Skip to content
  1. IB Question Bank
  2. Maths AI
  3. Geometry & Trigonometry
Topic 3.02 · SL and HL

Volume & surface area of 3D objects: notes and practice questions

Summary
  • Volume: Measure of 3D space a shape occupies.
  • Surface Area: Total area of all outer faces and curved surfaces of a 3D object.
  • Prism: 3D shape with two identical base shapes and a uniform cross-section.
  • Right-Pyramid/Cone: Apex is vertically above the exact center of the base; vertical height (h) is perpendicular to the base.
  • Volume of Prism: V=AhV = Ah (A = area of uniform cross-section, h = length/height).
  • Volume of Cuboid: V=lwhV = lwh.
  • Volume of Cylinder: V=πr2hV = \pi r^2 h.
  • Volume of Right-Pyramid: V=13AhV = \frac{1}{3}Ah (A = area of the base).
  • Volume of Right-Cone: V=13πr2hV = \frac{1}{3}\pi r^2 h.
  • Volume of Sphere: V=43πr3V = \frac{4}{3}\pi r^3.
  • Surface Area (General): Sum of areas of all 2D net faces.
  • Surface Area of Sphere: A=4πr2A = 4\pi r^2.
  • Curved Surface Area of Right-Cone: A=πrlA = \pi rl (l = slant height).
  • Total Surface Area of Right-Cone: A=πrl+πr2A = \pi rl + \pi r^2.
  • Cone relationship: Slant height (l), radius (r), and vertical height (h) form a right-angled triangle: l2=r2+h2l^2 = r^2 + h^2.
  • Formulas are in the IB formula booklet: "Prior Learning" (cuboids, cylinders, prisms) and "Topic 3: Geometry" (pyramids, cones, spheres).
  • Keep intermediate values exact in GDC; round only final answers to 3 significant figures.

How it is examined

A reliable early question on both SL papers, usually a composite solid where the student finds a volume, then a surface area, then an angle. Because the formulas are in the booklet, the marks are for picking the right solid, decomposing the shape, and identifying the right-angled triangle inside it. The restriction to right-angled trigonometry in 3D at SL is the line to hold when writing questions.

Given in the booklet

The distance between two points in three dimensions, the coordinates of the midpoint, and the volume and surface area formulas for the right-pyramid, right cone, sphere and hemisphere. This is a real difference from AA, where students recall more of these.

Key ideas
  • The distance between two points in three-dimensional space, and their midpoint.
  • The volume and surface area of three-dimensional solids including the right-pyramid, right cone, sphere, hemisphere, and combinations of these solids.
  • The size of an angle between two intersecting lines, or between a line and a plane.

Linking questions

  • Other contexts: architecture and design.
  • Links to other subjects: design technology; volumes of stars and the inverse square law (physics).
  • TOK: what is an axiomatic system? Are axioms self evident to everybody?

Practice questions

29 questions · 17 medium · 12 hard
Showing 20 of 20

Question 1

MediumPaper 1 · calculator6 marks
(a)

A company manufactures decorative glass paperweights in the shape of a solid hemisphere. The radius of each paperweight is 8 cm.

A diagram showing a hemisphere with radius 8 cm

(a) Calculate the total surface area of one such paperweight.

[4]
(b)

Each paperweight is coated with a protective sealant. It is known that 1 mL of the sealant covers an area of 150 cm2^2.

(b) Calculate the volume of sealant required to coat one paperweight.

[2]

Question 2

HardPaper 1 · calculator8 marks
(a)

A scientist is preparing a cylindrical container for an experiment. She measures the radius of the base, rr, to be 5.0 cm and the height, hh, to be 12 cm.

Calculate the volume of the cylindrical container using these measurements. Give your answer to three significant figures.

[2]
(b)

It is known that the measurements are accurate to the number of significant figures given.

Find the lower bound and upper bound of the volume of the cylindrical container. Give your answers to three significant figures.

[3]
(c)

Find, with justification, the largest possible percentage error if the answer to part (a) is recorded as the volume of the cylindrical container.

