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Topic 3.17 · HL only

Vector product: notes and practice questions

Summary
  • The vector product (cross product) is defined only for 3D vectors, resulting in a vector perpendicular to both operands.
  • It can be calculated algebraically using a determinant formula or geometrically via magnitude ∣a×b∣=∣a∣∣b∣sinθ|\boldsymbol{a} \times \boldsymbol{b}| = |\boldsymbol{a}| |\boldsymbol{b}| \boldsymbol{\boldsymbol{\text{sin}}} \theta.
  • Key properties include anti-commutativity (a×b=−b×a\boldsymbol{a} \times \boldsymbol{b} = -\boldsymbol{b} \times \boldsymbol{a}) and that the cross product of parallel vectors is the zero vector.
  • Applications include finding the area of parallelograms and triangles, determining the normal vector to a plane, calculating the volume of a parallelepiped, and finding the direction vector of the intersection of two planes.

How it is examined

Two uses only: a normal vector for a plane (AHL 3.17), and an area. Anti-commutativity means sign errors are graded, and the area of a triangle is 12∣v×w∣\frac{1}{2}|\boldsymbol{v} \times \boldsymbol{w}| with the half that students forget. 3 to 6 marks.

Given in the booklet

The component form of the vector product and the area of a parallelogram are given.

Key ideas
  • The definition of the vector product of two vectors.
  • Properties of the vector product.
  • Geometric interpretation of ∣v×w∣|\boldsymbol{v} \times \boldsymbol{w}|.

Linking questions

  • Links to other subjects: magnetic forces and fields (physics).

Practice questions

14 questions · 8 medium · 6 hard
Showing 14 of 14

Question 1

MediumPaper 1 · no calculator4 marks

Let u\boldsymbol{u} and v\boldsymbol{v} be two non-zero vectors. The vectors representing the diagonals of a parallelogram with sides u\boldsymbol{u} and v\boldsymbol{v} are d1=u+v\boldsymbol{d}_1 = \boldsymbol{u} + \boldsymbol{v} and d2=u−v\boldsymbol{d}_2 = \boldsymbol{u} - \boldsymbol{v}.

Show that ∣d1×d2∣2=4(∣u∣2∣v∣2−(u⋅v)2)|\boldsymbol{d}_1 \times \boldsymbol{d}_2|^2 = 4(|\boldsymbol{u}|^2|\boldsymbol{v}|^2 - (\boldsymbol{u} \cdot \boldsymbol{v})^2).

Question 2

HardPaper 1 · no calculator19 marks
(a)

Two spacecraft, S1 and S2, travel along straight paths, represented by the lines L1L_1 and L2L_2 respectively. The paths of the spacecraft intersect at a docking station D. A probe is located at a point P on the path of L2L_2. This is shown in the following diagram.

Diagram showing two intersecting lines L1 and L2, with point D at the intersection and point P on L2

The direction vector of L1L_1 is (21−2)\begin{pmatrix} 2 \\ 1 \\ -2 \end{pmatrix}. The vector DP⃗\vec{\text{DP}} is given by (k40)\begin{pmatrix} k \\ 4 \\ 0 \end{pmatrix}, where k≥0k \ge 0.

The acute angle between the paths L1L_1 and L2L_2 is θ\theta, where cos⁡θ=13\cos\theta = \frac{1}{3}.

(a) Show that 2k+4=k2+162k+4 = \sqrt{k^2+16}.

[4]
(b)

(b) Find the value of kk.

[3]
(c)

(c) Hence, find the shortest distance from the probe at P to the path L1L_1.

[3]
(d)

The paths L1L_1 and L2L_2 lie on a plane, Π\Pi.

(d) Find a vector normal to the plane Π\Pi.

[2]
(e)

A satellite dish is modelled as a right circular cone with its vertex at V. The base of the cone lies in the plane Π\Pi and is centred at P. The path L1L_1 is tangent to the circular base of the cone. The volume of the cone is 128π29\frac{128\pi\sqrt{2}}{9} cubic units. The position vector of P is (123)\begin{pmatrix} 1 \\ 2 \\ 3 \end{pmatrix}.

