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Topic 1.07 · SL and HL

Logarithms: notes and practice questions

Summary
  • A logarithm is the inverse of exponentiation. If ax=ba^x = b, then log⁡ab=x\log_a b = x.
  • Key rules:

1. log⁡a(mn)=log⁡am+log⁡an\log_a(mn) = \log_a m + \log_a n
2. log⁡a(mn)=log⁡am−log⁡an\log_a\left(\frac{m}{n}\right) = \log_a m - \log_a n
3. log⁡a(mk)=klog⁡am\log_a(m^k) = k \log_a m
4. log⁡aa=1\log_a a = 1, log⁡a1=0\log_a 1 = 0
5. Change of base: log⁡ab=log⁡cblog⁡ca\log_a b = \frac{\log_c b}{\log_c a}

  • The natural logarithm (ln⁡x\ln x) uses base ee: ln⁡x=log⁡ex\ln x = \log_e x.

How it is examined

Heavily used on Paper 1, where the whole point is that a calculator cannot do it. Typical shape: an equation in log⁡a\log_a of two different bases, change base, solve. Answers are expected exact (ln⁡10/ln⁡2\ln 10 / \ln 2, not 3.32) unless the question says otherwise. 4 to 7 marks.

Given in the booklet

The three log laws and change of base are given. The exponent laws are not.

Key ideas
  • Laws of exponents with rational exponents.
  • Laws of logarithms: log⁡axy=log⁡ax+log⁡ay\log_a xy = \log_a x + \log_a y; log⁡axy=log⁡ax−log⁡ay\log_a \frac{x}{y} = \log_a x - \log_a y; log⁡axm=mlog⁡ax\log_a x^m = m \log_a x, for a,x,y>0a, x, y > 0.
  • Change of base of a logarithm: log⁡ax=log⁡bxlog⁡ba\log_a x = \dfrac{\log_b x}{\log_b a}, for a,b,x>0a, b, x > 0.
  • Solving exponential equations, including using logarithms.

Linking questions

  • Links to other subjects: pH, buffer calculations and finding activation energy from experimental data (chemistry).

Practice questions

63 questions · 4 easy · 44 medium · 15 hard
Showing 20 of 20

Question 1

EasyPaper 1 · no calculator2 marks

Show that log⁡ab=2log⁡ab\log_{\sqrt{a}} b = 2 \log_a b where a,b∈R+,a≠1a, b \in \mathbb{R}^+, a \neq 1.

Question 2

MediumPaper 2 · calculator5 marks

(a) In a theoretical model describing the interaction between two variables, aa and bb, their relationship is given by the equation:

logk(123(a+3b))=12(logka+logkb)log_k \left( \frac{1}{2\sqrt{3}} (a + 3b) \right) = \frac{1}{2} (log_k a + log_k b)

Given that a>0a > 0, b>0b > 0, and k>0,k≠1k > 0, k \neq 1, find aa in terms of bb.

Question 3

HardPaper 1 · no calculator5 marks

Solve the equation 9x+1−2⋅3x=19^{x+1} - 2 \cdot 3^x = 1.

Question 4

EasyPaper 1 · no calculator6 marks
(a)

(a) Find the value of log⁡464\log_4 64.

[2]
(b)

(b) Find the value of log⁡3(19)\log_3 \left(\frac{1}{9}\right).

[2]
(c)

(c) Find the value of log⁡255\log_{25} 5.

[2]

Question 5

MediumPaper 2 · calculator5 marks

Given that 2ln⁡(x+2y)=ln⁡x+ln⁡y+ln⁡82 \ln(x + 2y) = \ln x + \ln y + \ln 8, where x>0,y>0x > 0, y > 0, find the value of the ratio xy\frac{x}{y}.

Question 6

HardPaper 3 · calculator24 marks
(a)

A biologist is modelling the growth of two different bacterial colonies. The first colony, A, grows such that its population at time xx is given by PA(x)=axP_A(x) = a^x, where aa is a growth factor and x≥0x \ge 0. The second colony, B, grows linearly such that its population at time xx is PB(x)=xP_B(x) = x.

Consider the cases where the growth factor a=2a = 2 and a=10a = 10. On the same set of axes, sketch the following three graphs for x≥0x \ge 0:

y=2xy = 2^x

y=10xy = 10^x

y=xy = x

Clearly label each graph with its equation and state the coordinates of any non-zero yy-axis intercepts.

[4]
(b)

In parts (b) and (c), consider the case where the growth factor a=ea = e.

