Venn diagrams, tree diagrams, probability tables (+ notation & combined & mutually exclusive events): notes and practice questions
Probability uses diagrams and notation to model combined events.
- Mutually Exclusive Events: Cannot occur together. . So, .
- Independent Events: Outcome of one does not affect others. .
- Set Notation:
- Union (): "A or B or both".
- Intersection (): "A and B".
- Complement (): "Not A".
- Addition Rule: .
- Conditional Probability: .
- Alternative Rule: .
- Venn Diagrams: Use overlapping circles to show event relationships. Fill intersection first.
- Tree Diagrams: Show sequences of events. Multiply along branches for intersections, add paths for unions.
How it is examined
A guaranteed question. Tree diagrams with and without replacement are the most common form, and the second-stage probabilities changing is the whole point of the "without replacement" version. Because a diagram alone is an acceptable solution, a mark scheme has to award the diagram, which matters for handwritten answers. Testing independence means checking and stating the conclusion, and students often compute without concluding.
The combined events rule, the conditional probability rule, and the independence condition.
- The use of Venn diagrams, tree diagrams, sample space diagrams and tables of outcomes to calculate probabilities.
- Combined events, .
- Mutually exclusive events, .
- Conditional probability, .
Linking questions
- Aim 8: the gambling issue, and the use of probability in casinos. Could or should mathematics help increase incomes in gambling?
- TOK: can calculating gambling probabilities be considered an ethical application of mathematics? Should mathematicians be held responsible for unethical applications of their work?
Practice questions
23 questions · 18 medium · 5 hardQuestion 1
MediumPaper 1 · calculator6 marksA bakery produced a batch of 200 loaves of bread, consisting of sourdough and rye. The sales outcomes for these loaves are shown in the following table.
| Sold | Unsold | |
|---|---|---|
| Sourdough | 45 | 30 |
| Rye | 60 | 65 |
(a) Find the probability that a randomly chosen loaf from this batch was sold by the bakery.
A loaf is chosen at random from this batch. It is found that this loaf was sold.
(b) Find the probability that the loaf was a sourdough loaf.
Two different loaves are chosen at random from the original batch of 200 loaves.
(c) Find the probability that both loaves were rye.
To find the probability of an event, divide the number of favourable outcomes by the total number of possible outcomes. First, determine the total number of loaves sold.
This is a conditional probability problem. You are given that the loaf was sold, so your sample space is reduced to only the sold loaves. Then, find the number of sourdough loaves among those sold.
This involves probability without replacement. Calculate the probability of the first loaf being rye, then consider how the total number of loaves and the number of rye loaves changes for the second selection.
Question 2
HardPaper 1 · calculator6 marksA board game involves drawing cards from a special deck. Each card has a score printed on it. The possible scores are . The following table shows the probability distribution for the score, , when a card is drawn.
Score
(a) Find the exact value of .
(b) Calculate the expected score when drawing one card.
A player draws two cards from the deck, replacing the first card before drawing the second. Find the probability that the total score from the two cards is .
Remember that the sum of all probabilities in a probability distribution must equal 1.
The expected value is calculated by summing the product of each score and its corresponding probability: .
List all possible pairs of scores such that . Since the cards are replaced, the draws are independent events.
Question 3
MediumPaper 1 · calculator7 marksA game involves two stages. First, a player draws a marble from a bag containing 3 red marbles and 2 blue marbles. After drawing a marble, the player spins a fair three-sided spinner with sections labeled 1, 2, and 3.
If a red marble is drawn, the player's final score is the number shown on the spinner.
If a blue marble is drawn, the player's final score is two more than the number shown on the spinner.
Find the probability that a player's final score is 4.
Complete the following table, showing the probability distribution of the final score.
| Final score () | 1 | 2 | 3 | 4 | 5 |
|---|---|---|---|---|---|
| Probability P() |
Calculate the expected value of the player's final score.
Consider the specific marble color and spinner outcome that would lead to a final score of 4. Calculate the probability of each event and then combine them.
List all possible combinations of marble drawn and spinner outcome. For each final score, identify all combinations that lead to it and sum their probabilities. Remember that the sum of all probabilities must be 1.
The expected value E(X) is calculated by summing the product of each possible score and its corresponding probability: E(X) = .