(e) Find the two possible position vectors for V.

[7]

Question 3

MediumPaper 1 · no calculator8 marks
(a)

The paths of two submarines, A and B, are described by the vector equations below, where s,t∈Rs, t \in \mathbb{R} are time parameters in hours, and the coordinates are in kilometres.

LA:r=(111)+s(12−1)L_A: \boldsymbol{r} = \begin{pmatrix} 1 \\ 1 \\ 1 \end{pmatrix} + s \begin{pmatrix} 1 \\ 2 \\ -1 \end{pmatrix}

LB:r=(1121)+t(2−11)L_B: \boldsymbol{r} = \begin{pmatrix} 11 \\ 2 \\ 1 \end{pmatrix} + t \begin{pmatrix} 2 \\ -1 \\ 1 \end{pmatrix}

(a) Show that the paths of the two submarines do not cross.

[3]
(b)

(b) Find the shortest distance between the paths of the two submarines.

[5]

Question 4

HardPaper 1 · no calculator19 marks
(a)

(a) The line L1L_1 passes through the point Q(2, 0, 5) and has a direction vector (1−22)\begin{pmatrix} 1 \\ -2 \\ 2 \end{pmatrix}.

Write down a vector equation for L1L_1.

[1]
(b)

(b) A second line, L2L_2, passes through the points C(3, 1, 0) and D(4, 3, -2).

Find a vector equation for L2L_2.

[2]
(c)

(c) Show that L1L_1 and L2L_2 are skew.

[5]
(d)

(d) Find QM⃗⋅CD⃗\vec{\text{QM}} \cdot \vec{\text{CD}} in terms of μ\mu, where M is a general point on L2L_2.

[4]
(e)

(e) Hence, find the coordinates of the point M on L2L_2 that is closest to Q.

[3]
(f)

(f) The origin is denoted by O(0, 0, 0). Find the equation of the plane that contains the points O, Q and the point M found in part (e). Give your answer in the form ax+by+cz=dax + by + cz = d, where a,b,c,d∈Za, b, c, d \in \mathbb{Z}.

[4]

Question 5

MediumPaper 2 · calculator6 marks
(a)

A team of architects is designing a new building and needs to define a support beam's orientation. The beam must be perpendicular to two existing structural walls, Wall A and Wall B. The equations of the planes representing these walls are given by:

Wall A (ΠA\Pi_A): x+2y−z=7x + 2y - z = 7

Wall B (ΠB\Pi_B): 2x−y+3z=12x - y + 3z = 1

Find a Cartesian equation of the plane (ΠC\Pi_C) that represents the orientation of the support beam, given that it passes through the origin (0, 0, 0).

[3]
(b)

Find the coordinates of the point where Wall A, Wall B, and the support beam's plane (ΠC\Pi_C) intersect.

[3]

Question 6

HardPaper 1 · no calculator15 marks
(a)

Consider the points given by the coordinates P(2,1,0)P(2, 1, 0), Q(0,3,1)Q(0, 3, 1), R(1,0,4)R(1, 0, 4).

Find the vector PQ⃗×PR⃗\vec{PQ} \times \vec{PR}.

[4]
(b)

Hence, find the exact area of triangle PQR.

[3]
(c)

Show that the Cartesian equation of the plane Π1\Pi_1, which contains the triangle PQR, is 9x+7y+4z=259x + 7y + 4z = 25.

[3]
(d)

A second plane is given by the equation Π2:x+y−z=1\Pi_2: x + y - z = 1. Find a vector equation for the line of intersection of the planes Π1\Pi_1 and Π2\Pi_2.

[5]

Question 7

MediumPaper 2 · calculator9 marks
(a)

A landscape architect is designing a triangular shade sail for a patio. The vertices of the sail are defined by points A, B, and C in a 3D coordinate system, where the z-axis represents height.

The coordinates of the vertices are A(0,k,1)(0, k, 1), B(2,1,0)(2, 1, 0) and C(k,0,3)(k, 0, 3), where kk is a positive constant representing a design parameter.

