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Topic 1.05 · SL and HL

Exponents: notes and practice questions

Summary
  • Standard Form (Scientific Notation): Expresses numbers in the form a×10ka \times 10^k, where 1≤a<101 \le a < 10 and kk is an integer (k∈Zk \in \mathbb{Z}).
  • Laws of Indices (Exponents): Rules used to simplify and manipulate expressions involving exponents. They require terms to have the same base and are not in the formula booklet. Key laws include:
  • xm×xn=xm+nx^m \times x^n = x^{m+n}
  • xm÷xn=xm−nx^m \div x^n = x^{m-n}
  • (xm)n=xmn(x^m)^n = x^{mn}
  • (xy)m=xmym(xy)^m = x^m y^m
  • x0=1x^0 = 1
  • x−m=1xmx^{-m} = \frac{1}{x^m}
  • x1n=xnx^{\frac{1}{n}} = \sqrt[n]{x}
  • xmn=xmnx^{\frac{m}{n}} = \sqrt[n]{x^m}

How it is examined

Paper 1 asks for exponent manipulation with no calculator, usually as a step inside a longer question rather than on its own. Base 10 and e only at this subtopic; general bases arrive at SL 1.7. 2 to 4 marks.

Given in the booklet

The exponent laws are not given. ax=b⇔log⁡ab=xa^x = b \Leftrightarrow \log_a b = x is listed under the laws of logarithms.

Key ideas
  • Laws of exponents with integer exponents.
  • Introduction to logarithms with base 10 and e.
  • Numerical evaluation of logarithms using technology.

Linking questions

  • Other contexts: the Richter scale and the decibel scale.
  • Links to other subjects: calculation of pH and buffer solutions (chemistry).

Practice questions

35 questions · 1 easy · 25 medium · 9 hard
Showing 20 of 20

Question 1

EasyPaper 1 · no calculator6 marks
(a)

(a) Find the value of log⁡464\log_4 64.

[2]
(b)

(b) Find the value of log⁡3(19)\log_3 \left(\frac{1}{9}\right).

[2]
(c)

(c) Find the value of log⁡255\log_{25} 5.

[2]

Question 2

MediumPaper 1 · no calculator5 marks

A researcher is studying the propagation of a signal through a medium. The signal strength SS at a certain point is related to a characteristic parameter PP of the medium by the equation:

log2(P3)−1log32=log2(P4)log_2 (P^3) - \frac{1}{log_3 2} = log_2 (\frac{P}{4})

where P>0P > 0.

(a) Determine the value of PP.

Question 3

HardPaper 1 · no calculator5 marks

Solve the equation log2(x2)=3log52+log2(x425)log_{2}(x^{2}) = \frac{3}{log_{5}2} + log_{2}\left(\frac{x^{4}}{25}\right), where x>0x > 0.

Question 4

MediumPaper 1 · no calculator5 marks
(a)

(a) A scientist is studying the rate at which a certain chemical compound dissolves in a solution. The rate of dissolution, RR, in grams per minute, at time tt minutes, is modeled by the expression R(t)=4t−7tR(t) = \frac{4\sqrt{t} - 7}{\sqrt{t}}.

This expression can be written in the form A−BtpA - Bt^p, where AA, BB, and pp are constants. Write down the value of pp.

[1]
(b)

(b) Hence, calculate the total amount of compound dissolved between t=4t=4 minutes and t=9t=9 minutes.

[4]

Question 5

HardPaper 3 · calculator16 marks
(a)

In a study of wave propagation, a mathematical model uses the function g(x)=ex−e−x2g(x) = \frac{e^x - e^{-x}}{2}, where x∈Rx \in \mathbb{R}, to describe a certain physical quantity. This function is also known as the hyperbolic sine function, sinh⁡x\sinh x.

Verify that y=g(x)y = g(x) satisfies the differential equation d2ydx2=y\frac{d^2y}{dx^2} = y.

[2]
(b)

Another related function, the hyperbolic cosine, is defined as f(x)=ex+e−x2f(x) = \frac{e^x + e^{-x}}{2}, also known as cosh⁡x\cosh x. Show that (cosh⁡x)2−(sinh⁡x)2=1(\cosh x)^2 - (\sinh x)^2 = 1.

[3]
(c)(i)

The functions cosh⁡x\cosh x and sinh⁡x\sinh x can be extended to complex numbers. Using Euler's formula eiθ=cos⁡θ+isin⁡θe^{i\theta} = \cos \theta + i \sin \theta, where θ∈R\theta \in \mathbb{R}, express cosh⁡(iθ)\cosh(i\theta) in terms of cos⁡θ\cos \theta and sin⁡θ\sin \theta.

