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Topic 3.18 · HL only

Vector equations of a plane: notes and practice questions

Summary
  • A plane can be represented by a vector equation (r=a+λu+μvr = a + \lambda u + \mu v), parametric equations, or a scalar product form (r⋅n=a⋅nr \cdot n = a \cdot n).
  • The Cartesian equation of a plane is ax+by+cz=dax + by + cz = d, where n=(abc)n = \begin{pmatrix} a \\ b \\ c \end{pmatrix} is the normal vector.
  • To find the equation of a plane, you can use three non-collinear points, a line and a point, or two parallel lines, often involving cross products to find the normal vector.
  • Angles between lines and planes, or between two planes, are calculated using dot products involving direction vectors and normal vectors.
  • Intersections can be a point (line and plane), a line (two planes), or a point, line, or no intersection (three planes).
  • The distance from a point to a plane is found using a projection onto the normal vector.

How it is examined

Convert between the three forms, usually starting from three points: two displacement vectors, a cross product for the normal, then r⋅n=a⋅n\boldsymbol{r} \cdot \boldsymbol{n} = \boldsymbol{a} \cdot \boldsymbol{n} and finally the Cartesian form. The coefficients of the Cartesian equation are the normal, which is the insight the question is testing. 5 to 8 marks.

Given in the booklet

All three forms are given.

Key ideas
  • Vector equations of a plane: r=a+λb+μc\boldsymbol{r} = \boldsymbol{a} + \lambda\boldsymbol{b} + \mu\boldsymbol{c}, where b\boldsymbol{b} and c\boldsymbol{c} are non-parallel vectors within the plane.
  • r⋅n=a⋅n\boldsymbol{r} \cdot \boldsymbol{n} = \boldsymbol{a} \cdot \boldsymbol{n}, where n\boldsymbol{n} is a normal to the plane and a\boldsymbol{a} is the position vector of a point on the plane.
  • Cartesian equation of a plane ax+by+cz=dax + by + cz = d.

Linking questions

  • Uses AHL 3.16 to produce the normal from two vectors in the plane.

Practice questions

20 questions · 9 medium · 11 hard
Showing 20 of 20

Question 1

MediumPaper 2 · calculator6 marks
(a)

A team of architects is designing a new building and needs to define a support beam's orientation. The beam must be perpendicular to two existing structural walls, Wall A and Wall B. The equations of the planes representing these walls are given by:

Wall A (ΠA\Pi_A): x+2y−z=7x + 2y - z = 7

Wall B (ΠB\Pi_B): 2x−y+3z=12x - y + 3z = 1

Find a Cartesian equation of the plane (ΠC\Pi_C) that represents the orientation of the support beam, given that it passes through the origin (0, 0, 0).

[3]
(b)

Find the coordinates of the point where Wall A, Wall B, and the support beam's plane (ΠC\Pi_C) intersect.

[3]

Question 2

HardPaper 1 · no calculator19 marks
(a)

Two spacecraft, S1 and S2, travel along straight paths, represented by the lines L1L_1 and L2L_2 respectively. The paths of the spacecraft intersect at a docking station D. A probe is located at a point P on the path of L2L_2. This is shown in the following diagram.

Diagram showing two intersecting lines L1 and L2, with point D at the intersection and point P on L2

The direction vector of L1L_1 is (21−2)\begin{pmatrix} 2 \\ 1 \\ -2 \end{pmatrix}. The vector DP⃗\vec{\text{DP}} is given by (k40)\begin{pmatrix} k \\ 4 \\ 0 \end{pmatrix}, where k≥0k \ge 0.

The acute angle between the paths L1L_1 and L2L_2 is θ\theta, where cos⁡θ=13\cos\theta = \frac{1}{3}.

(a) Show that 2k+4=k2+162k+4 = \sqrt{k^2+16}.

[4]
(b)

(b) Find the value of kk.

[3]
(c)

(c) Hence, find the shortest distance from the probe at P to the path L1L_1.

