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Topic 1.12 · HL only

Complex numbers (cartesian form, complex plane, imaginary solutions to quadratic equations): notes and practice questions

Summary
  • The imaginary unit: i=−1i = \sqrt{-1}, so i2=−1i^2 = -1.
  • Square roots of negative numbers: −k=ik\sqrt{-k} = i\sqrt{k} for k>0k > 0.
  • Cartesian form of a complex number: z=a+biz = a + bi, where a=Re(z)a = \text{Re}(z) and b=Im(z)b = \text{Im}(z).
  • Two complex numbers are equal if their real parts are equal and their imaginary parts are equal.
  • Addition: (a+bi)+(c+di)=(a+c)+(b+d)i(a + bi) + (c + di) = (a + c) + (b + d)i
  • Subtraction: (a+bi)−(c+di)=(a−c)+(b−d)i(a + bi) - (c + di) = (a - c) + (b - d)i
  • Multiplication: (a+bi)(c+di)=(ac−bd)+(ad+bc)i(a + bi)(c + di) = (ac - bd) + (ad + bc)i (using i2=−1i^2 = -1).
  • Powers of i cycle: i1=ii^1 = i, i2=−1i^2 = -1, i3=−ii^3 = -i, i4=1i^4 = 1.
  • Complex conjugate: For z=a+biz = a + bi, its conjugate is z∗=a−biz^* = a - bi.
  • Conjugate properties:
  • z+z∗=2az + z^* = 2a
  • z−z∗=2biz - z^* = 2bi
  • z×z∗=a2+b2z \times z^* = a^2 + b^2
  • Division: Multiply the numerator and denominator by the complex conjugate of the denominator.
  • Complex plane (Argand diagram): z=a+biz = a + bi is plotted as the point (a,b)(a, b) or a vector from the origin to (a,b)(a, b).
  • Real axis (horizontal) represents aa.
  • Imaginary axis (vertical) represents bb.
  • Quadratic equations ax2+bx+c=0ax^2 + bx + c = 0 with b2−4ac<0b^2 - 4ac < 0 have two complex roots.
  • If a,b,ca, b, c are real, complex roots always occur in conjugate pairs (p±qip \pm qi).
  • The real part of complex roots (pp) is the x-coordinate of the quadratic's turning point.
  • Factorisation with complex roots: (z−z1)(z−z2)=0(z - z_1)(z - z_2) = 0.
  • GDC: Set to "Rectangular" mode for a+bia + bi output; use polynomial solver for complex roots.

How it is examined

Usually a short Paper 1 question: solve a quadratic with a negative discriminant, or add and multiply a couple of complex numbers in Cartesian form. The Argand diagram turns up as a sketch mark, and a wrong sign on the imaginary part of a conjugate is the most common slip. Heavier arithmetic (powers, quotients) leans on the GDC rather than testing algebra by hand.

Given in the booklet

The quadratic formula (shared with SL 1, under AHL 1.12) and the definition i2=−1i^2 = -1.

Key ideas
  • Work with the number ii such that i2=−1i^2 = -1.
  • Use Cartesian form z=a+biz = a + bi, and the terms real part, imaginary part, conjugate, modulus and argument.
  • Calculate sums, differences, products and quotients by hand and with technology.
  • Calculate powers of complex numbers in Cartesian form, with technology.

Linking questions

  • TOK: how does language shape knowledge? Do the words "imaginary" and "complex" make the concepts harder than if they had different names?

Practice questions

8 questions · 7 medium · 1 hard
Showing 8 of 8

Question 1

MediumPaper 1 · calculator13 marks
(a)(i)

In a complex signal processing system, an input signal zz is transformed into an output signal ww using the relationship w=−iz+(3+2i)w = -iz + (3 + 2i), where w,z∈Cw, z \in \mathbb{C}.

(a.i) Calculate ww when z=4+iz = 4 + i.

[3]
(a)(ii)

(a.ii) Calculate ww when z=5z = 5.

[2]
(b)

(b) Describe the two geometric transformations that map point zz to point ww on the Argand diagram, stating the order in which they are applied.

[4]
(c)

(c) Find the complex number zz such that the output signal w=1−iw = 1 - i.

[4]

Question 2

HardPaper 1 · calculator8 marks
(a)(i)

A specialized navigation chart uses complex numbers to represent locations. The central hub is at the origin (0,0)(0,0). Two important landmarks, 'Anchor Point' (zAz_A) and 'Beacon Tower' (zBz_B), are located at zA=5−2iz_A = 5 - 2i and zB=4eiπ3z_B = 4e^{i\frac{\pi}{3}} respectively.

(a) (i) Find the modulus of zAz_A.

[2]
(a)(ii)

(a) (ii) Find the argument of zAz_A, giving your answer in radians.

[2]
(b)

(b) Find the area of the triangular region formed by the central hub, Anchor Point (zAz_A), and Beacon Tower (zBz_B).

[4]

Question 3

MediumPaper 1 · calculator5 marks

A signal processing unit performs an operation on a complex input signal Z1=4Z_1 = 4. The operation involves dividing Z1Z_1 by another complex number Z2=1+iZ_2 = 1+i. The output signal is Z3=Z1Z2Z_3 = \frac{Z_1}{Z_2}.