Question 4
HardPaper 2 · calculator19 marksA manufacturing company inspects the first 50 items produced each morning for defects.
(a) State the sampling method being used.
The company uses an automated machine to test products for defects. This machine is not perfect.
It is known that 3% of all products manufactured are defective (D).
If a product is defective, the machine correctly identifies it as defective (tests positive, ) 98% of the time.
If a product is not defective (D'), the machine incorrectly identifies it as defective (tests positive, ) 1% of the time.
The tree diagram shows some of this information.

(b) (i) Write down the value of .
(ii) Write down the value of .
(iii) Write down the value of .
(iv) Write down the value of .
(c) Use the tree diagram to find the probability that a randomly selected product:
(i) is not defective and tests positive.
(ii) tests negative.
(iii) is defective given that it tested negative.
(d) The company finds the actual number of defective products in their sample is different than predicted by the tree diagram. Explain why this might be the case.
(e) The factory manager surveyed all employees on a particular shift. All employees on this shift worked in at least one of these departments: Assembly (A), Painting (P), or Quality Control (Q). It was found that:
- 85 employees worked in Assembly;
- 55 employees worked in Painting;
- 35 employees worked in Quality Control;
- 10 employees worked in all three departments;
- 20 employees worked in Assembly and Quality Control but not Painting;
- 15 employees worked in Assembly and Painting but not Quality Control;
- 4 employees worked only in Quality Control.
Draw a Venn diagram to illustrate this information, placing all relevant information on the diagram.
(f) Find the total number of employees on this shift.
Consider how the sample is chosen. Is it completely random, or is there a specific, non-random criterion for selection?
The sum of probabilities for all possible outcomes at any branch point must be 1.
The sum of probabilities for all possible outcomes at any branch point must be 1. If is given, how can you find ?
This value is directly given in the problem description.
The sum of probabilities for all possible outcomes at any branch point must be 1. If is given, how can you find ?
To find the probability of two independent events both occurring, multiply their individual probabilities.
A product can test negative in two ways: it is defective and tests negative, or it is not defective and tests negative. Sum these probabilities.
This is a conditional probability problem. Recall Bayes' Theorem: .
Consider the nature of the sampling method used and how it relates to the entire population of products.
Start by filling in the innermost region (the intersection of all three sets) and then work outwards to the two-set intersections and single-set regions. Remember that 'only' means not in any other specified set.
Sum the numbers in all the distinct regions of your Venn diagram.
Question 5
MediumPaper 1 · calculator6 marksA local university collects data on student performance in two elective courses: 'Introduction to Robotics' (R) and 'Advanced Data Structures' (D). It is found that the event a student passes Robotics is independent of the event a student passes Data Structures.
The probability that a student passes both courses is , and the probability that a student fails Robotics but passes Data Structures is .
Find the probability that a student either fails Introduction to Robotics or passes Advanced Data Structures (or both).
Recall the properties of independent events, the relationship between intersection and union, and how to use complements in probability. Start by finding the individual probabilities of passing each course.
Question 6
HardPaper 2 · calculator14 marksThe diameter of a certain type of industrial component is modelled by a normal distribution with a mean of mm and a standard deviation of mm.
Find the probability that a randomly selected component has a diameter less than mm.
Find the probability that a randomly selected component has a diameter greater than mm.
Assuming the diameters of components are independent, find the probability that two consecutive components both have a diameter greater than mm.
A component is classified as 'premium' if its diameter is between mm and mm. A batch of three components is considered 'high quality' if all three components in the batch are premium. Find the probability that a randomly selected batch is NOT high quality.
In a production run, batches of three components are produced. Find the probability that at least of these batches are high quality.
Find the probability that between and (exclusive of ) of these batches are high quality.
Given that at least batches are high quality, find the probability that less than batches are high quality.
Use the normal cumulative distribution function (CDF) on your GDC. Remember that is directly calculated by the CDF.
Use the normal cumulative distribution function (CDF) or the normal survival function (SF) on your GDC. Remember that .
For independent events and , the probability of both occurring is .
First, find the probability that a single component is 'premium'. Then, use this to find the probability that a batch of three is 'high quality'. Finally, calculate the complementary probability.
This scenario involves a fixed number of trials (batches), each with two possible outcomes (high quality or not), and the trials are independent. This suggests a binomial distribution. Remember .
This means finding , which is equivalent to .
