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Topic 5.15 · HL only

Related rates of change: notes and practice questions

Summary
  • Related rates problems involve finding the rate of change of one quantity in terms of the rate of change of another quantity.
  • The Chain Rule is fundamental: dydt=dydx×dxdt\frac{dy}{dt} = \frac{dy}{dx} \times \frac{dx}{dt}.
  • Steps: Draw a diagram, list knowns/unknowns, find a connecting equation (geometry, trig), differentiate implicitly with respect to time (tt), substitute values after differentiating, and solve.
  • Remember to differentiate terms like xnx^n as nxn−1dxdtnx^{n-1}\frac{dx}{dt}.
  • Pay attention to units and signs (positive for increasing, negative for decreasing).
  • Angles are typically measured in radians for rate calculations.

How it is examined

Related rates questions are chain-rule bookkeeping with units, usually a cone or a ladder. Implicit differentiation shows up as "find the equation of the tangent to this curve", where the curve is not a function. 6 to 9 marks across parts.

Key ideas
  • Implicit differentiation.
  • Related rates of change.
  • Optimisation problems.

Linking questions

  • Other contexts: links between mathematical and physical models.

Worked example

A 5 m ladder leans against a vertical wall. Its foot slides away from the wall at 0.5 m s−10.5\text{ m s}^{-1}. How fast is the top sliding down when the foot is 3 m from the wall?

  1. x2+y2=25x^2 + y^2 = 25, where xx is the distance of the foot from the wall and yy the height of the top.
  2. Differentiate with respect to tt: 2xdxdt+2ydydt=02x\frac{dx}{dt} + 2y\frac{dy}{dt} = 0.
  3. When x=3x = 3, y=4y = 4. Substitute: 2(3)(0.5)+2(4)dydt=02(3)(0.5) + 2(4)\frac{dy}{dt} = 0.
  4. dydt=−0.375\frac{dy}{dt} = -0.375, so the top slides down at 0.375 m s−10.375\text{ m s}^{-1}.

Practice questions

13 questions · 2 easy · 10 medium · 1 hard
Showing 13 of 13

Question 1

EasyPaper 1 · no calculator5 marks

If a square has its Area, AA in cm2cm^{2}, increasing at a rate of 0.5 cm2s−10.5\ cm^{2}s^{- 1}, find the rate at which each side xx is increasing when the area is 100 cm2100\ cm^{2}.

Question 2

MediumPaper 1 · no calculator5 marks

A block of ice is in the shape of a perfect cube. It is melting in such a way that its surface area is decreasing at a constant rate of 12 cm2 s−112 \text{ cm}^2 \text{ s}^{-1}.

Find the rate at which the volume of the ice block is decreasing at the instant when the side length is 10 cm10 \text{ cm}.

Question 3

HardPaper 2 · calculator20 marks
(a)

A designer is creating a decorative glass container shaped like a dome. The outer profile of the container can be modelled by the function f(x)=9−x2f(x) = \sqrt{9-x^2}, where 0≤x≤30 \le x \le 3 and xx and yy are measured in metres.

Sketch the curve y=f(x)y = f(x), clearly indicating the coordinates of the endpoints.

[2]
(b)(i)

Show that the inverse function of ff is given by f−1(x)=9−x2f^{-1}(x) = \sqrt{9-x^2}.

[3]
(b)(ii)

State the domain and range of f−1f^{-1}.

[2]
(c)(i)

The container is formed by rotating the curve y=f(x)y = f(x) by 2π2\pi about the y-axis. Show that the volume, V m3V \text{ m}^3, of liquid in the container when it is filled to a height of hh metres is given by V=π(9h−13h3)V = \pi \left( 9h - \frac{1}{3}h^3 \right).

[3]
(c)(ii)

Hence, determine the maximum volume of the container.

[2]
(d)

At t=0t = 0, the container is empty. Liquid is then added to the container at a constant rate of 0.5 m3s−10.5 \text{ m}^3\text{s}^{-1}.

Find the time it takes to fill the container to its maximum volume.

[2]
(e)

Find the rate of change of the height of the liquid when the container is filled to half its maximum volume.

[6]

Question 4

EasyPaper 2 · calculator5 marks
(a)

If a balloon that has a shape of a sphere is being inflated with helium at a rate of 0.2 m3s−1m^{3}s^{- 1}.

aa Find the radius of the balloon at which the volume according to the given model would be 2π2\pi m3m^{3}.

[2]
(b)

bb Calculate the rate of change of the radius of this model for the calculated value in the previous part.

[3]

Question 5

MediumPaper 1 · no calculator5 marks

A perfectly spherical soap bubble is being formed. Its radius, rr cm, is increasing at a rate of 0.5 cm s−10.5 \text{ cm s}^{-1}.

Find the rate at which the volume of the bubble, V cm3V \text{ cm}^3, is increasing when the surface area of the bubble is 36π cm236\pi \text{ cm}^2.

