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Topic 5.04 · SL and HL

Definite integrals: notes and practice questions

Summary
  • Definite integral calculates exact accumulation or area between limits aa (lower) and bb (upper).
  • Integrand is f(x)f(x), antiderivative is F(x)F(x).
  • Fundamental Theorem of Calculus: ∫abf(x)dx=[F(x)]ab=F(b)−F(a)\int_{a}^{b} f(x) dx = \left[ F(x) \right]_{a}^{b} = F(b) - F(a)
  • Constant of integration (+c+c) is not needed for definite integrals.
  • Negative area: If area is below x-axis, integral result is negative; take modulus for physical area.
  • Area under a curve (x-axis): A=∫aby dxA = \int_{a}^{b} y \ dx (use A=∫ab∣y∣ dxA = \int_{a}^{b} |y| \ dx if below x-axis).
  • Area between a curve and y-axis: A=∫abx dyA = \int_{a}^{b} x \ dy (rearrange y=f(x)y = f(x) to x=g(y)x = g(y)).
  • To find definite integral analytically:
  • Rewrite integrand to integrable form.
  • Integrate to F(x)F(x) (no +c+c), place in square brackets with limits: [F(x)]ab[F(x)]_a^b.
  • Evaluate: F(b)−F(a)F(b) - F(a).
  • For area questions:
  • Sketch graph to identify areas below x-axis.
  • Find limits (e.g., roots if not given).
  • Set up integral, splitting or using modulus for negative areas.
  • GDC can compute definite integrals using ∫□□□\int_{\square}^{\square} \square function or graphing screen "area" option.
  • Use GDC's 'Abs' function for modulus to make negative areas positive.
  • GDC may require 'x' as dummy variable even for integrals with respect to 'y' (e.g., ∫g(y)dy\int g(y) dy typed as ∫g(x)dx\int g(x) dx).
  • GDC provides approximate decimals; manual calculation is needed for exact fractions.
  • Always use GDC to check manual integration results.
  • Sketching is crucial for area problems to prevent incorrect cancellation of positive and negative areas.

How it is examined

The "write the expression first" rule is the most useful thing here for marking: an answer that gives only the numerical area loses the method mark even when the number is right, so the mark scheme has to look for the integral. The exclusion of n=−1n = -1 means no ln⁡\ln at SL, and the f(x)>0f(x) > 0 restriction means the curve stays above the axis over the interval.

Given in the booklet

The integral of xnx^n.

Key ideas
  • Integration as anti-differentiation of functions of the form f(x)=axn+bx n−1+…f(x) = ax^n + bx^{\,n-1} + \dots, where n∈Zn \in \mathbb{Z}, n≠−1n \neq -1.
  • Anti-differentiation with a boundary condition, to determine the constant term.
  • Definite integrals using technology.
  • The area of a region enclosed by a curve y=f(x)y = f(x) and the xx-axis, where f(x)>0f(x) > 0.

Linking questions

  • Other contexts: velocity-time graphs.
  • Links to other subjects: velocity-time and acceleration-time graphs (physics and sports exercise and health science).
  • TOK: is it possible for an area of knowledge to describe the world without transforming it?

Practice questions

50 questions · 5 easy · 38 medium · 7 hard
Showing 20 of 20

Question 1

EasyPaper 1 · calculator5 marks

If a company is analyzing the efficiency of a machine by studying its energy consumption rate (in kilowatts per hour), which is modelled by the function:

E′(t)=3t2−2t+cE^{'}(t) = 3t^{2} - 2t + c

Determine the value of cc if it was given that the total energy consumed by the machine during the first 4 hours of operation is 68 kW68\ kW.

Question 2

MediumPaper 1 · calculator8 marks
(a)(i)

(a) An architect is designing the entrance to a new tunnel. The shape of the entrance is modelled by a quadratic curve, with the base of the tunnel on the x-axis. The curve has end points (0, 6) and (10, 6), and its vertex is (5, 9). Distances are measured in metres.

The quadratic curve can be expressed in the form y=ax2+bx+cy = ax^2 + bx + c for 0≤x≤100 \leq x \leq 10.

(a.i) Write down the value of cc.

[1]
(a)(ii)

(a.ii) Hence, form two equations in terms of aa and bb.

[2]
(a)(iii)

(a.iii) Hence, find the equation of the quadratic curve.

[2]
(b)

(b) Calculate the area of the tunnel entrance.