This is a conditional probability problem: . Here, is 'less than batches are high quality' and is 'at least batches are high quality'. The intersection is 'between and (exclusive of ) batches are high quality'.
Question 7
MediumPaper 1 · calculator8 marksIn a survey of students at a local college, it was found that the probability a student studies Art (event ) is . The probability a student studies Biology (event ) is . The probability that a student studies either Art or Biology or both is .
(a) Calculate the probability that a randomly selected student studies Biology but not Art.
(b) Determine the probability that a randomly selected student studies Art or does not study Biology.
(c) Find the probability that a randomly selected student does not study both Art and Biology.
Start by finding the probability that a student studies both Art and Biology using the formula for the union of two events.
Consider the complement of event B, . Then use the formula for the union of and , or consider regions in a Venn diagram.
This involves the complement of the intersection of A and B.
Question 8
HardPaper 2 · calculator17 marksA company manufactures custom-designed shelving units. The number of shelf segments in a unit is determined by a "tier number", . The th tier number, , represents the total number of individual shelf segments required to build a triangular display unit with levels, and is defined as .
Calculate the total number of shelf segments required for a unit with 6 levels, .
Determine the formula for in the form .
A designer combines two units: one with 5 levels and another with 4 levels. Find the total number of shelf segments needed, .
Find the simplest expression for the total number of shelf segments required if a designer combines a unit with levels and another with levels, i.e., .
In a quality control batch, there are 15 standard shelf segments and 10 reinforced shelf segments. Two segments are chosen at random from the batch without replacement.
Calculate the probability that the two segments are of different types (one standard, one reinforced).
A new batch of shelf segments contains standard segments and reinforced segments. Two segments are chosen at random from the batch without replacement.
Show that the probability that the two segments are of different types is independent of .
Recall the definition of as a sum. You can either sum the first 6 natural numbers directly or use the formula for the sum of an arithmetic series.
The sum is an arithmetic series. Use the formula for the sum of an arithmetic series, or , where and . Then expand and simplify to match the given form.
First, calculate and using the definition or formula from part (a). Then, add these values together.
Substitute the formula for from part (a.ii) and the corresponding expression for into the sum. Then, simplify the algebraic expression.
Consider the two possible orders for drawing different types of segments: (Standard then Reinforced) or (Reinforced then Standard). Calculate the probability for each order and then add them together. Remember to adjust the total number of segments for the second draw since it's without replacement.
Use the formula for the probability of drawing two different types, similar to part (c), but using and . Substitute the expressions for and and the simplified expression for from part (b.ii). Simplify the resulting algebraic expression to show that cancels out.
Question 9
MediumPaper 1 · calculator8 marksIn a survey of students at a high school, data was collected on their subject choices. It was found that students were studying Mathematics, and students were studying Physics.
Every student surveyed was studying at least one of these two subjects.
(a) Determine how many students were studying both Mathematics and Physics.
(b) Find the probability that a randomly selected student studies Mathematics, but not Physics.
(c) Explain why the events "studying Mathematics" and "studying Physics" are not independent events.
Recall the formula for the union of two sets: .
First, find the number of students who study Mathematics only. Then divide by the total number of students.
For two events and to be independent, must equal . Calculate these values and compare them.
Question 10
HardPaper 2 · calculator15 marksTech Solutions Inc. is a customer support company. They are analyzing their call center efficiency. Over a long period, they collect data on the number of calls, , already in the queue when a new customer's call arrives. The probability distribution of is shown in the following table.
| Number of calls in queue, | 0 | 1 | 2 | 3 | |
|---|---|---|---|---|---|
| P() | 0.15 | 0.30 | 0.35 | 0.20 | 0 |
Find the probability that there are at least two calls in the queue when a new customer's call arrives.
Find E().
The time in seconds, , taken to resolve a single customer's issue can be modelled by the normal distribution .
The company's management estimates that the expected total time a new customer will wait before their issue is resolved can be found by calculating E() E().
Find the value of E() E().
The company considers a service time to be 'long' if it takes more than three minutes to resolve a single customer's issue.
Using the distribution of given above, find the probability that it takes more than three minutes to resolve a randomly selected customer's issue.
Find the probability it takes more than four minutes in total to resolve two randomly selected customers' issues. You may assume all service times are independent of all other service times.
