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Topic 5.13 · HL only

1st order Differential equations (separable method): notes and practice questions

Summary
  • Differential Equations: Equations relating a function with its derivatives, used for modeling.
  • Separation of Variables: Analytical method for first-order differential equations where variables can be separated.
  • Separable Differential Equation Form: dydx=g(x)h(y)\frac{dy}{dx} = g(x)h(y)
  • Slope Fields: Visual representation of dydx=g(x,y)\frac{dy}{dx} = g(x,y) showing tangent lines and solution curve flow.
  • Family of Solutions: General solution representing a whole family of curves.
  • Boundary/Initial Conditions: Specific values (e.g., (x0,y0)(x_0, y_0)) needed to determine a particular solution.
  • Euler’s Method: Numerical method for approximating solutions to differential equations.
  • To sketch a solution from a slope field: Locate initial point, follow nearby tangent lines, trace curve conforming to the flow.
  • Euler's Method recursive formulas:
  • xn+1=xn+hx_{n+1} = x_n + h
  • yn+1=yn+h⋅dydx(xn,yn)y_{n+1} = y_n + h \cdot \frac{dy}{dx}(x_n, y_n)
  • For Euler's Method, identify initial conditions (x0,y0)(x_0, y_0) and step size hh, and rearrange the DE to isolate dydx\frac{dy}{dx}.
  • GDC Euler's Method: Carefully translate exam variables to calculator input fields.
  • This entire topic (Differential Equations, Separation of Variables, Slope Fields, Euler's Method) is HL only (Topic 5.6).
  • Variable Letters: Be prepared for variables other than xx and yy in differential equations.
  • Final Solution Format: Do not rearrange to y=f(x)y = f(x) unless explicitly requested.
  • Improving Euler's Approximation: Decrease the step size (hh).

How it is examined

Two skills stacked on each other: translating a verbal proportionality statement into dydx=ky\dfrac{dy}{dx} = ky or similar, then solving it by separating the variables and integrating both sides. The general-solution wording matters for mark schemes, since a question that gives a boundary condition expects the constant to be found and substituted back in, and stopping at the general solution loses that final mark.

Key ideas
  • Set up a model, a differential equation, from a context.
  • Solve a first order differential equation by separation of variables.
  • Use the term "general solution."

Linking questions

  • The guide lists no connections for AHL 5.14.

Practice questions

31 questions · 19 medium · 12 hard
Showing 20 of 20

Question 1

MediumPaper 1 · calculator7 marks
(a)

If a tank of water is leaking through a hole at the bottom and the rate at which the volume of water V (cm3)V\ \left( cm^{3} \right) changes with respect to time t(seconds)t(seconds) is proportional to the volume itself, and is described by the differential equation:

dVdt=−Vt\frac{dV}{dt} = - \frac{V}{t}

aa solve the differential equation to find the equation of V(t)V(t) if after 5 seconds the volume of the water becomes 30,000 cm330,000\ cm^{3}.

[5]
(b)

bb Find at what time the volume of the tank becomes 10,000 cm310,000\ cm^{3} according to the calculated model.

[2]

Question 2

HardPaper 2 · calculator12 marks
(a)

(a) A cylindrical grain silo with a radius of 2.52.5 m and an initial grain height of 1010 m is being emptied. The rate at which the grain is removed from the silo is proportional to the square root of the height of the grain.

Using VV for the volume of grain in the silo and hh for the height of the grain, write down a differential equation relating these variables.

[2]
(b)

(b) Apply the chain rule and the formula for the volume of a cylinder to show that dVdt=6.25πdhdt\frac{dV}{dt} = 6.25\pi \frac{dh}{dt}. Hence, write your answer to part (a) in terms of hh and tt.

[3]
(c)

(c) After 3030 minutes, the height of the grain has dropped to 6.256.25 m. Predict how long it will take for the silo to be completely empty from the initial height of 1010 m.

[7]

Question 3

MediumPaper 1 · calculator8 marks
(a)

If a vehicle is moving along a straight road, where its position yy at time tt for t≥0t \geq 0 is given by the following differential equation:

dydt=ysin(t+1)\frac{dy}{dt} = ysin(t + 1)

At t=0t = 0 take y=1y = 1.

aa Use Euler's method with a step size of 0.1 and estimate yy at t=0.3t = 0.3.

[3]
(b)

bb By solving the differential equation analytically, calculate the percentage error in your approximation from part (a) at t=0.3.t = 0.3.