Use calculus to find the minimum value of the expression ex−xe^x - x, justifying that this value is a minimum.

[5]
(c)

Hence deduce that ex>xe^x > x for all x∈Rx \in \mathbb{R}.

[1]
(d)

There exist values of aa for which the graph of y=axy = a^x and the line y=xy = x have different numbers of intersection points. The following table gives three intervals for the value of aa.

IntervalNumber of intersection points
0<a<10 < a < 1pp
1<a<1.41 < a < 1.4qq
1.5<a<21.5 < a < 2rr

By investigating the graph of y=axy = a^x for different values of aa, write down the values of p,qp, q and rr.

[4]
(e)

In parts (e) and (f), consider a∈R+,a≠1a \in \mathbb{R}^+, a \neq 1.

For 1.4≤a≤1.51.4 \leq a \leq 1.5, a value of aa exists such that the line y=xy = x is a tangent to the graph of y=axy = a^x at a point P.

Find the exact coordinates of P and the exact value of aa.

[8]
(f)(i)

Write down the exact set of values for aa such that the graphs of y=axy = a^x and y=xy = x have

(i) two intersection points;

[1]
(f)(ii)

(ii) no intersection points.

[1]

Question 7

EasyPaper 1 · no calculator5 marks
(a)

Exponential relationships appear frequently in models of population growth and radioactive decay. It is often useful to express these relationships in logarithmic form.

(a) Write the equation 53=1255^3 = 125 in logarithmic form.

[1]
(b)

(b) Write the equation 122=14412^2 = 144 in logarithmic form.

[1]
(c)

(c) Write the equation 4−2=1164^{-2} = \frac{1}{16} in logarithmic form.

[1]
(d)

(d) Write the equation pq=rp^q = r in logarithmic form, where p>0p > 0 and p≠1p \neq 1.

[1]
(e)

(e) Write the equation ey=7e^y = 7 in logarithmic form.

[1]

Question 8

MediumPaper 1 · no calculator5 marks

Solve the equation 9x−2⋅3x+1=39^x - 2 \cdot 3^{x+1} = 3.

Question 9

HardPaper 1 · no calculator5 marks

Solve the equation log⁡2(xx)=log⁡8(27)+log⁡2(x2)\log_2(x\sqrt{x}) = \log_8(27) + \log_2\left(\frac{x}{2}\right), where x>0x > 0.

Question 10

EasyPaper 1 · no calculator10 marks
(a)

(a) Solve the equation 4log⁡2(3x)=124 \log_2(3x) = 12.

[2]
(b)

(b) Solve the equation ln⁡(5−x)=1\ln(5-x) = 1.

[2]
(c)

(c) Solve the equation 2log⁡(x3)=−42 \log(\frac{x}{3}) = -4.

[3]
(d)

(d) Solve the equation log⁡5(2x+1)+1=3\log_5(2x+1) + 1 = 3.

[3]

Question 11

MediumPaper 1 · no calculator5 marks
(a)

Consider the functions f(x)=e2xf(x) = e^{2x} and g(x)=x+cg(x) = x+c, where cc is a real constant.

(a) Write down an expression for (f∘g)(x)(f \circ g)(x).

[2]
(b)

(b) Given that (f∘g)(ln⁡3)=36(f \circ g)(\ln 3) = 36, find the value of cc.

[3]

Question 12

HardPaper 1 · no calculator14 marks
(a)

Consider the function f(x)=axf(x) = a^x where x,a∈Rx, a \in \mathbb{R} and a>1a > 1. The graph of ff contains the point (32,27)(\frac{3}{2}, 27).

(a) Show that a=9a = 9.

[2]
(b)

(b) Write down an expression for f−1(x)f^{-1}(x).

[1]
(c)

(c) Find the value of f−1(181)f^{-1}(\frac{1}{81}).

[3]
(d)(i)

Consider the arithmetic sequence log⁡98,log⁡9p,log⁡9q,log⁡927\log_9 8, \log_9 p, \log_9 q, \log_9 27, where p>1p > 1 and q>1q > 1.

(i) Show that 8,p,q8, p, q and 2727 are four consecutive terms in a geometric sequence.

[4]
(d)(ii)

Consider the arithmetic sequence log⁡98,log⁡9p,log⁡9q,log⁡927\log_9 8, \log_9 p, \log_9 q, \log_9 27, where p>1p > 1 and q>1q > 1.

(ii) Find the value of pp and the value of qq.

