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Topic 3.12 · HL only

Vector basics (position, displacement vectors, components ijk, rescaling/normalising vectors): notes and practice questions

Summary
  • Scalar: quantity with magnitude only. Vector: quantity with magnitude and direction.
  • Vector notation: bold lowercase (e.g., a) or arrow over points (e.g., AB⃗\vec{AB}).
  • Parallel vectors: a=kba = kb where kk is a scalar constant.
  • Column vector representation:

(xyz) \begin{pmatrix} x \\ y \\ z \end{pmatrix}

  • Base vector representation: xi+yj+zkxi + yj + zk. (e.g., (50−2)=5i−2k\begin{pmatrix} 5 \\ 0 \\ -2 \end{pmatrix} = 5i - 2k).
  • Position vector (OA⃗\vec{OA} or aa): describes a point's location from the origin; components match point coordinates.
  • Displacement vector (AB⃗\vec{AB}): describes the shortest route, distance, and direction between two points.
  • Displacement calculation:

AB⃗=OB⃗−OA⃗=b−a \vec{AB} = \vec{OB} - \vec{OA} = b - a

  • Vector addition/subtraction (numerically): Add/subtract corresponding components.

(3−5)+(−27)=(12) \begin{pmatrix} 3 \\ -5 \end{pmatrix} + \begin{pmatrix} -2 \\ 7 \end{pmatrix} = \begin{pmatrix} 1 \\ 2 \end{pmatrix}

  • Vector addition (geometrically): "Nose to tail" method; resultant from start of first to end of last.
  • Magnitude (∣v∣|v| or ∣AB⃗∣|\vec{AB}|): the length or size of a vector.
  • Magnitude formula:

∣v∣=v12+v22+v32 |v| = \sqrt{v_1^2 + v_2^2 + v_3^2}
(Square negative signs inside the formula).

  • Unit vector: a vector with a magnitude of exactly 1.
  • Normalising a vector: rescaling it to a length of 1 while maintaining its direction.
  • Unit vector formula:

Unit Vector=v∣v∣ \text{Unit Vector} = \frac{v}{|v|}

  • GDC tip: Enter column vectors as matrices (3×13 \times 1 or 2×12 \times 1) for operations.
  • GDC tip: Verify parallel vectors by dividing corresponding components to check for a constant scalar kk.

How it is examined

The rescaling example above is the archetype: normalise a direction, multiply by a speed. Column and ijk\boldsymbol{i}\boldsymbol{j}\boldsymbol{k} notation are both accepted, so a mark scheme has to allow either. Vectors here are the foundation for AHL 3.11 to 3.13, and most exam questions reach one of those rather than stopping at pure vector arithmetic.

Given in the booklet

The magnitude of a vector in component form.

Key ideas
  • The concept of a vector and a scalar.
  • The representation of vectors using directed line segments.
  • Unit vectors and base vectors i\boldsymbol{i}, j\boldsymbol{j}, k\boldsymbol{k}.
  • Components of a vector, and column representation, v=(v1v2v3)=v1i+v2j+v3k\boldsymbol{v} = \begin{pmatrix} v_1 \\ v_2 \\ v_3 \end{pmatrix} = v_1\boldsymbol{i} + v_2\boldsymbol{j} + v_3\boldsymbol{k}.

Linking questions

  • Links to other subjects: vector sums, differences and resultants (physics).
  • Aims: vector theory is used for tracking displacement of objects, including peaceful and harmful purposes.
  • TOK: vectors are used to solve many problems in position location. That can save a lost sailor or destroy a building with a laser-guided bomb. To what extent does possessing knowledge carry an ethical obligation?

Practice questions

25 questions · 1 easy · 18 medium · 6 hard
Showing 20 of 20

Question 1

EasyPaper 1 · calculator6 marks
(a)

Consider the points A(1,2,5), B(7,3,0)A(1,2,5),\ B(7,3,0) and C(4,6,2)C(4,6,2) and take all distances to be measured in meters.

aa Find AB→\overrightarrow{AB} and AC→\overrightarrow{AC}.

[2]
(b)

aa Find the area of triangle ABC.

[4]

Question 2

MediumPaper 1 · calculator10 marks
(a)

A high-tech drone is launched from a control tower at coordinates (1.5, 2.0, 0.8) relative to the base of the tower at the origin O. The x direction is due east, the y direction is due north, and the z direction is vertically upwards.