[5]

Question 4

HardPaper 2 · calculator14 marks
(a)

A specialized chemical reactor is designed to produce a certain compound. The rate of change of the concentration of a key reactant, CC, with respect to time, tt, is modeled by the differential equation dCdt=t2C\frac{dC}{dt} = \frac{t^2}{C}.

At t=1t = 1 minute, the concentration CC is 22 mol/L.

(a) Use Euler's method with a step size of 0.10.1 to find approximate values of CC when t=1.1t = 1.1, 1.21.2, and 1.31.3 minutes. Give your answers to three decimal places.

[4]
(b)

(b) Solve the differential equation dCdt=t2C\frac{dC}{dt} = \frac{t^2}{C} to find the exact concentration CC as a function of tt. Hence, find the absolute errors for each of your approximations in part (a). Give your exact values to five decimal places and absolute errors to five decimal places.

[10]

Question 5

MediumPaper 1 · calculator8 marks
(a)

If a transformation SS maps the vector (xy)\begin{pmatrix} x \\ y \end{pmatrix} to (x′y′)\begin{pmatrix} x' \\ y' \end{pmatrix} as follows:

S:(x′y′)=(4−735)(xy)+(2−3)S:\begin{pmatrix} x' \\ y' \end{pmatrix} = \begin{pmatrix} 4 & - 7 \\ 3 & 5 \end{pmatrix}\begin{pmatrix} x \\ y \end{pmatrix} + \begin{pmatrix} 2 \\ - 3 \end{pmatrix}

aa If the image of a point A(x,y)A(x,y), due to this transformation, has coordinates (0,16), Find the coordinates of point A(x,y)A(x,y).

[6]
(b)

bb If a quadrilateral MM undergoes the transformation SS, what happens to the area of its image?

[2]

Question 6

HardPaper 2 · calculator12 marks
(a)

A microbiologist is studying the interaction between two competing species of bacteria, species A and species B, in a controlled environment. Let AA represent the population of species A (measured in millions) and BB represent the population of species B (measured in millions). Let tt represent time, in hours.

The interaction can be modelled by the coupled differential equations:

dAdt=A(1−B)\frac{dA}{dt} = A(1 - B)

dBdt=B(A−3)\frac{dB}{dt} = B(A - 3)

State the two equilibrium points for this model.

[3]
(b)

Initially, there are 44 million bacteria of species A and 0.50.5 million bacteria of species B. Use the Euler method with a step size of 0.20.2 hours to estimate the population of species A and species B after 11 hour (to the nearest integer). Show the intermediate values that are obtained in the working, in the format of a table.

[7]
(c)

Suggest whether stating the population of bacteria to the nearest integer is a valid level of accuracy when using Euler's method in part (b).

[2]

Question 7

MediumPaper 2 · calculator6 marks

The path of a submarine is monitored on a 2D sonar screen. The path is described by the ellipse with equation x2+4y2=100x^2 + 4y^2 = 100, where xx and yy are the coordinates in kilometres. Both xx and yy are functions of time, tt, in hours.

At an instant when the submarine is at a point with a y-coordinate of 4 km, its rate of change of horizontal position is given by dxdt=−3 km/h\frac{dx}{dt} = -3 \text{ km/h}. Find the possible values of dydt\frac{dy}{dt} at this instant.

Question 8

HardPaper 2 · calculator16 marks
(a)

A scientific experiment involves a platform that oscillates with damped motion. The displacement, xx, of the platform, measured in centimetres from its equilibrium position, can be modelled by the second order differential equation:

x¨+5x˙+4x=0\ddot{x} + 5\dot{x} + 4x = 0, where tt is the time in seconds after the initial displacement.

Given that y=x˙y = \dot{x}, show that y˙=−4x−5y\dot{y} = -4x - 5y.

[2]
(b)

The differential equation can be expressed in the form (x˙y˙)=A(xy)\begin{pmatrix} \dot{x} \\ \dot{y} \end{pmatrix} = A \begin{pmatrix} x \\ y \end{pmatrix}, where A is a 2×22 \times 2 matrix.

Write down the matrix A.

[1]
(c)(i)

Find the eigenvalues of matrix A.

[3]
(c)(ii)

Find the eigenvectors of matrix A.

[4]
(d)

Given that at t=0t = 0, the platform is displaced 66 cm from equilibrium and its velocity is 33 cm/s, find an expression for xx in terms of tt.