[3]

Question 3

MediumPaper 1 · calculator10 marks
(a)(i)

(a) A satellite dish is supported by three anchor points A, B, and C on a mast. The coordinates of these points, relative to a fixed origin, are A(1, 2, 0), B(7, 2, 0), and C(4, 6, 1), where distances are measured in metres.

(i) Find the vector CA→\overrightarrow{\text{CA}}.

[2]
(a)(ii)

(ii) Find the vector CB→\overrightarrow{\text{CB}}.

[2]
(b)

(b) Calculate CA→×CB→\overrightarrow{\text{CA}} \times \overrightarrow{\text{CB}}.

[3]
(c)

(c) Hence, determine the area of the triangular support surface formed by points A, B, and C.

[3]

Question 4

HardPaper 2 · calculator11 marks
(a)

A rectangular prism with length 10 cm, width 8 cm, and height 6 cm is used as a base for a sculpture. One corner, vertex H, is cut off by a flat plane passing through points P, Q, and R. Point P is on edge HE such that HP = 3 cm. Point Q is on edge HG such that HQ = 4 cm. Point R is on edge HD such that HR = 3 cm.

(a) Calculate the volume of the remaining part of the prism.

[3]
(b)

(b) Calculate the total surface area of the remaining part of the prism.

[8]

Question 5

MediumPaper 1 · calculator10 marks
(a)

A landscape architect is designing a section of a park. The boundary of a planned pathway can be modelled by the line y=−x+8y = -x + 8 and a decorative flower bed by the curve y=0.5x2−4x+10.5y = 0.5x^2 - 4x + 10.5. These two features intersect at points (1,7)(1, 7) and (5,3)(5, 3), as shown in the following diagrams.

In diagram 1, the region enclosed by the line y=−x+8y = -x + 8, x=1x = 1, x=5x = 5 and the xx-axis has been shaded.

Diagram 1 showing a shaded region under the line y=-x+8 from x=1 to x=5, with intersection points (1,7) and (5,3).

Calculate the area of the shaded region in diagram 1.

[2]
(b)(i)

In diagram 2, the region enclosed by the curve y=0.5x2−4x+10.5y = 0.5x^2 - 4x + 10.5, and the lines x=1x = 1, x=5x = 5 and the xx-axis has been shaded.

Diagram 2 showing a shaded region under the curve y=0.5x^2-4x+10.5 from x=1 to x=5, with intersection points (1,7) and (5,3).

Write down an integral for the area of the shaded region in diagram 2.

[3]
(b)(ii)

Calculate the area of this region.

[3]
(c)

Hence, determine the area enclosed between the line y=−x+8y = -x + 8 and the curve y=0.5x2−4x+10.5y = 0.5x^2 - 4x + 10.5.

[2]

Question 6

HardPaper 2 · calculator12 marks
(a)

(a) A cylindrical grain silo with a radius of 2.52.5 m and an initial grain height of 1010 m is being emptied. The rate at which the grain is removed from the silo is proportional to the square root of the height of the grain.

Using VV for the volume of grain in the silo and hh for the height of the grain, write down a differential equation relating these variables.

[2]
(b)

(b) Apply the chain rule and the formula for the volume of a cylinder to show that dVdt=6.25πdhdt\frac{dV}{dt} = 6.25\pi \frac{dh}{dt}. Hence, write your answer to part (a) in terms of hh and tt.

[3]
(c)

(c) After 3030 minutes, the height of the grain has dropped to 6.256.25 m. Predict how long it will take for the silo to be completely empty from the initial height of 1010 m.

[7]

Question 7

MediumPaper 1 · calculator6 marks
(a)

The ancient civilization of Eldoria constructed monumental structures using a unit of measurement called the Ancient Eldorian Rod (AER).

Historians have determined that 1 AER is equivalent to 0.74 metres, rounded to two decimal places.

Write down the upper and lower bounds of 1 AER in metres.

[2]
(b)

The grand 'Tower of Eldoria' is modelled as a square-based pyramid with a base side length of 380 AER and a height of 250 AER. Assume these measurements are exact.

Find the minimum possible volume of the pyramid in cubic metres.

[4]

Question 8

HardPaper 2 · calculator13 marks
(a)

A company is designing an open-top storage container with a square base. The side length of the base is xx cm and the height is hh cm. The container needs to have a volume of 500500 cm3^3.

