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Topic 5.02 · SL and HL

Power rule (standard derivative): notes and practice questions

Summary

The derivative of f(x)=axn f(x) = ax^n with respect to xx is:

$$
f'(x) = n \cdot a \cdot x^{n-1}

where where nisarealnumberand is a real number and a$$ is a constant. This rule is fundamental for finding the slope of functions in calculus.

How it is examined

Never asked alone past the first line of a question. It is the tool for tangents, stationary points and optimization. The reliable error is differentiating a term like 3x2\frac{3}{x^2} without first writing it as 3x−23x^{-2}. 1 to 3 marks.

Given in the booklet

The derivative of xnx^n is in the standard derivatives table.

Key ideas
  • Derivative of f(x)=axnf(x) = ax^n is f′(x)=anxn−1f'(x) = anx^{n-1}, n∈Zn \in \mathbb{Z}.
  • The derivative of functions of the form f(x)=axn+bxn−1+…f(x) = ax^n + bx^{n-1} + \ldots where all exponents are integers.
At HL

Extended at SL 5.6 to n∈Qn \in \mathbb{Q}.

Linking questions

  • The integer restriction here is real: rational exponents arrive at SL 5.6.

Practice questions

48 questions · 1 easy · 34 medium · 13 hard
Showing 20 of 20

Question 1

EasyPaper 1 · no calculator9 marks
(a)

Consider the function f(x)=x3+5x2−x+5f(x) = x^{3} + 5x^{2} - x + 5.

(a) Find f′(x)f'(x).

[1]
(b)

(b) Find the equation of the tangent line at x=1x = 1.

[5]
(c)

(c) For the equation of the normal line at x=1x = 1.

[3]

Question 2

MediumPaper 1 · no calculator7 marks
(a)

Consider the functions f(x)=ln⁡(x−p)f(x) = \ln(x-p) and g(x)=14x2+qg(x) = \frac{1}{4}x^2 + q where p,q∈Rp, q \in \mathbb{R}.

(a) Find g′(x)g'(x).

[1]
(b)

The graphs of ff and gg have a common tangent at the point where x=2x = 2.

(b) Show that p=1p = 1.

[3]
(c)

(c) Hence, find the value of qq.

[3]

Question 3

HardPaper 1 · no calculator15 marks
(a)

A drone takes off from a platform. Its height, hh metres, above the platform after tt seconds is given by h(t)=6t−t2h(t) = 6t - t^2, for 0≤t≤80 \le t \le 8. This is shown in the following diagram.

Graph of height h versus time t for the drone, showing a parabola opening downwards with vertex in the first quadrant and passing through the origin

The drone lands back on the platform when t=pt=p.

Find the value of pp.

[2]
(b)(i)

The drone reaches its maximum height when t=qt=q.

Find the value of qq.

[3]
(b)(ii)

Find the drone's maximum height above the platform.

[2]
(c)

Find the drone's vertical distance from the platform when t=8t=8.

[2]
(d)

The total vertical distance travelled by the drone in the first 8 seconds is given by dd.

Find the value of dd.

[2]
(e)

A second drone, Drone B, takes off from the same platform. Its velocity is given by vB(t)=8−2tv_B(t) = 8 - 2t, for t≥0t \ge 0.

When t=kt = k, the total vertical distance travelled by Drone B is equal to dd.

Find the value of kk.

[4]

Question 4

MediumPaper 1 · no calculator5 marks

Find the value of ∫193x−2xdx\int_{1}^{9} \frac{3x-2}{\sqrt{x}} dx.

Question 5

HardPaper 1 · no calculator17 marks
(a)

A hollow pipe is manufactured by removing a smaller cylinder of radius rr from the centre of a larger cylinder of radius 3r3r. Both cylinders have the same height, hh. This is shown in the following diagram.

All lengths are measured in centimetres.

Diagram of a hollow cylinder with no top with outer radius 3r, inner radius r, and both with height h

The total surface area of the hollow pipe, in cm2^2, is given by SS.

(a) Show that S=16πr2+8πrhS = 16\pi r^2 + 8\pi rh.

[3]
(b)

The total surface area of the hollow pipe is 128π cm2128\pi \text{ cm}^2.