All distances are measured in kilometres.

The drone travels with a constant velocity, and its direction of travel is given by the vector (−1−2−0.4)\begin{pmatrix} -1 \\ -2 \\ -0.4 \end{pmatrix}.

Assuming the drone travels in a straight line, write down an equation for the line along which it travels.

[2]
(b)(i)

The drone is programmed to land on a designated pad at ground level (where z=0z=0 ).

(i) Find the value of the parameter λ\lambda when the drone reaches ground level.

[2]
(b)(ii)

The drone is programmed to land on a designated pad at ground level (where z=0z=0 ).

(ii) Determine the coordinates of the landing pad.

[3]
(c)

Calculate the distance the drone travels from its initial position to the landing pad.

[3]

Question 3

HardPaper 2 · calculator13 marks
(a)

(a) The position of a reconnaissance drone, relative to a control tower, is given by the vector equation r=(72)+t(−34)r = \begin{pmatrix} 7 \\ 2 \end{pmatrix} + t \begin{pmatrix} -3 \\ 4 \end{pmatrix}, where rr is the position vector in metres and tt is the time in minutes.

Write down the position vector of the drone when t=0t = 0 and when t=1t = 1.

[2]
(b)

(b) Calculate the speed of the drone.

[3]
(c)

(c) Find an expression for the distance of the drone from the origin at time tt.

[3]
(d)

(d) Hence find the minimum distance of the drone from the origin and the time at which it occurs.

[5]

Question 4

MediumPaper 1 · calculator10 marks
(a)(i)

(a) A satellite dish is supported by three anchor points A, B, and C on a mast. The coordinates of these points, relative to a fixed origin, are A(1, 2, 0), B(7, 2, 0), and C(4, 6, 1), where distances are measured in metres.

(i) Find the vector CA→\overrightarrow{\text{CA}}.

[2]
(a)(ii)

(ii) Find the vector CB→\overrightarrow{\text{CB}}.

[2]
(b)

(b) Calculate CA→×CB→\overrightarrow{\text{CA}} \times \overrightarrow{\text{CB}}.

[3]
(c)

(c) Hence, determine the area of the triangular support surface formed by points A, B, and C.

[3]

Question 5

HardPaper 2 · calculator14 marks
(a)

A drone A takes off from a control tower at 10:00. It flies north-east at a horizontal speed of 702 kmh−170\sqrt{2} \text{ kmh}^{-1} and climbs at a rate of 3 kmh−13 \text{ kmh}^{-1}. At 10:00, it is at a height of 5 km5 \text{ km} directly above the control tower.

Find an expression for the displacement of drone A from the control tower at time tt hours after 10:00. Assume the control tower is at the origin (0,0,0) and the positive y-axis points North, and the positive x-axis points East.

[3]
(b)

At 10:30, a second drone B is 12 km12 \text{ km} directly above the control tower. It flies on a bearing of 300∘300^\circ at a horizontal speed of 80 kmh−180 \text{ kmh}^{-1} and descends at a rate of 2 kmh−12 \text{ kmh}^{-1}.

Find an expression for the displacement of drone B from the control tower tt hours after 10:00.

[4]
(c)

Find the distance the two drones are apart when they have the same height.

[7]

Question 6

MediumPaper 1 · calculator7 marks
(a)

A small drone is tracking a moving target. Its position vector, r⃗\vec{r}, relative to a fixed origin OO at time tt (in seconds, t≥0t \ge 0) is given by

r⃗(t)=(tcos⁡(t)tsin⁡(t))\vec{r}(t) = \begin{pmatrix} t \cos(t) \\ t \sin(t) \end{pmatrix}.

(a) Find the velocity vector of the drone, v(t)\mathbf{v}(t).

[2]
(b)

(b) Show that the velocity vector of the drone is never parallel to its position vector for t>0t > 0.

[5]

Question 7

HardPaper 2 · calculator35 marks
(a)(i)

(a) The position vector of Drone A at time tt seconds is given by rA=4cos⁡(3t)i+5sin⁡(3t)j\boldsymbol{r}_A = 4 \cos(3t)\boldsymbol{i} + 5 \sin(3t)\boldsymbol{j}, where displacement is measured in metres.