[3]
(c)(ii)

Similarly, express sinh⁡(iθ)\sinh(i\theta) in terms of cos⁡θ\cos \theta and sin⁡θ\sin \theta.

[2]
(d)

Hence, show that (cosh⁡(iθ))2+(sinh⁡(iθ))2=cos⁡(2θ)(\cosh(i\theta) )^2 + (\sinh(i\theta) )^2 = \cos(2\theta).

[2]
(e)

In a design project, a component's profile is described by a hyperbola with parametric equations x=Acosh⁡tx = A \cosh t and y=Bsinh⁡ty = B \sinh t, where A,BA, B are positive constants and t∈Rt \in \mathbb{R}.

Given that the component's profile passes through the point (6,0)(6, 0) and has asymptotes y=±43xy = \pm \frac{4}{3}x, find the values of AA and BB.

[4]

Question 6

MediumPaper 1 · no calculator5 marks

(a) Solve the equation log⁡5(x2)=1log⁡25+log⁡5(8x)\log_5 (x^2) = \frac{1}{\log_2 5} + \log_5 \left(\frac{8}{x}\right), where x>0x>0.

Question 7

HardPaper 3 · calculator24 marks
(a)

A biologist is modelling the growth of two different bacterial colonies. The first colony, A, grows such that its population at time xx is given by PA(x)=axP_A(x) = a^x, where aa is a growth factor and x≥0x \ge 0. The second colony, B, grows linearly such that its population at time xx is PB(x)=xP_B(x) = x.

Consider the cases where the growth factor a=2a = 2 and a=10a = 10. On the same set of axes, sketch the following three graphs for x≥0x \ge 0:

y=2xy = 2^x

y=10xy = 10^x

y=xy = x

Clearly label each graph with its equation and state the coordinates of any non-zero yy-axis intercepts.

[4]
(b)

In parts (b) and (c), consider the case where the growth factor a=ea = e.

Use calculus to find the minimum value of the expression ex−xe^x - x, justifying that this value is a minimum.

[5]
(c)

Hence deduce that ex>xe^x > x for all x∈Rx \in \mathbb{R}.

[1]
(d)

There exist values of aa for which the graph of y=axy = a^x and the line y=xy = x have different numbers of intersection points. The following table gives three intervals for the value of aa.

IntervalNumber of intersection points
0<a<10 < a < 1pp
1<a<1.41 < a < 1.4qq
1.5<a<21.5 < a < 2rr

By investigating the graph of y=axy = a^x for different values of aa, write down the values of p,qp, q and rr.

[4]
(e)

In parts (e) and (f), consider a∈R+,a≠1a \in \mathbb{R}^+, a \neq 1.

For 1.4≤a≤1.51.4 \leq a \leq 1.5, a value of aa exists such that the line y=xy = x is a tangent to the graph of y=axy = a^x at a point P.

Find the exact coordinates of P and the exact value of aa.

[8]
(f)(i)

Write down the exact set of values for aa such that the graphs of y=axy = a^x and y=xy = x have

(i) two intersection points;

[1]
(f)(ii)

(ii) no intersection points.

[1]

Question 8

MediumPaper 1 · no calculator6 marks
(a)

Show that (x+1x)2(\sqrt{x} + \frac{1}{\sqrt{x}})^2 can be written as x+2+1xx + 2 + \frac{1}{x}.

[2]
(b)

Hence, find the exact value of ∫1e2(x+1x)2dx\int_{1}^{e^2} (\sqrt{x} + \frac{1}{\sqrt{x}})^2 dx.

[4]

Question 9

HardPaper 1 · no calculator14 marks
(a)

Consider the function f(x)=axf(x) = a^x where x,a∈Rx, a \in \mathbb{R} and a>1a > 1. The graph of ff contains the point (32,27)(\frac{3}{2}, 27).

(a) Show that a=9a = 9.

[2]
(b)

(b) Write down an expression for f−1(x)f^{-1}(x).

[1]
(c)

(c) Find the value of f−1(181)f^{-1}(\frac{1}{81}).

[3]
(d)(i)

Consider the arithmetic sequence log⁡98,log⁡9p,log⁡9q,log⁡927\log_9 8, \log_9 p, \log_9 q, \log_9 27, where p>1p > 1 and q>1q > 1.

(i) Show that 8,p,q8, p, q and 2727 are four consecutive terms in a geometric sequence.

[4]
(d)(ii)

Consider the arithmetic sequence log⁡98,log⁡9p,log⁡9q,log⁡927\log_9 8, \log_9 p, \log_9 q, \log_9 27, where p>1p > 1 and q>1q > 1.

