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Topic 5.10 · HL only

Continuity & differentiability: notes and practice questions

Summary
  • Strategy: Visualize, define variables and constraints, construct constraint and optimization equations (in one variable), differentiate, solve f'(x)=0, and justify max/min using sign diagrams or the second derivative test.
  • Justification: Use the first derivative test (sign change of f'(x)) or the second derivative test (sign of f''(x)) to confirm stationary points as local maxima or minima.
  • Global Extrema: Check endpoints of the domain if applicable, alongside stationary points.
  • Quadratic Optimization: For y=ax^2+bx+c, the vertex at x=-b/(2a) gives the max (if a<0) or min (if a>0) without calculus.
  • Common Errors: Neglecting domain restrictions (e.g., x>0), failing to check endpoints, and not justifying the nature of stationary points.

How it is examined

Continuity and differentiability are understood informally and never tested, so a question asking a student to test them is out of syllabus. First principles is polynomials only, so differentiating sin⁡x\sin x from first principles is out of syllabus even though it looks like a natural HL question. Higher derivatives usually appear as the nnth derivative of a simple function proved by induction. 5 to 7 marks.

Given in the booklet

The first principles definition is given.

Key ideas
  • Informal understanding of continuity and differentiability of a function at a point.
  • Understanding of limits (convergence and divergence).
  • Definition of derivative from first principles f′(x)=lim⁡h→0f(x+h)−f(x)hf'(x) = \displaystyle\lim_{h \to 0} \frac{f(x+h) - f(x)}{h}.
  • Higher derivatives.
Not assessed

In examinations, students will not be asked to test for continuity and differentiability.

Linking questions

  • Links to other subjects: theory of the firm (economics).
  • Enrichment: the fundamental theorem of calculus.

Practice questions

6 questions · 6 medium
Showing 6 of 6

Question 1

MediumPaper 1 · no calculator5 marks
(a)

aa Find ∫cos⁡2(x)dx\int_{}^{}{\cos^{2}(x)}dx.

[3]
(b)

bb Hence, evaluate ∫0π2cos⁡2(x)dx\int_{0}^{\frac{\pi}{2}}{\cos^{2}(x)}dx.

[2]

Question 2

MediumPaper 1 · no calculator5 marks
(a)

aa Find ∫cos⁡2(x)dx\int_{}^{}{\cos^{2}(x)}dx.

[3]
(b)

bb Hence, evaluate ∫0π2cos⁡2(x)dx\int_{0}^{\frac{\pi}{2}}{\cos^{2}(x)}dx.

[2]

Question 3

MediumPaper 1 · no calculator13 marks
(a)

Let g(x)=7x+17x2+5x+6g(x) = \frac{7x+17}{x^2+5x+6}, for x∈R,x≠−2,x≠−3x \in \mathbb{R}, x \neq -2, x \neq -3.

Express g(x)g(x) in partial fractions.

[5]
(b)

Hence, show that g(x)g(x) is a decreasing function.

[3]
(c)

Hence, find the exact value of ∫01g(x) dx\int_{0}^{1} g(x) \,dx. Give your answer in the form ln⁡k\ln k, where kk is a rational number.

[5]

Question 4

MediumPaper 1 · no calculator7 marks
(a)

Consider the function defined for all x∈Rx \in \mathbb{R} by

g(x)={x2+2x−3x−1,for x<1b2−5b+8,for x=1,b∈Rln⁡(x)+4,for x>1g(x) = \begin{cases} \frac{x^2+2x-3}{x-1}, & \text{for } x < 1 \\ b^2 - 5b + 8, & \text{for } x = 1, b \in \mathbb{R} \\ \ln(x) + 4, & \text{for } x > 1 \end{cases}

Show that lim⁡x→1g(x)\lim_{x \to 1} g(x) exists and state its value.

[4]
(b)

Hence, find the possible value(s) for bb such that gg is continuous at x=1x = 1.

[3]

Question 5

MediumPaper 1 · no calculator5 marks

Consider the function h(x)={sin⁡(2x)x,x<0k,x=02cos⁡(x),x>0h(x) = \begin{cases} \frac{\sin(2x)}{x}, & x < 0 \\ k, & x = 0 \\ 2\cos(x), & x > 0 \end{cases}.

Find the value of the constant kk such that the function hh is continuous at x=0x=0.

Question 6

MediumPaper 1 · no calculator7 marks
(a)

A function ff is defined by

f(x)={asin⁡(x)+b,x≤π2cos⁡(2x),x>π2f(x) = \begin{cases} a \sin(x) + b, & x \le \frac{\pi}{2} \\ \cos(2x), & x > \frac{\pi}{2} \end{cases}

where a,b∈Ra, b \in \mathbb{R}.

(a) Find an equation relating aa and bb, given that ff is continuous at x=π2x = \frac{\pi}{2}.

[3]
(b)

(b) Given further that f′(0)=3f'(0) = 3, find the value of aa and the value of bb.

[4]

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What does Continuity & differentiability cover in IB Maths AA?

Strategy: Visualize, define variables and constraints, construct constraint and optimization equations (in one variable), differentiate, solve f'(x)=0, and justify max/min using sign diagrams or the second derivative test. Justification: Use the first derivative test (sign change of f'(x)) or the second derivative test (sign of f''(x)) to confirm stationary points as local maxima or minima. Global Extrema: Check endpoints of the domain if applicable, alongside stationary points.

Is Continuity & differentiability SL or HL?

Continuity & differentiability is HL only. SL students are not examined on it.

How do I revise Continuity & differentiability for IB Maths AA?

Start from the core idea: strategy: Visualize, define variables and constraints, construct constraint and optimization equations (in one variable), differentiate, solve f'(x)=0, and justify max/min using sign diagrams or the second derivative test. In the exam: continuity and differentiability are understood informally and never tested, so a question asking a student to test them is out of syllabus. First principles is polynomials only, so differentiating sin x from first principles is out of syllabus even though it looks like a natural HL question. Then practise exam-style questions, easiest first, writing out every step of your working before you check it.

How does FourtyFive help me practise Continuity & differentiability?

FourtyFive has 6 Continuity & differentiability questions. Every answer you write is marked mark by mark, IB-style, and you see where each mark was won or lost. Every part has a hint, the AI tutor helps you through the step you are stuck on, and your Study Profile picks what to practise next.

Is FourtyFive free for Continuity & differentiability practice?

Yes. A free account gives you 50 marked answers a month, and you do not need a card to sign up.

Can I handwrite Continuity & differentiability answers on an iPad?

Yes. In the FourtyFive iPad app you write your working by hand with Apple Pencil, the way you would on paper, and it is marked the same way.

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