[3]
(d)

The paths L1L_1 and L2L_2 lie on a plane, Π\Pi.

(d) Find a vector normal to the plane Π\Pi.

[2]
(e)

A satellite dish is modelled as a right circular cone with its vertex at V. The base of the cone lies in the plane Π\Pi and is centred at P. The path L1L_1 is tangent to the circular base of the cone. The volume of the cone is 128π29\frac{128\pi\sqrt{2}}{9} cubic units. The position vector of P is (123)\begin{pmatrix} 1 \\ 2 \\ 3 \end{pmatrix}.

(e) Find the two possible position vectors for V.

[7]

Question 3

MediumPaper 2 · calculator18 marks
(a)

Two automated guided vehicles (AGVs), AGV-1 and AGV-2, are moving along straight paths in a 3D warehouse. The path of AGV-1 is given by the vector equation r1=(14−1)+s(112)\mathbf{r}_1 = \begin{pmatrix} 1 \\ 4 \\ -1 \end{pmatrix} +s\begin{pmatrix} 1 \\ 1 \\ 2 \end{pmatrix} where s∈Rs\in \mathbb{R}.

The path of AGV-2 is given by the vector equation r2=(542)+t(3−11)\mathbf{r}_2 = \begin{pmatrix} 5 \\ 4 \\ 2 \end{pmatrix} +t\begin{pmatrix} 3 \\ -1 \\ 1 \end{pmatrix} where t∈Rt\in \mathbb{R}.

All coordinates are in meters.

(a) Show that the paths of AGV-1 and AGV-2 intersect at a point P and find the position vector of P.

[5]
(b)

(b) A safety sensor plane Π\Pi is installed in the warehouse. The plane is given by the equation r⋅(35−4)=27\mathbf{r}\cdot \begin{pmatrix} 3 \\ 5 \\ -4 \end{pmatrix} =27. Verify that the paths of both AGV-1 and AGV-2 lie entirely within this safety sensor plane Π\Pi.

[3]
(c)(i)

(c) An emergency charging station is located at point Q with position vector (1−24)\begin{pmatrix} 1 \\ -2 \\ 4 \end{pmatrix}.

(i) A charging drone is dispatched from Q and travels along a path perpendicular to the plane Π\Pi. This drone lands on the plane Π\Pi at point R. Find the position vector of R.

[4]
(c)(ii)

(ii) Calculate the shortest distance from the emergency charging station Q to the safety sensor plane Π\Pi.

[3]
(d)

(d) Due to a system malfunction, AGV-1 needs to be redirected to a virtual point Q' which is the reflection of the emergency charging station Q in the plane Π\Pi. Find the position vector of Q'.

[3]

Question 4

HardPaper 1 · no calculator21 marks
(a)

The plane Π1\Pi_1 has equation x−2y+3z=1x - 2y + 3z = 1.

(a) Show that the point A(2,2,1)A(2, 2, 1) lies on the plane Π1\Pi_1.

[1]
(b)

The plane Π2\Pi_2 is given by ax+(a2−15)y+bz=dax + (a^2 - 15)y + bz = d, where a,b,d∈Ra, b, d \in \mathbb{R} and b≠0b \neq 0.

(b) In the case where b=5b = 5, Π2\Pi_2 is perpendicular to Π1\Pi_1 and point A lies on Π2\Pi_2. Given that a>0a > 0, find the value of aa and the value of dd.

[5]
(c)

For parts (c), (d) and (e) it is now given that Π2\Pi_2 is parallel to Π1\Pi_1.

(c) Given that a=3a=3, determine the value of bb.

[2]
(d)(i)

It is also given that d=31d = 31.

The line through A that is perpendicular to Π1\Pi_1 meets Π2\Pi_2 at the point B.

(d) (i) Find the coordinates of B.

[7]
(d)(ii)

(ii) Hence, find the perpendicular distance between Π1\Pi_1 and Π2\Pi_2.