[6]

Question 9

MediumPaper 1 · calculator8 marks
(a)

A chemical compound is dissolving in a solvent. Initially, there are 225 grams of the compound. After 15 minutes, 144 grams of the compound remain undissolved.

The mass of the undissolved compound, M grams, remaining after t minutes, can be modelled by the differential equation dMdt=−kM \frac{dM}{dt} = -k\sqrt{M} , where k is a positive constant.

(a) Show that M=(15−t5)2 M = (15 - \frac{t}{5})^2 .

[6]
(b)

(b) Calculate the time it takes for the entire compound to dissolve.

[2]

Question 10

HardPaper 2 · calculator22 marks
(a)(i)

The concentration of a chemical, CC (in mol dm−3^{-3}), in a reaction vessel at time tt seconds is modelled by the differential equation

d2Cdt2+7dCdt+10C=0\frac{\mathrm{d}^2C}{\mathrm{d}t^2} + 7\frac{\mathrm{d}C}{\mathrm{d}t} + 10C = 0

(a) (i) Use the substitution V=dCdtV = \frac{\mathrm{d}C}{\mathrm{d}t} to show that this equation can be written as

(dCdtdVdt)=(01−10−7)(CV)\begin{pmatrix} \frac{\mathrm{d}C}{\mathrm{d}t} \\ \frac{\mathrm{d}V}{\mathrm{d}t} \end{pmatrix} = \begin{pmatrix} 0 & 1 \\ -10 & -7 \end{pmatrix} \begin{pmatrix} C \\ V \end{pmatrix}.

[5]
(a)(ii)

(ii) Find the eigenvalues for the matrix (01−10−7)\begin{pmatrix} 0 & 1 \\ -10 & -7 \end{pmatrix}.

[3]
(a)(iii)

(iii) Hence state the long-term rate of change of the chemical concentration.

[1]
(b)(i)

The chemical reaction is now subjected to an external input, and the equation for the concentration is amended to

d2Cdt2+7dCdt+10C=2t+5\frac{\mathrm{d}^2C}{\mathrm{d}t^2} + 7\frac{\mathrm{d}C}{\mathrm{d}t} + 10C = 2t + 5.

(b) (i) Use the substitution V=dCdtV = \frac{\mathrm{d}C}{\mathrm{d}t} to write the differential equation as a system of coupled, first order differential equations. State the initial conditions given that, at t=0t = 0, the concentration of chemical C is 11 mol dm−3^{-3} and its rate of change is 00 mol dm−3^{-3} s−1^{-1}.

[3]
(b)(ii)

(ii) Use Euler's method with a step length of 0.10.1 to find the concentration of the chemical when t=1t = 1 s. Give your answer to three significant figures.

[7]
(b)(iii)

(iii) Find the long-term rate of change of the chemical concentration.

[3]

Question 11

MediumPaper 1 · calculator7 marks
(a)

A chemical reaction is monitored in a laboratory. The concentration of a specific compound, C, in milligrams per litre (mg/L), changes over time, t, in minutes.

The rate of change of the compound's concentration is modelled by

dCdt=−0.5t+10,t≥0\frac{\mathrm{d}C}{\mathrm{d}t} = -0.5t + 10, \quad t \ge 0

At 8 minutes, the concentration of the compound is 70 mg/L.

Find an expression for C in terms of t.

[5]
(b)

The experiment continues for an extended period.

Describe how the compound's concentration changes if the time elapsed is between 25 minutes and 35 minutes. Justify your answer.

[2]

Question 12

HardPaper 2 · calculator16 marks
(a)

A chemical engineer is studying the concentration of an intermediate product, CC, in a reaction vessel. The change in concentration over time tt (in minutes) is modelled by the second order differential equation:

d2Cdt2+4dCdt+3C=0\frac{d^2C}{dt^2} + 4\frac{dC}{dt} + 3C = 0

where t≥0t \ge 0. It is known that when t=0t = 0, the initial concentration is C=0C = 0 and the rate of change of concentration is dCdt=2\frac{dC}{dt} = 2.

Show that the system of coupled first order equations:

dCdt=y\frac{dC}{dt} = y

dydt=−3C−4y\frac{dy}{dt} = -3C - 4y

can be written as the given second order differential equation.

[2]
(b)

Find the eigenvalues of the system of coupled first order equations given in part (a).