(a) Show that the vector product AB⃗×AC⃗\vec{AB} \times \vec{AC} is given by (2−3k−k−4k2−3k)\begin{pmatrix} 2-3k \\ -k-4 \\ k^2-3k \end{pmatrix}.

[4]
(b)

(b) The architect wants to minimize the tension in the sail, which is proportional to the magnitude of the vector product of two adjacent sides. Find the smallest possible value of ∣AB⃗×AC⃗∣|\vec{AB} \times \vec{AC}|.

[3]
(c)

(c) Calculate the smallest possible area of the shade sail.

[2]

Question 8

HardPaper 2 · calculator13 marks
(a)

Two drones, Drone Alpha and Drone Beta, are flying in a 3D space. At a particular instant, Drone Alpha passes through point A(1,2,3)A(1, 2, 3) and then point B(5,0,1)B(5, 0, 1).

(a) Find a vector equation of the line representing Drone Alpha's path.

[3]
(b)

At the same instant, Drone Beta passes through point C(2,−1,4)C(2, -1, 4) and then point D(0,3,2)D(0, 3, 2).

(b) Find a vector equation of the line representing Drone Beta's path.

[3]
(c)

(c) Hence, or otherwise, find the shortest distance between the paths of Drone Alpha and Drone Beta.

[7]

Question 9

MediumPaper 1 · no calculator6 marks

A modern art sculpture is in the shape of a tetrahedron with vertices at points P(2, 1, 0), Q(3, -1, 2), R(0, 2, 1), and S(4, 3, 5). The coordinates are given in metres relative to a fixed origin O.

Calculate the volume of the sculpture.

Question 10

HardPaper 2 · calculator21 marks
(a)

Consider the non-zero vectors u⃗\vec{u} and v⃗\vec{v}. Let θ\theta be the angle between u⃗\vec{u} and v⃗\vec{v}.

Using the definitions of u⃗⋅v⃗\vec{u} \cdot \vec{v} and u⃗×v⃗\vec{u} \times \vec{v} in terms of ∣u⃗∣|\vec{u}|, ∣v⃗∣|\vec{v}| and θ\theta, show that (u⃗⋅v⃗)2+∣u⃗×v⃗∣2=∣u⃗∣2∣v⃗∣2(\vec{u} \cdot \vec{v})^2 + |\vec{u} \times \vec{v}|^2 = |\vec{u}|^2|\vec{v}|^2.

[2]
(b)(i)

A triangle PQR has vertices P(1, 0, 1), Q(a,ba, b, 2) and R(4, 1, 1), where a,b∈Qa, b \in \mathbb{Q}.

The vectors u⃗\vec{u} and v⃗\vec{v} are defined as u⃗=PQ⃗\vec{u} = \vec{PQ} and v⃗=PR⃗\vec{v} = \vec{PR}.

It is given that u⃗⋅v⃗=4\vec{u} \cdot \vec{v} = 4 and the area of triangle PQR is 142\frac{\sqrt{14}}{2} square units.

Find the value of ∣u⃗×v⃗∣|\vec{u} \times \vec{v}|.

[1]
(b)(ii)

Hence, or otherwise, find the value of ∣u⃗∣|\vec{u}|.

[4]
(b)(iii)

Hence, or otherwise, find the possible values of aa and the corresponding values of bb.

[8]
(c)

Consider a new point S, the vector w⃗\vec{w} is defined as w⃗=RS⃗\vec{w} = \vec{RS}.

It is given that u⃗⋅w⃗=0\vec{u} \cdot \vec{w} = 0 and v⃗⋅w⃗=0\vec{v} \cdot \vec{w} = 0, and the area of triangle PRS is 10 square units.

Assuming that a=2a = 2, find the possible vectors for w⃗\vec{w}.

[6]

Question 11

MediumPaper 1 · no calculator8 marks
(a)

Two vectors are given by u⃗=i+pj+(p+1)k\vec{u} = \mathbf{i} + p\mathbf{j} + (p+1)\mathbf{k} and v⃗=(p−2)i−j+2k\vec{v} = (p-2)\mathbf{i} - \mathbf{j} + 2\mathbf{k}, where p∈Rp \in \mathbb{R}.