[3]

Question 3

HardPaper 1 · calculator9 marks
(a)(i)

A landscape architect is designing a decorative water channel. The cross-section of the channel is modelled by the function f(x)=x3−4xf(x) = x^3 - 4x, for −2≤x≤2-2 \leq x \leq 2. The shaded region, RR, represents the cross-sectional area of the channel, bounded by the graph of y=f(x)y = f(x) and the xx-axis.

Graph of y=f(x) = x^3-4x from -2 to 2, with shaded region R between the curve and x-axis. The curve is above the x-axis for x in [-2,0 and below for x in [0,2].]

Write down an integral that represents the area of RR.

[2]
(a)(ii)

Find the area of RR.

[2]
(b)

The architect considers a modified design, where the cross-section is given by g(x)=0.5f(x+1)g(x) = 0.5f(x+1).

On the following set of axes, the graph of y=f(x)y = f(x) has been drawn. On the same set of axes, sketch the graph of y=g(x)y = g(x).

Axes with graph of y=f(x)=x^3-4x drawn from -3 to 3, ready for sketch of y=g(x). The graph of f(x) has roots at -2, 0, 2 and local max/min at approx (-1.15, 3.08) and (1.15, -3.08).
[2]
(c)

The region RR (the original cross-section) is rotated through 2π2\pi radians about the xx-axis to form a three-dimensional decorative element. Find the volume of this element.

[3]

Question 4

EasyPaper 1 · calculator5 marks

If a company is analyzing the efficiency of a machine by studying its energy consumption rate (in kilowatts per hour), which is modelled by the function:

E′(t)=3t2−2t+cE^{'}(t) = 3t^{2} - 2t + c

Determine the value of cc if it was given that the total energy consumed by the machine during the first 4 hours of operation is 68 kW68\ kW.

Question 5

MediumPaper 1 · calculator8 marks
(a)

The cross-section of a proposed tunnel entrance is modelled by a curve. The heights of the tunnel are measured at horizontal intervals and are given in the table below. All measurements are in cm.

Horizontal distance, x (cm)

0

10

20

30

40

50

60

Vertical distance, y (cm)

0

1.875

6.0

10.125

12.0

9.375

0

(a) Use the trapezoidal rule with h=10h = 10 to find an approximation for the cross-sectional area of the tunnel entrance.

[2]
(b)(i)

(b)

It is given that the equation of the curve is y=0.0225x2−0.000375x3y = 0.0225x^2 - 0.000375x^3, for 0≤x≤600 \le x \le 60.

(i) Write down an integral to find the exact cross-sectional area.

[2]
(b)(ii)

(ii) Calculate the value of the cross-sectional area to two decimal places.

[2]
(c)

(c) Find the percentage error in the area found using the trapezoidal rule. Give your answer to two decimal places.

[2]

Question 6

HardPaper 1 · calculator10 marks
(a)

Alex is preparing for a calculus exam and encounters a series of integrals. For each integral, identify whether it can be evaluated analytically using standard techniques (and if so, state the appropriate analytical method) or if it requires numerical approximation using technology (e.g., a GDC).

(a) ∫cos⁡(3x+2) dx\int \cos(3x + 2)\,dx

[2]
(b)

(b) ∫2xex2 dx\int 2x e^{x^2}\,dx

[2]
(c)

(c) ∫xsin⁡(x) dx\int x \sin(x)\,dx

[2]
(d)

(d) ∫e2x2 dx\int e^{2x^2}\,dx

[1]
(e)

(e) ∫124x2x3+3 dx\int_{1}^{2} \frac{4x^2}{x^3 + 3}\,dx

[2]
(f)

(f) ∫144sin⁡(x2) dx\int_{1}^{4} 4\sin(x^2)\,dx

[1]

Question 7

EasyPaper 1 · calculator5 marks

If an athlete is training by monitoring the rate at which calories are burned during a workout. The calorie burn rate (in calories per minute) is modelled by the function:

C′(t)=5t2−4t+cC'(t) = 5t^{2} - 4t + c

where tt is taken as the time in minutes. According to this model if an athlete burns a total of 240 calories during the first 6 minutes, determine the value of cc.

Question 8

MediumPaper 1 · calculator7 marks
(a)

The internal shape of a specialized chemical reactor vessel is formed by rotating the curve y=8ln⁡xy = 8 \ln x, for 0≤y≤120 \le y \le 12, about the yy-axis, where xx and yy are measured in centimetres. The vessel contains a liquid to a height of hh cm.

Show that the volume of the liquid, VV, in terms of hh is V=4π(eh4−1)V = 4\pi(e^{\frac{h}{4}} - 1).

[5]
(b)

Hence find the maximum capacity of the reactor vessel in cm3^3. Give your answer to three significant figures.