[2]
(e)

(e) Find the equation of a third parallel plane Π3\Pi_3 which is also a perpendicular distance of 2143\frac{2\sqrt{14}}{3} from Π1\Pi_1.

[4]

Question 5

MediumPaper 1 · no calculator4 marks

Consider the two planes Π1\Pi_1 and Π2\Pi_2 defined by the equations:

Π1:(cos⁡θ+sin⁡θ)x+(cos⁡θ−sin⁡θ)y+z=1\Pi_1: (\cos\theta + \sin\theta)x + (\cos\theta - \sin\theta)y + z = 1

Π2:(cos⁡θ−sin⁡θ)x−(cos⁡θ+sin⁡θ)y−3z=4\Pi_2: (\cos\theta - \sin\theta)x - (\cos\theta + \sin\theta)y - 3z = 4

where θ∈R\theta \in \mathbb{R}.

Show that the two planes are not perpendicular for any value of θ\theta.

Question 6

HardPaper 1 · no calculator19 marks
(a)

(a) The line L1L_1 passes through the point Q(2, 0, 5) and has a direction vector (1−22)\begin{pmatrix} 1 \\ -2 \\ 2 \end{pmatrix}.

Write down a vector equation for L1L_1.

[1]
(b)

(b) A second line, L2L_2, passes through the points C(3, 1, 0) and D(4, 3, -2).

Find a vector equation for L2L_2.

[2]
(c)

(c) Show that L1L_1 and L2L_2 are skew.

[5]
(d)

(d) Find QM⃗⋅CD⃗\vec{\text{QM}} \cdot \vec{\text{CD}} in terms of μ\mu, where M is a general point on L2L_2.

[4]
(e)

(e) Hence, find the coordinates of the point M on L2L_2 that is closest to Q.

[3]
(f)

(f) The origin is denoted by O(0, 0, 0). Find the equation of the plane that contains the points O, Q and the point M found in part (e). Give your answer in the form ax+by+cz=dax + by + cz = d, where a,b,c,d∈Za, b, c, d \in \mathbb{Z}.

[4]

Question 7

MediumPaper 2 · calculator10 marks
(a)

A drone's initial flight path from its base station at the origin is represented by a displacement vector d⃗=xi+yj+zk\vec{d} = x\mathbf{i} + y\mathbf{j} + z\mathbf{k}. Let α\alpha, β\beta, and γ\gamma be the angles that d⃗\vec{d} makes with the positive xx-axis, yy-axis, and zz-axis respectively.

Show that cos⁡2α+cos⁡2β+cos⁡2γ=1\cos^2\alpha + \cos^2\beta + \cos^2\gamma = 1.

[3]
(b)

If the drone's initial displacement vector is d⃗=4i−5j+2k\vec{d} = 4\mathbf{i} - 5\mathbf{j} + 2\mathbf{k} meters, calculate the angles α\alpha, β\beta, and γ\gamma to one decimal place.

[4]
(c)

A security laser beam is emitted from the base station (origin) along a direction perpendicular to the drone's initial flight path. Show that the equation of the plane containing this laser beam can be expressed in the form xcos⁡α+ycos⁡β+zcos⁡γ=0x\cos \alpha + y \cos \beta + z \cos \gamma = 0, where α\alpha, β\beta, and γ\gamma are the angles found in part (b).

[3]

Question 8

HardPaper 2 · calculator20 marks
(a)

Three points D(1,2,0)D(1, 2, 0), E(3,0,−1)E(3, 0, -1) and F(0,1,4)F(0, 1, 4) lie on the plane Π1\Pi_1.

Find the vector DE⃗\vec{DE} and the vector DF⃗\vec{DF}.

[2]
(b)

Hence find the equation of Π1\Pi_1, expressing your answer in the form ax+by+cz=dax + by + cz = d, where a,b,c,d∈Za, b, c, d \in \mathbb{Z}.

[4]
(c)

Plane Π2\Pi_2 has equation x+y−z=2x + y - z = 2.