Question 6

MediumPaper 2 · calculator6 marks

A square metal plate is expanding due to heating, and a circular hole in its center is also expanding. At a certain moment, the side length of the square is 12 cm12 \text{ cm} and is increasing at a rate of 0.4 cm s−10.4 \text{ cm s}^{-1}. At the same moment, the radius of the circular hole is 4 cm4 \text{ cm} and is increasing at a rate of 0.3 cm s−10.3 \text{ cm s}^{-1}. Find the rate of change of the area of the metal plate at this moment.

Question 7

MediumPaper 2 · calculator5 marks

(a) A spherical ice sculpture is melting such that its volume is decreasing at a constant rate of 1.6 cm3 min−11.6 \text{ cm}^3 \text{ min}^{-1}. Find the rate at which the surface area of the ice sculpture is decreasing when its radius is 2 cm2 \text{ cm}.

Question 8

MediumPaper 1 · no calculator6 marks

A block of ice in the shape of a right prism has a square base with side length xx cm and height yy cm. The block is melting such that the side length of the base is decreasing at a rate of 0.05 cm s−10.05 \text{ cm s}^{-1} and the height is decreasing at a rate of 0.1 cm s−10.1 \text{ cm s}^{-1}.

Find the rate of change of the volume of the ice block at the instant when the side length of the base is 88 cm and the height is 1212 cm.

Question 9

MediumPaper 2 · calculator6 marks

A spherical hot air balloon is being inflated. Its volume increases at a constant rate of 0.8 m3s−10.8 \text{ m}^3\text{s}^{-1}.

Find the rate, in m s−1\text{m s}^{-1}, at which the radius of the balloon is increasing when its volume is 100 m3100 \text{ m}^3.

Question 10

MediumPaper 2 · calculator5 marks
(a)

A machine pours sand onto a flat horizontal surface at a constant rate of 0.5 m³ per minute. The sand forms a pile in the shape of a right circular cone whose base radius is always equal to its height.

(a) Find the height of the pile when the volume of sand is 12 m³.

[2]
(b)

(b) Find the rate at which the height of the pile is increasing at the instant when the volume of sand is 12 m³.

[3]

Question 11

MediumPaper 2 · calculator5 marks
(a)

A machine is pouring gravel onto a pile, which forms the shape of a right circular cone. The height of the cone, hh, is always equal to the diameter of its base. The gravel is being added at a constant rate of 1.5 m3min−1m^{3}min^{-1}.

(a) Find the height of the conical pile when its volume is 10 m3m^{3}.

[2]
(b)

(b) Calculate the rate at which the height of the pile is increasing at the instant when the volume is 10 m3m^{3}.

[3]

Question 12

MediumPaper 2 · calculator5 marks
(a)

A spherical hailstone melts such that its volume decreases at a constant rate of 12 mm³s⁻¹.

(a) Find the radius of the hailstone, in mm, when its volume is 972π972\pi mm³.

[2]
(b)

(b) Calculate the rate of change of the radius of the hailstone at the instant its volume is 972π972\pi mm³.

[3]

Question 13

MediumPaper 2 · calculator5 marks
(a)

A pile of gravel is being formed in the shape of a right circular cone whose base radius, rr, is always equal to its height, hh. Gravel is being added to the pile at a rate of 0.5 m3min−10.5 \, \text{m}^3 \text{min}^{-1}.

(a) Find the height of the pile when its volume is 12 m312 \, \text{m}^3.

[2]
(b)

(b) Calculate the rate at which the height of the pile is increasing at the instant when its volume is 12 m312 \, \text{m}^3.

[3]

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What does Related rates of change cover in IB Maths AA?

Related rates problems involve finding the rate of change of one quantity in terms of the rate of change of another quantity. The Chain Rule is fundamental: (dy)/(dt) = (dy)/(dx) × (dx)/(dt). Steps: Draw a diagram, list knowns/unknowns, find a connecting equation (geometry, trig), differentiate implicitly with respect to time (t), substitute values after differentiating, and solve.

Is Related rates of change SL or HL?

Related rates of change is HL only. SL students are not examined on it.

How do I revise Related rates of change for IB Maths AA?

Start from the core idea: related rates problems involve finding the rate of change of one quantity in terms of the rate of change of another quantity. In the exam: related rates questions are chain-rule bookkeeping with units, usually a cone or a ladder. Implicit differentiation shows up as "find the equation of the tangent to this curve", where the curve is not a function. Then practise exam-style questions, easiest first, writing out every step of your working before you check it.

How does FourtyFive help me practise Related rates of change?

FourtyFive has 13 Related rates of change questions. Every answer you write is marked mark by mark, IB-style, and you see where each mark was won or lost. Every part has a hint, the AI tutor helps you through the step you are stuck on, and your Study Profile picks what to practise next.

Is FourtyFive free for Related rates of change practice?

Yes. A free account gives you 50 marked answers a month, and you do not need a card to sign up.

Can I handwrite Related rates of change answers on an iPad?

Yes. In the FourtyFive iPad app you write your working by hand with Apple Pencil, the way you would on paper, and it is marked the same way.

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