Probability distribution of discrete random variables (table + applications): notes and practice questions
- A random variable's value depends on a random event's outcome.
- A discrete random variable takes specific, separate values (e.g., non-negative integers).
- A discrete uniform distribution has finite values, each with probability .
- The sum of probabilities for all possible outcomes must equal 1:
- To calculate probabilities:
- Construct a table with possible values and corresponding .
- If given a function , substitute values to find individual probabilities.
- If an unknown (e.g., ) exists, use to form an equation and solve for it.
- Find specific probabilities by adding relevant values.
- if is not a possible value of the random variable.
- Translate word phrases to inequalities:
- "At most" / "no greater than":
- "Fewer than":
- "At least" / "no fewer than":
- "Greater than":
- For basic discrete distributions, use GDC for standard algebra/arithmetic; check that probabilities sum to 1.
- Always check the domain of ; probabilities are 0 for values outside the specified domain.
- Draw only necessary branches of tree diagrams, not full complex ones, unless explicitly required.
How it is examined
Two reliable steps: use to find a missing probability, then compute . The fair game idea gives a natural third part, solve for a stake. Note that variance of a general discrete random variable is not SL content, so an SL question must stop at the expected value.
.
- The concept of discrete random variables and their probability distributions.
- The expected value (mean), , for discrete data.
- Applications.
Linking questions
- Other contexts: games of chance.
- Aim 8: why has it been argued that theories based on the calculable probabilities found in casinos are pernicious when applied to everyday life, for example in economics?
- TOK: what do we mean by a "fair" game? Is it fair that casinos should make a profit?
Practice questions
35 questions · 1 easy · 24 medium · 10 hardQuestion 1
EasyPaper 1 · calculator5 marksConsider the following probability distribution of a discrete random variable :
| 1 | 2 | 3 | 4 | |
|---|---|---|---|---|
Where .
Find the value of and when .
Of course. Here is the probability distribution table in markdown format:
Remember that two unknowns will need to equations to be solved.
Question 2
MediumPaper 1 · calculator11 marksIn a security system, two independent sensors, System A and System B, report a threat level for an incident. System A reports a level with probabilities , , . System B reports a level with probabilities , , , . The overall threat assessment, , for an incident is defined as the higher of the two reported threat levels (i.e., ).
Complete the following table to show the probability distribution of .
| 1 | 2 | 3 | 4 | |
|---|---|---|---|---|
Find the probability that an incident has an overall threat assessment of at least 3.
Given that the overall threat assessment is at least 3, find the probability that System A reported a level of 2.
Calculate the expected overall threat assessment, .
Consider all possible pairs of and their joint probabilities. For each pair, determine and sum the probabilities for each unique value of .
Recall how to sum probabilities from a discrete probability distribution for a given range of values.
Remember the formula for conditional probability: . Identify events A and B correctly.
The expected value of a discrete random variable is the sum of each possible outcome multiplied by its probability.
Question 3
HardPaper 1 · calculator9 marks(a) A company produces a new board game that includes a four-sided spinner. The spinner is designed to be fair, meaning each side (labelled 1, 2, 3, 4) should have an equal probability of being spun. During a quality control test, the spinner is spun times. The observed frequencies are:
| Number on spinner | ||||
|---|---|---|---|---|
| Frequency |
Find the expected frequencies for each number if the spinner is fair.
(b) Write down the number of degrees of freedom for this test.
(c) The critical value for a goodness of fit test at the significance level with the appropriate degrees of freedom is .
Determine the results of a goodness of fit test to find out whether the observed data fits a uniform distribution. Remember to write down the null and alternative hypotheses.
For a fair spinner, each outcome should have an equal probability. The expected frequency is the total number of trials multiplied by this probability.
The degrees of freedom for a goodness of fit test is calculated as the number of categories minus one.
First, state the null and alternative hypotheses. Then, calculate the chi-squared test statistic using the formula . Finally, compare this value to the given critical value and draw a conclusion in context.
Question 4
MediumPaper 1 · calculator7 marksA manufacturing plant produces a specific electronic component. Due to the complexity of the manufacturing process, there is a 15% chance that any given component will be defective. A batch of 12 components is randomly selected for quality control inspection. Each component's defect status is independent of others.
(a) Calculate the expected number of components in the batch that are non-defective.
(b) Calculate the probability that exactly 3 components in the batch are defective.
(c) Determine the probability that more than 9 components in the batch are non-defective.
Recall the formula for the expected value of a binomial distribution. First, identify the probability of a component being non-defective.