[3]
(c)

Hence find the exact solution of the second order differential equation, given the initial conditions C(0)=0C(0) = 0 and dCdt(0)=2\frac{dC}{dt}(0) = 2.

[5]
(d)

Sketch the graph of CC against tt for t≥0t \ge 0, labelling the maximum point of the graph with its coordinates.

[2]
(e)

If the concentration of the intermediate product CC exceeds 0.20.2 arbitrary units, the reaction needs to be monitored closely. Use the model to calculate the total amount of time (in minutes) during which the reaction needs to be monitored closely.

[3]
(f)

The chemical engineer decides to monitor the reaction for 15% longer than the time found from the model in part (e).

Write down one reason, with reference to the context, to support this decision.

[1]

Question 13

MediumPaper 1 · calculator6 marks
(a)

The rate of change of the volume of water in a reservoir, in thousands of cubic meters per year, is given by the equation:

dVdt=6t2−20t\frac{\mathrm{d}V}{\mathrm{d}t} = 6t^2 - 20t

where VV is the volume of water in thousands of cubic meters and tt is the time in years since the start of monitoring.

(a) Determine whether the volume of water in the reservoir is increasing or decreasing when t=2t=2 years.

[2]
(b)

(b) One year after the start of monitoring, the volume of water in the reservoir was 5 thousand cubic meters. Find an expression for V(t)V(t), the volume of water in the reservoir at time tt, for t≥0t \ge 0.

[4]

Question 14

HardPaper 2 · calculator31 marks
(a)

A marine engineer is modelling the vertical displacement, hh meters, of a buoy from its equilibrium position at time tt minutes after being disturbed by a wave. The motion is described by the differential equation:

d2hdt2+6dhdt+8h=0\frac{\text{d}^2 h}{\text{d}t^2} + 6\frac{\text{d}h}{\text{d}t} + 8h = 0.

This equation can be rewritten as a system of coupled first-order differential equations:

dhdt=y\frac{\text{d}h}{\text{d}t} = y

dydt=−8h−6y\frac{\text{d}y}{\text{d}t} = -8h - 6y.

Find the general solution for hh.

[5]
(b)(i)

Initially, the buoy is at its equilibrium position (h=0h = 0) and has an initial upward velocity of 22 m/min (dhdt=2\frac{\text{d}h}{\text{d}t} = 2).

Find an expression for hh in terms of tt.

[6]
(b)(ii)

Sketch hh against tt in the interval 0≤t≤40 \le t \le 4.

[6]
(c)(i)

The engineer is interested in the maximum upward displacement of the buoy.

Find the time, in minutes, when this maximum displacement occurs.

[4]
(c)(ii)

Calculate the maximum upward displacement of the buoy.

[4]
(d)

An improved model for the buoy's motion, considering an external periodic force, is given by:

d2hdt2+6dhdt+8h=hcos⁡t\frac{\text{d}^2 h}{\text{d}t^2} + 6\frac{\text{d}h}{\text{d}t} + 8h = h \cos t.

The same initial conditions as in part (b.i) apply (h(0)=0h(0) = 0 and dhdt(0)=2\frac{\text{d}h}{\text{d}t}(0) = 2).

Use Euler's method with a tt-interval of 0.10.1 to predict the value of hh when t=1t = 1.

[6]

Question 15

MediumPaper 1 · calculator8 marks
(a)

A colony of bacteria is growing in a nutrient solution. The rate of change of the population, PP, with respect to time, tt (in hours), is modelled by the differential equation dPdt=Pcos⁡t(e−sin⁡t)\frac{dP}{dt} = P \cos t (e^{-\sin t}). At time t=0t = 0, the population is P=10P = 10.

(a) By using Euler's method with a step length of 0.1, find an approximate value for the population when t=0.3t = 0.3. Give your answer to three significant figures.

[3]
(b)

(b) By solving the differential equation, find the percentage error in your approximation for the population when t=0.3t = 0.3. Give your answer to three significant figures.

[5]

Question 16

HardPaper 3 · calculator27 marks
(a)(i)

This question explores models for the temperature of a cooling metal object.

A metal object is heated and then allowed to cool in a room where the ambient temperature is 2020 °C. The temperature, TT °C, of the object is recorded every 55 minutes, starting from t=0t = 0 minutes.

Time (tt minutes)Temperature (TT °C)
090.0
574.5
1062.5
1553.1
2045.8
2540.1

The data is first modelled using a linear function, T(t)=at+bT(t) = at + b, where a,b∈Ra, b \in \mathbb{R}.

