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Topic 5.02 · SL and HL

Power rule: notes and practice questions

Summary
  • Differentiation is the process of finding the gradient function.
  • The Power Rule applies to functions where xx is raised to any rational power.
  • If f(x)=axnf(x) = ax^n, then f′(x)=anxn−1f'(x) = anx^{n-1}.
  • If f(x)=xnf(x) = x^n, then f′(x)=nxn−1f'(x) = nx^{n-1}.
  • If y=cy = c (where cc is a constant), then dydx=0\frac{dy}{dx} = 0.
  • Differentiate expressions that are sums or differences of powers of xx term by term.
  • Before differentiating: Rewrite all terms strictly as powers of xx.
  • Rewrite roots as fractional powers (e.g., 2x=2x122\sqrt{x} = 2x^{\frac{1}{2}}).
  • Rewrite terms with xx in the denominator as negative powers (e.g., 4x=4x−1\frac{4}{x} = 4x^{-1}).
  • Expand products and quotients into a sum or difference of powers before applying the rule.
  • To differentiate a term: Multiply the front coefficient by the current power, then subtract 1 from the power.
  • Simplify the resulting derivative, optionally rewriting negative exponents as fractions.
  • Use a GDC to verify analytical derivatives by plotting the original function and its derivative (e.g., turning points of original align with x-intercepts of derivative).
  • The power rule for all rational indices is standard for both IB SL and HL (Topic 5.1).
  • Common Pitfall: Always expand products/quotients before differentiating; do not differentiate terms within unexpanded brackets separately.
  • Common Pitfall: When subtracting 1 from a negative power, ensure correct arithmetic (e.g., −3−1=−4-3 - 1 = -4).
  • Common Pitfall: Remember that standalone constant terms differentiate to 0.

How it is examined

The only differentiation rule an SL student has, which sharply limits what an SL calculus question can look like. Writing 1x2\frac{1}{x^2} as x−2x^{-2} before differentiating is the step students miss. Anything needing a chain rule, a product, a quotient, or a fractional power is HL.

Given in the booklet

The power rule.

Key ideas
  • The derivative of f(x)=axnf(x) = ax^n, which is f′(x)=anx n−1f'(x) = anx^{\,n-1}, n∈Zn \in \mathbb{Z}.
  • The derivative of functions of the form f(x)=axn+bx n−1+…f(x) = ax^n + bx^{\,n-1} + \dots where all exponents are integers.

Linking questions

  • TOK: the seemingly abstract concept of calculus allows us to create mathematical models that permit human feats such as getting a man on the Moon. What does that tell us about the links between mathematical models and reality?

Practice questions

51 questions · 1 easy · 42 medium · 8 hard
Showing 20 of 20

Question 1

EasyPaper 1 · calculator2 marks

Find the derivative of the function f(x)=−2x−0.5f(x) = - 2x^{- 0.5}

Question 2

MediumPaper 1 · calculator6 marks
(a)

A company is designing a closed cylindrical container to hold a specific volume of liquid. The total surface area of the container, in cm2^2, with a fixed volume of 16π16\pi cm3^3 and a radius of rr cm, is given by the function A(r)=2πr2+32πrA(r) = 2\pi r^2 + \frac{32\pi}{r}, where r>0r > 0.

Find A′(r)A'(r).

[3]
(b)(i)

Solve A′(r)=0A'(r) = 0.

[2]
(b)(ii)

Interpret your answer to (b)(i) in context.

[1]

Question 3

HardPaper 1 · calculator10 marks
(a)

The concentration of a reactant A, in mg/L, in a chemical reaction over time tt (in minutes) is modelled by the function:

C(t)=−t3+15t2−48t+100C(t) = -t^3 + 15t^2 - 48t + 100, for 0≤t≤100 \le t \le 10.

(a) Find the coordinates of the local minimum point of the concentration.

[3]
(b)

(b) Find the coordinates of the local maximum point of the concentration.

[3]
(c)

(c) Find the set of values of tt for which the concentration of reactant A is above 100100 mg/L.

[4]

Question 4

MediumPaper 1 · calculator7 marks
(a)

The height of a section of a roller coaster track, in metres, can be modelled by the function h(x)=14x4−2x2h(x) = \frac{1}{4}x^4 - 2x^2, where xx is the horizontal distance in metres from a central point.

(a) Find an expression for the gradient function of the track, h′(x)h'(x).

[2]
(b)

(b) At a specific point on the track, where x=1x=1, a support beam L is tangent to the track. The coordinates of this point are (1,−74)(1, -\frac{7}{4}).