[2]

Question 9

HardPaper 1 · calculator11 marks
(a)

(a) A designer is creating a prototype for a decorative vase. The cross-section of the vase can be modelled by the function f(x)=x4−x2f(x) = x\sqrt{4-x^2}, for −2≤x≤2-2 \le x \le 2.

Sketch the graph of y=f(x)y = f(x) on the following pair of axes.

graph of y=f(x) on axes from -3 to 3 for x and -3 to 3 for y. The curve passes through the origin, has a maximum in the first quadrant and a minimum in the third quadrant. The curve is symmetric about the origin. The endpoints are at x=-2 and x=2. The maximum is at x=sqrt(2) and y=2, and the minimum is at x=-sqrt(2) and y=-2. The curve is smooth. The x-axis is labelled from -3 to 3 and the y-axis is labelled from -3 to 3.
[2]
(b)(i)

(b) The region enclosed by the graph of y=f(x)y = f(x) and the x-axis is rotated 360∘360^\circ about the x-axis to form the body of the vase.

(i) Write down an integral that represents the volume of this vase.

[2]
(b)(ii)

(ii) Calculate the value of this integral.

[4]
(c)

(c) The designer decides to create a new, larger version of the vase, y=g(x)y = g(x), by applying the following transformations to the original cross-section y=f(x)y = f(x):

  • A horizontal stretch by a scale factor of 3, parallel to the x-axis.
  • A vertical stretch by a scale factor of 0.75, parallel to the y-axis.

Find the volume of this new vase.

[3]

Question 10

EasyPaper 1 · calculator5 marks

If a chemical reaction is monitored by observing the rate at which a reactant is consumed over time (in grams per minute) according to the following model:

R′(t)=3t2+2t+kR^{'}(t) = 3t^{2} + 2t + k

Where tt is taken as the time in minutes. If the total amount of the reactant consumed during the first 5 minutes is 150 grams, determine the value of kk.

Question 11

MediumPaper 1 · calculator10 marks
(a)

A landscape architect is designing a section of a park. The boundary of a planned pathway can be modelled by the line y=−x+8y = -x + 8 and a decorative flower bed by the curve y=0.5x2−4x+10.5y = 0.5x^2 - 4x + 10.5. These two features intersect at points (1,7)(1, 7) and (5,3)(5, 3), as shown in the following diagrams.

In diagram 1, the region enclosed by the line y=−x+8y = -x + 8, x=1x = 1, x=5x = 5 and the xx-axis has been shaded.

Diagram 1 showing a shaded region under the line y=-x+8 from x=1 to x=5, with intersection points (1,7) and (5,3).

Calculate the area of the shaded region in diagram 1.

[2]
(b)(i)

In diagram 2, the region enclosed by the curve y=0.5x2−4x+10.5y = 0.5x^2 - 4x + 10.5, and the lines x=1x = 1, x=5x = 5 and the xx-axis has been shaded.

Diagram 2 showing a shaded region under the curve y=0.5x^2-4x+10.5 from x=1 to x=5, with intersection points (1,7) and (5,3).

Write down an integral for the area of the shaded region in diagram 2.

[3]
(b)(ii)

Calculate the area of this region.

[3]
(c)

Hence, determine the area enclosed between the line y=−x+8y = -x + 8 and the curve y=0.5x2−4x+10.5y = 0.5x^2 - 4x + 10.5.

[2]

Question 12

HardPaper 1 · calculator7 marks
(a)

A population of microorganisms grows according to the function P(t)=t3−9t2+23t−15P(t) = t^3 - 9t^2 + 23t - 15, where P(t)P(t) is the population in thousands and tt is the time in hours, for 0≤t≤50 \le t \le 5 hours.

The population is zero when t=1t=1, t=5t=5 and t=at=a hours.

Find the value of aa.

[2]
(b)

Calculate the total population growth (area enclosed by the curve and the tt-axis) from t=1t=1 hour to t=at=a hours.

[2]
(c)

Another species of microorganism has its population modelled by Q(t)=−2t2+10t−8Q(t) = -2t^2 + 10t - 8 (in thousands). The total population growth of species PP from t=1t=1 to t=bt=b hours is equal to the total population growth of species QQ from t=1t=1 to t=bt=b hours.

Find the value of bb, where 1<b<31 < b < 3.

[3]

Question 13

EasyPaper 1 · calculator5 marks

If a chemical reaction is monitored by observing the rate at which a reactant is consumed over time (in grams per minute) according to the following model:

R′(t)=3t2+2t+kR^{'}(t) = 3t^{2} + 2t + k

Where tt is taken as the time in minutes. If the total amount of the reactant consumed during the first 5 minutes is 150 grams, determine the value of kk.

