Electron sharing reactions: notes and practice questions
- This topic explains electron sharing reactions involving highly reactive radicals.
- A radical is a molecular entity with an unpaired electron.
- Radicals are produced by homolytic fission, where a covalent bond breaks, with each atom retaining one electron.
- Single-barbed arrows (fish hooks) are used to show the movement of a single electron.
- Radical substitution reactions with alkanes and halogens involve initiation, propagation, and termination steps.
- Alkanes are kinetically stable due to the strength and non-polar nature of C-C and C-H bonds.
How it is examined
Two hours of teaching, so a small share of marks, but it is examined every session because it is easy to write clean marking points for. The standard shape is "State the equation for the initiation step" [1], "State two propagation steps" [2], "State an equation for a termination step" [1]. Radical dots are part of the mark: an equation written without them can be refused. The "why a mixture of products" answer wants further substitution, not just "many reactions happen".
Average bond enthalpies, which support the "why does UV break Cl-Cl and not C-H" reasoning. The radical dot notation and the three stage names are recall.
- 3.3.1 A radical is a molecular entity that has an unpaired electron. Radicals are highly reactive. Students identify and represent radicals, for example `·CH₃` and `Cl·`.
- 3.3.2 Radicals are produced by homolytic fission, for example of halogens, in the presence of ultraviolet (UV) light or heat. Students explain, including with equations, the homolytic fission of halogens, known as the initiation step in a chain reaction.
- 3.3.3 Radicals take part in substitution reactions with alkanes, producing a mixture of products. Students explain, using equations, the propagation and termination steps in the reactions between alkanes and halogens.
None for Reactivity 3.3.
Guiding questions
- What happens when a species possesses an unpaired electron?
Linking questions
- Structure 2.1 How is it possible for a radical to be an atom, a molecule, a cation or an anion? Consider examples of each type.
- Structure 2.2 What is the reverse process of homolytic fission? Chlorine radicals released from CFCs are able to break down ozone, O₃, but not oxygen, O₂, in the stratosphere. What does this suggest about the relative strengths of bonds in the two allotropes?
- Reactivity 1.2 Why do chlorofluorocarbons (CFCs) in the atmosphere break down to release chlorine radicals but typically not fluorine radicals?
- Reactivity 2.2 Why are alkanes described as kinetically stable but thermodynamically unstable?
Practice questions
24 questions · 9 easy · 15 mediumQuestion 1
EasyPaper 2 · calculator1 markFree radicals are highly reactive species characterized by the presence of an unpaired electron. They are involved in many atmospheric processes. Which of the following species is not a free radical?
A.
B.
C.
D.
A free radical is defined as a species with at least one unpaired electron. To determine if a species is a radical, calculate the total number of valence electrons. If the total is an odd number, it must be a radical.
Question 2
MediumPaper 1A · calculator1 markWhich alcohol and conditions would produce the highest yield of butanal?
Alcohol
Conditions
A. Butan-1-ol
Reflux
B. Butan-2-ol
Reflux
C. Butan-1-ol
Distillation
D. 2-methylpropan-2-ol
Distillation
Consider the type of functional group in butanal. What class of alcohol is oxidized to form this functional group? What specific reaction conditions are needed to ensure this is the major product and prevent further oxidation?
Question 3
EasyPaper 2 · calculator1 markEthane, , is exposed to chlorine gas, , in the presence of ultraviolet (UV) light. Which equation represents the initial reaction that occurs via a free radical mechanism?
A.
B.
C.
D.
Consider the type of reaction that alkanes undergo with halogens. What are the specific conditions required for this reaction, and what type of mechanism does it follow? Eliminate the options that represent other reaction types like addition, nucleophilic substitution, or combustion.
Question 4
MediumPaper 2 · calculator1 markWhich structural isomer of hexane, , will form exactly two different structural isomers of monochlorohexane, , upon free-radical substitution?
A. Hexane
B. 2-Methylpentane
C. 2,2-Dimethylbutane
D. 2,3-Dimethylbutane
Draw the structure of each isomer of hexane listed. Identify the number of unique environments for hydrogen atoms in each molecule. A unique environment will lead to a different substitution product.
Question 5
EasyPaper 2 · calculator1 markWhich equation correctly represents the homolytic fission of a chlorine molecule, , during the initiation step of a free-radical substitution reaction?
A.
B.
C.
D.
Homolytic fission involves the symmetrical breaking of a covalent bond, where each atom receives one electron from the bonding pair. Consider what type of chemical species is formed.
Question 6
MediumPaper 2 · calculator1 markWhat is the major organic product formed when but-1-ene reacts with hydrogen bromide?
A. 1-bromobutane
B. 2-bromobutane
C. 1,2-dibromobutane
D. 2,2-dibromobutane
This is an electrophilic addition reaction involving an unsymmetrical alkene. Recall Markovnikov's rule to predict the regioselectivity of the addition of HBr across the C=C double bond.
Question 7
EasyPaper 1A · calculator1 markWhich equation represents a termination step in the free-radical substitution of ethane with bromine?
A.
B.
C.
D.
Recall the three stages of a free-radical substitution mechanism: initiation, propagation, and termination. Consider what defines a termination step in terms of the number of radical species on the reactant and product sides of the equation.
Question 8
MediumPaper 2 · calculator5 marksEthane, , reacts with bromine, , in the presence of ultraviolet (UV) light to form bromoethane, , via a free-radical substitution mechanism. The first step of the mechanism is initiation.
(i) Define the term homolytic fission.
(ii) State the number of electrons and the overall charge of a bromine radical.
(iii) Write an equation for the initiation step of this reaction.
(b) The mechanism continues with propagation and termination steps.
(i) Write one equation for a propagation step.
(ii) Write one equation for a termination step that results in the formation of butane, .
