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Topic 4.07 · SL and HL

Conditional probability and independent events: notes and practice questions

Summary
  • Conditional Probability: The probability of event AA given that BB has occurred:

P(A∣B)=P(A∩B)P(B), P(B)≠0 P(A|B) = \frac{P(A \cap B)}{P(B)}, \, P(B) \neq 0

  • Independent Events: Events AA and BB are independent if:

P(A∩B)=P(A)⋅P(B) P(A \cap B) = P(A) \cdot P(B)
or equivalently P(A∣B)=P(A)P(A|B) = P(A).

How it is examined

With or without replacement changes the second branch of a tree and is the standard discriminator. The guidance that problems can be solved without explicit formulae means a correct tree diagram plus a correct answer is worth full marks, so a mark scheme should not demand the formula. Paper 2, 5 to 8 marks. The difference from SL 4.6 is that here the formula is required rather than a diagram. Testing for independence means checking P(A∩B)=P(A)P(B)\mathrm{P}(A \cap B) = \mathrm{P}(A)\mathrm{P}(B) numerically and stating a conclusion, and the conclusion sentence is a mark. 3 to 5 marks.

Given in the booklet
  • All four formulas are given.
  • The conditional probability formula is given.
Key ideas
  • Use of Venn diagrams, tree diagrams, sample space diagrams and tables of outcomes to calculate probabilities.
  • Combined events: P(A∪B)=P(A)+P(B)−P(A∩B)\mathrm{P}(A \cup B) = \mathrm{P}(A) + \mathrm{P}(B) - \mathrm{P}(A \cap B).
  • Mutually exclusive events: P(A∩B)=0\mathrm{P}(A \cap B) = 0.
  • Conditional probability: P(A∣B)=P(A∩B)P(B)\mathrm{P}(A \mid B) = \dfrac{\mathrm{P}(A \cap B)}{\mathrm{P}(B)}.
At HL

Extended at AHL 4.13 (Bayes' theorem).

Linking questions

  • Aim 8: use of probability in casinos.
  • Other contexts: use of probability methods in medical studies to assess risk factors.

Practice questions

42 questions · 1 easy · 28 medium · 13 hard
Showing 20 of 20

Question 1

EasyPaper 1 · no calculator5 marks
(a)

If there are two events A and B are its given that P(A)=0.5P(A) = 0.5 and P(B)=0.2P(B) = 0.2. let P(AUB)=x.P(AUB) = x.

aa Find the value of xx if the events A and B are said to be mutually exclusive.

[2]
(b)

bb Find the value of xx if the events A and B are said to be independent.

[3]

Question 2

MediumPaper 1 · no calculator6 marks
(a)

If two events A and B are said to be independent events where P(A)=0.4P(A) = 0.4 and P(A′∩B)=0.3P\left( A^{'} \cap B \right) = 0.3. let P(A∩B)=x.P(A \cap B) = x.

aa Find the value of xx.

[3]
(b)

bb Find P(A∣B′).P(A|B').

[3]

Question 3

HardPaper 1 · no calculator16 marks
(a)

A spinner with four sectors is spun. The sectors are numbered 1, 2, 3, and 4. Let XX be the score obtained when the spinner is spun. The probability distribution for XX is given in the following table.

xx1234
**P(X=xX=x)**0.1kk2k2k0.3

(a) Find the value of kk.

[2]
(b)

(b) Find the value of E(X)E(X).

[2]
(c)(i)

A second spinner, B, is also spun. Let YY be the score obtained. The probability distribution for YY is given in the following table.

yy1234
**P(Y=yY=y)**mmmmnnmm

(c) (i) State the range of possible values of nn.

[1]
(c)(ii)

(ii) Hence, find the range of possible values of mm.

[2]
(d)

(d) Hence, find the range of possible values for E(Y)E(Y).

[3]
(e)

Leo spins spinner A once and Mia spins spinner B once. The probability that Leo's score is greater than Mia's score is 25\frac{2}{5}.

(e) Find the value of E(Y)E(Y).

[6]

Question 4

MediumPaper 2 · calculator7 marks
(a)

A manufacturer produces electronic components. It is known that the probability that a randomly selected component is defective is 0.03. A quality control inspector takes a random sample of 40 components from a large batch.

(a) Find the probability that there is at least one defective component in the sample.

[3]
(b)

(b) Given that there is at least one defective component in the sample, find the probability that there are at most three defective components.

[4]

Question 5

HardPaper 1 · no calculator16 marks
(a)

A biased four-sided spinner, A, is spun. Let SAS_A be the score obtained. The probability distribution for SAS_A is given in the following table.

Score (ss)1234
P(SA=s)P(S_A=s)kk2k2k3k3kkk

Find the value of kk.

[2]
(b)

Hence, find the value of E(SA)E(S_A).