(i) Find an expression for the velocity of Drone A at time tt.

[4]
(a)(ii)

(ii) Hence, find the speed of Drone A when t=1.2t = 1.2 seconds.

[4]
(b)(i)

(b) (i) Find an expression for the acceleration of Drone A at time tt.

[4]
(b)(ii)

(ii) Show that the acceleration of Drone A is always directed towards the origin.

[4]
(c)

(c) The position vector of a second drone, Drone B, is given by rB=−5sin⁡(4t)i+4cos⁡(4t)j\boldsymbol{r}_B = -5 \sin(4t)\boldsymbol{i} + 4 \cos(4t)\boldsymbol{j}.

For 0≤t≤100 \le t \le 10, find the time when the two drones are closest to each other.

[5]
(d)(i)

(d) At time kk, where 0<k<1.50 < k < 1.5, Drone B is moving parallel to Drone A.

(i) Find the value of kk.

[7]
(d)(ii)

(ii) At time kk, show that the two drones are moving in the opposite direction.

[7]

Question 8

MediumPaper 1 · calculator8 marks
(a)

In this question, i\mathbf{i} denotes a unit vector due east, and j\mathbf{j} denotes a unit vector due north.

Two drones, P and Q, are each flying with constant velocities.

The position vector of drone P, at time tt minutes, is given as rP=(2+3t)i+(5−2t)j\mathbf{r}_P = (2 + 3t)\mathbf{i} + (5 - 2t)\mathbf{j}.

The position vector of drone Q, at time tt minutes, is given as rQ=(−1+t)i+(1+4t)j\mathbf{r}_Q = (-1 + t)\mathbf{i} + (1 + 4t)\mathbf{j}.

(a) Find the bearing on which drone P is flying.

[3]
(b)

(b) Find the value of tt when drone Q is directly west of drone P.

[2]
(c)

(c) Find the value of tt when drone Q is directly north-west of drone P.

[3]

Question 9

HardPaper 2 · calculator15 marks
(a)

The position of a drone, D1_1, tt seconds after leaving a control tower T, is given by

r=(351)+t(−234)\mathbf{r} = \begin{pmatrix} 3 \\ 5 \\ 1 \end{pmatrix} + t \begin{pmatrix} -2 \\ 3 \\ 4 \end{pmatrix}, t≥0t \ge 0.

The units of distance are metres.

Write down the coordinates of the control tower T.

[1]
(b)(i)

Four seconds after leaving T, D1_1 is at point P.

Find the displacement vector TP⃗\vec{\text{TP}}.

[2]
(b)(ii)

Find the distance ∣TP⃗∣|\vec{\text{TP}}|.

[2]
(c)

A second drone, D2_2, leaves the control tower T at the same time as D1_1. D2_2 is moving in the direction of the vector (1−12)\begin{pmatrix} 1 \\ -1 \\ 2 \end{pmatrix}.

Find the angle between the initial flight paths of Drone 1 and Drone 2.

[5]
(d)

The drone D2_2 has a speed of 1010 m s−1^{-1}.

Find the distance between Drone 1 and Drone 2 when t=4t = 4 seconds.

[5]

Question 10

MediumPaper 1 · calculator9 marks
(a)

A triangular section of a modern architectural roof is being designed. The vertices of this section are represented by points P, Q, and R in a 3D coordinate system, where distances are measured in metres.

Point P is at (0,0,2)(0, 0, 2).

Point Q is at (4,7,3)(4, 7, 3).

Point R is at (9,2,2)(9, 2, 2).

Calculate the vector product PQ⃗×PR⃗\vec{PQ} \times \vec{PR}.

[2]
(b)

Hence, find the area of the triangular roof section.

[2]
(c)

A support beam is to be installed from point Q perpendicular to the edge PR. Find the length of this support beam.

[3]
(d)

The building's base lies on the horizontal plane (z=0). Find the acute angle that the roof section makes with the horizontal plane.

[2]

Question 11

HardPaper 2 · calculator17 marks
(a)

A deep-sea research submersible, 'Nautilus', is being tracked relative to an underwater research station, 'Triton Base'. The coordinates (x,y,z)(x, y, z) represent the submersible's displacement in kilometres, where xx is east, yy is north, and zz is vertical displacement (positive upwards, so negative for depths below sea level).