The line LL is the intersection of Π1\Pi_1 and Π2\Pi_2. Verify that the vector equation of LL can be written as r=(−141)+λ(−11132)\mathbf{r} = \begin{pmatrix} -1 \\ 4 \\ 1 \end{pmatrix} + \lambda \begin{pmatrix} -11 \\ 13 \\ 2 \end{pmatrix}.

[3]
(d)(i)

The plane Π3\Pi_3 is given by x+2y−z=5x + 2y - z = 5. The line LL and the plane Π3\Pi_3 intersect at the point PP.

Show that at the point PP, λ=−113\lambda=-\frac{1}{13}.

[2]
(d)(ii)

Hence find the coordinates of PP.

[1]
(e)(i)

The point Q(−1,4,1)Q(-1, 4, 1) lies on LL.

Find the reflection of the point QQ in the plane Π3\Pi_3.

[5]
(e)(ii)

Hence find the vector equation of the line formed when LL is reflected in the plane Π3\Pi_3.

[3]

Question 9

MediumPaper 1 · no calculator8 marks
(a)

Two vectors are given by u⃗=i+pj+(p+1)k\vec{u} = \mathbf{i} + p\mathbf{j} + (p+1)\mathbf{k} and v⃗=(p−2)i−j+2k\vec{v} = (p-2)\mathbf{i} - \mathbf{j} + 2\mathbf{k}, where p∈Rp \in \mathbb{R}.

(a) Find the value of pp for which the vectors u⃗\vec{u} and v⃗\vec{v} are orthogonal.

[3]
(b)

(b) For this value of pp, find the Cartesian equation of the plane that contains the vectors u⃗\vec{u} and v⃗\vec{v} and passes through the point (3,−1,0)(3, -1, 0).

[5]

Question 10

HardPaper 1 · no calculator15 marks
(a)

Consider the points given by the coordinates P(2,1,0)P(2, 1, 0), Q(0,3,1)Q(0, 3, 1), R(1,0,4)R(1, 0, 4).

Find the vector PQ⃗×PR⃗\vec{PQ} \times \vec{PR}.

[4]
(b)

Hence, find the exact area of triangle PQR.

[3]
(c)

Show that the Cartesian equation of the plane Π1\Pi_1, which contains the triangle PQR, is 9x+7y+4z=259x + 7y + 4z = 25.

[3]
(d)

A second plane is given by the equation Π2:x+y−z=1\Pi_2: x + y - z = 1. Find a vector equation for the line of intersection of the planes Π1\Pi_1 and Π2\Pi_2.

[5]

Question 11

MediumPaper 1 · no calculator6 marks

A flat rectangular mirror is mounted on a wall. In a 3D coordinate system, with the origin at a corner of the room, the mirror lies on a plane Π\Pi.

One of the edges of the mirror is represented by the line LL with equation r=(125)+t(−112)r = \begin{pmatrix} 1 \\ 2 \\ 5 \end{pmatrix} + t \begin{pmatrix} -1 \\ 1 \\ 2 \end{pmatrix}.

The plane Π\Pi also contains the point P(4,3,1)(4, 3, 1).

Find the Cartesian equation of the plane Π\Pi.

Question 12

HardPaper 1 · no calculator9 marks
(a)

A laser beam is emitted from a source at point A(3,−1,5)A(3, -1, 5). The beam reflects off a flat mirror which lies on the plane π:x−2y+2z=6\pi: x - 2y + 2z = 6. The reflected beam appears to originate from a virtual source at point BB, where BB is the reflection of AA in the plane π\pi.

Determine the coordinates of BB.

[6]
(b)

Find the exact distance between the laser source AA and the virtual source BB.