This is a binomial probability problem. Identify the number of trials (n), the number of successes (k), and the probability of success (p) for a defective component.
Consider the number of non-defective components. 'More than 9' means 10, 11, or 12 non-defective components. You can use the binomial cumulative distribution function (CDF) or calculate individual probabilities and sum them.
Question 5
HardPaper 2 · calculator19 marksA game involves a player attempting to hit a target. The number of successful hits, , in a round follows a discrete probability distribution given by:
(a) Find .
(b) Giving your answers as fractions, calculate:
(i)
(c) The variance of is . Let the random variable .
(i) Find .
(ii) Find .
(d) Let the random variable , be the total of four independent values of .
(i) Find .
(ii) Find .
(e) Let the random variable .
(i) Calculate giving the answer as a fraction.
(ii) Hence, determine whether or not the statement is true. You must justify your answer.
To find , sum the probabilities for and .
The expected value is calculated as .
For a linear transformation , the expected value .
For a linear transformation , the variance .
For independent random variables, the expected value of their sum is the sum of their individual expected values: .
For independent random variables, the variance of their sum is the sum of their individual variances: .
To find , you need to calculate the value of for each value and then use the formula .
Compare your calculated from part (e.i) with the value of using from part (b.i).
Question 6
MediumPaper 1 · calculator8 marksA high-end watch manufacturer implements a quality control system. The average number of defective watches, , in a standard production batch is related to the quality control score, , by the equation , where .
For a quality control score of , the manufacturer observes an average of defective watches per standard batch.
(a) Find the value of .
(b) The equation relating and can also be expressed in the form .
Find the value of .
(c) The manufacturer aims for an extremely high quality control score of .
Find the average number of defective watches in a standard batch for this quality score.
(d) The number of defective watches in a production run can be modelled by a Poisson distribution. The average number of defective watches in a standard batch (from part (c) ) represents the mean for a single production unit.
A large order consists of such standard production batches. Find the probability that this entire large order has no defective watches.
Recall the definition of logarithms and how to solve for an unknown in a logarithmic equation.
Remember the relationship between logarithmic and exponential forms, specifically for base 10.
Use the value of found in part (b) and substitute the new quality score.
Consider how the mean of a Poisson distribution changes when combining multiple independent units. The probability of zero events in a Poisson distribution is .
Question 7
HardPaper 2 · calculator16 marksA factory produces specialized electronic components. The total "quality score" of a component, , is a combination of scores from three independent inspection stages:
- Stage 1: Automated visual inspection. The score from this stage has an expectation of and a standard deviation of .
- Stage 2: Manual functional test. A batch of critical functions are tested, and the score is the number of functions that pass. Each function has a probability of passing, independently.
- Stage 3: Environmental stress test. The score from this stage, representing the number of successful stress cycles, follows a Poisson distribution with a mean of .
The overall quality score for a component is given by .
Calculate the expected value and variance of the total quality score .
Given that the distribution of can be approximated by a Normal distribution, find the probability that a randomly selected component has a total quality score between and (inclusive of , exclusive of ).
The factory manager wants to ensure that the mean total quality score of a sample of components is within units of the true mean, with a probability of at least . Find the minimum sample size required.
Recall the formulas for the expectation and variance of Binomial and Poisson distributions. For independent random variables and constants , and . Remember that .
When approximating a discrete distribution with a continuous Normal distribution, remember to apply a continuity correction. For , the continuous approximation would be .
The Central Limit Theorem states that for a sufficiently large sample size , the sample mean is approximately normally distributed with mean and variance . You will need to use the inverse normal function to find the critical Z-value for the given probability.
Question 8
MediumPaper 1 · calculator7 marksThe number of incoming calls received by a tech support hotline in a particular 30-minute period is historically known to follow a Poisson distribution with a mean of 48 calls per hour.
A new automated system is implemented, and it is claimed that this system has decreased the number of calls requiring human intervention.
To test this claim, the number of calls, Y, requiring human intervention in a 30-minute period on a particular day will be recorded. The test will have the following hypotheses:
: the mean number of calls requiring human intervention has not changed,
: the mean number of calls requiring human intervention has decreased.
The alternative hypothesis will be accepted if .
Assuming the null hypothesis to be true, state the distribution of Y.
Find the probability of a Type I error.
Find the probability of a Type II error, if the number of calls now follows a Poisson distribution with a mean of 35 calls per hour.
Recall the definition of a Poisson distribution and how to calculate its mean over a specific time period.