Explain why x2h=500x^2 h = 500.

[1]
(b)

Rearrange the equation in part (a) to make hh the subject.

[1]
(c)

Write down an expression for the surface area, AA, of the open-top container.

[2]
(d)

Show that this can be written as

A=x2+2000xA = x^2 + \frac{2000}{x}

[3]
(e)

Plot the graph of A=x2+2000xA = x^2 + \frac{2000}{x} for x>0x > 0.

[2]
(f)

Find the minimum surface area and the value of xx when this occurs.

[4]

Question 9

MediumPaper 1 · calculator9 marks
(a)(i)

A spherical ice sculpture is melting in a gallery. Initially, the sculpture has a radius of 30 cm. This information is illustrated in the following diagram.

diagram not to scale. Image of a spherical ice sculpture with a radius of 30 cm.

The gallery curator predicts that, as the ice sculpture melts, its radius will decrease at a constant rate of 0.5 cm per hour.

According to this model, find

(i) the radius of the ice sculpture, 10 hours after it begins melting.

[2]
(a)(ii)

(ii) the volume of the ice sculpture, 10 hours after it begins melting. Give your answer to one decimal place.

[2]
(b)

Let the function V(t)V(t) represent the volume of the ice sculpture, cm3\text{cm}^3, tt hours after it begins melting. V(t)V(t) is given by

V(t)=113000−5000t+150t2−1.5t3V(t) = 113000 - 5000t + 150t^2 - 1.5t^3, for 0≤t≤200 \le t \le 20.

Find V′(t)V'(t).

[2]
(c)

Find the rate of change of the volume of the ice sculpture at t=10t = 10 hours.

[2]
(d)

State one reason why the radius of the ice sculpture may not always decrease at a constant rate.

[1]

Question 10

HardPaper 2 · calculator15 marks
(a)

(a) A pharmaceutical company is designing a new cylindrical container for a special liquid. The container has a fixed volume V=500 cm3V = 500 \text{ cm}^3.

The radius of the container is r cmr \text{ cm} and the height is h cmh \text{ cm}.

Show that πr2h=500\pi r^2 h = 500.

[2]
(b)

(b) Find an expression for the total surface area SS of the container.

[2]
(c)

(c) Substitute an expression for hh (from part (a) ) into your expression for SS (from part (b) ) and hence show that S=2πr2+1000rS = 2\pi r^2 + \frac{1000}{r}.

[3]
(d)

(d) Find dSdr\frac{dS}{dr}.

[2]
(e)

(e) Find the minimum value of SS and the values of rr and hh when this occurs. Show that this value of SS is indeed a minimum.

[6]

Question 11

MediumPaper 1 · calculator5 marks
(a)

(a) A spherical decorative orb has a radius of 4.5 cm. A craftsman plans to cover 27\frac{2}{7} of its surface with intricate filigree work.

Calculate the volume of the orb that will NOT be covered by the filigree work.

[3]
(b)

(b) A conical party hat has a slant height of 15 cm and a base radius of 6 cm. The outside of the hat (excluding the base) is to be decorated with glitter.

Calculate the surface area of the hat that will be covered with glitter. Give your answer correct to the nearest cm2^2.

[2]

Question 12

HardPaper 1 · calculator8 marks
(a)(i)

A landscape architect is designing a large decorative fountain for a new public park. The outer structure of the fountain consists of a cylindrical base topped by a conical section. The inner part of the fountain, which holds the water, is a hollow space created by rotating a specific curve around the vertical axis.

The shape of the inner hollow is based on a transformation of the graph y=−x3y = -x^3. The curve that defines the profile of the inner hollow is given by y=40−0.064x3y = 40 - 0.064x^3. This transformation involves a vertical translation of aa units and a stretch parallel to the x-axis with a scale factor of bb.

(a.i) Write down the value of aa.

[1]
(a)(ii)

(a.ii) Find the value of bb.

[2]
(b)

The cylindrical base of the fountain has a radius of 1515 m and a height of 55 m. The conical section on top has the same base radius of 1515 m and a height of 88 m. The inner hollow, described by the curve y=40−0.064x3y = 40 - 0.064x^3, extends from the base of the fountain (y=0y=0) up to the total height of the outer structure.