[3]

Question 13

MediumPaper 2 · calculator8 marks
(a)

A satellite dish is positioned at a ground control station A(3,1,4)A(3, 1, 4). The dish is designed to track a celestial object whose path can be modelled by a line L1L_1 with vector equation r=(120)+t(2−11)\mathbf{r} = \begin{pmatrix} 1 \\ 2 \\ 0 \end{pmatrix} + t \begin{pmatrix} 2 \\ -1 \\ 1 \end{pmatrix}, where t∈Rt \in \mathbb{R}.

The plane Π1\Pi_1 of the satellite dish contains the line L1L_1 and passes through the ground control station AA.

Show that the Cartesian equation of the plane Π1\Pi_1 is x+2y=5x + 2y = 5.

[4]
(b)

Consider three large display screens in a museum, represented by the planes:

Π1:x+2y=5\Pi_1 : x + 2y = 5

Π2:3x+ay−z=7\Pi_2 : 3x + ay - z = 7

Π3:2x−y+z=k\Pi_3 : 2x - y + z = k

where a,k∈Qa, k \in \mathbb{Q}.

For a special holographic effect, the three planes must intersect along a single line.

Find the value of aa and the value of kk.

[4]

Question 14

HardPaper 2 · calculator8 marks

A deep-sea probe's trajectory is modelled by a straight line with a direction vector d⃗=(12k)\vec{d} = \begin{pmatrix} 1 \\ 2 \\ k \end{pmatrix}, where kk is a constant. The probe needs to pass through a specific geological layer, which can be approximated by a plane with a normal vector n⃗=(312)\vec{n} = \begin{pmatrix} 3 \\ 1 \\ 2 \end{pmatrix}. The efficiency of data collection is maximized when the acute angle between the probe's trajectory and the geological layer is maximized.

Determine the value of kk that maximizes this acute angle, and hence find the maximum acute angle. Give your answer in degrees, correct to 11 decimal place.

Question 15

MediumPaper 2 · calculator11 marks
(a)

Consider the three points P(4,0,1), Q(0,−3,1), and R(2,2,−5) lie on a plane Π1.\Pi_{1}.

aa Find the vector PQ→\overrightarrow{PQ} and the vector PR→\overrightarrow{PR}.

[3]
(b)

bb Find the cartesian equation of plane Π1\Pi_{1}.

[4]
(c)

cc Find the equation of the line L that passes through the point S(-8,1,23) and perpendicular to Π1\Pi_{1} .

[1]
(d)

dd Find the coordinates of the point of intersection between line L and plane Π1\Pi_{1}.

[3]

Question 16

HardPaper 1 · no calculator11 marks
(a)

A plane Π\Pi has the Cartesian equation x+3y−2z=5x + 3y - 2z = 5. A point B has coordinates (1,0,4)(1, 0, 4).

(a) Find the vector equation of the line LL that passes through the point B and is perpendicular to the plane Π\Pi.

[2]
(b)

(b) Find the coordinates of the point of intersection, N, of the line LL and the plane Π\Pi. Hence, find the exact distance between the point B and the plane Π\Pi.

[5]
(c)

(c) The point P has coordinates (x0,y0,z0)(x_0, y_0, z_0).

Show that the distance between the point P and the plane Π\Pi is given by

∣x0+3y0−2z0−5∣14\frac{|x_0 + 3y_0 - 2z_0 - 5|}{\sqrt{14}}

[4]

Question 17

MediumPaper 2 · calculator6 marks
(a)

A structural engineer is designing a framework and needs to define the orientation of certain surfaces. Consider two existing planar surfaces, Π1\Pi_1 and Π2\Pi_2, with the following Cartesian equations:

Π1: 2x+y−z=5\Pi_1\text{: } 2x + y - z = 5

Π2: x−3y+2z=−1\Pi_2\text{: } x - 3y + 2z = -1

Find a Cartesian equation of a third planar surface, Π3\Pi_3, which is perpendicular to both Π1\Pi_1 and Π2\Pi_2, and passes through the point (1,2,3)(1, 2, 3).

[3]
(b)

Determine the coordinates of the point where Π1\Pi_1, Π2\Pi_2, and Π3\Pi_3 intersect.

