1 asked candidates to deduce the monomer that forms a given polymer [1] and then describe a chemical property that makes it useful [1]. The repeating-unit convention (brackets, continuation bonds through the brackets, subscript n) is marked, so a drawing without the trailing bonds can be refused.

Given in the booklet

The bonding triangle and electronegativity values. Everything else is recall or is supplied in the question stem, including monomer structures.

Key ideas
  • 2.4.1 Bonding is best described as a continuum between the ionic, covalent and metallic models, and can be represented by a bonding triangle. Students use bonding models to explain the properties of a material.
  • 2.4.2 The position of a compound in the bonding triangle is determined by the relative contributions of the three bonding types to the overall bond. Students determine the position of a compound in the bonding triangle from electronegativity data, and predict the properties of a compound based on its position.
  • 2.4.3 Alloys are mixtures of a metal and other metals or non-metals. They have enhanced properties. Students explain the properties of alloys in terms of non-directional bonding.
  • 2.4.4 Polymers are large molecules, or macromolecules, made from repeating subunits called monomers. Students describe the common properties of plastics in terms of their structure.
Not assessed

Calculations of percentage ionic character are not required. The bonding triangle is read off, not computed into a percentage.

At HL

2.4.6 Condensation polymers form by the reaction between functional groups in each monomer with the release of a small molecule. Students represent the repeating unit of polyamides and polyesters from given monomer structures.

Guiding questions

  • What role do bonding and structure have in the design of materials?

Linking questions

  • Structure 3.1 How do the trends in properties of period 3 oxides reflect the trend in their bonding?
  • Nature of science, Structures 2.1, 2.2 What are the limitations of discrete bonding categories?
  • Structure 2.1, 2.2, 2.3 Why do composites like reinforced concretes, which are made from ionic and covalently bonded components and steel bars, have unique properties?
  • Structure 1.1 Why are alloys more correctly described as mixtures rather than as compounds?
  • Structure 3.2 What are the structural features of some plastics that make them biodegradable? What functional groups in molecules can enable them to act as monomers for addition reactions? (HL) for condensation reactions?
  • Reactivity 2.1 Why is the atom economy 100% for an addition polymerization reaction?
  • Structure 3.2 (HL) What is the nature of the reaction that occurs when two amino acids form a dipeptide?

Practice questions

15 questions · 9 easy · 5 medium · 1 hard
Showing 15 of 15

Question 1

EasyPaper 1A · calculator1 mark

Which force is primarily responsible for the significantly higher boiling point of water, H2OH_2O, compared to hydrogen sulfide, H2SH_2S?

A. Covalent bonds

B. London (dispersion) forces

C. Dipole-dipole forces

D. Hydrogen bonds

Question 2

MediumPaper 1A · calculator1 mark

The properties of four allotropes of carbon are described below.

Description 1: A molecular solid composed of spherical molecules, soluble in some non-polar solvents.

Description 2: A 2D material with exceptionally high tensile strength and electrical conductivity.

Description 3: A hard, transparent crystal that is an electrical insulator, with each atom bonded to four others.

Description 4: A soft, black solid that conducts electricity and is used as a lubricant.

Which row correctly matches the allotropes to their descriptions?

Description 1Description 2Description 3Description 4
A.BuckminsterfullereneGrapheneDiamondGraphite
B.DiamondGraphiteGrapheneBuckminsterfullerene
C.GrapheneDiamondGraphiteBuckminsterfullerene
D.GraphiteBuckminsterfullereneDiamondGraphene

Question 3

HardPaper 1B · calculator16 marks
(a)

Nitrogen dioxide, a pollutant from car exhausts, reacts with water in the atmosphere to form nitric acid and nitrous acid. This is a disproportionation reaction.

2NO2(g)+H2O(l)⇌HNO3(aq)+HNO2(aq)2NO_{2}(g) + H_{2}O(l) \rightleftharpoons HNO_{3}(aq) + HNO_{2}(aq)

(a) Deduce the oxidation states of nitrogen in the reactant and products.

Reactant: NO2NO_{2}

Products: HNO3HNO_{3}, HNO2HNO_{2}

[2]
(b)

(b) Explain, with reference to the equilibrium, why more nitrogen dioxide gas dissolves when the reaction occurs in alkaline rainwater.