At 10:00 AM, the submersible is detected at a position 60 km east and 24 km north of Triton Base, and at a depth of 15 km below sea level. Its velocity is given as (−120−48−10)\begin{pmatrix} -120 \\ -48 \\ -10 \end{pmatrix} kmh−1^{-1}. Let tt be the length of time in hours from 10:00 AM.

Write down a vector equation for the displacement, r⃗\vec{r}, of the submersible in terms of tt.

[2]
(b)(i)

If the submersible continued to travel with the given velocity,

verify that it would pass directly over Triton Base (the point (0,0,0)(0,0,0));

[4]
(b)(ii)

state the depth of the submersible at this point;

[1]
(b)(iii)

find the time at which it would pass directly over Triton Base.

[1]
(c)(i)

When the submersible is at a depth of 18 km below sea level, it continues to move horizontally on the same bearing but adjusts its vertical velocity so that it will dock precisely at Triton Base (0,0,0)(0,0,0).

Find the time at which the submersible is at a depth of 18 km below sea level.

[3]
(c)(ii)

Find the direct distance of the submersible from Triton Base at this point.

[3]
(d)

Given that the velocity of the submersible, after the adjustment of the vertical velocity, is (−120−48a)\begin{pmatrix} -120 \\ -48 \\ a \end{pmatrix} kmh−1^{-1}, find the value of aa.

[3]

Question 12

MediumPaper 1 · calculator7 marks
(a)

(a) A drone is programmed to fly along a straight path LL. Its position at time tt (in minutes) can be modelled by the vector equation r=(130)+t(112)\mathbf{r} = \begin{pmatrix} 1 \\ 3 \\ 0 \end{pmatrix} + t \begin{pmatrix} 1 \\ 1 \\ 2 \end{pmatrix}, where the coordinates are in metres. A stationary sensor SS is located at the point (10,4,4)(10, 4, 4).

Find the coordinates of the point PP on the drone's path that is closest to the sensor SS.

[4]
(b)

(b) Find a vector that is perpendicular to both the drone's path LL and the line segment connecting point PP to the sensor SS.

[3]

Question 13

HardPaper 3 · calculator27 marks
(a)(i)

(a) A ground crew on Luna Prime is tracking a supply drone. From the Aether station's control tower, the drone is observed to be 85008500 km East and 40004000 km North in a localized flat-map approximation.

(i) Find the straight-line distance from the Aether station to the drone.

[2]
(a)(ii)

(ii) Find the bearing of the drone from the Aether station. Give your answer in degrees, correct to one decimal place.

[3]
(b)(i)

(b) The Aether station (A) is located at the origin (0,0,0)(0,0,0) of a 3D Cartesian coordinate system for this part. A research probe (P) is located at (4000,0,0)(4000, 0, 0) km. A navigation beacon (B) is located at (0,4000,0)(0, 4000, 0) km.

(i) Show that the position vector of the research probe, p⃗\vec{p}, is perpendicular to the position vector of the navigation beacon, b⃗\vec{b}.

[2]
(b)(ii)

(ii) Assuming the probe and beacon are on the surface of Luna Prime with a radius of 40004000 km, calculate the shortest distance along the surface between the research probe and the navigation beacon.

[2]
(c)(i)

(c) Consider the Aether station (A) at (4000,0,0)(4000, 0, 0) km, the Boreas station (B) at (0,4000,0)(0, 4000, 0) km, and a North Pole reference point (N) at (0,0,4000)(0, 0, 4000) km. Let a⃗\vec{a}, b⃗\vec{b}, and n⃗\vec{n} be their respective position vectors from the centre of Luna Prime.

(i) Find the vector a⃗×b⃗\vec{a} \times \vec{b}.

[2]
(c)(ii)

(ii) Show that the angle at vertex A in the spherical triangle formed by Aether, Boreas, and the North Pole (ABN) is 90∘90^{\circ}.

[3]
(d)

(d) A supply route between Aether and a new outpost, Delta, has an arc length of 20002000 km. Given that the radius of Luna Prime is 40004000 km, show that the central angle θ\theta between Aether and Delta is 28.6∘28.6^{\circ}, correct to three significant figures.

[2]
(e)

(e) The Aether station (A) is located at 40∘40^{\circ} N, 20∘20^{\circ} E, and the Boreas station (B) is located at 70∘70^{\circ} N, 100∘100^{\circ} E on Luna Prime, which has a radius of 60006000 km. Find the shortest distance along the surface from Aether to Boreas.