Use your answer to part (a) to find the gradient of the support beam L.

[2]
(c)

(c) Determine the number of other points on the track where the tangent line is parallel to the support beam L. Justify your answer.

[3]

Question 5

HardPaper 2 · calculator15 marks
(a)

(a) A pharmaceutical company is designing a new cylindrical container for a special liquid. The container has a fixed volume V=500 cm3V = 500 \text{ cm}^3.

The radius of the container is r cmr \text{ cm} and the height is h cmh \text{ cm}.

Show that πr2h=500\pi r^2 h = 500.

[2]
(b)

(b) Find an expression for the total surface area SS of the container.

[2]
(c)

(c) Substitute an expression for hh (from part (a) ) into your expression for SS (from part (b) ) and hence show that S=2πr2+1000rS = 2\pi r^2 + \frac{1000}{r}.

[3]
(d)

(d) Find dSdr\frac{dS}{dr}.

[2]
(e)

(e) Find the minimum value of SS and the values of rr and hh when this occurs. Show that this value of SS is indeed a minimum.

[6]

Question 6

MediumPaper 1 · calculator7 marks
(a)

A designer is creating a decorative curve for a new architectural feature. The profile of the curve can be modelled by the function f(x)=x3+4xf(x) = x^3 + \frac{4}{x}, for x≠0x \neq 0.

(a) Find f′(x)f'(x).

[3]
(b)

(b) The designer wants to place a support beam perpendicular to the curve at the point where x=1x=1. Given that the point on the curve is (1,5)(1, 5), find the equation of the normal to the curve at this point, in the form ax+by+d=0ax + by + d = 0, where a,b,d∈Za, b, d \in \mathbb{Z}.

[4]

Question 7

HardPaper 2 · calculator15 marks
(a)

A drone is launched vertically upwards from a platform. Its vertical velocity, v ms−1v \text{ ms}^{-1}, at time tt seconds, is given by the function:

v=−3t2+18t−15v = -3t^2 + 18t - 15, for t≥0t \ge 0.

Find the times when the drone is momentarily at rest.

[2]
(b)

Find the magnitude of the drone's vertical acceleration at t=5t = 5 seconds.

[4]
(c)

Find the greatest speed of the drone in the interval 0≤t≤50 \le t \le 5.

[2]
(d)

The drone starts from an initial height of 1010 metres above the ground. Find an expression for the height of the drone, hh metres, above the ground at time tt seconds.

[4]
(e)

Find the total distance travelled by the drone in the interval 0≤t≤40 \le t \le 4.

[3]

Question 8

MediumPaper 1 · calculator7 marks
(a)

The power output PP, in watts (W), of a solar panel is modelled by the equation

P=250−1.5θ0.25P = 250 - 1.5\theta^{0.25}

where θ\theta is the angle of inclination of the panel to the sun in degrees. Find an expression for dPdθ\frac{dP}{d\theta}.

[2]
(b)

At a particular moment, the solar panel is inclined at an angle of 30 degrees, and this angle is increasing at a rate of 2 degrees per minute.

Find the rate of change of the power output at this time.

[5]

Question 9

HardPaper 2 · calculator19 marks
(a)

A tech company, 'CaseCrafters', designs and sells custom phone cases. Their market research suggests that the average number of cases they will sell each month is modelled by the equation

n=15000−500xn = 15000 - 500x

where nn represents the number of cases sold and xx represents the selling price, in USD, of each case.

The marketing team proposes selling the cases for 2222 USD each.

Find the average number of phone cases that this model predicts CaseCrafters will sell at this price.

[2]
(b)

Calculate CaseCrafters' average monthly income, before any expenses, at this selling price.

[2]
(c)

Hence, write down the function R(x)R(x) that can be used to predict CaseCrafters' average monthly income, before expenses, at any selling price, xx.

[1]
(d)

CaseCrafters has 80008000 USD of fixed monthly operational costs. Additionally, CaseCrafters must pay their supplier 88 USD for each phone case.

Calculate CaseCrafters' average monthly profit if they sell each case at a price of 2222 USD.

[3]
(e)

Show that the average monthly profit for any selling price, xx, can be found using the function P(x)=−500x2+19000x−128000P(x) = -500x^2 + 19000x - 128000.

[2]
(f)(i)

Find P′(x)P'(x).

[2]
(f)(ii)

Show that the marketing team's selling price of 2222 USD does not maximize their average monthly profit.