A Type I error occurs when the null hypothesis is rejected when it is actually true. This corresponds to the probability of observing a value in the critical region under the null hypothesis.
A Type II error occurs when the null hypothesis is accepted when it is actually false. This means observing a value outside the critical region when the alternative hypothesis is true. Remember to calculate the new mean for the observation period.
Question 9
HardPaper 2 · calculator8 marksA pharmaceutical company manufactures a drug where the concentration of the active ingredient, (in mg/mL), is crucial. The concentration is influenced by the reaction time, (in minutes), during the production process.
The relationship between the concentration and the reaction time is given by .
Due to slight variations in the manufacturing process, the reaction time is normally distributed with a mean of minutes and a standard deviation of minutes. That is, .
The quality control department assigns points to each batch based on the final concentration :
| Interval (mg/mL) | Points scored |
|---|---|
| Otherwise |
Find the expected total quality points scored from batches.
First, determine the mean and standard deviation of the concentration . Then, calculate the probability of a batch falling into each scoring interval using the normal distribution. Finally, use these probabilities to find the expected points per batch and then the total expected points for all batches.
Question 10
MediumPaper 1 · calculator5 marksA baker attempts to bake a batch of 4 special occasion cakes. The random variable X represents the number of perfectly baked cakes in a batch. The probability distribution for X is given in the following table.
| X (Number of perfectly baked cakes) | P(X=x) |
|---|---|
| 0 | 0.10 |
| 1 | 0.25 |
| 2 | k |
| 3 | 0.20 |
| 4 | 0.15 |
(a) Find the value of k.
The baker incurs costs and makes profit based on the number of perfectly baked cakes. The net gain (profit/loss) for the baker, in dollars, for a batch is shown in the following table.
| X (Number of perfectly baked cakes) | Net Gain ($) |
|---|---|
| 0 | -15 |
| 1 | -5 |
| 2 | 2 |
| 3 | 10 |
| 4 | 25 |
(b) Determine whether, on average, the baker expects to make a profit or a loss from baking a batch of these cakes. Justify your answer.
Remember that the sum of all probabilities in a probability distribution must equal 1.
To determine the expected outcome, calculate the expected value of the net gain. A positive expected value indicates an average profit, while a negative value indicates an average loss.
Question 11
HardPaper 1 · calculator12 marksTwo unbiased dice, each with faces numbered from 1 to 6 inclusive, are rolled. The numbers on the uppermost faces of the dice are noted.
Let the random variable be the sum of the numbers on the dice.
(a)(i) Find .
(a)(ii) Find .
(b) Complete the table to show the probability distribution of .
The probability that is shown.
| 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 | 10 | 11 | 12 | |
|---|---|---|---|---|---|---|---|---|---|---|---|
(c) Calculate .
(d) Given that the sum of the numbers on the dice is a prime number, find the probability that .
List all possible outcomes when rolling two dice and identify those where the sum is 7. Remember there are total possible outcomes.
Similar to part (a.i), identify the outcomes where the sum is 10.
Systematically list all possible sums and the number of ways each sum can be achieved. Remember that the sum of all probabilities must equal 1.
The expected value is calculated as . Use the probabilities from your completed table.
Recall the definition of conditional probability: . First, identify all prime sums and calculate the probability of getting a prime sum.
Question 12
MediumPaper 1 · calculator7 marksA player participates in a dart game where they throw one dart at a target with three distinct regions: an inner ring, a middle ring, and an outer ring. The probability of hitting each region in any given throw is shown in the following table.
| Region | Probability |
|---|---|
| Inner Ring | 0.2 |
| Middle Ring | 0.3 |
| Outer Ring | 0.5 |
The score awarded for hitting each region is:
- Inner Ring: 2 points
- Middle Ring: 1 point
- Outer Ring: 0 points
The player throws two darts independently. Find the probability that the player achieves a total score of exactly 2 points from the two throws.
In a different version of the game, the player wins points if they hit the Inner Ring, wins 4 points if they hit the Middle Ring, and loses 8 points if they hit the Outer Ring.
Find the value of such that the game is fair.
Consider all the combinations of two throws that result in a total score of 2 points. Remember that the throws are independent.
A game is considered fair if the expected value of the points won or lost is zero. Set up an equation for the expected value and solve for .
Question 13
HardPaper 1 · calculator6 marksA board game involves drawing cards from a special deck. Each card has a score printed on it. The possible scores are . The following table shows the probability distribution for the score, , when a card is drawn.
Score
(a) Find the exact value of .
(b) Calculate the expected score when drawing one card.