(a) Calculate the argument of the output signal Z3Z_3, giving your answer in radians between −π-\pi and π\pi.

Question 4

MediumPaper 1 · calculator5 marks

A landscape architect is designing a square-shaped garden feature on a Cartesian grid, where each point (x,y)(x, y) corresponds to a complex number x+yix + yi. Two adjacent corners of the square, named the 'Fountain' (FF) and the 'Gazebo' (GG), are located at the complex numbers F=−2+3iF = -2 + 3i and G=1+iG = 1 + i, respectively. The square is labelled FGHJFGHJ in a counter-clockwise direction.

(a) Determine the complex numbers represented by the other two corners, HH and JJ.

Question 5

MediumPaper 1 · calculator10 marks
(a)(i)

A signal generator produces a sequence of complex voltage signals, VnV_n, where nn is the signal number. The first signal is V1=10V_1 = 10 volts. Each subsequent signal is generated by multiplying the previous signal by a complex factor k=12+12ik = \frac{1}{2} + \frac{1}{2}i.

Write down the value of V2V_2.

[2]
(a)(ii)

Write down the value of V3V_3.

[2]
(b)

The engineering team claims that the sequence of signal magnitudes ∣V1∣,∣V2∣,∣V3∣,…|V_1|, |V_2|, |V_3|, \dots also forms a geometric sequence.

Show that this claim is correct, stating the exact value of the common ratio for this sequence.

[4]
(c)

Hence, find the sum of the infinite sequence of magnitudes ∣V1∣,∣V2∣,∣V3∣,…|V_1|, |V_2|, |V_3|, \dots.

[2]

Question 6

MediumPaper 1 · calculator7 marks
(a)

The stability of a new energy shield is modeled by a complex number ww, which satisfies the equation w2−2kw+(k2+9)=0w^2 - 2kw + (k^2 + 9) = 0, where kk is a control parameter and k∈Rk \in \mathbb{R}.

(a) When k=−2k = -2, find the value of ww which satisfies π2<arg⁡w<π\frac{\pi}{2} < \arg w < \pi. Give your answer in the form a+bia + bi.

[3]
(b)

The stability index of the shield is given by ∣w∣2|w|^2. The control parameter kk can vary in the interval [−4,4][-4, 4].

(b) Find the value(s) of kk in the interval [−4,4][-4, 4] for which the stability index is maximized.

[4]

Question 7

MediumPaper 1 · calculator5 marks
(a)

Two complex numbers are P=k+3iP = k + 3i and Q=m+2iQ = m + 2i, where k,m∈Rk, m \in \mathbb{R}.

(a) Find an expression for the real part of P2P^2, in terms of kk.

[2]
(b)

(b) Given that P2+2Q=1+8iP^2 + 2Q = 1 + 8i, find the value of kk and of mm.

[3]

Question 8

MediumPaper 2 · calculator12 marks
(a)

Let ω=−1+i32ω = \frac{-1 + \text{i}\sqrt{3}}{2}.

Show that ω2+ω+1=0ω^2 + ω + 1 = 0.

[2]
(b)

Hence, find the value of (1+ω)9(1+ω)^9.

[3]
(c)

A matrix BB is defined by B=(−11−10)B = \begin{pmatrix} -1 & 1 \\ -1 & 0 \end{pmatrix}.

Show that B2+B+I=OB^2 + B + I = O, where II is the 2×22 \times 2 identity matrix and OO is the 2×22 \times 2 zero matrix.

[3]
(d)

Hence, or otherwise, deduce that B3=IB^3 = I.

[2]
(e)

Find an expression for B−1B^{-1} in the form aB+bIaB + bI, where a,b∈Za, b \in \mathbb{Z}.

[2]

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What does Complex numbers (cartesian form, complex plane, imaginary solutions to quadratic equations) cover in IB Maths AI?

The imaginary unit: i = √-1, so i^2 = -1. Square roots of negative numbers: √-k = i√k for k > 0. Cartesian form of a complex number: z = a + bi, where a = Re(z) and b = Im(z).

Is Complex numbers (cartesian form, complex plane, imaginary solutions to quadratic equations) SL or HL?

Complex numbers (cartesian form, complex plane, imaginary solutions to quadratic equations) is HL only. SL students are not examined on it.

How do I revise Complex numbers (cartesian form, complex plane, imaginary solutions to quadratic equations) for IB Maths AI?

Start from the core idea: the imaginary unit: i = √-1, so i^2 = -1. In the exam: usually a short Paper 1 question: solve a quadratic with a negative discriminant, or add and multiply a couple of complex numbers in Cartesian form. The Argand diagram turns up as a sketch mark, and a wrong sign on the imaginary part of a conjugate is the most common slip. Then practise exam-style questions, easiest first, writing out every step of your working before you check it.

How does FourtyFive help me practise Complex numbers (cartesian form, complex plane, imaginary solutions to quadratic equations)?

FourtyFive has 8 Complex numbers (cartesian form, complex plane, imaginary solutions to quadratic equations) questions. Every answer you write is marked mark by mark, IB-style, and you see where each mark was won or lost. Every part has a hint, the AI tutor helps you through the step you are stuck on, and your Study Profile picks what to practise next.

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Yes. In the FourtyFive iPad app you write your working by hand with Apple Pencil, the way you would on paper, and it is marked the same way.

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