Vector equations in 2&3D (+ angle between two lines): notes and practice questions
- Vector Equation of a Line:
- : position vector of any point on the line.
- : position vector of a known point on the line.
- : direction vector parallel to the line.
- : scalar parameter.
- Finding Direction Vector (from two points A and B):
- **Checking if a Point Lies on a Line:**
- Equate point's position vector to the line equation:
- Solve for from each component equation.
- Point lies on the line if a single, consistent value satisfies all components.
- Angle Between Two Lines:
- Determined by their direction vectors and .
- Acute angle formula:
- Absolute value of dot product ensures the acute angle.
- **Shortest Distance from a Point to a Line:**
- Define a general point on the line using parameter .
- Form the displacement vector .
- Apply perpendicular condition: (where is the line's direction vector).
- Solve for .
- Substitute back into and calculate its magnitude .
- GDC Tips:
- Use GDC for solving systems of linear equations (e.g., when checking if a point lies on a line).
- Use GDC's vector tools for dot product and magnitude calculations.
How it is examined
The scalar product is asked far more often than the vector product, usually as "find the angle between". The cross product turns up for areas and for a normal direction. Proofs of the general properties are explicitly not required, so a question asking a student to prove distributivity is out of syllabus. The component formulas at the end are what physics-adjacent Paper 3 questions lean on.
Both products in component and in magnitude-angle form, and the area of a parallelogram.
- The definition and calculation of the scalar product of two vectors.
- The angle between two vectors, and the acute angle between two lines.
- The definition and calculation of the vector product of two vectors.
- The geometric interpretation of .
Not required: generalized properties and proofs of scalar and cross product.
Linking questions
- Other contexts, computer graphics: lighting, normalising one vector onto another to determine the intensity of light on a surface. Perspective, projecting a three-dimensional vector onto a two-dimensional plane using the scalar product.
- Other contexts, physics: torque, where the magnitude of the rotational force applied to a point is the magnitude of the cross product of the length of the lever and the force applied to it, and the direction of the torque says whether the force tightens or loosens the bolt. Electromagnetic forces and the right and left hand rules, . Forces, and what component of one force acts in the direction of another, which matters for strain analysis.
- Links to other subjects: magnetic forces and fields, and dynamics (physics).
- TOK: what counts as understanding in mathematics? Is it more than just getting the right answer?
Practice questions
7 questions · 6 medium · 1 hardQuestion 1
MediumPaper 1 · calculator7 marksThe paths of two automated guided vehicles (AGVs), and , in a large warehouse are modelled by the following vector equations, where is a constant:
It is known that the paths of the AGVs are perpendicular.
(a) Find the possible value(s) for .
(b) In the case that , determine whether the lines intersect.
For two lines to be perpendicular, the dot product of their direction vectors must be zero. Set up the dot product using the given direction vectors and solve the resulting equation for .
Substitute the appropriate value of (the negative one) into both line equations. Then, equate the corresponding components to form a system of three linear equations with two unknowns ( and ). Attempt to solve this system.
Question 2
HardPaper 2 · calculator19 marks(a) A space probe, 'Voyager Alpha', is launched from a space station. The position of the probe at time days after launch is given by the vector
Distances are measured in thousands of kilometres.
Find the position vector of the probe days after launch.
(b) A second space probe, 'Explorer Beta', is launched from a different station. The position vector of this probe is given by the vector
Determine if the two flight paths intersect and, if so, state the point of intersection.
(c) The two probes were launched at the same time, so .
State, with a reason, whether the two probes actually collide.
(d) Calculate the distance between the two space stations (the initial launch points).
(e) Calculate the shortest distance that ever exists between the two probes and the time when this occurs. Assume days.
Substitute the given time value into the vector equation for the probe's position.
Equate the components of the two position vectors to form a system of linear equations. Solve for and using two of the equations, then check if these values satisfy the third equation.
Consider the results from part (b). For a collision to occur, the paths must intersect AND the probes must be at the intersection point at the same time.