[2]
(g)

CaseCrafters negotiates a new deal with their supplier. Under the new deal, the supplier agrees to discount the cost of each case based on the number of cases purchased by CaseCrafters. The cost charged by the supplier for each case can be found using the function

Csupplier(n)=8−0.00005nC_{\text{supplier}}(n) = 8 - 0.00005n

where nn represents the number of cases sold by CaseCrafters.

Find the function that can be used to find CaseCrafters' average monthly profit using the new deal from the supplier.

[3]
(h)

Hence, find the selling price, per case, that CaseCrafters should choose in order to maximize their average monthly profit under the new deal.

[2]

Question 10

MediumPaper 1 · calculator7 marks
(a)

A company is designing a new cylindrical storage tank. The cost of manufacturing, in thousands of dollars, is modelled by the function C(r)=r2+100rC(r) = r^2 + \frac{100}{r}, where rr is the radius of the tank in metres, and r>0r > 0.

(a) Write down the equation of the vertical asymptote of C(r)C(r).

[1]
(b)

(b) Find C′(r)C'(r).

[3]
(c)

(c) Determine the interval in which C(r)C(r) is decreasing.

[3]

Question 11

HardPaper 2 · calculator28 marks
(a)(i)

(a) (i) Consider the function f(x)=x3f(x) = x^3. Find f′(x)f'(x).

[1]
(a)(ii)

(ii) The first section of the stone wall's profile is given by y=f(x)y = f(x) for 0≤x≤0.50 \le x \le 0.5. A straight glass panel is to be installed tangent to this section of the wall at the point where x=0.5x=0.5. Find the equation of this tangent line.

[3]
(b)

The full profile of the stone wall, F(x)F(x), is defined by:

F(x)={x30≤x≤0.50.75x−0.250.5<x≤1.0F(x) = \begin{cases} x^3 & 0 \le x \le 0.5 \\ 0.75x - 0.25 & 0.5 < x \le 1.0 \end{cases}

A smaller, decorative stone insert is designed using a transformation of F(x)F(x). The graph of G(x)G(x) is obtained from the graph of F(x)F(x) by:

  • a stretch scale factor of 12\frac{1}{2} in the xx direction,
  • followed by a stretch scale factor of 12\frac{1}{2} in the yy direction,
  • followed by a translation of 0.50.5 units to the right.

Point P lies on the graph of F(x)F(x) and has coordinates (1.0,0.5)(1.0, 0.5). Point Q is the image of P under the given transformations and has coordinates (qx,qy)(q_x, q_y).

Find the value of qxq_x and the value of qyq_y.

[3]
(c)(i)

The piecewise function G(x)G(x) is given by

G(x)={k(x)c≤x≤dmx+nd<x≤qxG(x) = \begin{cases} k(x) & c \le x \le d \\ mx + n & d < x \le q_x \end{cases}

(c) Find

(i) an expression for k(x)k(x).

[4]
(c)(ii)

(ii) the value of dd.

[2]
(c)(iii)

(iii) the value of nn.

[3]
(d)(i)

(d) (i) Calculate the total area of the profile of the stone wall, enclosed by y=F(x)y = F(x), the xx-axis, and the line x=1.0x = 1.0.

[7]
(d)(ii)

The decorative insert G(x)G(x) is placed within the main wall profile F(x)F(x). The region of the main wall profile that is not covered by the insert is to be painted a contrasting colour. This region is bounded by y=F(x)y=F(x), the xx-axis, and the lines x=0x=0 and x=1x=1, excluding the area under G(x)G(x) from x=0.5x=0.5 to x=1.0x=1.0. Find the area of this region.

[5]

Question 12

MediumPaper 1 · calculator10 marks
(a)(i)

A company models the profit from a new product launch using the function P(t)=3t(2−e−t)P(t) = 3t(2 - e^{-t}), where PP is the profit in thousands of dollars and tt is the time in months since launch.

Find dPdt\frac{dP}{dt}.

[4]
(a)(ii)

Find d2Pdt2\frac{d^2P}{dt^2}.

[4]
(b)

The company observes that the rate of change of profit growth begins to slow down after a certain point, indicating a point of inflexion. Find the time, tt, in months at which this point of inflexion occurs.

[2]

Question 13

HardPaper 2 · calculator24 marks
(a)(i)

A landscape architect is designing a new public park. The northern boundary of the park is modelled by the function g(x)g(x), and other boundaries are straight lines. The plan view of the park is shown in the following diagram, where both axes represent distance and are measured in metres.

Graph showing a shaded region representing a park, bounded by a curve g(x) and straight lines, with points A, B, C, D.

