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Topic 3.07 · SL and HL

Unit circle, exact values of main trig ratios, ambiguous case: notes and practice questions

Summary
  • The unit circle has a radius of 1, centered at (0,0)(0,0), with trigonometric values derived from (cos⁡θ,sin⁡θ)(\cos \theta, \sin \theta).
  • Exact values for angles 0∘,30∘,45∘,60∘,90∘0^\circ, 30^\circ, 45^\circ, 60^\circ, 90^\circ are used frequently.
  • Ambiguous case applies to non-right triangles (SSA condition), where 0, 1, or 2 triangles may be possible based on given values.

How it is examined

Paper 1, where the calculator is gone and the exact values are the point. The ambiguous case lives here rather than at SL 3.2, so a "find the two possible values of the angle" question is legitimate and giving only the acute answer is half marks. Answers stay exact and surds stay rationalised where the mark scheme says so. 3 to 6 marks.

Key ideas
  • Definition of cos⁡θ\cos\theta and sin⁡θ\sin\theta in terms of the unit circle.
  • Definition of tan⁡θ\tan\theta as sin⁡θcos⁡θ\dfrac{\sin\theta}{\cos\theta}.
  • Exact values of trigonometric ratios of 00, π6\dfrac{\pi}{6}, π4\dfrac{\pi}{4}, π3\dfrac{\pi}{3}, π2\dfrac{\pi}{2} and their multiples.
  • Extension of the sine rule to the ambiguous case.

Linking questions

  • International-mindedness: the first work to refer explicitly to the sine as a function of an angle is the Aryabhatiya of Aryabhata (ca 510).

Practice questions

33 questions · 2 easy · 21 medium · 10 hard
Showing 20 of 20

Question 1

EasyPaper 1 · no calculator3 marks

A landscape designer is creating a triangular garden bed. Two sides of the garden bed measure 8 m and 10 m, and the angle between them is 120∘120^\circ. Find the exact area of the garden bed.

Question 2

MediumPaper 1 · no calculator7 marks
(a)

(a) Show that 2x+5+3x−1=2x2+3x−2x−12x+5 + \frac{3}{x-1} = \frac{2x^2 + 3x - 2}{x-1}, for x∈R,x≠1x \in \mathbb{R}, x \neq 1.

[2]
(b)

(b) Hence or otherwise, solve the equation 2sin⁡θ+5+3sin⁡θ−1=02\sin{\theta} + 5 + \frac{3}{\sin{\theta}-1} = 0 for 0≤θ≤2π0 \leq \theta \leq 2\pi, θ≠π2\theta \neq \frac{\pi}{2}.

[5]

Question 3

HardPaper 1 · no calculator7 marks
(a)

Consider the complex numbers w1=1+kiw_1 = 1 + k\text{i} and w2=k−iw_2 = k - \text{i}, where k∈Rk \in \mathbb{R} and k≠0k \neq 0.

(a) Find an expression for w1w2w_1 w_2 in terms of kk.

[3]
(b)

(b) Hence, given that arg(w1w2)=π6\text{arg}(w_1 w_2) = \frac{\pi}{6}, find all possible values of kk.

[4]

Question 4

EasyPaper 1 · no calculator6 marks
(a)

Solve the following equations for θ\theta in the interval 0≤θ≤2π0 \le \theta \le 2\pi. Give your answers as multiples of π\pi.

(a) cos⁡θ=−32\cos \theta = -\frac{\sqrt{3}}{2}

[2]
(b)

(b) sin⁡θ=−12\sin \theta = -\frac{1}{2}

[2]
(c)

(c) tan⁡θ=−3\tan \theta = -\sqrt{3}

[2]

Question 5

MediumPaper 1 · no calculator4 marks

It is given that sec⁡θ=−3\sec \theta = -3, where π<θ<2π\pi < \theta < 2\pi. Find the exact value of tan⁡θ\tan \theta.

Question 6

HardPaper 1 · no calculator19 marks
(a)

A ladder must be placed against a tall vertical building, clearing a monument that is 8 m high and stands on horizontal ground 1 m away from the building's base. The ladder touches the ground, the top corner of the monument, and the wall of the building.

A diagram showing a vertical building and the horizontal ground. A monument of height 8m stands 1m away from the base of the building. A ladder is shown leaning against the building, just touching the top of the monument. The angle the ladder makes with the ground is labelled as theta.