[3]

Question 18

HardPaper 2 · calculator15 marks
(a)

A laser beam is modelled by the line LL with equation r⃗=(12−1)+λ(10−2)\vec{r} = \begin{pmatrix} 1 \\ 2 \\ -1 \end{pmatrix} + \lambda \begin{pmatrix} 1 \\ 0 \\ -2 \end{pmatrix}. The beam strikes a flat mirror surface, which lies on the plane Π\Pi with equation 2x−y+3z=52x - y + 3z = 5.

(a) Find the coordinates of the point where the laser beam hits the mirror.

[4]
(b)

(b) Determine the acute angle between the laser beam and the mirror surface.

[4]
(c)

(c) Find the vector equation of the reflected laser beam.

[7]

Question 19

HardPaper 2 · calculator20 marks
(a)

A drone is programmed to follow a straight flight path LL. The path is described by the Cartesian equation L:x+34=y−12=z+2L: \frac{x+3}{4} = \frac{y-1}{2} = z+2.

Find the vector equation of the drone's flight path LL, expressing your answer in the form r=a+λb\mathbf{r} = \mathbf{a} + \lambda\mathbf{b}, where λ∈R\lambda \in \mathbb{R}.

[3]
(b)

A ground control station is located at the origin O(0,0,0)O(0,0,0).

Determine the minimum distance from the ground control station to the drone's flight path LL.

[5]
(c)

A security laser grid is set up, forming a plane Π\Pi with the equation Π:x+y−6z=10\Pi: x+y-6z=10.

Verify that the drone's flight path LL lies entirely within the security laser grid Π\Pi.

[5]
(d)

A second drone is launched from a point P(5,2,−1)P(5, 2, -1). This drone's flight path, MM, is parallel to the security laser grid Π\Pi and is designed to intersect the yy-axis.

Find the vector equation of the second drone's flight path MM, expressing your answer in the form s=c+μd\mathbf{s} = \mathbf{c} + \mu\mathbf{d}, where μ∈R\mu \in \mathbb{R}.

[7]

Question 20

HardPaper 1 · no calculator14 marks
(a)

Let P(1, 0, 1), Q(1, 2, 0), and R(k+1, 1, -1) be three points in R3\mathbb{R}^3, where k > 0.

Let ΠΠ be the plane containing the points P, Q, and R.

(a) Find a Cartesian equation for the plane ΠΠ in terms of k.

[5]
(b)

(b) Let N be the midpoint of the line segment [PR]. A line L passes through N and is perpendicular to the plane ΠΠ. Find a vector equation for the line L in terms of k.

[3]
(c)

(c) Let L′L' be the line defined by the equations y=x,z=1y=x, z=1. Show that the line L does not intersect the line L′L' for any k > 0.

[6]

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What does Vector equations of a plane cover in IB Maths AA?

A plane can be represented by a vector equation (r = a + λ u + μ v), parametric equations, or a scalar product form (r · n = a · n). The Cartesian equation of a plane is ax + by + cz = d, where n = beginpmatrix a \ b \ c endpmatrix is the normal vector. To find the equation of a plane, you can use three non-collinear points, a line and a point, or two parallel lines, often involving cross products to find the normal vector.

Is Vector equations of a plane SL or HL?

Vector equations of a plane is HL only. SL students are not examined on it.

How do I revise Vector equations of a plane for IB Maths AA?

Start from the core idea: a plane can be represented by a vector equation (r = a + λ u + μ v), parametric equations, or a scalar product form (r · n = a · n). In the exam: convert between the three forms, usually starting from three points: two displacement vectors, a cross product for the normal, then boldsymbolr · boldsymboln = boldsymbola · boldsymboln and finally the Cartesian form. The coefficients of the Cartesian equation are the normal, which is the insight the question is testing. Then practise exam-style questions, easiest first, writing out every step of your working before you check it.

How does FourtyFive help me practise Vector equations of a plane?

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