Question 14

MediumPaper 1 · calculator8 marks
(a)

A civil engineer is surveying a river to estimate its cross-sectional area for flow rate calculations. The depth of the river is measured at regular horizontal intervals across its width, as shown in the table below.

Horizontal distance, x (m)0102030405060
Depth, y (m)02.5813.51612.50

Use the trapezoidal rule with h=10h = 10 m to find an approximation for the cross-sectional area of the river.

[2]
(b)(i)

It is given that the equation of the curve modelling the riverbed cross-section is y=0.0005x2(60−x)y = 0.0005x^2(60-x), for 0≤x≤600 \le x \le 60.

Write down an integral to find the exact cross-sectional area.

[2]
(b)(ii)

Calculate the value of the cross-sectional area to two decimal places.

[2]
(c)

Find the percentage error in the area found using the trapezoidal rule compared to the exact area.

[2]

Question 15

HardPaper 2 · calculator9 marks
(a)

The cross-section of a decorative garden bed is modelled by the curve y=2(x−1)(x−3)2y = 2(x-1)(x-3)^2, where xx and yy are measured in metres. The garden bed is built on flat ground, represented by the xx-axis.

(a) Write down the xx-intercepts of this curve.

[2]
(b)

(b) Write down a definite integral that represents the area of the cross-section of the garden bed.

[2]
(c)

(c) Find the value of this area.

[5]

Question 16

MediumPaper 1 · calculator8 marks
(a)

The rate of profit, P(t)P(t), in thousands of dollars per month, for a new product is modelled by the piecewise function

P(t)={P1(t),0≤t≤TP2(t),t≥TP(t) = \begin{cases} P_1(t), & 0 \leq t \leq T \\ P_2(t), & t \geq T \end{cases}

where P1(t)=−t2+6tP_1(t) = -t^2 + 6t and P2(t)=−2t+16P_2(t) = -2t + 16. For a smooth transition in the profit rate, it is required that P1(T)=P2(T)P_1(T) = P_2(T).

Find the value of TT.

[2]
(b)

Show that P1′(T)=P2′(T)P_1'(T) = P_2'(T).

[2]
(c)

The total profit from the product at time t=0t=0 is zero.

Find the time when the total profit returns to its initial position.

[4]

Question 17

HardPaper 2 · calculator28 marks
(a)(i)

(a) (i) Consider the function f(x)=x3f(x) = x^3. Find f′(x)f'(x).

[1]
(a)(ii)

(ii) The first section of the stone wall's profile is given by y=f(x)y = f(x) for 0≤x≤0.50 \le x \le 0.5. A straight glass panel is to be installed tangent to this section of the wall at the point where x=0.5x=0.5. Find the equation of this tangent line.

[3]
(b)

The full profile of the stone wall, F(x)F(x), is defined by:

F(x)={x30≤x≤0.50.75x−0.250.5<x≤1.0F(x) = \begin{cases} x^3 & 0 \le x \le 0.5 \\ 0.75x - 0.25 & 0.5 < x \le 1.0 \end{cases}

A smaller, decorative stone insert is designed using a transformation of F(x)F(x). The graph of G(x)G(x) is obtained from the graph of F(x)F(x) by:

  • a stretch scale factor of 12\frac{1}{2} in the xx direction,
  • followed by a stretch scale factor of 12\frac{1}{2} in the yy direction,
  • followed by a translation of 0.50.5 units to the right.

Point P lies on the graph of F(x)F(x) and has coordinates (1.0,0.5)(1.0, 0.5). Point Q is the image of P under the given transformations and has coordinates (qx,qy)(q_x, q_y).

Find the value of qxq_x and the value of qyq_y.

[3]
(c)(i)

The piecewise function G(x)G(x) is given by

G(x)={k(x)c≤x≤dmx+nd<x≤qxG(x) = \begin{cases} k(x) & c \le x \le d \\ mx + n & d < x \le q_x \end{cases}

(c) Find

(i) an expression for k(x)k(x).

[4]
(c)(ii)

(ii) the value of dd.

[2]
(c)(iii)

(iii) the value of nn.

[3]
(d)(i)

(d) (i) Calculate the total area of the profile of the stone wall, enclosed by y=F(x)y = F(x), the xx-axis, and the line x=1.0x = 1.0.