Let LL be the length of the ladder in metres.

Let θ\theta be the angle that the ladder makes with the ground, where 0<θ<π20 < \theta < \frac{\pi}{2}.

(a) Show that L=sec⁡θ+8csc⁡θL = \sec \theta + 8\csc \theta.

[2]
(b)(i)

(b) (i) Find dLdθ\frac{dL}{d\theta}.

[2]
(b)(ii)

(b) (ii) When dLdθ=0\frac{dL}{d\theta} = 0, show that tan⁡θ=2\tan\theta = 2.

[3]
(c)(i)

(c) (i) Find d2Ldθ2\frac{d^2L}{d\theta^2}.

[3]
(c)(ii)

(c) (ii) When tan⁡θ=2\tan\theta = 2, find the value of d2Ldθ2\frac{d^2L}{d\theta^2}.

[4]
(d)(i)

(d) (i) Hence, justify that LL is a minimum when tan⁡θ=2\tan\theta = 2.

[1]
(d)(ii)

(d) (ii) Determine this minimum value of LL.

[2]
(e)

(e) A construction company only has ladders with a maximum length of 11 m. Determine whether it is possible to position a ladder against the building over the monument, giving a reason for your answer.

[2]

Question 7

MediumPaper 1 · no calculator7 marks
(a)

Consider the functions f(x)=sin⁡x−cos⁡xf(x) = \sin x - \cos x and h(x)=x+π4h(x) = x + \frac{\pi}{4} for x∈Rx \in \mathbb{R}.

(a) Find an expression for (f∘h)(x)(f \circ h)(x).

[2]
(b)

(b) Hence, solve the equation (f∘h)(x)=1(f \circ h)(x) = 1 for 0≤x≤2π0 \le x \le 2\pi.

[5]

Question 8

HardPaper 1 · no calculator17 marks
(a)

By using an appropriate substitution, show that ∫sin⁡(x) dx=2sin⁡(x)−2xcos⁡(x)+C\int \sin(\sqrt{x}) \, dx = 2\sin(\sqrt{x}) - 2\sqrt{x} \cos(\sqrt{x}) + C.

[6]
(b)

The following diagram shows part of the curve y=sin⁡(x)y = \sin(\sqrt{x}) for x≥0x \ge 0.

Graph of y = sin(sqrt(x) ) showing x-intercepts and regions R1, R2, R3

The curve intersects the x-axis at x1,x2,x3,…x_1, x_2, x_3, \dots.

The nth x-intercept of the curve, xnx_n, is given by xn=n2π2x_n = n^2 \pi^2, where n∈Z+n \in \mathbb{Z}^+.

Write down an expression for xn+1x_{n+1}.

[1]
(c)

The regions bounded by the curve and the x-axis are denoted by R1,R2,R3,…R_1, R_2, R_3, \dots as shown on the diagram.

Calculate the area of region RnR_n.

Give your answer in the form (an+b)π(an+b)\pi, where a,b∈Z+a, b \in \mathbb{Z}^+.

[7]
(d)

Hence, show that the areas of the regions R1,R2,R3,…R_1, R_2, R_3, \dots form an arithmetic sequence.

[3]

Question 9

MediumPaper 1 · no calculator6 marks
(a)

Show that the equation 2sin⁡2x−cos⁡x−1=02\sin^2x - \cos x - 1 = 0 may be written in the form

2cos⁡2x+cos⁡x−1=02\cos^2x + \cos x - 1 = 0.

[2]
(b)

Hence, solve the equation 2sin⁡2x−cos⁡x−1=02\sin^2x - \cos x - 1 = 0, for 0≤x≤2π0 \le x \le 2\pi.

[4]

Question 10

HardPaper 1 · no calculator7 marks
(a)

Consider the functions f(x)=−2cos⁡(x)+5f(x) = -2\cos(x) + 5 and g(x)=−2cos⁡(x−π4)+5−kg(x) = -2\cos(x - \frac{\pi}{4}) + 5 - k, where x∈Rx \in \mathbb{R} and k>0k > 0.

The graph of gg is obtained by two transformations of the graph of ff.

(a) Describe these two transformations.

[2]
(b)

The yy-intercept of the graph of gg is at (0,s)(0, s).

(b) Given that the maximum value of g(x)g(x) is 1, find the value of ss.