Find the equation of the regression line of TT on tt.

[2]
(a)(ii)

Interpret the meaning of the parameter aa in the context of the model.

[1]
(a)(iii)

Suggest why using this linear regression equation to predict the time it will take for the object to cool to 2020 °C could be unreliable.

[1]
(b)(i)

The data is then modelled using a quadratic function, T(t)=pt2+qt+rT(t) = pt^2 + qt + r, where p,q,r∈Rp, q, r \in \mathbb{R}.

Find the equation of the least squares quadratic regression curve.

[1]
(b)(ii)

Use this quadratic equation to predict the time it will take for the object to cool to 4040 °C.

[2]
(b)(iii)

Hence, write down a suitable domain for the function T(t)=pt2+qt+rT(t) = pt^2 + qt + r in the context of this cooling process.

[1]
(c)

A metal object with a constant heat capacity CC Joules/°C is cooling in a room. The rate of heat transfer from the object to its surroundings is given by P=αA(T−Ta)P = \alpha A (T - T_a), where PP is the rate of heat loss in Joules/minute, α\alpha is the heat transfer coefficient, AA is the surface area of the object, TT is the object's temperature, and TaT_a is the ambient temperature. The rate of change of the object's internal energy is given by dEdt=CdTdt\frac{dE}{dt} = C \frac{dT}{dt}.

Given that the ambient temperature is Ta=20T_a = 20 °C and assuming that all heat loss is due to this process, show that the differential equation for the temperature of the object can be written as dTdt=−K(T−20)\frac{dT}{dt} = -K(T - 20), where KK is a positive constant.

[3]
(d)

By solving the differential equation dTdt=−K(T−20)\frac{dT}{dt} = -K(T - 20), show that the general solution is given by T=20+Ae−KtT = 20 + Ae^{-Kt}, where A∈RA \in \mathbb{R}.

[5]
(e)

Use the general solution from part (d) and the initial condition T(0)=90T(0) = 90 °C, along with the data point T(5)=74.5T(5) = 74.5 °C, to find the values of AA and KK. Hence, predict the time it takes for the object to cool to 2525 °C.

[4]
(f)

If the object was initially heated to a different temperature, T0′T_0' °C, such that it cools to 3030 °C in 3030 minutes, find this new initial temperature T0′T_0'. Use the value of K≈0.0500589K \approx 0.0500589 from part (e).

[3]
(g)

Now, consider a scenario where the object is cooling, but also receives a small amount of heat from an external source that decreases over time. The temperature of the object, TT °C, is modelled by the differential equation dTdt=−0.05(T−20)+1.5e−0.1t\frac{dT}{dt} = -0.05(T - 20) + 1.5 e^{-0.1t}.

Given the initial temperature T(0)=90T(0) = 90 °C, use Euler's method with a step length of h=2h = 2 minutes to estimate the temperature of the object at t=6t = 6 minutes.

[4]

Question 17

MediumPaper 1 · calculator6 marks
(a)

The rate of change of the concentration of a chemical compound, CC (in mol/L), in a reaction vessel with respect to time, tt (in minutes), is modeled by the differential equation

(t3+1)dCdt=t22C−6(t^3+1)\frac{dC}{dt} = \frac{t^2}{2C-6}, for t≥0,C≥3t \ge 0, C \ge 3.

Given that C=3C = 3 when t=0t = 0.

Explain why Euler's method cannot be used to find an approximate value for CC when t=0.1t = 0.1.

[1]
(b)

By solving the differential equation, show that C=3+13ln⁡(t3+1)C = 3+\sqrt{\frac{1}{3}\ln(t^3+1)}.

[4]
(c)

Hence deduce the value of CC when t=0.2t = 0.2.

[1]

Question 18

HardPaper 3 · calculator26 marks
(a)

A chemical spill has contaminated a section of a river. Environmental engineers are monitoring the concentration of a particular pollutant. Let P(t)P(t), measured in milligrams per litre (mgL−1^{-1}), be the concentration of the pollutant, tt days after a new batch of pollutant is introduced. The rate at which the pollutant naturally degrades or is flushed away is modelled as directly proportional to its concentration, leading to the differential equation

dPdt=−kP\frac{dP}{dt} = -kP, where k∈R+k \in \mathbb{R}^+.