[1]
(c)(i)

(c) The solubility of nitrogen dioxide gas in water was measured by different scientific groups. A summary of their results is shown.

SourceTemperature / °CSolubility of NO2NO_{2} gas in 0.100 dm³ of water
A00.380 dm³
B100.28 dm³
C20200 cm³
D250.15 L
E300.120 dm³

(i) Identify a problem in comparing the data from the different sources as presented in the table.

[1]
(c)(ii)

(ii) The units of solubility are converted to mol dm⁻³. Complete the table by calculating the value for source A. Assume the atmospheric pressure is 100 kPa and the density of the resulting solution is 1.00 g cm⁻³.

[2]
(c)(iii)

(iii) Suggest an explanation for the effect of temperature on the solubility of nitrogen dioxide gas.

[1]
(d)

(d) Suggest one reason why nitrogen dioxide is considered a major air pollutant.

[1]
(e)(i)

(e) Nitrous acid, HNO2HNO_2, is a weak acid. The graph shows the percentage of nitrous acid and its conjugate base, the nitrite ion (NO2−NO_2^-), present at different pH values.

(GRAPH IS A STANDARD SPECIATION PLOT FOR A WEAK ACID. X-AXIS: pH from 0 to 8. Y-AXIS: Percentage from 0 to 100. A curve for HA starts at 100% and goes down, a curve for A- starts at 0% and goes up. The two curves cross at pH = 3.3, where each is at 50%.)

(i) Deduce the pH range where nitrous acid, HNO2HNO_{2}, is the dominant nitrogen-containing species in the solution.

[1]
(e)(ii)

(ii) Determine, with reference to the graph, the pKapK_a of nitrous acid.

[2]
(f)(i)

(f) Nitrous acid can react with secondary amines to form N-nitrosamines, which are potent carcinogens. An example is the reaction with dimethylamine, (CH3)2NH(CH_3)_2NH.

(i) Deduce a balanced chemical equation for the formation of N-nitrosodimethylamine, (CH3)2NNO(CH_3)_2NNO, from dimethylamine and nitrous acid.

[1]
(f)(ii)

(ii) The rate of N-nitrosamine formation is highly dependent on pH. The reaction rate is highest under mildly acidic conditions where there is a sufficient concentration of both the unprotonated amine and nitrous acid. State two conditions that could be maintained in an industrial process to minimize the formation of N-nitrosamines.

[2]
(g)

(g) To combat the effects of acid rain, powdered limestone (CaCO3CaCO_3) is sometimes added to lakes. Suggest two distinct reasons why this 'liming' process is effective at restoring the aquatic ecosystem.

[2]

Question 4

EasyPaper 1A · calculator1 mark

An unknown silvery solid is analysed and found to have the following properties:

• High melting point (10851085 °C)

• Excellent electrical conductor as a solid

• Excellent electrical conductor when molten

• Malleable and ductile

What is the most probable structure of this substance?

A. Ionic lattice

B. Metallic lattice

C. Simple molecular

D. Covalent network

Question 5

MediumPaper 2 · calculator3 marks

High-voltage power lines are typically made of aluminium rather than copper, despite copper having a higher electrical conductivity. Explain, with reference to two distinct physical properties, why aluminium is often the preferred material for this application.

Question 6

EasyPaper 1A · calculator1 mark

Which substance has the lowest melting point?

A. Diamond

B. Graphite

C. Fullerene (C60C_{60})

D. Silicon dioxide (SiO2SiO_2)

Question 7

MediumPaper 1A · calculator1 mark

In which set do all species contain delocalized electrons?

A. SO2SO_2, C2H4C_2H_4, CC(diamond)

B. O3O_3, H2CO3H_2CO_3, C60C_{60}

C. C6H6C_6H_6, CO32−CO_3^{2-}, NO3−NO_3^-

D. CH3COO−CH_3COO^-, PO43−PO_4^{3-}, NH4+NH_4^+

Question 8

EasyPaper 2 · calculator2 marks

Pure gold, also known as 24-carat gold, is a relatively soft metal. For use in jewelry, it is often alloyed with other metals like copper to produce 18-carat gold.