(b) Show that the volume of the pipe, VV, is given by V=128πr−16πr3V = 128\pi r - 16\pi r^3.

[6]
(c)

(c) Find an expression for dVdr\frac{dV}{dr}.

[2]
(d)

(d) The hollow pipe has its maximum volume when r=k6r = k\sqrt{6}, where k∈Q+k \in \mathbb{Q}^+. Find the value of kk.

[3]
(e)

(e) Hence, find this maximum volume, giving your answer in the form mπ6m\pi\sqrt{6}, where m∈Q+m \in \mathbb{Q}^+.

[3]

Question 6

MediumPaper 1 · no calculator7 marks
(a)

Consider the functions f(x)=k−(x−h)2f(x) = k - (x-h)^2 and g(x)=ln⁡(x−1)+2g(x) = \ln(x-1) + 2 where h,k∈Rh, k \in \mathbb{R}.

The graphs of ff and gg have a common tangent at x=2x=2.

(a) Find g′(x)g'(x).

[1]
(b)

(b) Show that h=52h = \frac{5}{2}.

[3]
(c)

(c) Hence, find the value of kk.

[3]

Question 7

HardPaper 1 · no calculator16 marks
(a)

A particle moves in a straight line. Its velocity, v ms−1v \,\text{ms}^{-1}, at time tt seconds is given by v(t)=−t3+6t2−9tv(t) = -t^3 + 6t^2 - 9t, for 0≤t≤50 \le t \le 5. The particle is at the origin at t=0t=0.

The graph of vv is shown in the following diagram.

Graph of velocity v against time t, showing a cubic function starting at (0,0), going down to a minimum between t=0 and t=3, then up to touch the t-axis at t=3, and then continuing downwards.

(a) Find the displacement of the particle from the origin at t=3t=3.

[4]
(b)

(b) Find an expression for the acceleration of the particle.

[2]
(c)

(c) The particle is momentarily at rest at t=0t=0 and again at t=kt=k. Find the greatest speed of the particle in the interval 0≤t≤k0 \le t \le k.

[5]
(d)

(d) Find the greatest speed of the particle for 0≤t≤50 \le t \le 5.

[2]
(e)

(e) Write down an expression that represents the distance travelled by the particle while its speed is increasing. Do not evaluate the expression.

[3]

Question 8

MediumPaper 1 · no calculator6 marks
(a)

The expression 5x−2x3\frac{5x-2}{\sqrt[3]{x}} can be written in the form 5xp−2xq5x^p - 2x^q. Write down the value of pp and the value of qq.

[2]
(b)

Hence, find the value of ∫185x−2x3 dx\int_1^8 \frac{5x-2}{\sqrt[3]{x}} \, dx.

[4]

Question 9

HardPaper 1 · no calculator14 marks
(a)

A function is defined by f(x)=12x2+x+4f(x) = \frac{1}{2}x^2 + x + 4. The following diagram shows part of the graph of ff.

The graph has a vertex at V and intersects the y-axis at point P.

Graph of a parabola opening upwards, with vertex V and y-intercept P.

(a) Find the coordinates of the vertex V.

[3]
(b)

(b) Write down the coordinates of the y-intercept, P.

[1]
(c)

(c) The line L is the normal to the graph of ff at point P. Find the equation of L, giving your answer in the form y=mx+cy=mx+c.

[4]
(d)

(d) The line L intersects the graph of ff at a second point, Q. Calculate the distance between P and Q.

[6]

Question 10

MediumPaper 1 · no calculator6 marks

Consider the curve with equation y=ax2ln⁡(x)y = ax^2\ln(x), where x>0x > 0 and a∈Ra \in \mathbb{R}.

The normal to the curve at the point where x=ex = e is parallel to the line with equation y=−13ex+5y = -\frac{1}{3e}x + 5.

Find the value of aa.

Question 11

HardPaper 2 · calculator15 marks
(a)(i)

A landscape architect is designing a section of a garden path. The shape of one edge of the path can be modelled by the function h(x)=14x2+12h(x) = \frac{1}{4}x^2 + \frac{1}{2} for x≥0x \ge 0, where xx and h(x)h(x) are measured in metres.