[5]
(f)

(f) Using the vector method from part (c), find the initial bearing from Aether to Boreas. Give your answer in degrees, correct to one decimal place.

[6]

Question 14

MediumPaper 1 · calculator5 marks
(a)

Three observation points in a 3D geological survey are located at points P, Q, and R. Their position vectors relative to an origin O are given by OP⃗=(102)\vec{OP} = \begin{pmatrix} 1 \\ 0 \\ 2 \end{pmatrix}, OQ⃗=(3−14)\vec{OQ} = \begin{pmatrix} 3 \\ -1 \\ 4 \end{pmatrix} and OR⃗=(021)\vec{OR} = \begin{pmatrix} 0 \\ 2 \\ 1 \end{pmatrix}.

(a) Calculate PQ⃗×PR⃗\vec{PQ} \times \vec{PR}.

[3]
(b)

(b) Hence find the area of triangle PQR.

[2]

Question 15

MediumPaper 1 · calculator6 marks

A structural engineer is designing a complex joint for a bridge. The joint can be modelled as a tetrahedron, with its four critical connection points (vertices) given by the coordinates:

P1=(1,2,3)P_1 = (1, 2, 3)

P2=(4,1,2)P_2 = (4, 1, 2)

P3=(2,5,1)P_3 = (2, 5, 1)

P4=(3,3,6)P_4 = (3, 3, 6)

All coordinates are in metres.

Find the volume of this tetrahedral joint.

Question 16

MediumPaper 1 · calculator9 marks
(a)

A drone is programmed to fly from point A(1,2)A(1, 2) to point B(5,5)B(5, 5). During its flight, it experiences a constant wind force W=−10i+5j\mathbf{W} = -10\mathbf{i} + 5\mathbf{j} Newtons.

Calculate the scalar component of the wind force W\mathbf{W} in the direction of the drone's intended path from AA to BB.

[3]
(b)

Determine the scalar component of the wind force W\mathbf{W} which is perpendicular to the drone's intended path.

[3]
(c)

The wind force W\mathbf{W} can be resolved into two vector components: one acting in the direction of the drone's intended path and the other acting perpendicular to it.

State the component of the wind force W\mathbf{W} in the direction of the drone's intended path (from part (a) ) in vector form. Give your answer in terms of the unit vectors i\mathbf{i} and j\mathbf{j}.

[3]

Question 17

MediumPaper 1 · calculator7 marks
(a)

A deep-sea exploration probe is launched from a research vessel. Its velocity vector, v\mathbf{v}, at time tt seconds after launch, is given by

v=(2t3t2−14)\mathbf{v} = \begin{pmatrix} 2t \\ 3t^2 - 1 \\ 4 \end{pmatrix} m/s.

At the moment of launch (t=0t = 0), the probe's initial position relative to a fixed origin is r(0)=(10−2)\mathbf{r}(0) = \begin{pmatrix} 1 \\ 0 \\ -2 \end{pmatrix} m. Find the position vector, r(t)\mathbf{r}(t), of the probe at time tt.

[4]
(b)

Find the distance of the probe from the origin when t=2t = 2 seconds.

[3]

Question 18

MediumPaper 1 · calculator5 marks

A force F⃗\vec{F} acts on a particle. The effect of this force is often analyzed by decomposing it into components parallel and perpendicular to a given direction vector d⃗\vec{d} (where d⃗≠0⃗\vec{d} \neq \vec{0}).

The scalar component of F⃗\vec{F} in the direction of d⃗\vec{d} is given by Fparallel=F⃗⋅d⃗∣d⃗∣F_{\text{parallel}} = \frac{\vec{F} \cdot \vec{d}}{|\vec{d}|}.

The magnitude of the component of F⃗\vec{F} perpendicular to d⃗\vec{d} is given by Fperpendicular=∣F⃗×d⃗∣∣d⃗∣F_{\text{perpendicular}} = \frac{|\vec{F} \times \vec{d}|}{|\vec{d}|}.

(a) Show that ∣F⃗∣2=Fparallel2+Fperpendicular2|\vec{F}|^2 = F_{\text{parallel}}^2 + F_{\text{perpendicular}}^2.