The function g(x)g(x) models the northern boundary of the park between points B and C and is given by

g(x)=−110x2+4x+15g(x) = -\frac{1}{10}x^2 + 4x + 15, for 0≤x≤400 \le x \le 40.

(i) Find g′(x)g'(x).

[2]
(a)(ii)

(ii) Hence find the coordinates of the point on the park's northern boundary that is furthest north.

[3]
(b)(i)

Point A has coordinates (0,0)(0, 0), point B has coordinates (0,15)(0, 15), point C has coordinates (40,15)(40, 15) and point D has coordinates (40,0)(40, 0).

(i) Write down the integral which can be used to find the area of the shaded region representing the park.

[2]
(b)(ii)

(ii) Find the area of the park.

[2]
(c)(i)

(i) A landscaper uses the trapezoidal rule with 4 intervals to estimate the area of the park. Calculate this estimate.

[3]
(c)(ii)

(ii) Calculate the percentage error in the landscaper's estimate.

[3]
(c)(iii)

(iii) Suggest how the landscaper might be able to reduce the error whilst still using the trapezoidal rule.

[1]
(d)(i)

A square-shaped meditation garden, PQRS, is to be built within the park. The side [PS] lies on the southern boundary (x-axis), and the side [QR] lies on the eastern boundary of the park (x=40x=40). Point Q lies on the northern boundary curve g(x)g(x).

(i) Find the x-coordinate of point P for the largest area of the meditation garden.

[4]
(d)(ii)

(ii) Find the largest area of the meditation garden.

[4]

Question 14

MediumPaper 1 · calculator6 marks
(a)

A company's daily production cost, C(x)C(x), in thousands of dollars, for producing xx units of a specialized component, is modelled by the function C(x)=x2+54xC(x) = x^2 + \frac{54}{x}, for x>0x > 0.

Write down the equation of the vertical asymptote of C(x)C(x).

[1]
(b)

Find C′(x)C'(x), the marginal cost function.

[3]
(c)

Determine the interval for xx where the production cost C(x)C(x) is increasing.

[2]

Question 15

HardPaper 2 · calculator23 marks
(a)

(a) A confectionery company is designing a new wrapper for a chocolate bar. The wrapper is in the shape of a rectangular prism with a square base of side length xx cm. The height, hh cm, is twice the side length of the base.

Write down an expression for hh in terms of xx.

[1]
(b)

(b) The chocolate bar has a volume of 250250 cm3^3.

Find the value of xx and hh.

[3]
(c)

(c) Calculate the total external surface area of this rectangular prism wrapper.

[3]
(d)

(d) The company also considers a cylindrical wrapper with radius rr cm and height HH cm. This wrapper must also hold 250250 cm3^3 of chocolate.

Find an expression for the height, HH, of the cylindrical wrapper in terms of rr.

[2]
(e)

(e) Let the total external surface area of the cylindrical wrapper be AA cm2^2.

Show that A=2πr2+500rA = 2\pi r^2 + \frac{500}{r}.

[2]
(f)

(f) Find dAdr\frac{dA}{dr}.

[3]
(g)(i)

(g.i) Hence or otherwise, find the value of rr that will minimize AA.

[3]
(g)(ii)

(g.ii) Find the minimum value of AA for the cylindrical wrapper.

[3]
(h)

(h) To account for manufacturing waste and overlap, an additional 12%12\% of the calculated surface area is required for the rectangular prism wrapper, and 20%20\% for the cylindrical wrapper.

Determine which wrapper design the company should choose to minimize material usage. Justify your answer.

[3]

Question 16

MediumPaper 1 · calculator9 marks
(a)(i)

A spherical ice sculpture is melting in a gallery. Initially, the sculpture has a radius of 30 cm. This information is illustrated in the following diagram.

diagram not to scale. Image of a spherical ice sculpture with a radius of 30 cm.

The gallery curator predicts that, as the ice sculpture melts, its radius will decrease at a constant rate of 0.5 cm per hour.

According to this model, find

(i) the radius of the ice sculpture, 10 hours after it begins melting.

[2]
(a)(ii)

(ii) the volume of the ice sculpture, 10 hours after it begins melting. Give your answer to one decimal place.

[2]
(b)

Let the function V(t)V(t) represent the volume of the ice sculpture, cm3\text{cm}^3, tt hours after it begins melting. V(t)V(t) is given by

V(t)=113000−5000t+150t2−1.5t3V(t) = 113000 - 5000t + 150t^2 - 1.5t^3, for 0≤t≤200 \le t \le 20.

Find V′(t)V'(t).