The initial launch points are the constant vectors in the position equations (when or ). Use the 3D distance formula.
Form a vector representing the difference in position of the two probes at time (since they launched simultaneously, ). Find the magnitude squared of this difference vector, then differentiate with respect to and set to zero to find the minimum. Remember to consider the domain .
Question 3
MediumPaper 1 · calculator9 marksA triangular section of a modern architectural roof is being designed. The vertices of this section are represented by points P, Q, and R in a 3D coordinate system, where distances are measured in metres.
Point P is at .
Point Q is at .
Point R is at .
Calculate the vector product .
Hence, find the area of the triangular roof section.
A support beam is to be installed from point Q perpendicular to the edge PR. Find the length of this support beam.
The building's base lies on the horizontal plane (z=0). Find the acute angle that the roof section makes with the horizontal plane.
First, determine the component vectors and . Then, remember the formula for the cross product of two 3D vectors.
The magnitude of the cross product of two vectors forming two sides of a triangle is related to the area of the triangle. Specifically, the area is half the magnitude of the cross product.
The area of a triangle can also be calculated using the formula . You can use the area from part (b) and the length of as the base.
The angle between two planes can be found using the angle between their normal vectors. The normal vector to the horizontal plane (z=0) is . The normal vector to the roof section is the cross product you calculated in part (a).
Question 4
MediumPaper 1 · calculator7 marks(a) A drone is programmed to fly along a straight path . Its position at time (in minutes) can be modelled by the vector equation , where the coordinates are in metres. A stationary sensor is located at the point .
Find the coordinates of the point on the drone's path that is closest to the sensor .
(b) Find a vector that is perpendicular to both the drone's path and the line segment connecting point to the sensor .
To find the point on the line closest to the sensor, consider the vector connecting a general point on the line to the sensor. This vector must be perpendicular to the direction vector of the line at the closest point. Use the scalar product to express this condition.
To find a vector perpendicular to two given vectors, you can use the vector product (cross product). You will need the direction vector of the drone's path and the vector from point P to sensor S.
Question 5
MediumPaper 1 · calculator5 marksA force acts on a particle. The effect of this force is often analyzed by decomposing it into components parallel and perpendicular to a given direction vector (where ).
The scalar component of in the direction of is given by .
The magnitude of the component of perpendicular to is given by .
(a) Show that .
Consider expressing and in terms of the magnitudes of the vectors and the angle between them.
Question 6
MediumPaper 1 · calculator7 marks(a) A reconnaissance drone is launched from a base station at point relative to an origin , where lengths are measured in metres and time, , is measured in seconds. It flies in a straight line with vector equation
Find the speed of the reconnaissance drone (in m/s).
(b) A patrol drone is dispatched from a different location with position vector , relative to . It flies with a constant velocity vector of to intercept the reconnaissance drone.
Write down the vector equation for , that models the flight of the patrol drone.
(c) Find the position vector at which the patrol drone intercepts the reconnaissance drone.
The speed of the drone is the magnitude of its velocity vector. The velocity vector is the direction vector in the vector equation of the line.
A vector equation of a line is given by , where is a position vector on the line and is the direction vector (velocity vector in this case).
At the point of interception, the position vectors of both drones must be equal. Equate the components of the two vector equations and solve for the time . Then substitute the value of back into either vector equation to find the position vector.
Question 7
MediumPaper 1 · calculator6 marksA mechanic applies a force, N, to the end of a wrench. The direction of this force is perpendicular to a vector .
(a) Find the value of .
The wrench applies the force at a point P, which has a position vector m relative to the bolt (which is at the origin). The torque, , is given by the vector equation . The actual force applied is given by , where .
(b) Given that the magnitude of the torque is 20 Nm, find the value of .
Remember the property of the scalar (dot) product for two perpendicular vectors. What is the value of their dot product?
First, calculate the cross product in terms of c. Then, find the magnitude of this resulting vector and set it equal to the given value of 20. Solve for c.
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