Find the volume of the solid material that makes up the fountain (i.e., the volume of the outer structure minus the volume of the inner hollow).

[5]

Question 13

MediumPaper 1 · calculator5 marks
(a)

A conical tank is being filled with water. The tank has a height of 12 cm and a radius of 4 cm at its top. Water is poured into the tank such that the volume of water is increasing at a rate of 10 cm3^3s−1^{-1}.

(a) Find the height of the water in the tank when its volume is 8π\pi cm3^3.

[2]
(b)

(b) Hence or otherwise, find the rate of change of the height of the water at this instant.

[3]

Question 14

HardPaper 2 · calculator14 marks
(a)

A botanical garden is constructing a large planter box for exotic plants. The planter is shaped like an inverted frustum of a right pyramid, with a horizontal square top opening of side length 120120 metres and a smaller horizontal square base of side length 8080 metres.

The depth of the planter is 99 metres.

Find the angle of inclination of the side walls of the planter to the horizontal.

[2]
(b)(i)

(b) The point V is the theoretical vertex of the full pyramid from which the frustum is cut, and C is the centre of the square top opening.

(i) Find the total height of the pyramid from its theoretical vertex V to the centre of the top opening C.

[2]
(b)(ii)

(ii) Hence or otherwise, show that the volume of the planter is 91200 m391200 \text{ m}^3.

[3]
(c)

The botanical garden orders 180000180000 bags of a special soil mix, with each bag containing 0.5 m30.5 \text{ m}^3 of soil. Determine whether the ordered soil is sufficient to fill the planter.

[2]
(d)

To prevent soil erosion and water leakage, the entire interior surface of the planter (including the bottom base and the four side walls) needs to be lined with a waterproof membrane. Calculate the total area that needs to be lined.

[5]

Question 15

MediumPaper 2 · calculator13 marks
(a)

(a) A sculptor is creating a metal art piece from a solid cylindrical block. The block has a radius of 55 cm and a height of 1212 cm. A conical section is drilled out from the top center of the block. The conical hole has the same radius as the cylinder and a height of 99 cm.

Calculate the remaining volume of the metal sculpture.

[5]
(b)

(b) Determine the total surface area of the finished sculpture.

[8]

Question 16

HardPaper 2 · calculator18 marks
(a)

(a) An architect is designing a modular facade for a building. Each module is based on a fundamental rectangular panel, PP. The vertices of panel PP are (0,0)(0,0), (3,0)(3,0), (3,2)(3,2), and (0,2)(0,2).

Show that the area of the panel PP is 66 square units.

[2]
(b)(i)

(b) The design incorporates 30 elements, each obtained by transforming the panel PP. These elements form a symmetric pattern, with the y-axis acting as a line of symmetry.

The transformation that produces each of the elements on the right side of the design can be represented by a matrix of the form

Mk=((1−k15)cos⁡(k×12°)−(1−k15)sin⁡(k×12°)(1−k15)sin⁡(k×12°)(1−k15)cos⁡(k×12°))M_k = \begin{pmatrix} (1-\frac{k}{15})\cos(k\times12\degree) & -(1-\frac{k}{15})\sin(k\times12\degree) \\ (1-\frac{k}{15})\sin(k\times12\degree) & (1-\frac{k}{15})\cos(k\times12\degree) \end{pmatrix}

where k=0,1,2,...,14k = 0, 1, 2, ..., 14.

(i) Find the matrix M0M_0. Give your answer in the form (abcd)\begin{pmatrix} a & b \\ c & d \end{pmatrix} where a,b,c,d∈Qa, b, c, d \in \mathbb{Q}.

[2]
(b)(ii)

(ii) Hence find the coordinates of the image of the vertex (3,2)(3,2) after it is transformed by the matrix M0M_0.

[2]
(c)(i)

(c) The matrix MkM_k can be expressed as the product of a rotation matrix and an enlargement matrix.

(i) Write down, in terms of kk, the rotation matrix.

[1]
(c)(ii)

(ii) Write down, in terms of kk, the enlargement matrix.