[2]
(c)(i)

A second biased four-sided spinner, B, is spun. Let SBS_B be the score obtained. The probability distribution for SBS_B is given in the following table.

Score (ss)1234
P(SB=s)P(S_B=s)aaaaaabb

(i) State the range of possible values of bb.

[1]
(c)(ii)

(ii) Hence, find the range of possible values of aa.

[2]
(d)

Hence, find the range of possible values for E(SB)E(S_B).

[3]
(e)

Leo spins spinner A once and Mia spins spinner B once. The probability that Leo's score is greater than Mia's score is 1349\frac{13}{49}.

Find the value of E(SB)E(S_B).

[6]

Question 6

MediumPaper 2 · calculator6 marks

Events S and C are independent. The probability that a student passes a Statistics exam, P(S), is twice the probability that the student passes a Calculus exam, P(C).

Given that the probability a student passes at least one of these exams is 0.625, find the probability that the student passes the Calculus exam, P(C).

Question 7

HardPaper 2 · calculator5 marks
(a)

A factory produces two types of light bulbs: standard and long-life. The lifespan of the bulbs, in hours, can be modelled as normal distributions with the following parameters.

Bulb typeMean μ\muStandard deviation σ\sigma
Standard800 h50 h
Long-life1000 h100 h

(a) Find the percentage of standard bulbs that have a lifespan of less than 700 hours.

[1]
(b)

(b) The factory produces a large number of bulbs, of which 60% are standard bulbs. Both types of bulbs are produced and randomly mixed together for packaging. A quality control process identifies and removes all bulbs with a lifespan of less than 700 hours. An inspector randomly selects a bulb from this removed group. Find the probability that it is a standard bulb.

[4]

Question 8

MediumPaper 1 · no calculator5 marks
(a)

A student, Chloe, travels to school by bus. She can take one of two routes, Route X or Route Y. She is equally likely to choose either route on any given day.

The probability that she arrives on time when taking Route X is 34\frac{3}{4}.

The probability that she arrives on time when taking Route Y is 25\frac{2}{5}.

(a) Find the probability that Chloe arrives on time for school on a randomly chosen day.

[3]
(b)

Let XX be the event that Chloe chooses Route X and let TT be the event that she arrives on time.

(b) Determine whether events XX and TT are independent.

[2]

Question 9

HardPaper 2 · calculator16 marks
(a)

(a) The random variable XX follows a normal distribution with mean μ\mu and standard deviation σ\sigma.

Find P(μ−1.2σ<X<μ+1.2σ)P(\mu - 1.2\sigma < X < \mu + 1.2\sigma).

[3]
(b)

(b) The diameters of ball bearings produced by a factory, in mm, are normally distributed with mean μ\mu and standard deviation σ\sigma. The ball bearings are categorized as defective, standard, large, or premium, according to their diameter. The following table shows the probability a ball bearing is classified into each category.

CategoryProbability
Defective0.03
Standard0.65
Large0.25
Premium0.07

The maximum diameter of a defective ball bearing is 14.8 mm.

The minimum diameter of a premium ball bearing is 16.5 mm.

Find the value of μ\mu and of σ\sigma.

[6]
(c)(i)

(c) The factory rejects all defective ball bearings. The remaining ball bearings are sold.

Find the probability that a ball bearing chosen at random from those sold is categorized as

(i) standard;

[1]
(c)(ii)

(ii) large;

[1]
(c)(iii)

(iii) premium.

[1]
(d)

(d) The selling prices of the different categories of ball bearings at this factory are shown in the following table:

CategorySelling Price ($)
Standard1.50
Large1.80
Premium2.50

The factory incurs a fixed cost of $300 for the production run and assumes it will sell the accepted ball bearings in exactly the same proportion as calculated in part (c).

According to this model, find the minimum number of accepted ball bearings that must be sold so that the net profit for the factory is at least $550.

[4]

Question 10

MediumPaper 1 · no calculator5 marks

At a high school, students can study Chemistry and Physics. Let C be the event that a randomly selected student studies Chemistry and P be the event that they study Physics.

It is known that P(C)=0.5P(C) = 0.5, P(C∣P)=0.6P(C|P) = 0.6 and P(C∪P)=0.8P(C \cup P) = 0.8.

Find the probability that a randomly selected student studies Physics, P(P)P(P).

Question 11

HardPaper 2 · calculator16 marks
(a)

(a) An electronics factory produces two types of resistors: Type A and Type B.

The resistance, RAR_A (in Ohms), of Type A resistors is normally distributed with a mean of 120 Ohms and a standard deviation of 5 Ohms.

Find the probability that a randomly selected Type A resistor has a resistance less than 115 Ohms.

[2]
(b)

(b) In a random selection of 10 Type A resistors, find the probability that exactly 3 have a resistance less than 115 Ohms.