[5]

Question 11

MediumPaper 1 · no calculator7 marks
(a)

Show that 3x+2−2x+1=3x2+5xx+13x + 2 - \frac{2}{x+1} = \frac{3x^2 + 5x}{x+1}, for x∈R,x≠−1x \in \mathbb{R}, x \neq -1.

[2]
(b)

Hence or otherwise, solve the equation 3cos⁡(θ)+2−2cos⁡(θ)+1=03\cos(\theta) + 2 - \frac{2}{\cos(\theta)+1} = 0 for 0≤θ≤2π,θ≠π0 \le \theta \le 2\pi, \theta \neq \pi.

[5]

Question 12

HardPaper 1 · no calculator14 marks
(a)(i)

Consider an acute angle xx such that cos⁡x=34\cos x = \frac{3}{4}.

Find the value of sin⁡x\sin x.

[2]
(a)(ii)

Find the value of cos⁡(2x)\cos(2x).

[2]
(b)

The following diagram shows triangle ABC, with BC^A=x\text{B}\hat{\text{C}}\text{A} = x, BA^C=2x\text{B}\hat{\text{A}}\text{C} = 2x, and AB = 14.

A diagram of triangle ABC. Angle at vertex C is labelled x. Angle at vertex A is labelled 2x. The side opposite vertex C, AB, is labelled 14.

(b) Show that BC = 21.

[3]
(c)(i)

The line segment CA is extended to a point D such that triangle ABD is isosceles with AB = AD.

The same triangle ABC as before. The line segment CA is extended to a point D, so that C, A, D are collinear. A line segment connects B and D, forming a new triangle ABD.

Find the size of angle ADB in terms of xx.

[3]
(c)(ii)

Find the area of triangle ABD.

[4]

Question 13

MediumPaper 1 · no calculator6 marks

The function ff is defined as f(x)=arctan⁡x1+x2f(x) = \sqrt{\frac{\arctan x}{1+x^2}}, where x≥0x \ge 0.

Consider the shaded region R enclosed by the graph of ff, the xx-axis and the line x=1x = 1, as shown in the following diagram.

Graph of y=f(x) with shaded region R

The shaded region R is rotated by 2π2\pi radians about the xx-axis to form a solid.

Show that the volume of the solid is π332\frac{\pi^3}{32}.

Question 14

HardPaper 1 · no calculator22 marks
(a)(i)

Consider the complex number z1=1−i3z_1 = 1 - i\sqrt{3}.

(a) (i) Express z1z_1 in modulus-argument form.

[2]
(a)(ii)

(a) (ii) Find the smallest positive integer nn for which z1nz_1^n is a real number.

[3]
(b)

Consider the equation (z+i)5−(z−i)5=0(z+i)^5 - (z-i)^5 = 0, where z∈Cz \in \mathbb{C}.

(b) Show that the roots of the equation are given by z=cot⁡(kπ5)z = \cot\left(\frac{k\pi}{5}\right) for k=1,2,3,4k=1, 2, 3, 4.

[6]
(c)(i)

(c) (i) By using the binomial expansion, show that the equation in part (b) can be written as 5z4−10z2+1=05z^4 - 10z^2 + 1 = 0.

[4]
(c)(ii)

(c) (ii) Let the roots of the equation in (c)(i) be z1,z2,z3,z4z_1, z_2, z_3, z_4. Without finding the roots, show that ∑j=14zj2=4\sum_{j=1}^4 z_j^2 = 4.

[3]
(d)

(d) Hence, find the exact value of cot⁡2(π5)\cot^2\left(\frac{\pi}{5}\right).

[4]

Question 15

MediumPaper 1 · no calculator7 marks
(a)

Consider the functions f(x)=sin⁡x+3cos⁡xf(x) = \sin x + \sqrt{3}\cos x and g(x)=2xg(x) = 2x.

(a) Find (f∘g)(x)(f \circ g)(x).

[2]
(b)

(b) Solve the equation (f∘g)(x)=2sin⁡(2x)(f \circ g)(x) = 2\sin(2x) for 0≤x≤π0 \leq x \leq \pi.

[5]

Question 16

HardPaper 2 · calculator15 marks
(a)(i)

A team of engineers is testing two autonomous robots, Alpha and Beta, on a straight track. Their positions are measured as the distance from a fixed starting point. The experiment runs for 10 minutes.