(a) (i) Find h−1(x)h^{-1}(x), the inverse of h(x)h(x), and state its domain.

[4]
(a)(ii)

(ii) Write down the range of h−1(x)h^{-1}(x).

[1]
(b)

(b) The graph of hh intersects the graph of h−1h^{-1} at two points. Find the xx -coordinates of these two points.

[3]
(c)

(c) Find the area enclosed by the graph of hh and the graph of h−1h^{-1}.

[2]
(d)

(d) Find h′(x)h'(x).

[2]
(e)

(e) Find the value of xx for which the graph of hh and the graph of h−1h^{-1} have the same gradient.

[3]

Question 12

MediumPaper 1 · no calculator13 marks
(a)

A function, gg, has its derivative given by g′(x)=−2x2+8x+kg'(x) = -2x^2 + 8x + k, where k∈Rk \in \mathbb{R}. The following diagram shows part of the graph of g′g'.

Graph of g' showing a parabola opening downwards, with vertex in the first quadrant.

The graph of g′g' has an axis of symmetry x=qx = q.

(a) Find the value of qq.

[2]
(b)

(b) The vertex of the graph of g′g' has a y-coordinate of 10. Find the value of kk.

[3]
(c)

(c) Find the equation of the tangent to the graph of g′g' at x=0x = 0.

[4]
(d)(i)

The graph of gg has a point of inflexion at x=cx = c.

(d) (i) Find the value of cc.

[2]
(d)(ii)

(ii) Find the values of xx for which the graph of gg is concave-up. Justify your answer.

[2]

Question 13

HardPaper 2 · calculator15 marks
(a)

A remote-controlled drone is launched from a platform and moves horizontally in a straight line. Its velocity, vv m s−1^{-1}, at time tt seconds after launch, is given by v(t)=t+1−4t+16v(t) = t + 1 - \sqrt{4t + 16}, for t≥0t \ge 0.

(a) Find the drone's initial velocity.

[2]
(b)

(b) Find the time when the drone is at rest.

[4]
(c)

(c) Find the drone's acceleration at the instant it comes to rest.

[4]
(d)(i)

(d) Determine the time interval(s) when the drone is:

(i) slowing down

[3]
(d)(ii)

(ii) speeding up.

[2]

Question 14

MediumPaper 1 · no calculator5 marks

Consider the function g(x)=14x4−2x2+5g(x) = \frac{1}{4}x^4 - 2x^2 + 5, where x∈Rx \in \mathbb{R}.

The graph of y=g(x)y = g(x) has a local minimum point at (p,q)(p, q) where p<0p < 0.

Find the value of pp and the value of qq.

Question 15

HardPaper 1 · no calculator22 marks
(a)

Differentiate each of the following expressions with respect to xx:

10ex−4ln⁡x+210e^x - 4\ln x + 2

[2]
(b)

e−5xe^{-5x}

[2]
(c)

x2exx^2 e^x

[3]
(d)

ln⁡(4x3−2x)\ln(4x^3 - 2x)

[3]
(e)

esin⁡(x)e^{\sin(x)}

[2]
(f)

ln⁡xx3\frac{\ln x}{x^3}

[3]
(g)

ln⁡(1x2+1)\ln(\frac{1}{x^2+1})

[3]
(h)

excos⁡(x)e^{x\cos(x)}

[4]

Question 16

MediumPaper 2 · calculator12 marks
(a)(i)

The trajectory of a small drone flying over a landscape can be modelled by the function f(x)=−0.5x2+4x+1f(x) = -0.5x^2 + 4x + 1, where xx is the horizontal distance in meters from the launch point and f(x)f(x) is the altitude in meters. The drone passes through a checkpoint A at a horizontal distance of 2 meters.

(a) (i) Find the gradient of the tangent to the drone's trajectory at checkpoint A.

[3]
(a)(ii)

(a) (ii) Hence, write down the gradient of the normal to the drone's trajectory at checkpoint A.

[2]
(b)

(b) Write down the equation of the normal to the drone's trajectory at checkpoint A.

[3]
(c)

(c) A searchlight beam is directed along the normal line found in part (b). This beam intersects the drone's trajectory again at a second point B. Find the coordinates of B.