The initial concentration is P0P_0 mgL−1^{-1}, P0>0P_0 > 0.

By solving the differential equation, show that P=P0e−ktP = P_0 e^{-kt}.

[3]
(b)

For the remainder of this question, you will consider this pollutant where it is known that k=0.15k = 0.15. The first significant spill occurs at time t=0t = 0 and it is assumed that before this there is no pollutant present in the river.

Find the time, in days, for this pollutant to reach 10% of its initial concentration.

[2]
(c)

The pollutant is added to the river every TT days due to regular discharges, and in constant amounts, such that the concentration of the pollutant is increased by an amount P0P_0 mgL−1^{-1}. To simplify the model, it is assumed that each time the pollutant is added, the concentration in the river increases instantaneously.

Show that the concentration of the pollutant is P0(1+e−0.15T+e−0.30T)P_0(1+e^{-0.15T} + e^{-0.30T}) immediately after the third discharge is given.

[4]
(d)

Immediately after the nthn^{th} discharge is given, the concentration of the pollutant is

P0(1+e−0.15T+e−0.30T+...+e−0.15(n−1)T)P_0(1+e^{-0.15T} + e^{-0.30T} + ... + e^{-0.15(n-1)T}).

Show that this concentration can be expressed as P0(1−e−0.15nT1−e−0.15T)P_0\left(\frac{1-e^{-0.15nT}}{1-e^{-0.15T}}\right).

[2]
(e)(i)

After the river has been subjected to these discharges for a long time, it is required to keep the pollutant concentration within a particular range to ensure ecological safety.

Let HnH_n be the highest concentration of the pollutant in the river for the interval (n−1)T<t<nT(n-1)T < t < nT.

Let LnL_n be the lowest concentration of the pollutant in the river for the interval (n−1)T<t<nT(n-1)T < t < nT.

This is shown in the following graph.

Graph showing pollutant concentration over time with highest and lowest concentrations indicated

H∞H_\infty is defined as lim⁡n→∞Hn\lim_{n\to\infty} H_n and L∞L_\infty is defined as lim⁡n→∞Ln\lim_{n\to\infty} L_n.

Find, in terms of P0P_0 and TT, an expression for

H∞H_\infty.

[2]
(e)(ii)

L∞L_\infty.

[3]
(f)(i)

Show that

H∞−L∞=P0H_\infty - L_\infty = P_0.

[2]
(f)(ii)

10.15ln⁡(H∞L∞)=T\frac{1}{0.15} \ln\left(\frac{H_\infty}{L_\infty}\right) = T.

[3]
(g)(i)

It is known that this pollutant is considered safe if the long-term concentration never exceeds 0.50 mgL−10.50 \text{ mgL}^{-1} and ecologically effective if it never drops below 0.10 mgL−10.10 \text{ mgL}^{-1}.

Hence, for this pollutant, find a suitable value for

P0P_0.

[1]
(g)(ii)

TT.

[1]
(h)

For the values of P0P_0 and TT found in part (g), find the proportion of time for which the concentration of the pollutant is at least 0.10 mgL−10.10 \text{ mgL}^{-1} between the first and second discharges.

[2]
(i)

Suggest a reason why the environmental regulations might specify a different value for TT to that found in part (g)(ii).

[1]

Question 19

MediumPaper 2 · calculator16 marks
(a)

A chemical reaction's rate is modelled by the differential equation dydx=2yx\frac{dy}{dx} = \frac{2y}{x}, where yy represents the concentration of a product at time xx (in minutes), for x>0x > 0 and y>0y > 0. At x=1x = 1 minute, the concentration is y=3y = 3 units.

(a) Use Euler's method with a step size of 0.50.5 to find an approximation for the concentration at x=2x = 2 minutes. For each value of xx, show the corresponding value of yy in your working.

[5]
(b)

(b) Solve the differential equation dydx=2yx\frac{dy}{dx} = \frac{2y}{x}, giving the answer in the form y=f(x)y = f(x) for some function ff.

[7]
(c)

(c) Hence, find the exact value of the concentration at x=2x = 2 minutes.

[2]
(d)

(d) Find the absolute percentage error in the value of y(2)y(2) given by Euler's method. Give your answer to 22 significant figures.

[2]

Question 20

HardPaper 3 · calculator28 marks
(a)(i)

A small scientific probe is launched into a dense liquid to collect data. Its descent is affected by gravity, buoyancy, and liquid resistance. The direction downwards is taken to be positive.