The position of Robot Alpha, PAP_A metres, at time tt minutes can be modelled by the function PA(t)=3sin⁡(2t+5)+14t+20P_A(t) = 3\sin(2t + 5) + 14t + 20, where 0≤t≤100 \le t \le 10.

The position of Robot Beta, PBP_B metres, at time tt minutes can be modelled by the function PB(t)=12t+25P_B(t) = 12t + 25, where 0≤t≤100 \le t \le 10.

Use the engineers' models to find the initial position of

(i) Robot Beta;

[1]
(a)(ii)

(ii) Robot Alpha correct to three significant figures.

[2]
(b)

Find the values of tt when Robot Alpha and Robot Beta are at the same position. Give your answers correct to three significant figures.

[3]
(c)

For t>5t > 5, prove that Robot Alpha was always ahead of Robot Beta.

[3]
(d)

For 0≤t≤100 \le t \le 10, find the total amount of time when the speed of Robot Beta was greater than the speed of Robot Alpha. Give your answer correct to three significant figures.

[6]

Question 17

MediumPaper 1 · no calculator6 marks
(a)

Show that the equation cos⁡(2x)+cos⁡(x)=0\cos(2x) + \cos(x) = 0 can be written in the form 2cos⁡2(x)+cos⁡(x)−1=02\cos^2(x) + \cos(x) - 1 = 0.

[1]
(b)

Hence, solve cos⁡(2x)+cos⁡(x)=0\cos(2x) + \cos(x) = 0, for 0≤x≤2π0 \le x \le 2\pi.

[5]

Question 18

HardPaper 1 · no calculator11 marks
(a)

Find ∫xsec⁡2x dx\int x \sec^2 x \, dx.

[6]
(b)

The region RR is enclosed by the curve y=xsec⁡2xy = x \sec^2 x, the xx-axis, and the lines x=0x=0 and x=π3x=\frac{\pi}{3}. Show that the area of RR is π33−ln⁡2\frac{\pi\sqrt{3}}{3} - \ln 2.

[5]

Question 19

MediumPaper 1 · no calculator7 marks
(a)

Consider the function g(x)=csc⁡(x+π3)g(x) = \csc\left(x+\frac{\pi}{3}\right), for 0≤x≤π30\le x\le \frac{\pi}{3}.

Determine the range of gg.

[3]
(b)

The region bounded by the graph of y=g(x)y = g(x), the xx-axis and the lines x=0x = 0 and x=π3x = \frac{\pi}{3} is rotated 2π2\pi radians about the xx-axis.

Find the volume of the solid generated.

[4]

Question 20

HardPaper 1 · no calculator10 marks
(a)

Given that cos⁡θ=513\cos \theta = \frac{5}{13}, and 3π2<θ<2π\frac{3\pi}{2} < \theta < 2\pi,

find sin⁡θ\sin \theta and tan⁡θ\tan \theta.

[4]
(b)

Solve 3cos⁡x=cot⁡x3 \cos x = \cot x for 0≤x≤2π0 \le x \le 2\pi.

[6]

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What does Unit circle, exact values of main trig ratios, ambiguous case cover in IB Maths AA?

The unit circle has a radius of 1, centered at (0,0), with trigonometric values derived from (cos θ, sin θ). Exact values for angles 0^°, 30^°, 45^°, 60^°, 90^° are used frequently. Ambiguous case applies to non-right triangles (SSA condition), where 0, 1, or 2 triangles may be possible based on given values.

Is Unit circle, exact values of main trig ratios, ambiguous case SL or HL?

Both. SL and HL students study Unit circle, exact values of main trig ratios, ambiguous case to the same depth.

How do I revise Unit circle, exact values of main trig ratios, ambiguous case for IB Maths AA?

Start from the core idea: the unit circle has a radius of 1, centered at (0,0), with trigonometric values derived from (cos θ, sin θ). In the exam: paper 1, where the calculator is gone and the exact values are the point. The ambiguous case lives here rather than at SL 3.2, so a "find the two possible values of the angle" question is legitimate and giving only the acute answer is half marks. Then practise exam-style questions, easiest first, writing out every step of your working before you check it.

How does FourtyFive help me practise Unit circle, exact values of main trig ratios, ambiguous case?

FourtyFive has 33 Unit circle, exact values of main trig ratios, ambiguous case questions. Every answer you write is marked mark by mark, IB-style, and you see where each mark was won or lost. Every part has a hint, the AI tutor helps you through the step you are stuck on, and your Study Profile picks what to practise next.

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