[4]

Question 13

MediumPaper 1 · no calculator13 marks
(a)

The functions ff and gg are defined by

f(x)=2ln⁡xf(x) = 2\ln x, where x>0x > 0

g(x)=ln⁡(k(x−2))g(x) = \ln(k(x-2) ), where x>2,k∈R+x > 2, k \in \mathbb{R}^+.

The graphs of y=f(x)y = f(x) and y=g(x)y = g(x) intersect at two distinct points.

(a) State the equation of the vertical asymptote to the graph of y=g(x)y = g(x).

[1]
(b)(i)

(b) (i) Show that, at the points of intersection, x2−kx+2k=0x^2 - kx + 2k = 0.

[3]
(b)(ii)

(b) (ii) Hence show that k2−8k>0k^2 - 8k > 0.

[2]
(b)(iii)

(b) (iii) Find the range of possible values of kk.

[2]
(c)

The graphs intersect at x=px=p and x=qx=q, where p<qp<q.

(c) In the case where k=10k=10, find the value of q−pq-p. Express your answer in the form aba\sqrt{b}, where a,b∈Z+a, b \in \mathbb{Z}^+.

[5]

Question 14

HardPaper 1 · no calculator21 marks
(a)

Let f(x)=ln⁡(1+ax)f(x) = \ln(1+ax), where ax>−1,a≠0ax > -1, a \neq 0.

The nthn^{\text{th}} derivative of f(x)f(x) is denoted by f(n)(x)f^{(n)}(x), for n∈Z+n \in \mathbb{Z}^+.

Prove by induction that f(n)(x)=(−1)n−1(n−1)!an(1+ax)−nf^{(n)}(x) = (-1)^{n-1} (n-1)! a^n (1+ax)^{-n}, for n∈Z+n \in \mathbb{Z}^+.

[8]
(b)

Hence or otherwise, find the Maclaurin series for f(x)=ln⁡(1+ax)f(x) = \ln(1+ax) up to and including the x3x^3 term.

[3]
(c)

Hence, find the series expansion of ln⁡(1+2x1−3x)\ln\left(\frac{1+2x}{1-3x}\right) up to and including the x3x^3 term.

[4]
(d)

State the restriction which must be placed on xx for the approximation in part (c) to be valid.

[2]
(e)

Use a suitable value of xx to determine an approximate value for ln⁡(2)\ln(2).

Give your answer as a rational number.

[4]

Question 15

MediumPaper 1 · no calculator6 marks
(a)

It is given that log⁡2(y)=−32\log_2(y) = -\frac{3}{2}, where y>0y > 0.

(a) Find the value of log⁡2(8y2)\log_2(8y^2).

[3]
(b)

(b) Find the value of log⁡8(y)\log_8(y).

[3]

Question 16

HardPaper 2 · calculator20 marks
(a)

The rate of change of a certain quantity RR with respect to a variable xx is given by R′(x)=1x(M−x)R'(x)=\frac{1}{x(M-x)}, x∈Rx \in \mathbb{R}, x≠0x \neq 0, x≠Mx \neq M where MM is a positive constant.

The expression for R′(x)R'(x) can be written in the form Ax+BM−x\frac{A}{x} + \frac{B}{M-x}, where A,B∈RA, B \in \mathbb{R}.

Find AA and BB in terms of MM.

[3]
(b)

Hence, find an expression for R(x)R(x).

[3]
(c)

The concentration of a certain chemical product, CC (in mol/L), in a reaction vessel at time tt (in minutes) can be modelled by the differential equation dCdt=C(L−C)8L\frac{dC}{dt} = \frac{C(L-C)}{8L}, where LL is the maximum possible concentration and C(0)=0.2C(0) = 0.2 mol/L is the initial concentration.

By solving the differential equation, show that C=0.2L(L−0.2)e−t8+0.2C = \frac{0.2 L}{(L-0.2)e^{-\frac{t}{8}}+0.2}.

[8]
(d)

At t=12t=12 minutes, the concentration of the product has reached 0.60.6 mol/L.

Find the value of LL, giving your answer correct to four significant figures.

[3]
(e)

Find the value of tt when the rate of change of the concentration is at its maximum.

[3]

Question 17

MediumPaper 1 · no calculator16 marks
(a)

Consider the arithmetic sequence c,d,e,...c, d, e, ..., where c,d,e≠0c, d, e \neq 0.

Show that c+e=2dc + e = 2d.