Question 19

MediumPaper 2 · calculator11 marks
(a)

(a) A deep-sea submersible is exploring an underwater trench. It is subjected to several forces, all measured in kN (11 kN =1000= 1000 N).

Two main thrusters provide forces represented by the vectors (45105)\begin{pmatrix} 45 \\ 10 \\ 5 \end{pmatrix} and (45−105)\begin{pmatrix} 45 \\ -10 \\ 5 \end{pmatrix}.

Two lateral thrusters exert forces of (080)\begin{pmatrix} 0 \\ 8 \\ 0 \end{pmatrix} and (0−80)\begin{pmatrix} 0 \\ -8 \\ 0 \end{pmatrix}.

The water resistance acting on the submersible is (−1500)\begin{pmatrix} -15 \\ 0 \\ 0 \end{pmatrix} kN.

The buoyant force is (00120)\begin{pmatrix} 0 \\ 0 \\ 120 \end{pmatrix} kN, and the weight of the submersible produces a force of (00−100)\begin{pmatrix} 0 \\ 0 \\ -100 \end{pmatrix} kN.

Find the resultant force acting on the submersible.

[3]
(b)

(b) Given that the mass of the submersible is 15 00015\,000 kg, find the acceleration of the submersible in ms−2^{-2}. The acceleration (ms−2^{-2}) of an object subject to a resultant force of F\mathbf{F} N is given by the formula a=Fm\mathbf{a} = \frac{\mathbf{F}}{m}, where mm is the mass of the object in kilograms.

[3]
(c)(i)

(c) The submersible is initially at the origin (0,0,0)(0,0,0) and has an initial velocity of (100−5)\begin{pmatrix} 10 \\ 0 \\ -5 \end{pmatrix} ms−1^{-1}.

(i) Find the displacement of the submersible at time tt.

[3]
(c)(ii)

(ii) Find the displacement of the submersible at t=60t = 60 s.

[2]

Question 20

MediumPaper 2 · calculator12 marks
(a)

A robot arm applies a force F\mathbf{F} to move a component. The force vector is F=(7−3)\mathbf{F} = \begin{pmatrix} 7 \\ -3 \end{pmatrix} newtons (N). The component is moved from an initial position P1(2,5)P_1(2, 5) to a final position P2(8,1)P_2(8, 1), where coordinates are in metres. Calculate the work done by the robot arm.

[3]
(b)

In physics, the work done WW by a constant force F\mathbf{F} moving an object through a displacement d⃗\vec{d} is generally given by the scalar product W=F⋅d⃗W = \mathbf{F} \cdot \vec{d}. Explain why, if the force is applied exactly in the direction of the displacement, the formula simplifies to W=∣F∣∣d⃗∣W = |\mathbf{F}| |\vec{d}|.

[4]
(c)

A deep-sea submersible starts its descent from an initial position Q1(10,20,5)Q_1(10, 20, 5) metres and travels in a straight line to a target location Q2(70,60,25)Q_2(70, 60, 25) metres. The coordinates are relative to a fixed origin on the surface. The submersible's propulsion system generates a constant force of 150 000150\,000 N in the direction of motion. Using the simplified formula from part (b), calculate the total energy expended by the propulsion system during this descent. Give your answer to three significant figures.

[5]

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What does Vector basics (position, displacement vectors, components ijk, rescaling/normalising vectors) cover in IB Maths AI?

Scalar: quantity with magnitude only. Vector: quantity with magnitude and direction. Vector notation: bold lowercase (e.g., a) or arrow over points (e.g., vecAB). Parallel vectors: a = kb where k is a scalar constant.

Is Vector basics (position, displacement vectors, components ijk, rescaling/normalising vectors) SL or HL?

Vector basics (position, displacement vectors, components ijk, rescaling/normalising vectors) is HL only. SL students are not examined on it.

How do I revise Vector basics (position, displacement vectors, components ijk, rescaling/normalising vectors) for IB Maths AI?

Start from the core idea: scalar: quantity with magnitude only. Vector: quantity with magnitude and direction. In the exam: the rescaling example above is the archetype: normalise a direction, multiply by a speed. Column and boldsymboliboldsymboljboldsymbolk notation are both accepted, so a mark scheme has to allow either. Then practise exam-style questions, easiest first, writing out every step of your working before you check it.

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