[2]
(c)

Find the rate of change of the volume of the ice sculpture at t=10t = 10 hours.

[2]
(d)

State one reason why the radius of the ice sculpture may not always decrease at a constant rate.

[1]

Question 17

HardPaper 2 · calculator20 marks
(a)

(a) SweetTreats is designing new packaging for a line of artisanal chocolates. The initial design is a box in the shape of a cuboid with a square base of side length LL cm. Its height, HH cm, is twice the length of the base.

Write down an expression for HH in terms of LL.

[1]
(b)

(b) The box is designed to hold 250250 cm3^3 of chocolates.

Find the value of LL and HH.

[3]
(c)

(c) Calculate the total external surface area of the box.

[3]
(d)

(d) To minimize the amount of material needed, SweetTreats is considering changing the shape to a cylinder with radius rr cm and height hh cm. The cylindrical container must also hold 250250 cm3^3 of chocolates.

Find an expression for the height, hh, of the container in terms of rr.

[2]
(e)

(e) Let the total external surface area of the cylindrical container be AA cm2^2.

Show that A=2πr2+500rA = 2\pi r^2 + \frac{500}{r}.

[2]
(f)

(f) Find dAdr\frac{\text{d}A}{\text{d}r}.

[3]
(g)(i)

(g.i) Hence or otherwise, find the value of rr that will minimize AA.

[2]
(g)(ii)

(g.ii) Find the minimum value of AA needed for the cylinder.

[1]
(h)(i)

(h.i) Find d2Adr2\frac{\text{d}^2 A}{\text{d}r^2}.

[1]
(h)(ii)

(h.ii) Hence determine whether the graph of AA is concave-up or concave-down for r>0r > 0. Justify your answer.

[2]

Question 18

MediumPaper 1 · calculator9 marks
(a)

A landscape architect is designing a walking path in a new park. The path consists of three segments. The first segment is a straight path connecting point A(0, 0) to point B(2, 4).

Graph of a walking path with three segments, including points (-2,2), (0,0), (2,4), (5,1)

Write down the equation of the line segment for 0≤x≤20 \leq x \leq 2.

[1]
(b)

A curved section of the path, modeled by a quadratic function, connects point C(-2, 2) to point A(0, 0). At point A(0, 0), the curve has the same gradient as the straight path segment AB.

Find the equation of the curve between (-2, 2) and (0, 0).

[3]
(c)

The second curved section of the path, also modeled by a quadratic function, connects point B(2, 4) to point D(5, 1). At point B(2, 4), the curve has the same gradient as the straight path segment AB.

Find the equation of this curve.

[4]
(d)

Write down the equation of the entire walking path as a piecewise function, P(x)P(x).

[1]

Question 19

MediumPaper 1 · calculator7 marks

A civil engineer is designing a parabolic arch for a new bridge. The cross-section of the arch can be modelled by the curve y=ax2+bx−7y = ax^2 + bx - 7. The arch passes through the point P(1, -2). At this point, the gradient of the normal to the curve is −14-\frac{1}{4}.

Calculate the value of aa and the value of bb.

Question 20

MediumPaper 1 · calculator7 marks
(a)

12. [Maximum mark: 7]

The path of a small drone flying over a landscape can be modelled by the curve with equation y=3x2−8x2y = 3x^2 - \frac{8}{x^2}, where xx is the horizontal distance in meters from a reference point and yy is the altitude in meters.

(a) Find dydx\frac{dy}{dx}.

[3]
(b)

(b) Write down the gradient of the path when the drone is at a horizontal distance of x=2x = 2 meters.

[1]
(c)

(c) Hence, find the equation of the normal to the drone's path at x=2x = 2.

[3]

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What does Power rule cover in IB Maths AI?

Differentiation is the process of finding the gradient function. The Power Rule applies to functions where x is raised to any rational power. If f(x) = ax^n, then f'(x) = anx^n-1.

Is Power rule SL or HL?

Both. SL and HL students study Power rule to the same depth.

How do I revise Power rule for IB Maths AI?

Start from the core idea: differentiation is the process of finding the gradient function. In the exam: the only differentiation rule an SL student has, which sharply limits what an SL calculus question can look like. Writing (1)/(x^2) as x^-2 before differentiating is the step students miss. Then practise exam-style questions, easiest first, writing out every step of your working before you check it.

How does FourtyFive help me practise Power rule?

FourtyFive has 51 Power rule questions. Every answer you write is marked mark by mark, IB-style, and you see where each mark was won or lost. Every part has a hint, the AI tutor helps you through the step you are stuck on, and your Study Profile picks what to practise next.

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