(ii) Find the value of pp and the value of qq.

[4]

Question 10

MediumPaper 1 · no calculator5 marks
(a)

The expression 2x3−5x3 \frac{2\sqrt[3]{x}-5}{\sqrt[3]{x}} can be written as 2−5xp2-5x^{p}. Write down the value of pp.

[1]
(b)

Hence, find the value of ∫18(2x3−5x3)dx \int_{1}^{8} \left(\frac{2\sqrt[3]{x}-5}{\sqrt[3]{x}}\right) dx .

[4]

Question 11

HardPaper 2 · calculator20 marks
(a)

The rate of change of a certain quantity RR with respect to a variable xx is given by R′(x)=1x(M−x)R'(x)=\frac{1}{x(M-x)}, x∈Rx \in \mathbb{R}, x≠0x \neq 0, x≠Mx \neq M where MM is a positive constant.

The expression for R′(x)R'(x) can be written in the form Ax+BM−x\frac{A}{x} + \frac{B}{M-x}, where A,B∈RA, B \in \mathbb{R}.

Find AA and BB in terms of MM.

[3]
(b)

Hence, find an expression for R(x)R(x).

[3]
(c)

The concentration of a certain chemical product, CC (in mol/L), in a reaction vessel at time tt (in minutes) can be modelled by the differential equation dCdt=C(L−C)8L\frac{dC}{dt} = \frac{C(L-C)}{8L}, where LL is the maximum possible concentration and C(0)=0.2C(0) = 0.2 mol/L is the initial concentration.

By solving the differential equation, show that C=0.2L(L−0.2)e−t8+0.2C = \frac{0.2 L}{(L-0.2)e^{-\frac{t}{8}}+0.2}.

[8]
(d)

At t=12t=12 minutes, the concentration of the product has reached 0.60.6 mol/L.

Find the value of LL, giving your answer correct to four significant figures.

[3]
(e)

Find the value of tt when the rate of change of the concentration is at its maximum.

[3]

Question 12

MediumPaper 1 · no calculator6 marks

Solve the equation log⁡2(x2)=1log⁡42+log⁡2(x)\log_{2}\left(\frac{x}{2}\right) = \frac{1}{\log_{4}2} + \log_{2}(\sqrt{x}) for x>0x > 0.

Question 13

HardPaper 2 · calculator23 marks
(a)(i)

The following table shows the annual revenue of a tech startup, Quantum Innovations, tt years after its launch in 2015.

tt (years after 2015)02468
RR (revenue in millions of USD)1.52.84.25.57.1

A data analyst uses linear regression to model the revenue of Quantum Innovations using these data.

The analyst's model is R=at+bR = at + b.

(a)(i) Write down the value of aa and the value of bb.

[3]
(a)(ii)

(a)(ii) Interpret, in context, the value of aa.

[3]
(b)

(b) The analyst uses this model to predict the revenue of Quantum Innovations in the year 2030, where t=15t = 15, and calculates a revenue of approximately 11.811.8 million USD.

Comment on the reliability of the analyst's prediction.

[1]
(c)(i)

(c)(i) A financial expert, Elena, develops an exponential model for Quantum Innovations' future revenue.

In this model, RE(t)=1.6(1.08)tR_E(t) = 1.6(1.08)^t represents the revenue in millions of USD tt years after 2015, where 10≤t≤2510 \le t \le 25.

Use Elena's model to predict the revenue of Quantum Innovations in the year 2035.

[3]
(c)(ii)

(c)(ii) Interpret, in context, the value 1.081.08 in Elena's model.

[3]
(d)

(d) Another financial expert, Carlos, develops a third model for Quantum Innovations' revenue.

In this model, RL(t)=201+21e−0.15tR_L(t) = \frac{20}{1+21e^{-0.15t}} represents the revenue in millions of USD tt years after 2015, where 10≤t≤2510 \le t \le 25.

Use Carlos's model to predict the revenue of Quantum Innovations in the year 2035.

[1]
(e)

(e) Determine the year in which the difference between the predictions from Elena's model and Carlos's model is greatest.

[3]
(f)(i)

(f)(i) Find the value of

RE′(18)R_E'(18);

[2]
(f)(ii)

(f)(ii) Find the value of

RL′(18)R_L'(18).

[2]
(g)

(g) Compare and interpret, in context, the values of RE′(18)R_E'(18) and RL′(18)R_L'(18).

[2]

Question 14

MediumPaper 1 · no calculator4 marks
(a)

A scientist is studying a spherical microbe. The radius of the microbe is measured to be 3×10−53 \times 10^{-5} cm.