[2]
(c)(i)

(c) The resistance, RBR_B (in Ohms), of Type B resistors is normally distributed with a mean of 135 Ohms and a standard deviation of 7 Ohms.

Each day, 70% of the resistors produced are Type A, and 30% are Type B.

On a particular day, a resistor is randomly selected from all those produced at the factory.

Let AA represent 'Type A resistor' and BB represent 'Type B resistor'.

(i) Find the probability that the randomly selected resistor has a resistance less than 115 Ohms.

[4]
(c)(ii)

(ii) Given that a randomly selected resistor has a resistance less than 115 Ohms, find the probability that it is a Type A resistor.

[3]
(d)

(d) The machine that makes the Type A resistors is adjusted so that the mean resistance of the Type A resistors remains the same, but their standard deviation changes to σ\sigma Ohms. The machine that makes the Type B resistors is not adjusted. The probability that the resistance of a randomly selected resistor from these machines is now less than 115 Ohms is 0.18.

Find the value of σ\sigma.

[5]

Question 12

MediumPaper 1 · no calculator5 marks
(a)

Two archers, Clara and David, are competing. To decide who shoots an arrow, a fair six-sided die is rolled. If the die shows a 1, Clara is chosen. If the die shows any other number, David is chosen.

The probability that Clara hits the target is 45\frac{4}{5}. The probability that David hits the target is 23\frac{2}{3}.

(a) Find the probability that the target is hit.

[3]
(b)

(b) Let CC be the event that Clara is chosen and let HH be the event that the target is hit. Determine, with a reason, whether events CC and HH are independent.

[2]

Question 13

HardPaper 2 · calculator18 marks
(a)

(a) A new automated coffee machine is programmed to dispense coffee. The volume of coffee dispensed, VV ml, is normally distributed with a mean of 200 ml and a standard deviation of σ\sigma ml.

On 15% of occasions, the machine dispenses more than 210 ml of coffee.

Find the value of σ\sigma.

[4]
(b)

(b) On a randomly selected occasion, find the probability that the machine dispenses more than 205 ml of coffee.

[2]
(c)

(c) The machine is considered to have 'over-filled' a cup if it dispenses more than 215 ml of coffee. Seven customers order coffee. Assume the volume dispensed for each customer is independent.

Find the probability that at least one of these seven coffees is over-filled.

[3]
(d)

(d) Given that at least one of the seven coffees is over-filled, find the probability that exactly two of them are over-filled.

[5]
(e)

(e) The café serves 25 customers in an hour. The machine requires maintenance if it over-fills more than 3 coffees during that hour. So far, 18 customers have been served, and the machine has over-filled 2 coffees.

Find the probability that the machine will NOT require maintenance by the end of the hour.

[4]

Question 14

MediumPaper 1 · no calculator5 marks

Events XX and YY are such that P(X)=0.3P(X) = 0.3, P(X∣Y)=0.2P(X|Y) = 0.2 and P(X∪Y)=0.9P(X \cup Y) = 0.9.

Find P(Y)P(Y).

Question 15

HardPaper 2 · calculator18 marks
(a)(i)

In a large university, 200 students were surveyed. Of those, 120 were undergraduates (U) and the rest postgraduates (P).

Each student in the survey was asked whether they preferred quiet zones (Q) or collaborative areas (C) for studying. It was found that 75 of the undergraduates preferred quiet zones. The total number of students who preferred collaborative areas was 100. This information is shown in the following table.

Quiet Zones (Q)Collaborative Areas (C)Total
Undergraduates (U)75p120
Postgraduates (P)x5580
Totalq100200

Find the value of

pp;

[1]
(a)(ii)

qq.

[2]
(b)

Three students are chosen at random from those surveyed. Find the probability that all three are postgraduates.

[4]
(c)(i)

Given that P(P∣Q)=14P(P|Q) = \frac{1}{4}, find the value of xx.

[3]
(c)(ii)

A student is chosen at random from those surveyed. Write down the probability that they are a postgraduate who prefers quiet zones.

[2]
(d)

Determine if the events P (Postgraduate) and Q (prefers Quiet Zones) are independent. Justify your answer.

[3]
(e)

It can be assumed that the survey results are representative of the university population. Ten students from the university are chosen at random. Find the probability that at least five of them prefer quiet zones.

[4]

Question 16

MediumPaper 1 · no calculator6 marks
(a)

Consider events CC and DD such that P(C′)=23P(C') = \frac{2}{3}, P(C∪D)=23P(C \cup D) = \frac{2}{3} and P(D∣C)=12P(D|C) = \frac{1}{2}.

(a) Find P(C∩D)P(C \cap D).

[3]
(b)

(b) Determine if events CC and DD are independent. Justify your answer.