[7]
(d)(ii)

The decorative insert G(x)G(x) is placed within the main wall profile F(x)F(x). The region of the main wall profile that is not covered by the insert is to be painted a contrasting colour. This region is bounded by y=F(x)y=F(x), the xx-axis, and the lines x=0x=0 and x=1x=1, excluding the area under G(x)G(x) from x=0.5x=0.5 to x=1.0x=1.0. Find the area of this region.

[5]

Question 18

MediumPaper 1 · calculator4 marks
(a)

(a) A company's quarterly profit, in millions of dollars, is modelled by the function P(x)=0.5x3−2.5x2+x+4P(x) = 0.5x^3 - 2.5x^2 + x + 4, where xx represents the number of production batches (in hundreds) and x≥0x \ge 0. The company breaks even when P(x)=0P(x) = 0.

Given that the company experiences an initial profitable period, then breaks even, and then becomes profitable again, find the largest value of xx for which the company breaks even after its initial profitable period, denoted as aa.

[2]
(b)

(b) Use your graphic display calculator to find the total profit (in millions of dollars) made by the company when the production batches range from x=2x = 2 to x=ax = a.

[2]

Question 19

HardPaper 2 · calculator24 marks
(a)(i)

A landscape architect is designing a new public park. The northern boundary of the park is modelled by the function g(x)g(x), and other boundaries are straight lines. The plan view of the park is shown in the following diagram, where both axes represent distance and are measured in metres.

Graph showing a shaded region representing a park, bounded by a curve g(x) and straight lines, with points A, B, C, D.

The function g(x)g(x) models the northern boundary of the park between points B and C and is given by

g(x)=−110x2+4x+15g(x) = -\frac{1}{10}x^2 + 4x + 15, for 0≤x≤400 \le x \le 40.

(i) Find g′(x)g'(x).

[2]
(a)(ii)

(ii) Hence find the coordinates of the point on the park's northern boundary that is furthest north.

[3]
(b)(i)

Point A has coordinates (0,0)(0, 0), point B has coordinates (0,15)(0, 15), point C has coordinates (40,15)(40, 15) and point D has coordinates (40,0)(40, 0).

(i) Write down the integral which can be used to find the area of the shaded region representing the park.

[2]
(b)(ii)

(ii) Find the area of the park.

[2]
(c)(i)

(i) A landscaper uses the trapezoidal rule with 4 intervals to estimate the area of the park. Calculate this estimate.

[3]
(c)(ii)

(ii) Calculate the percentage error in the landscaper's estimate.

[3]
(c)(iii)

(iii) Suggest how the landscaper might be able to reduce the error whilst still using the trapezoidal rule.

[1]
(d)(i)

A square-shaped meditation garden, PQRS, is to be built within the park. The side [PS] lies on the southern boundary (x-axis), and the side [QR] lies on the eastern boundary of the park (x=40x=40). Point Q lies on the northern boundary curve g(x)g(x).

(i) Find the x-coordinate of point P for the largest area of the meditation garden.

[4]
(d)(ii)

(ii) Find the largest area of the meditation garden.

[4]

Question 20

MediumPaper 1 · calculator7 marks
(a)

The rate of change of a certain quantity, QQ, with respect to time, tt (in minutes), is modelled by the function dQdt=105t−2\frac{dQ}{dt} = \frac{10}{5t-2}.

(a) Find an expression for Q(t)Q(t) in terms of tt, assuming an arbitrary constant of integration.

[3]
(b)

(b) Given that the model is valid for t>25t > \frac{2}{5}, find the exact total change in the quantity QQ from t=1t=1 minute to t=4t=4 minutes. Give your answer in the form aln⁡ba \ln b, where a,b∈Na, b \in \mathbb{N}.

[4]

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What does Definite integrals cover in IB Maths AI?

Definite integral calculates exact accumulation or area between limits a (lower) and b (upper). Integrand is f(x), antiderivative is F(x). Fundamental Theorem of Calculus: ∫_a^b f(x) dx = [ F(x) ]_a^b = F(b) - F(a).

Is Definite integrals SL or HL?

Both. SL and HL students study Definite integrals to the same depth.

How do I revise Definite integrals for IB Maths AI?

Start from the core idea: definite integral calculates exact accumulation or area between limits a (lower) and b (upper). In the exam: the "write the expression first" rule is the most useful thing here for marking: an answer that gives only the numerical area loses the method mark even when the number is right, so the mark scheme has to look for the integral. The exclusion of n = -1 means no ln at SL, and the f(x) > 0 restriction means the curve stays above the axis over the interval. Then practise exam-style questions, easiest first, writing out every step of your working before you check it.

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