[1]
(c)(iii)

(iii) Write down, in terms of kk, the angle of the rotation.

[1]
(c)(iv)

(iv) Write down, in terms of kk, the scale factor of the enlargement.

[1]
(d)

(d) Using your answer to part (c)(iv), or otherwise, find the determinant of the matrix MkM_k in terms of kk.

[2]
(e)

(e) Hence, or otherwise, find the total area of the elements in the whole design. Give your answer to three significant figures.

[4]
(f)

(f) Each element on the left side of the design can be obtained through a transformation of the panel PP by applying the matrix NkN_k, where k=0,1,2,...,14k = 0, 1, 2, ..., 14.

Write down the matrix NkN_k as a product of two matrices.

[2]

Question 17

MediumPaper 2 · calculator13 marks
(a)(i)

A company is designing heat sinks for a new line of high-performance microchips. They want to maximize the heat dissipation efficiency, which is directly related to the surface area to volume ratio (SA:VSA:V) of the heat sink material. A higher SA:VSA:V ratio allows for faster heat transfer away from the chip.

(a) Calculate the surface area, volume, and surface area to volume ratio (SA:VSA:V) for each of the heat sink designs below. Give your answers to three significant figures where appropriate.

(i) Square Prisms

Base side (ss) ×\times Height (hh)22 cm ×\times 22 cm22 cm ×\times 44 cm44 cm ×\times 22 cm
Surface area (SASA) (cm2^2)
Volume (VV) (cm3^3)
Surface area to volume ratio, SA:VSA:V (cm−1^{-1})
[5]
(a)(ii)

(ii) Cylinders

Radius (rr) ×\times Height (hh)11 cm ×\times 22 cm11 cm ×\times 44 cm22 cm ×\times 22 cm
Surface area (SASA) (cm2^2)
Volume (VV) (cm3^3)
Surface area to volume ratio, SA:VSA:V (cm−1^{-1})
[5]
(b)

(b) Based on your calculations, state what conclusions can be drawn about the design principles for heat sinks to achieve a higher surface area to volume ratio (SA:VSA:V).

[3]

Question 18

HardPaper 2 · calculator23 marks
(a)

(a) A confectionery company is designing a new wrapper for a chocolate bar. The wrapper is in the shape of a rectangular prism with a square base of side length xx cm. The height, hh cm, is twice the side length of the base.

Write down an expression for hh in terms of xx.

[1]
(b)

(b) The chocolate bar has a volume of 250250 cm3^3.

Find the value of xx and hh.

[3]
(c)

(c) Calculate the total external surface area of this rectangular prism wrapper.

[3]
(d)

(d) The company also considers a cylindrical wrapper with radius rr cm and height HH cm. This wrapper must also hold 250250 cm3^3 of chocolate.

Find an expression for the height, HH, of the cylindrical wrapper in terms of rr.

[2]
(e)

(e) Let the total external surface area of the cylindrical wrapper be AA cm2^2.

Show that A=2πr2+500rA = 2\pi r^2 + \frac{500}{r}.

[2]
(f)

(f) Find dAdr\frac{dA}{dr}.

[3]
(g)(i)

(g.i) Hence or otherwise, find the value of rr that will minimize AA.

[3]
(g)(ii)

(g.ii) Find the minimum value of AA for the cylindrical wrapper.

[3]
(h)

(h) To account for manufacturing waste and overlap, an additional 12%12\% of the calculated surface area is required for the rectangular prism wrapper, and 20%20\% for the cylindrical wrapper.

Determine which wrapper design the company should choose to minimize material usage. Justify your answer.

[3]

Question 19

MediumPaper 2 · calculator12 marks
(a)

A rectangular prism (cuboid) is used as a building block. It has one vertex at the origin O(0,0,0). Its dimensions are 6 units along the x-axis, 4 units along the y-axis, and 3 units along the z-axis. The vertices are given by O(0,0,0), A(6,0,0), B(6,4,0), C(0,4,0), D(0,0,3), E(6,0,3), F(6,4,3), and G(0,4,3).

Find the surface area of the cuboid.

[2]
(b)

Find the length of the space diagonal [OF].

[2]
(c)(i)

The space diagonals [OF] and [CE] intersect at the point M.