(i) Consider how a covalent bond can break. The prefix 'homo-' means 'same'.
(ii) A radical is formed from a neutral molecule. How many electrons does a bromine atom have according to the periodic table? Is a radical charged?
(iii) The initiation step is where radicals are first generated from a stable molecule, using energy from UV light.
(i) A propagation step involves a radical reacting with a stable molecule to produce a new radical and a new stable molecule. The number of radicals stays the same.
(ii) A termination step involves two radicals reacting together, which removes radicals from the reaction mixture.
Question 9
EasyPaper 1A · calculator1 markWhich equation represents a termination step in the free-radical substitution of ethane with bromine?
A.
B.
C.
D.
A termination step is one where two radicals combine to form a stable molecule, thus removing radicals from the reaction mixture and stopping the chain reaction. Look for the option that shows two species with unpaired electrons (radicals) reacting.
Question 10
MediumPaper 1A · calculator1 markWhich compound(s) will decolorize warm, acidified potassium manganate(VII) solution?
I.
II.
III.
A. I only
B. I and III only
C. II and III only
D. I, II and III
Consider the classification of each alcohol as primary, secondary, or tertiary. Recall how each class of alcohol reacts with a strong oxidizing agent like acidified potassium manganate(VII).
Question 11
EasyPaper 1A · calculator1 markWhich compound is produced by the oxidation of propan-2-ol with acidified potassium dichromate(VI)?
A. Propanal
B. Propanoic acid
C. Propanone
D. Propene
Identify propan-2-ol as a primary, secondary, or tertiary alcohol. Recall the product formed from the oxidation of this class of alcohol.
Question 12
MediumPaper 1A · calculator1 markWhich radical is most likely to be formed by the homolytic fission of one covalent bond in a molecule of 1-bromo-1-chloro-2,2,2-trifluoroethane, , when exposed to ultraviolet radiation?
A.
B.
C.
D.
Consider the relative strengths of the different covalent bonds in the molecule. The weakest bond is the most likely to undergo homolytic fission when exposed to UV radiation. Compare the bond enthalpies of C-H, C-F, C-Cl, and C-Br.
Question 13
EasyPaper 1A · calculator1 markThe reaction between methane and chlorine in the presence of UV light proceeds via a free-radical mechanism. Which species is formed in the initiation step?
A.
B.
C.
D.
The initiation step involves the breaking of the bond in the halogen molecule. Consider what type of bond fission (homolytic or heterolytic) is caused by UV light and what products result from it.
Question 14
MediumPaper 1A · calculator1 markPropene, , is an important feedstock in the chemical industry.
Which row correctly identifies the major organic product formed when propene reacts with the given reagent?
A. Reagent: (acid catalyst), Product: Propan-1-ol
B. Reagent: , Product: 2-bromopropane
C. Reagent: , Product: 1,1-dibromopropane
D. Reagent: (Ni catalyst), Product: Prop-1-ene
Recall the addition reactions of alkenes. For unsymmetrical alkenes like propene, consider Markovnikov's rule to predict the major product in reactions with reagents like and . Remember what products are formed during halogenation and hydrogenation.
Question 15
EasyPaper 1A · calculator1 markWhich compound is formed from the complete oxidation of ?
A.
B.
C.
D.
Recall the oxidation pathway for primary alcohols. Complete oxidation, typically under reflux with a strong oxidizing agent, converts the alcohol functional group into a different oxygen-containing functional group.
Question 16
MediumPaper 1A · calculator1 markWhich product is formed when butan-1-ol is heated under reflux with an excess of acidified potassium dichromate(VI) solution?
A.
B.
C.
D.
Consider the type of alcohol (primary, secondary, or tertiary) and the conditions of the oxidation reaction (reflux with a strong oxidizing agent). What is the final product of fully oxidizing a primary alcohol?
Question 17
EasyPaper 1A · calculator1 markWhich species acts as the nucleophile in the reaction below?
A.
B.
C.
D.
A nucleophile is a species that donates a pair of electrons to form a new covalent bond. Look for a species with a lone pair of electrons or a negative charge that attacks an electron-deficient centre.
Question 18
MediumPaper 1A · calculator1 markWhich reaction represents the reduction of a functional group?
A.
B.
C.
D.
Reduction in organic chemistry often involves an increase in the number of carbon-hydrogen bonds or a decrease in the number of carbon-oxygen bonds. Analyse each reaction to see which one fits this description.
Question 19
MediumPaper 1A · calculator1 markWhich alcohol(s) will decolorize acidified potassium permanganate(VII) solution upon warming?
I.
II.
III.
A. I only
B. III only
C. I and III only
D. I, II and III
Consider the classification of each alcohol as primary, secondary, or tertiary. Recall which classes of alcohols can be oxidized by common oxidizing agents like acidified potassium permanganate(VII).
Question 20
MediumPaper 1A · calculator1 markBromochlorofluoromethane, , is a compound that was once used in fire extinguishers. Its release into the atmosphere contributes to ozone depletion. Which organic radical is most likely to form from the homolytic fission of one covalent bond in a molecule of when exposed to ultraviolet radiation?
A.
B.
C.
D.
Homolytic fission is initiated by UV radiation breaking the weakest covalent bond in the molecule. Compare the bond enthalpies of the different carbon-halogen and carbon-hydrogen bonds to determine which is most likely to break.
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Where marks are lost
- Reaching for "human error" or "only one trial." A source of error has to be a specific step in the method, not a general apology for the result.
- Joining the dots instead of drawing a curve.
- Naming a chemical instead of the property that distinguishes it, or vice versa. Answering with the nearest fact that comes to mind rather than the fact the command term and stem jointly ask for is a recurring way to answer a question that was not, quite, the one asked.