(a) Find the value of pp for which the vectors u⃗\vec{u} and v⃗\vec{v} are orthogonal.

[3]
(b)

(b) For this value of pp, find the Cartesian equation of the plane that contains the vectors u⃗\vec{u} and v⃗\vec{v} and passes through the point (3,−1,0)(3, -1, 0).

[5]

Question 12

HardPaper 1 · no calculator14 marks
(a)

Let P(1, 0, 1), Q(1, 2, 0), and R(k+1, 1, -1) be three points in R3\mathbb{R}^3, where k > 0.

Let ΠΠ be the plane containing the points P, Q, and R.

(a) Find a Cartesian equation for the plane ΠΠ in terms of k.

[5]
(b)

(b) Let N be the midpoint of the line segment [PR]. A line L passes through N and is perpendicular to the plane ΠΠ. Find a vector equation for the line L in terms of k.

[3]
(c)

(c) Let L′L' be the line defined by the equations y=x,z=1y=x, z=1. Show that the line L does not intersect the line L′L' for any k > 0.

[6]

Question 13

MediumPaper 1 · no calculator6 marks

A flat rectangular mirror is mounted on a wall. In a 3D coordinate system, with the origin at a corner of the room, the mirror lies on a plane Π\Pi.

One of the edges of the mirror is represented by the line LL with equation r=(125)+t(−112)r = \begin{pmatrix} 1 \\ 2 \\ 5 \end{pmatrix} + t \begin{pmatrix} -1 \\ 1 \\ 2 \end{pmatrix}.

The plane Π\Pi also contains the point P(4,3,1)(4, 3, 1).

Find the Cartesian equation of the plane Π\Pi.

Question 14

MediumPaper 2 · calculator6 marks
(a)

A structural engineer is designing a framework and needs to define the orientation of certain surfaces. Consider two existing planar surfaces, Π1\Pi_1 and Π2\Pi_2, with the following Cartesian equations:

Π1: 2x+y−z=5\Pi_1\text{: } 2x + y - z = 5

Π2: x−3y+2z=−1\Pi_2\text{: } x - 3y + 2z = -1

Find a Cartesian equation of a third planar surface, Π3\Pi_3, which is perpendicular to both Π1\Pi_1 and Π2\Pi_2, and passes through the point (1,2,3)(1, 2, 3).

[3]
(b)

Determine the coordinates of the point where Π1\Pi_1, Π2\Pi_2, and Π3\Pi_3 intersect.

[3]

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What does Vector product cover in IB Maths AA?

The vector product (cross product) is defined only for 3D vectors, resulting in a vector perpendicular to both operands. It can be calculated algebraically using a determinant formula or geometrically via magnitude |boldsymbola × boldsymbolb| = |boldsymbola| |boldsymbolb| boldsymbolboldsymbolsin θ. Key properties include anti-commutativity (boldsymbola × boldsymbolb = -boldsymbolb × boldsymbola) and that the cross product of parallel vectors is the zero vector.

Is Vector product SL or HL?

Vector product is HL only. SL students are not examined on it.

How do I revise Vector product for IB Maths AA?

Start from the core idea: the vector product (cross product) is defined only for 3D vectors, resulting in a vector perpendicular to both operands. In the exam: two uses only: a normal vector for a plane (AHL 3.17), and an area. Anti-commutativity means sign errors are graded, and the area of a triangle is (1)/(2)|boldsymbolv × boldsymbolw| with the half that students forget. Then practise exam-style questions, easiest first, writing out every step of your working before you check it.

How does FourtyFive help me practise Vector product?

FourtyFive has 14 Vector product questions. Every answer you write is marked mark by mark, IB-style, and you see where each mark was won or lost. Every part has a hint, the AI tutor helps you through the step you are stuck on, and your Study Profile picks what to practise next.

Is FourtyFive free for Vector product practice?

Yes. A free account gives you 50 marked answers a month, and you do not need a card to sign up.

Can I handwrite Vector product answers on an iPad?

Yes. In the FourtyFive iPad app you write your working by hand with Apple Pencil, the way you would on paper, and it is marked the same way.

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