[4]

Question 17

HardPaper 1 · no calculator13 marks
(a)

A function is defined by f(x)=x3−4xf(x) = x^3 - 4x.

(a) Find the equation of the tangent to the graph of ff at the point where x=−1x = -1.

[4]
(b)

(b) The tangent line found in part (a) intersects the graph of ff at a second point, P. Find the coordinates of P.

[4]
(c)

(c) Find the exact area of the finite region enclosed by the graph of ff and the tangent line.

[5]

Question 18

MediumPaper 2 · calculator14 marks
(a)

An engineer is designing an open-top rectangular container with a square base. The container must have a volume of 4 m34\text{ m}^3.

Let the side length of the square base be xx metres and the height of the container be hh metres.

Show that the total surface area, S m2S\text{ m}^2, of the material used for the container is given by S=x2+16xS = x^2 + \frac{16}{x}.

[3]
(b)(i)

Find an expression for dSdx\frac{dS}{dx}.

[2]
(b)(ii)

Hence, find the exact value of xx for which the surface area is a local minimum or maximum.

[3]
(c)(i)

Find an expression for d2Sdx2\frac{d^2S}{dx^2}.

[2]
(c)(ii)

Use the second derivative of SS to justify that SS is a minimum when x=2x = 2.

[2]
(c)(iii)

Find the minimum surface area of the container.

[2]

Question 19

HardPaper 2 · calculator19 marks
(a)

(a) A deep-sea submersible's vertical displacement, in metres, from a reference depth is given by s(t)=5sin⁡(2t)−3cos⁡(t)s(t) = 5 \sin(2t) - 3 \cos(t) for time tt minutes. Positive s(t)s(t) indicates the submersible is above the reference depth, and negative s(t)s(t) indicates it is below.

Find the submersible's vertical velocity and acceleration at any time tt.

[3]
(b)

(b) Find the time intervals during 0≤t≤2π0 \le t \le 2\pi when the submersible is moving upwards.

[5]
(c)

(c) Determine the time intervals during 0≤t≤2π0 \le t \le 2\pi when the submersible's vertical velocity is decreasing.

[5]
(d)

(d) Calculate the total vertical distance travelled by the submersible during the time 0≤t≤2π0 \le t \le 2\pi. Give your answer to three significant figures.

[6]

Question 20

MediumPaper 2 · calculator8 marks
(a)(i)

A civil engineer is designing a parabolic arch for a pedestrian bridge. The shape of the arch can be modelled by the function f(x)=−x2+7x−5f(x) = -x^2 + 7x - 5, where xx is the horizontal distance in meters from one end of the bridge and f(x)f(x) is the height of the arch above the ground in meters.

A support cable needs to be attached to the arch at a point A where x=2x=2.

(i) Calculate the gradient of the tangent to the arch at point A.

[2]
(a)(ii)

(ii) Hence, write down the gradient of the line perpendicular to the tangent at point A.

[1]
(b)

The support cable is designed to be perpendicular to the arch at point A. Write down the equation of the line representing this support cable.

[2]
(c)

The support cable (represented by the normal line) is extended and intersects the parabolic arch again at a second point B. Find the coordinates of point B.

[3]

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What does Power rule (standard derivative) cover in IB Maths AA?

The derivative of f(x) = ax^n with respect to x is:. $$. f'(x) = n \cdot a \cdot x^{n-1}.

Is Power rule (standard derivative) SL or HL?

Both. SL and HL students study Power rule (standard derivative), and HL goes further: Extended at SL 5.6 to n ∈ mathbbQ.

How do I revise Power rule (standard derivative) for IB Maths AA?

Start from the core idea: the derivative of f(x) = ax^n with respect to x is:. In the exam: never asked alone past the first line of a question. It is the tool for tangents, stationary points and optimization. Then practise exam-style questions, easiest first, writing out every step of your working before you check it.

How does FourtyFive help me practise Power rule (standard derivative)?

FourtyFive has 48 Power rule (standard derivative) questions. Every answer you write is marked mark by mark, IB-style, and you see where each mark was won or lost. Every part has a hint, the AI tutor helps you through the step you are stuck on, and your Study Profile picks what to practise next.

Is FourtyFive free for Power rule (standard derivative) practice?

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