A player draws two cards from the deck, replacing the first card before drawing the second. Find the probability that the total score from the two cards is .
Remember that the sum of all probabilities in a probability distribution must equal 1.
The expected value is calculated by summing the product of each score and its corresponding probability: .
List all possible pairs of scores such that . Since the cards are replaced, the draws are independent events.
Question 14
MediumPaper 1 · calculator6 marksA company manufactures microchips. On average, 1 in 20 microchips fails the final quality control test. The failure of any microchip is independent of others.
In a randomly selected batch of 30 microchips, calculate the probability that exactly three microchips fail quality control.
In a randomly selected batch of 30 microchips, calculate the probability that more than two microchips fail quality control.
The company sells functional microchips for 20 each.
Calculate the expected revenue, in dollars, from selling a randomly selected batch of 30 microchips.
This scenario involves a fixed number of trials (microchips), two possible outcomes (fail/pass), a constant probability of failure, and independent trials. Which probability distribution models this situation?
To find the probability of 'more than two', consider the complement event. How can you express 'more than two' in terms of cumulative probabilities?
First, calculate the expected number of functional microchips and the expected number of failed microchips in the batch. Then, multiply these expected numbers by their respective selling prices and sum them up.
Question 15
HardPaper 2 · calculator15 marksThe 'SoundWave' concert hall has a capacity of seats. Historical data shows that of ticket holders attend the concert. The management decides to sell tickets, hoping that no more than concertgoers will arrive.
The number of concertgoers who arrive is assumed to follow a binomial distribution with a probability of .
(a) Calculate the probability that more than concertgoers arrive for the performance.
(b) (i) Write down the expected number of concertgoers who will arrive if tickets are sold.
(ii) Find the maximum number of tickets that could be sold if the expected number of concertgoers who arrive must be less than or equal to .
Each ticket costs 200 in compensation to each concertgoer who cannot be seated.
(c) Find, to the nearest integer, the expected increase or decrease in the money made by the venue if they decide to sell tickets rather than .
For a binomial distribution , the probability of successes is given by . To find the probability that more than concertgoers arrive, consider the probabilities for concertgoers, or use the complement rule . You will need a GDC for this calculation.
The expected value of a binomial distribution is given by .
Let be the number of tickets sold. The expected number of attendees is . Set up an inequality with this expected value and the capacity, then solve for . Remember that the number of tickets must be an integer.
Calculate the total expected money made for each scenario (selling tickets and selling tickets). For the -ticket scenario, you need to consider the income from all tickets sold and subtract the expected compensation. The expected compensation is calculated by summing the products of the probability of a specific number of overbooked attendees and the corresponding compensation amount.
Question 16
MediumPaper 1 · calculator7 marksA game involves two stages. First, a player draws a marble from a bag containing 3 red marbles and 2 blue marbles. After drawing a marble, the player spins a fair three-sided spinner with sections labeled 1, 2, and 3.
If a red marble is drawn, the player's final score is the number shown on the spinner.
If a blue marble is drawn, the player's final score is two more than the number shown on the spinner.
Find the probability that a player's final score is 4.
Complete the following table, showing the probability distribution of the final score.
| Final score () | 1 | 2 | 3 | 4 | 5 |
|---|---|---|---|---|---|
| Probability P() |
Calculate the expected value of the player's final score.
Consider the specific marble color and spinner outcome that would lead to a final score of 4. Calculate the probability of each event and then combine them.
List all possible combinations of marble drawn and spinner outcome. For each final score, identify all combinations that lead to it and sum their probabilities. Remember that the sum of all probabilities must be 1.
The expected value E(X) is calculated by summing the product of each possible score and its corresponding probability: E(X) = .
Question 17
HardPaper 2 · calculator21 marksA customer service department receives contacts from two independent sources: phone calls and emails. The number of phone calls received per hour can be modelled by a Poisson distribution with a mean of . The number of emails received per hour can be modelled by a Poisson distribution with a mean of .
(a)(i) Find the probability that the department receives at most phone calls in a -hour period.
(a)(ii) Find the probability that the department receives a total of more than contacts (phone calls and emails combined) in one hour.
Each phone call takes an average of minutes to handle, and each email takes an average of minutes to handle. Let be the total time (in minutes) spent handling contacts in one hour.
(b)(i) Find .
(b)(ii) Find .
(c) State one reason why the distribution of cannot be a Poisson distribution.
(d) The customer service department operates for an -hour shift. Use the Central Limit Theorem to find the probability that the mean time spent per hour handling contacts during this shift is greater than minutes.