(a) Write down the diameter of the microbe.

[1]
(b)

(b) The volume of the microbe can be expressed in the form π(a×10k) cm3\pi(a \times 10^k) \text{ cm}^3 where 1≤a<101 \leq a < 10 and k∈Zk \in \mathbb{Z}.

Find the value of aa and the value of kk.

[3]

Question 15

HardPaper 3 · calculator27 marks
(a)(i)

A company is designing a new power generator. The power output, PP, in megawatts (MW), of a prototype generator at time tt hours after startup is modelled by the function P(t)=t3−3ct+KP(t) = t^3 - 3ct + K, where t∈Rt \in \mathbb{R}, cc is a control parameter, and KK is a constant representing the initial power. For parts (a) to (e), assume K=4K = 4.

On separate axes, sketch the graph of P=P(t)P = P(t) showing the value of the PP-intercept and the coordinates of any points with zero gradient, for

(i) c=1c = 1;

[3]
(a)(ii)

(ii) c=2c = 2.

[3]
(b)

Write down an expression for P′(t)P'(t).

[1]
(c)(i)

Hence, or otherwise, find the set of values of cc such that the graph of P=P(t)P = P(t) has

(i) a point of inflexion with zero gradient;

[1]
(c)(ii)

(ii) one local maximum point and one local minimum point;

[2]
(c)(iii)

(iii) no points where the gradient is equal to zero.

[1]
(d)(i)

Given that the graph of P=P(t)P = P(t) has one local maximum point and one local minimum point, show that

(i) the PP-coordinate of the local maximum point is 2c32+42c^{\frac{3}{2}} + 4;

[3]
(d)(ii)

(ii) the PP-coordinate of the local minimum point is −2c32+4-2c^{\frac{3}{2}} + 4.

[1]
(e)(i)

Hence, for c>0c > 0, find the set of values of cc such that the graph of P=P(t)P = P(t) has

(i) exactly one tt-axis intercept;

[2]
(e)(ii)

(ii) exactly two tt-axis intercepts;

[2]
(e)(iii)

(iii) exactly three tt-axis intercepts.

[2]
(f)

Consider a modified power output function Q(t)=t3−3ct+dQ(t) = t^3 - 3ct + d for t∈Rt \in \mathbb{R} and where c,d∈Rc, d \in \mathbb{R}. Find all conditions on cc and dd such that the graph of P=Q(t)P = Q(t) has exactly one tt-axis intercept, explaining your reasoning.

[6]

Question 16

MediumPaper 1 · no calculator6 marks
(a)

The expression 5x−2x3\frac{5x-2}{\sqrt[3]{x}} can be written in the form 5xp−2xq5x^p - 2x^q. Write down the value of pp and the value of qq.

[2]
(b)

Hence, find the value of ∫185x−2x3 dx\int_1^8 \frac{5x-2}{\sqrt[3]{x}} \, dx.

[4]

Question 17

HardPaper 3 · calculator30 marks
(a)

A pharmaceutical company is formulating a new drug. They are testing two active ingredients, x1x_1 and x2x_2, such that their total concentration is 2424 mg/mL. The drug's efficacy is modelled by the product of the concentrations of the two ingredients.

Find the efficacy, EE, as a function of x1x_1 only.

[2]
(b)(i)

Determine the concentration of x1x_1 that maximizes the drug's efficacy.

[1]
(b)(ii)

Hence, show that the maximum efficacy for two ingredients with a total concentration of 2424 mg/mL is 144144.

[1]
(c)

Let Mn(S)M_n(S) represent the maximum efficacy for a drug with nn active ingredients and a total concentration of SS mg/mL. For n=2n = 2, the maximum efficacy can be expressed as M2(S)=(S2)2M_2(S) = \left(\frac{S}{2}\right)^2.

Verify that M2(S)=(S2)2M_2(S) = \left(\frac{S}{2}\right)^2 is true for S=24S = 24.

[1]
(d)(i)

The relationship between the geometric mean and arithmetic mean states that for nn positive real numbers x1,x2,...,xnx_1, x_2, ..., x_n, their geometric mean (x1×x2×...×xn)1n(x_1 \times x_2 \times ... \times x_n)^{\frac{1}{n}} is always less than or equal to their arithmetic mean x1+x2+...+xnn\frac{x_1 + x_2 + ... + x_n}{n}.

Show that the geometric mean and arithmetic mean are equal when x1=x2=...=xnx_1 = x_2 = ... = x_n.

[2]
(d)(ii)

Use this result to prove that Mn(S)=(Sn)nM_n(S) = \left(\frac{S}{n}\right)^n.