Initially, a simple model for the probe's velocity, vv ms−1^{-1}, at time tt seconds, assumes constant effective acceleration due to gravity and buoyancy, g′g' ms−2^{-2}, given by:

dvdt=g′\frac{dv}{dt} = g'

When the probe enters the liquid at s=0s = 0 m, its initial velocity is v=5v = 5 ms−1^{-1}. The displacement from its initial position is ss metres.

(i) Use the chain rule to show that dvdt=vdvds\frac{dv}{dt} = v\frac{dv}{ds}.

[1]
(a)(ii)

(ii) Assuming that g′g' is a constant, solve the differential equation vdvds=g′v\frac{dv}{ds} = g' to find vv as a function of ss.

[4]
(a)(iii)

(iii) Using g′=9.8g' = 9.8 ms−2^{-2}, determine whether the model predicts that the probe will reach a velocity of 1515 ms−1^{-1} at some point before it reaches a depth of s=200s = 200 m. Justify your answer.

[3]
(b)(i)

To test the model dvdt=g′\frac{dv}{dt}=g', the probe conducted a trial descent, and data for vv against tt was recorded.

(i) If the model is correct, describe the shape of the graph of vv against tt.

[2]
(b)(ii)
Graph of velocity v against time t, showing a curve that increases with decreasing slope.

(ii) The observed data showed a graph where the velocity increased rapidly at first, then its rate of increase slowed down, eventually approaching a constant value. Use this observation to comment on the validity of the model in part (a).

[1]
(c)(i)

An improved model considers liquid resistance, using

dvdt=g′−k′v2\frac{dv}{dt} = g'-k'v^2

where k′k' is a positive constant. You are reminded that initially s=0s = 0 and v=5v = 5. You may assume that g′−k′v2>0g' - k'v^2 > 0.

(i) By using dvdt=vdvds\frac{dv}{dt} = v\frac{dv}{ds}, solve the differential equation to find vv in terms of ss, g′g' and k′k'.

[5]
(c)(ii)

The probe's engineers use the graph of vv against tt from the trial descent to estimate the value of k′k'.

(ii) The gradient dvdt\frac{dv}{dt} is estimated to be 3.053.05 ms−2^{-2} when v=15v = 15 ms−1^{-1}. Taking g′g' to be 9.89.8 ms−2^{-2}, use this information to show that the engineers found that k′=0.03k' = 0.03.

[2]
(c)(iii)

(iii) Hence, find the value of vv predicted by this model, as ss tends to infinity.

[2]
(c)(iv)

(iv) Find the upper bound for the velocity according to this model, given that 0<s≤2000 < s \le 200. Give your answer to four significant figures.

[2]
(d)

(d) A more refined model for the probe's descent suggests that the rate of change of velocity with respect to displacement is given by dvds=5000(1000−s)2−0.0001v2\frac{dv}{ds} = \frac{5000}{(1000-s)^2} - 0.0001 v^2. Use Euler's method with a step length of 5050 m to estimate the value of vv when s=200s = 200 m. Take the initial velocity v=5v = 5 ms−1^{-1} at s=0s = 0 m.

[4]
(e)(i)

(i) Suggest one improvement to the use of Euler's method which might increase the accuracy of the prediction of the model.

[1]
(e)(ii)

(ii) Suggest one factor not explicitly considered by the model in part (d) which might lead to a difference between the model's prediction and the data collected.

[1]

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What does 1st order Differential equations (separable method) cover in IB Maths AI?

Differential Equations: Equations relating a function with its derivatives, used for modeling. Separation of Variables: Analytical method for first-order differential equations where variables can be separated. Separable Differential Equation Form: (dy)/(dx) = g(x)h(y).

Is 1st order Differential equations (separable method) SL or HL?

1st order Differential equations (separable method) is HL only. SL students are not examined on it.

How do I revise 1st order Differential equations (separable method) for IB Maths AI?

Start from the core idea: differential Equations: Equations relating a function with its derivatives, used for modeling. In the exam: two skills stacked on each other: translating a verbal proportionality statement into dfracdydx = ky or similar, then solving it by separating the variables and integrating both sides. The general-solution wording matters for mark schemes, since a question that gives a boundary condition expects the constant to be found and substituted back in, and stopping at the general solution loses that final mark. Then practise exam-style questions, easiest first, writing out every step of your working before you check it.

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