The company assumes that when a new customer's call arrives, the person at the front of the queue has only just reached a support agent. They also assume that if there are three or more customers already in the queue, the new customer will definitely wait more than three minutes before being served.
Using these assumptions and the probabilities for given in the table above,
find the probability a customer just arriving at the call center will wait more than three minutes before being served.
The company has a policy to employ more staff if the probability that a customer has to wait more than three minutes before being served is greater than .
Hence state whether Tech Solutions Inc. will decide to employ more staff.
To find the probability of 'at least two calls', sum the probabilities for and .
The expected value E() is calculated as the sum of (each value of its corresponding probability ).
Recall that for a normal distribution , the expected value E() is simply . Then multiply this by E() found in part (a.ii).
Convert three minutes to seconds. Then use your GDC to find for the given normal distribution.
If and are independent normal random variables, then their sum is also a normal random variable. The mean of the sum is the sum of the means, and the variance of the sum is the sum of the variances.
Consider the different scenarios for the number of customers in the queue ().
If , the wait time is 0.
If , the wait time is .
If , the wait time is .
If , the wait time is assumed to be minutes.
Compare the probability calculated in part (e.i) with the threshold of .
Question 11
MediumPaper 2 · calculator12 marksA group of students were surveyed about their participation in three extracurricular clubs: Environmental Club (E), Music Club (M), and Theater Club (T). The probabilities of their participation are represented in the Venn diagram below.
| Region | Probability |
|---|---|
| P(E only) | 0.18 |
| P(M only) | 0.23 |
| P(T only) | 0.15 |
| P(E M only) | 0.12 |
| P(E T only) | 0 |
| P(M T only) | 0.05 |
| P(E M T) | 0 |
| P(Neither E, M, nor T) | 0.27 |
Justify that events M and T are not independent.
Explain why events E and T are mutually exclusive.
Determine whether events E and M are independent.
Determine whether events E' and M' are mutually exclusive.
Find P(T E').
For two events to be independent, the probability of their intersection must be equal to the product of their individual probabilities. Calculate both sides and compare.
Recall the definition of mutually exclusive events in terms of their intersection.
Calculate P(E), P(M), and P(E M) from the Venn diagram. Then check the condition for independence.
Events E' and M' are mutually exclusive if P(E' M') = 0. Recall that E' M' is equivalent to (E M)'.
P(T E') means the probability of a student being in the Theater Club but NOT in the Environmental Club. Identify the regions that satisfy this condition.
Question 12
MediumPaper 1 · calculator7 marksA quality control team at a manufacturing plant inspects newly produced widgets. The probability that a single widget has a detectable defect is . The inspections are independent events.
(a) Find an expression for the probability that at least one defect is detected in inspections.
(b) Hence, determine the least number of inspections required for the probability of detecting at least one defect to be greater than .
Consider the complementary event: what is the probability that no defects are detected in inspections?
Set up an inequality using your expression from part (a) and solve for . Remember to use logarithms and consider how the inequality sign changes when dividing by a negative number.
Question 13
MediumPaper 2 · calculator9 marksA factory produces two types of electronic components: Type A and Type B. of the components produced are Type A, and the remaining are Type B. The probability that a Type A component is defective is , and the probability that a Type B component is defective is . A component is chosen at random from the production line.
(a) Calculate the probability that the chosen component is defective.
(b) Calculate the probability that the chosen component is Type A and is defective.
(c) Calculate the probability that the chosen component is Type B or is defective.
Consider using a tree diagram or the law of total probability. Let D be the event that a component is defective.
Think about the definition of conditional probability and how it relates to the probability of an intersection.
Remember the addition rule for probability: P(X or Y) = P(X) + P(Y) - P(X and Y). You'll need to find P(B and D) first.
Question 14
MediumPaper 2 · calculator7 marksA new mobile game, "Fantasy Quest", involves players drawing two cards to determine their turn's action and reward.
- Action Card Deck: Contains three types of cards: 'Attack' (A), 'Defend' (D), and 'Heal' (H). The probabilities are: P(A) = 0.5, P(D) = 0.3, P(H) = 0.2.
- Reward Card Deck: Contains two types of cards: 'Gold' (G) and 'Experience Points' (XP). The probabilities are: P(G) = 0.6, P(XP) = 0.4.