Find the coordinates of M.

[4]
(c)(ii)

Find the acute angle between the diagonals [OF] and [CE] at their intersection point M.

[4]

Question 20

HardPaper 2 · calculator20 marks
(a)

(a) SweetTreats is designing new packaging for a line of artisanal chocolates. The initial design is a box in the shape of a cuboid with a square base of side length LL cm. Its height, HH cm, is twice the length of the base.

Write down an expression for HH in terms of LL.

[1]
(b)

(b) The box is designed to hold 250250 cm3^3 of chocolates.

Find the value of LL and HH.

[3]
(c)

(c) Calculate the total external surface area of the box.

[3]
(d)

(d) To minimize the amount of material needed, SweetTreats is considering changing the shape to a cylinder with radius rr cm and height hh cm. The cylindrical container must also hold 250250 cm3^3 of chocolates.

Find an expression for the height, hh, of the container in terms of rr.

[2]
(e)

(e) Let the total external surface area of the cylindrical container be AA cm2^2.

Show that A=2πr2+500rA = 2\pi r^2 + \frac{500}{r}.

[2]
(f)

(f) Find dAdr\frac{\text{d}A}{\text{d}r}.

[3]
(g)(i)

(g.i) Hence or otherwise, find the value of rr that will minimize AA.

[2]
(g)(ii)

(g.ii) Find the minimum value of AA needed for the cylinder.

[1]
(h)(i)

(h.i) Find d2Adr2\frac{\text{d}^2 A}{\text{d}r^2}.

[1]
(h)(ii)

(h.ii) Hence determine whether the graph of AA is concave-up or concave-down for r>0r > 0. Justify your answer.

[2]

9 more Volume & surface area of 3D objects questions in the app

Every answer is marked mark by mark, IB-style, and the AI tutor helps when you are stuck.

Where marks are lost

  • Using your own wrong value after failing a "show that." All follow through is withdrawn for the rest of that question.
Free. Every IB subject.
No card, no trial that runs out. Just a free account.
  • 50 marked answers a month
    Marked mark by mark, IB-style
  • Hints and mark schemes
    On every part of every question
  • 3,000+ questions
    All 6 subjects, SL and HL, mapped to the syllabus
  • Progress that adapts
    Your Study Profile picks what to practise next

Practise this topic as a session

Pick a difficulty and paper, and FourtyFive tracks your progress on this topic as you go.

or with email
FAQ

Questions,
answered.

Can't find what you're looking for? Email our student team.

What does Volume & surface area of 3D objects cover in IB Maths AI?

Volume: Measure of 3D space a shape occupies. Surface Area: Total area of all outer faces and curved surfaces of a 3D object. Prism: 3D shape with two identical base shapes and a uniform cross-section.

Is Volume & surface area of 3D objects SL or HL?

Both. SL and HL students study Volume & surface area of 3D objects to the same depth.

How do I revise Volume & surface area of 3D objects for IB Maths AI?

Start from the core idea: volume: Measure of 3D space a shape occupies. In the exam: a reliable early question on both SL papers, usually a composite solid where the student finds a volume, then a surface area, then an angle. Because the formulas are in the booklet, the marks are for picking the right solid, decomposing the shape, and identifying the right-angled triangle inside it. Then practise exam-style questions, easiest first, writing out every step of your working before you check it.

How does FourtyFive help me practise Volume & surface area of 3D objects?

FourtyFive has 29 Volume & surface area of 3D objects questions. Every answer you write is marked mark by mark, IB-style, and you see where each mark was won or lost. Every part has a hint, the AI tutor helps you through the step you are stuck on, and your Study Profile picks what to practise next.

Is FourtyFive free for Volume & surface area of 3D objects practice?

Yes. A free account gives you 50 marked answers a month, and you do not need a card to sign up.

Can I handwrite Volume & surface area of 3D objects answers on an iPad?

Yes. In the FourtyFive iPad app you write your working by hand with Apple Pencil, the way you would on paper, and it is marked the same way.

Start with the IB question
bank built for you.

Free to start, no card needed. Thousands of syllabus-mapped questions, AI Examiner marking, your weakest topics first.