(a) Explain, with reference to their structures, why 18-carat gold is harder than 24-carat gold.

Question 9

MediumPaper 2 · calculator8 marks
(a)

Silicon, a key component in electronics, can be purified to an exceptional degree, making it one of the purest elements commercially available. It reacts with oxygen to form silicon dioxide, a compound with a vast range of applications from glassmaking to fibre optics.

(a) Distinguish between the terms element and compound.

[2]
(b)

(b) Justify, using electronegativity values from the data booklet, why the Si-O bond is polar.

[1]
(c)

(c) Contrast the electrical conductivity of silicon and silicon dioxide. Relate the difference to their bonding and structure.

[2]
(d)

(d) The first ionization of a gaseous silicon atom can be initiated by electromagnetic radiation. Calculate the wavelength, in m, of the radiation corresponding to the first ionization energy of silicon. Use the data booklet.

[3]

Question 10

EasyPaper 2 · calculator2 marks

Polytetrafluoroethene (PTFE), widely known by the brand name Teflon, is a synthetic fluoropolymer of tetrafluoroethene. It has numerous applications due to its non-reactive and non-stick properties. The monomer is tetrafluoroethene, C2F4C_2F_4.

(a) Describe the key changes in bonding that occur when tetrafluoroethene monomers polymerize to form PTFE.

Question 11

MediumPaper 1A · calculator1 mark

In which allotropes of carbon is each carbon atom covalently bonded to three other carbon atoms?

I. Diamond

II. Graphite

III. Buckminsterfullerene (C60C_{60})

A. I and II only

B. I and III only

C. II and III only

D. I, II and III

Question 12

EasyPaper 1A · calculator1 mark

A white crystalline solid is investigated. It is found to be brittle, has a high melting point, and does not conduct electricity in the solid state. However, it conducts electricity when dissolved in water. Which type of bonding best describes this solid?

A. Covalent molecular

B. Covalent network

C. Ionic

D. Metallic

Question 13

EasyPaper 1A · calculator1 mark

An unknown substance is a lustrous solid at room temperature. It is found to have a high melting point and is an excellent electrical conductor in its solid form. Which structure best describes this substance?

A. Ionic lattice

B. Metallic lattice

C. Simple molecular

D. Covalent network

Question 14

EasyPaper 1A · calculator1 mark

What is the reason for the electrical conductivity of graphite?

A. The presence of mobile ions.

B. Strong covalent bonds within the layers.

C. Weak intermolecular forces between the layers.

D. The presence of delocalized electrons.

Question 15

EasyPaper 1A · calculator1 mark

A white crystalline solid is found to have a high melting point. It does not conduct electricity in the solid state, but it does conduct electricity when molten. Which type of structure and bonding is present in the solid?

A. Metallic

B. Ionic

C. Covalent molecular

D. Covalent network

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What does From models to materials cover in IB Chemistry?

This topic explores how bonding and structure influence material properties, using models to explain them. Bonding is best described as a continuum between ionic, covalent, and metallic models, represented by a bonding triangle. The position of a compound in the bonding triangle is determined by the relative contributions of the three bonding types.

Is From models to materials SL or HL?

Both. SL and HL students study From models to materials, and HL goes further: 2.4.6 Condensation polymers form by the reaction between functional groups in each monomer with the release of a small molecule. Students represent the repeating unit of polyamides and polyesters from given monomer structures.

How do I revise From models to materials for IB Chemistry?

Start from the core idea: this topic explores how bonding and structure influence material properties, using models to explain them. In the exam: bonding triangle questions give the electronegativity data and ask for a position or a predicted property, 1 to 2 marks. Polymer questions run both ways: draw the repeating unit from monomers, or deduce the monomer from a drawn polymer. Then practise exam-style questions, easiest first, writing out every step of your working before you check it.

How does FourtyFive help me practise From models to materials?

FourtyFive has 15 From models to materials questions. Every answer you write is marked mark by mark, IB-style, and you see where each mark was won or lost. Every part has a hint, the AI tutor helps you through the step you are stuck on, and your Study Profile picks what to practise next.

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