[2]
(b)

Consider the geometric sequence c,f,g,...c, f, g, ..., where c,f,g≠0c, f, g \neq 0.

Show that f2=cgf^2 = cg.

[2]
(c)

The first term of both sequences is cc. It is given that e=g=4e = g = 4 and that ff is a real number.

Show that d>2d > 2.

[2]
(d)(i)

Consider the case where c=16c = 16, f>0f > 0 and e=g=4e = g = 4.

(i) Write down the first four terms of the arithmetic sequence.

[2]
(d)(ii)

(ii) Write down the first four terms of the geometric sequence.

[2]
(e)(i)

A new sequence vnv_n is formed by combining the terms of the arithmetic sequence, AnA_n, and the geometric sequence, GnG_n, from part (d). The terms of vnv_n are given by vn=An−log⁡2(Gn)v_n = A_n - \log_2(G_n).

(i) Show that vnv_n is an arithmetic sequence and find its common difference.

[3]
(e)(ii)

(ii) Hence, find the value of ∑n=112vn\sum_{n=1}^{12} v_n.

[3]

Question 18

HardPaper 2 · calculator21 marks
(a)

The growth of a bacterial colony, BB, in a petri dish can be modelled by the logistic differential equation

dBdt=kB(1−BN)\frac{\text{d}B}{\text{d}t} = k B \left(1 - \frac{B}{N}\right)

where tt is the time measured in hours and k,Nk, N are positive constants.

The constant NN represents the maximum number of bacteria the petri dish can sustain indefinitely due to limited nutrients.

In the context of this bacterial growth model, interpret the meaning of dBdt\frac{\text{d}B}{\text{d}t}.

[1]
(b)

Show that d2Bdt2=k2B(1−BN)(1−2BN)\frac{\text{d}^2B}{\text{d}t^2} = k^2B\left(1-\frac{B}{N}\right)\left(1-\frac{2B}{N}\right).

[4]
(c)

Hence show that the bacterial colony will grow at its maximum rate when B=N2B = \frac{N}{2}. Justify your answer.

[5]
(d)

Hence determine the maximum value of dBdt\frac{\text{d}B}{\text{d}t} in terms of kk and NN.

[2]
(e)

Let B0B_0 be the initial number of bacteria.

By solving the logistic differential equation, show that its solution can be expressed in the form

kt=ln⁡(B(N−B0)B0(N−B))kt = \ln\left(\frac{B(N-B_0)}{B_0(N-B)}\right).

[7]
(f)

After 5 hours, the number of bacteria is 2B02B_0. It is known that N=3B0N = 3B_0.

Find the value of kk for this bacterial growth model.

[2]

Question 19

MediumPaper 1 · no calculator5 marks

Solve the equation 2e2x−5ex−3=02e^{2x} - 5e^x - 3 = 0.

Question 20

HardPaper 1 · no calculator22 marks
(a)

Differentiate each of the following expressions with respect to xx:

10ex−4ln⁡x+210e^x - 4\ln x + 2

[2]
(b)

e−5xe^{-5x}

[2]
(c)

x2exx^2 e^x

[3]
(d)

ln⁡(4x3−2x)\ln(4x^3 - 2x)

[3]
(e)

esin⁡(x)e^{\sin(x)}

[2]
(f)

ln⁡xx3\frac{\ln x}{x^3}

[3]
(g)

ln⁡(1x2+1)\ln(\frac{1}{x^2+1})

[3]
(h)

excos⁡(x)e^{x\cos(x)}

[4]

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What does Logarithms cover in IB Maths AA?

A logarithm is the inverse of exponentiation. If a^x = b, then log_a b = x. Key rules:. 1. log_a(mn) = log_a m + log_a n.

Is Logarithms SL or HL?

Both. SL and HL students study Logarithms to the same depth.

How do I revise Logarithms for IB Maths AA?

Start from the core idea: a logarithm is the inverse of exponentiation. If a^x = b, then log_a b = x. In the exam: heavily used on Paper 1, where the whole point is that a calculator cannot do it. Typical shape: an equation in log_a of two different bases, change base, solve. Then practise exam-style questions, easiest first, writing out every step of your working before you check it.

How does FourtyFive help me practise Logarithms?

FourtyFive has 63 Logarithms questions. Every answer you write is marked mark by mark, IB-style, and you see where each mark was won or lost. Every part has a hint, the AI tutor helps you through the step you are stuck on, and your Study Profile picks what to practise next.

Is FourtyFive free for Logarithms practice?

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