A player draws one card from each deck. The outcome of a turn is the combination of the Action card and the Reward card. Assume the draws are independent.
(a) Construct a probability table showing all possible outcomes and their associated probabilities.
(b) Calculate the probability that a player draws an 'Attack' card and receives 'Gold'.
(c) Calculate the probability that a player's turn involves either a 'Defend' action or receiving 'XP' (or both).
List all possible combinations of one action card and one reward card. Since the draws are independent, multiply their individual probabilities to find the probability of each combined outcome.
Refer to the probability table you constructed in part (a) to find the specific combined outcome.
You can use the formula P(A or B) = P(A) + P(B) - P(A and B), or sum the probabilities of all outcomes that satisfy the condition from your table.
Question 15
MediumPaper 1 · calculator6 marksA collector has a box containing 20 vintage stamps. Of these, 4 are considered rare editions.
Three stamps are randomly selected from the box.
(a) Find the probability that exactly one of the selected stamps is a rare edition.
(b) Find the probability that at least one of the selected stamps is a rare edition.
Consider using combinations to find the number of ways to select the rare stamp and the common stamps, and the total number of ways to select any three stamps.
Consider calculating the complementary event: the probability that none of the selected stamps are rare, and subtract this from 1.
Question 16
MediumPaper 1 · calculator6 marksA museum curator is selecting items for a new exhibit. From a collection of artifacts, are classified as ancient, and the remaining are modern. The curator randomly selects artifacts from the collection.
(a) Find the probability that exactly one of the selected artifacts is ancient.
(b) Find the probability that at least one of the selected artifacts is ancient.
To find the probability of selecting exactly one ancient artifact, consider the number of ways to choose one ancient artifact and one modern artifact, and divide this by the total number of ways to choose two artifacts from the collection.
The event 'at least one ancient artifact' can be calculated by summing the probabilities of 'exactly one ancient' and 'exactly two ancient', or by subtracting the probability of 'no ancient artifacts' from 1.
Question 17
MediumPaper 1 · calculator8 marksIn a survey, students were asked about their participation in extracurricular clubs. It was found that students were members of the Robotics Club, and students were members of the Chess Club.
Every student surveyed was a member of at least one of these two clubs.
(a) Determine how many students were members of both the Robotics Club and the Chess Club.
(b) Find the probability that a randomly selected student was a member of the Robotics Club, but not the Chess Club.
(c) Explain why the events "being a member of the Robotics Club" and "being a member of the Chess Club" are not independent events.
Use the principle of inclusion-exclusion for two sets: .
First, find the number of students who are only in the Robotics Club. Then, divide by the total number of students.
Recall the condition for two events and to be independent: . Calculate both sides of this equation and compare them.
Question 18
MediumPaper 1 · calculator8 marksA factory produces two types of electronic components: Type A and Type B. of the components produced are Type A, and are Type B. The probability that a Type A component passes a quality control test is , and the probability that a Type B component passes is . A component is chosen at random from the production line.
(a) Calculate the probability that the component passes the quality control test.
(b) Calculate the probability that the component is Type A and passes the quality control test.
(c) Calculate the probability that the component is Type B or it passes the quality control test.
To find the total probability that a component passes, consider the two mutually exclusive paths: being Type A and passing, or being Type B and passing. Use the formula for total probability.
This is a direct application of the definition of conditional probability: .
Use the formula for the probability of the union of two events: . You will need to calculate first.
Question 19
MediumPaper 1 · calculator8 marksThe discrete random variable represents the number of successful deliveries a courier makes in an hour. The probability distribution of is given by the following table:
Given that , find the values of and .
Find .
Remember that the sum of all probabilities in a distribution must equal 1. Also, use the formula for the expected value to set up a system of two linear equations in terms of and .
Recall the formula for conditional probability: . First, calculate the probabilities for each value of using the values of and found in part (a). Then, find and .
Question 20
MediumPaper 1 · calculator5 marksIn a certain school, the event that a randomly chosen student passes their final Mathematics exam, , is independent of the event that the student passes their final Physics exam, .
Given that and , find the probability that a randomly chosen student does not pass the Mathematics exam or passes the Physics exam, i.e., .
Recall the definition of independent events and how probabilities of intersections and complements are related. Consider using the complement rule for unions: . Also, remember that if events and are independent, then and are also independent.
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