[4]
(e)(i)

Using the formula for Mn(S)M_n(S), determine the value of:

M3(24)M_3(24);

[1]
(e)(ii)

M4(24)M_4(24);

[1]
(e)(iii)

M5(24)M_5(24).

[1]
(f)

For a fixed total concentration of S=24S = 24 mg/mL, the company wants to find the optimal number of active ingredients, nn, to maximize the drug's efficacy. Let P(S)P(S) denote this maximum efficacy.

Write down the value of P(24)P(24) and the value of nn at which it occurs.

[2]
(g)

Determine the value of P(30)P(30) and the value of nn at which it occurs.

[3]
(h)

Consider the continuous function hh, defined by ln⁡(h(x))=xln⁡(Sx)\ln(h(x) ) = x\ln\left(\frac{S}{x}\right), where x∈R+x \in \mathbb{R}^+. A sketch of the graph of y=h(x)y = h(x) is shown in the following diagram. Point A is the maximum point on this graph.

Graph of y=h(x) with a maximum point A

Find, in terms of SS, the xx-coordinate of point A.

[6]
(i)

Verify that h(x)=Mx(S)h(x) = M_x(S), when x∈Z+x \in \mathbb{Z}^+.

[2]
(j)

The company has a total concentration of S=150S = 150 mg/mL available. Use your answer to part (h) to find the largest possible efficacy. Give your answer in the form a×10ka \times 10^k, where 1≤a<101 \le a < 10 and k∈Z+k \in \mathbb{Z}^+.

[3]

Question 18

MediumPaper 1 · no calculator15 marks
(a)(i)

Consider the series e2x+ke2x+15e2x+...e^{2x} + k e^{2x} + \frac{1}{5}e^{2x} + ..., where x∈Rx \in \mathbb{R} and k∈R,k≠0k \in \mathbb{R}, k \neq 0.

(a) Consider the case where the series is geometric.

(i) Show that k=±15k = \pm \frac{1}{\sqrt{5}}.

[2]
(a)(ii)

(ii) Given that k>0k > 0 and the sum to infinity is 5+54\frac{5+\sqrt{5}}{4}, find the value of xx.

[5]
(b)(i)

(b) Now consider the case where the series is arithmetic.

(i) Show that k=35k = \frac{3}{5}.

[2]
(b)(ii)

(ii) Write down the common difference, dd, in the form ce2xc e^{2x} where c∈Qc \in \mathbb{Q}.

[1]
(b)(iii)

(iii) The sum of the first nn terms of the series is −8e2x-8e^{2x}. Find the value of nn.

[5]

Question 19

HardPaper 1 · no calculator5 marks

Solve the equation ln⁡(x3)=1log⁡4(e)+ln⁡(16x)\ln(x^3) = \frac{1}{\log_4(e)} + \ln(16x), where x>0x > 0.

Question 20

MediumPaper 1 · no calculator7 marks
(a)

Consider the complex number z=21−iz = 2^{1-i}.

(a) Write the integer 2 in the form eke^k where k∈Rk \in \mathbb{R}.

[1]
(b)

(b) Hence, find zz in the form x+iyx+iy, where xx and yy are expressed in terms of ln⁡2\ln 2.

[3]
(c)

(c) Find Im(z+z−1)\text{Im}(z + z^{-1}), where z−1z^{-1} is the multiplicative inverse of zz.

[3]

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What does Exponents cover in IB Maths AA?

Standard Form (Scientific Notation): Expresses numbers in the form a × 10^k, where 1 ≤ a < 10 and k is an integer (k ∈ mathbbZ). Laws of Indices (Exponents): Rules used to simplify and manipulate expressions involving exponents. They require terms to have the same base and are not in the formula booklet. Key laws include:. x^m × x^n = x^m+n.

Is Exponents SL or HL?

Both. SL and HL students study Exponents to the same depth.

How do I revise Exponents for IB Maths AA?

Start from the core idea: standard Form (Scientific Notation): Expresses numbers in the form a × 10^k, where 1 ≤ a < 10 and k is an integer (k ∈ mathbbZ). In the exam: paper 1 asks for exponent manipulation with no calculator, usually as a step inside a longer question rather than on its own. Base 10 and e only at this subtopic; general bases arrive at SL 1.7. Then practise exam-style questions, easiest first, writing out every step of your working before you check it.

How does FourtyFive help me practise Exponents?

FourtyFive has 35 Exponents questions. Every answer you write is marked mark by mark, IB-style, and you see where each mark was won or lost. Every part has a hint, the AI tutor helps you through the step you are stuck on, and your Study Profile picks what to practise next.

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