For a Poisson distribution, if the mean rate is per unit of time, then for units of time, the mean rate is . Use the cumulative distribution function for the Poisson distribution.
Since the two sources are independent, the sum of two independent Poisson variables is also a Poisson variable with a mean equal to the sum of their individual means. Remember that 'more than 12' means '13 or more'.
The expected value of a linear combination of random variables is .
For independent random variables and , . Remember that for a Poisson distribution, the variance is equal to its mean.
Consider the properties of a Poisson distribution, specifically regarding its mean, variance, and the types of values it can take.
The Central Limit Theorem states that for a large sample size , the sample mean is approximately normally distributed with mean and variance .
Question 18
MediumPaper 1 · calculator7 marksA tech startup is launching a new app and offers a reward program for early users. Users can achieve different statuses based on their engagement.
Let be the net reward (in points) a user receives. The probability distribution for is shown below:
| (points) | |||
|---|---|---|---|
(a) Find the value of .
(b) The startup expects to sign up new users. Find the expected number of users who will receive a penalty (score points).
(c) The startup wants the reward program to be 'balanced', meaning the average net reward per user is points. Calculate the value of for this condition.
Remember that the sum of all probabilities in a probability distribution must equal 1.
The expected number of occurrences of an event is the total number of trials multiplied by the probability of that event.
A 'balanced' program implies that the expected value of the net reward is zero. Use the formula .
Question 19
HardPaper 2 · calculator15 marksTech Solutions Inc. is a customer support company. They are analyzing their call center efficiency. Over a long period, they collect data on the number of calls, , already in the queue when a new customer's call arrives. The probability distribution of is shown in the following table.
| Number of calls in queue, | 0 | 1 | 2 | 3 | |
|---|---|---|---|---|---|
| P() | 0.15 | 0.30 | 0.35 | 0.20 | 0 |
Find the probability that there are at least two calls in the queue when a new customer's call arrives.
Find E().
The time in seconds, , taken to resolve a single customer's issue can be modelled by the normal distribution .
The company's management estimates that the expected total time a new customer will wait before their issue is resolved can be found by calculating E() E().
Find the value of E() E().
The company considers a service time to be 'long' if it takes more than three minutes to resolve a single customer's issue.
Using the distribution of given above, find the probability that it takes more than three minutes to resolve a randomly selected customer's issue.
Find the probability it takes more than four minutes in total to resolve two randomly selected customers' issues. You may assume all service times are independent of all other service times.
The company assumes that when a new customer's call arrives, the person at the front of the queue has only just reached a support agent. They also assume that if there are three or more customers already in the queue, the new customer will definitely wait more than three minutes before being served.
Using these assumptions and the probabilities for given in the table above,
find the probability a customer just arriving at the call center will wait more than three minutes before being served.
The company has a policy to employ more staff if the probability that a customer has to wait more than three minutes before being served is greater than .
Hence state whether Tech Solutions Inc. will decide to employ more staff.
To find the probability of 'at least two calls', sum the probabilities for and .
The expected value E() is calculated as the sum of (each value of its corresponding probability ).
Recall that for a normal distribution , the expected value E() is simply . Then multiply this by E() found in part (a.ii).
Convert three minutes to seconds. Then use your GDC to find for the given normal distribution.
If and are independent normal random variables, then their sum is also a normal random variable. The mean of the sum is the sum of the means, and the variance of the sum is the sum of the variances.
Consider the different scenarios for the number of customers in the queue ().
If , the wait time is 0.
If , the wait time is .
If , the wait time is .
If , the wait time is assumed to be minutes.
Compare the probability calculated in part (e.i) with the threshold of .
Question 20
MediumPaper 1 · calculator7 marks(a) Find the value of .
A fantasy adventure game involves exploring ancient ruins, where players can discover treasures or encounter perils. Points are awarded based on the outcome of each exploration:
- Discovering a rare relic scores points.
- Finding a common artifact scores points.
- Triggering a trap results in a loss of points.
Let be the number of points scored during a single exploration. The probability distribution is shown in the table below.
(b) The ruins are explored times. Find the expected number of times a player triggers a trap.
(c) Calculate the value of , given that the game is fair.
Remember that the sum of all probabilities in a probability distribution must equal 1.
To find the expected number of occurrences for an event over multiple trials, multiply the total number of trials by the probability of that event occurring in a single trial.
A 'fair game' implies that the expected value of the points scored, , is equal to zero. Use the formula for expected value: .
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