[3]

Question 17

HardPaper 2 · calculator16 marks
(a)

The lifespan, LL (in hours), of a certain type of LED light bulb is modelled by a normal distribution with mean μ\mu and standard deviation σ\sigma.

It is known that P(L<18500)=0.15P(L < 18500) = 0.15 and P(L>21500)=0.30P(L > 21500) = 0.30.

Find the probability that a randomly selected light bulb has a lifespan between 1850018500 hours and 2150021500 hours.

[2]
(b)

Find the value of μ\mu and the value of σ\sigma.

[5]
(c)(i)

A manufacturer tests a batch of 8080 randomly selected light bulbs. Any bulb with a lifespan greater than 2150021500 hours is considered a 'long-life' bulb. Lifespans of bulbs are independent of each other.

Find the probability that exactly 2525 bulbs in the batch are 'long-life' bulbs.

[2]
(c)(ii)

Given that fewer than 3030 bulbs are 'long-life' bulbs, find the probability that exactly 2525 bulbs are 'long-life' bulbs.

[4]
(d)

In another factory, a different type of LED light bulb is produced. The lifespan of these bulbs, FF (in hours), is normally distributed with a mean of 2200022000 hours. The interquartile range (IQR) for these bulbs is 30003000 hours.

Find the value of the standard deviation, dd, for this type of bulb.

[3]

Question 18

MediumPaper 2 · calculator6 marks
(a)

(a) The lifespan of a certain type of rechargeable battery, in hours, can be modelled by a normal distribution with a mean of 1500 hours and a standard deviation of 50 hours. A battery is deemed faulty and rejected if its lifespan is less than 1425 hours.

Find the probability that a randomly selected battery is rejected.

[2]
(b)

(b) Estimate the number of batteries that will be rejected from a random sample of 200 batteries.

[1]
(c)

(c) Given that a battery is not rejected, find the probability that it has a lifespan greater than 1575 hours.

[3]

Question 19

HardPaper 2 · calculator16 marks
(a)

(a) The resistance, R ohms, of resistors produced by a factory is normally distributed with a mean of 100 ohms and a standard deviation of 3.5 ohms.

Find the probability that a randomly selected resistor has a resistance less than 98 ohms.

[2]
(b)

(b) In a random sample of 15 resistors, find the probability that exactly 4 of them have a resistance less than 98 ohms.

[2]
(c)(i)

(c.i) The capacitance, C microfarads, of capacitors produced by the same factory is normally distributed with a mean of 50 μ\muF and a standard deviation of 2.8 μ\muF. Each day, 70% of the components produced are resistors and 30% are capacitors.

Find the probability that a randomly selected component has a value less than its respective threshold (i.e., less than 98 ohms for a resistor or less than 47 μ\muF for a capacitor).

[4]
(c)(ii)

(c.ii) Given that a randomly selected component has a value less than its respective threshold, find the probability that it is a resistor.

[3]
(d)

(d) The resistor manufacturing process is adjusted so that the mean resistance remains 100 ohms but its standard deviation changes to σ\sigma ohms. The capacitor manufacturing process is not adjusted. The probability that a randomly selected component from these machines has a value less than its respective threshold is now 0.160.

Find the value of σ\sigma.

[5]

Question 20

MediumPaper 2 · calculator8 marks
(a)

At a tech company, employees can participate in various initiatives. 70% of employees attend a professional development workshop (WW), and 20% of employees work on a special innovation project (PP). 20% of employees do neither activity.

An employee is selected at random.

Find the probability that the employee attends a professional development workshop and works on a special innovation project.

[2]
(b)

Find the probability that the employee works on a special innovation project, but does not attend a professional development workshop.

[2]
(c)

At the company, 40% of the employees are in the Marketing department. Of those in the Marketing department, 30% work on a special innovation project.

An employee is selected at random. Let MM be the event "the employee is in the Marketing department" and let PP be the event "the employee works on a special innovation project".

Find P(M∩P)P(M \cap P).

[2]
(d)

Determine if the events MM and PP are independent. Justify your answer.

[2]

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What does Conditional probability and independent events cover in IB Maths AA?

Conditional Probability: The probability of event A given that B has occurred:. P(A|B) = (P(A cap B))/(P(B)), P(B) ≠ 0. Independent Events: Events A and B are independent if:.

Is Conditional probability and independent events SL or HL?

Both. SL and HL students study Conditional probability and independent events, and HL goes further: Extended at AHL 4.13 (Bayes' theorem).

How do I revise Conditional probability and independent events for IB Maths AA?

Start from the core idea: conditional Probability: The probability of event A given that B has occurred:. In the exam: with or without replacement changes the second branch of a tree and is the standard discriminator. The guidance that problems can be solved without explicit formulae means a correct tree diagram plus a correct answer is worth full marks, so a mark scheme should not demand the formula. Then practise exam-style questions, easiest first, writing out every step of your working before you check it.

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