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Topic 3.06 · SL and HL

Circles (radians, arc length, sector area): notes and practice questions

Summary
  • Radians: θ \theta (in radians) = arc lengthradius\frac{\text{arc length}}{\text{radius}}.
  • Arc Length: l=rθ l = r\theta .
  • Sector Area: A=12r2θ A = \frac{1}{2}r^2\theta .

Where θ \theta is in radians.

How it is examined

Segment area (sector minus triangle) is the standard composite question and it uses 12r2θ−12r2sin⁡θ\frac{1}{2}r^2\theta - \frac{1}{2}r^2\sin\theta, neither half of which is given as a single formula. Both papers. A calculator left in degree mode ruins the whole question, which is why radians being the default matters. 5 to 7 marks.

Given in the booklet

l=rθl = r\theta and A=12r2θA = \frac{1}{2}r^2\theta, both in radians. The degree versions are not given in AA (they are an AI formula).

Key ideas

The circle: radian measure of angles; length of an arc; area of a sector.

Linking questions

  • Links to other subjects: diffraction patterns and circular motion (physics).
  • International-mindedness: why are there 360 degrees in a complete turn?

Practice questions

10 questions · 2 easy · 8 medium
Showing 10 of 10

Question 1

EasyPaper 2 · calculator6 marks
(a)

A garden sprinkler rotates through an angle of 2.5 radians, watering a sector of a circular lawn. The maximum reach of the water from the sprinkler is 15 metres.

(a) Calculate the length of the arc along the edge of the watered lawn.

[2]
(b)

(b) Determine the total length of the boundary of the watered sector.

[2]
(c)

(c) Find the area of the garden watered by the sprinkler.

[2]

Question 2

MediumPaper 1 · no calculator6 marks
(a)

A lighthouse, L, is situated on a cliff. It emits a beam of light that scans a sector of the sea. The diagram below is a top-down view of the area scanned by the light.

Diagram of a sector LMN representing the area scanned by a lighthouse beam. L is the vertex, and M and N are points on the arc.

The points M and N represent the furthest points on the edge of the scanned area. The angle of the sector, MÊN, is 1.5 radians.

The perimeter of the sector of the sea scanned by the light is 70 km.

(a) Find the maximum distance the light beam reaches from the lighthouse.

[2]
(b)

(b) Find the length of the arc MN.

[2]
(c)

(c) Find the area of the sea scanned by the light beam.

[2]

Question 3

EasyPaper 1 · no calculator8 marks
(a)

Rewrite each of the following angles from radians to degrees.

(a) π4\frac{\pi}{4}

[1]
(b)

(b) 2π3\frac{2\pi}{3}

[1]
(c)

(c) 5π6\frac{5\pi}{6}

[1]
(d)

(d) 7π4\frac{7\pi}{4}

[1]
(e)

(e) −π9-\frac{\pi}{9}

[1]
(f)

(f) −4π3-\frac{4\pi}{3}

[1]
(g)

(g) −3π2-\frac{3\pi}{2}

[1]
(h)

(h) 7π5\frac{7\pi}{5}

[1]

Question 4

MediumPaper 1 · no calculator8 marks
(a)

A company is designing a new logo in the shape of a sector of a circle with centre O and radius rr cm. The angle of the sector is θ\theta radians.

Diagram of a sector OAB with radius r and angle theta

The perimeter of the logo is 24 cm and its area is 32 cm2^2.

(a) Show that r2−12r+32=0r^2 - 12r + 32 = 0.

[4]
(b)

(b) Find the two possible values for rr and the corresponding values for θ\theta.

[4]

Question 5

MediumPaper 1 · no calculator6 marks
(a)

The following diagram shows a sector of a circle with centre O and radius r. The points A and B are on the circumference.

Sector of a circle with center O, radius r, and points A and B on circumference, forming a shaded sector

The angle AO^B=π3\text{A}\hat{\text{O}}\text{B} = \frac{\pi}{3} radians. The area of the shaded sector is 6π6\pi.

(a) Find the value of r.

[3]
(b)

(b) Hence, find the exact perimeter of the non-shaded region.

[3]

Question 6

MediumPaper 1 · no calculator5 marks
(a)

A decorative paper fan is made in the shape of a sector of a circle with centre O and radius rr. The angle of the sector is θ\theta radians.

Diagram of a sector of a circle with angle theta and radius r

The arc length of the fan is 24 cm and its area is 180 cm².

(a) Find the value of rr.

[3]
(b)

(b) Find the value of θ\theta.

[2]

Question 7

MediumPaper 2 · calculator6 marks
(a)

A circular pizza has a radius of RR cm. A chef makes a straight cut from point A on the crust to point B on the crust, such that the angle subtended at the centre O, AO^B\text{A}\hat{\text{O}}\text{B}, is θ\theta radians, where 0<θ<π0 < \theta < \pi. This cut creates a circular segment of pizza (the region bounded by the chord AB and the arc AB).

Another cut is made from the centre O to a point C on the crust, such that A, O, and C are collinear (i.e., AC is a diameter). This creates a triangular slice OBC\text{OBC}.

Given that the area of the circular segment (bounded by chord AB and arc AB) is equal to the area of the triangular slice OBC\text{OBC}, show that θ=2sin⁡θ\theta = 2 \sin \theta.

[5]
(b)

Hence determine the value of θ\theta.

[1]

Question 8

MediumPaper 2 · calculator6 marks
(a)

A craftsman is designing a decorative metal panel. A section of the design involves a circular arc within a larger piece. The arc is part of a circle with centre O and radius R=3R = 3 cm. Two points, P and Q, lie on the circle such that the angle POQ is θ\theta radians, where 0<θ<π0 < \theta < \pi.

Find the area of the circular segment defined by the arc PQ and the chord PQ, in terms of θ\theta.

[3]
(b)

The craftsman cuts this segment from a rectangular metal sheet measuring 66 cm by 55 cm. The remaining area of the rectangular sheet is 21.321.3 cm2^2.

Find the value of θ\theta.

[3]

Question 9

MediumPaper 2 · calculator6 marks
(a)

A rotating radar dish has a radius of 1515 m. The radar beam sweeps through an angle of 1.21.2 radians.

(a) Calculate the area of the sector swept by the radar beam.

[2]
(b)

(b) An obstruction blocks the signal in a triangular region within the sector. This triangular region has vertices at the centre of the dish and the two points on the edge of the dish that define the sweep angle. Calculate the area of this triangular region.

[2]
(c)

(c) Hence, determine the effective area covered by the radar.

[2]

Question 10

MediumPaper 2 · calculator6 marks

(a) The vertices of a regular hexagon are the solutions to the equation z6=64iz^6 = 64i. Find the area of this hexagon, giving your answer correct to 3 significant figures.

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What does Circles (radians, arc length, sector area) cover in IB Maths AA?

Radians: θ (in radians) = fracarc lengthradius. Arc Length: l = rθ. Sector Area: A = (1)/(2)r^2θ.

Is Circles (radians, arc length, sector area) SL or HL?

Both. SL and HL students study Circles (radians, arc length, sector area) to the same depth.

How do I revise Circles (radians, arc length, sector area) for IB Maths AA?

Start from the core idea: radians: θ (in radians) = fracarc lengthradius. In the exam: segment area (sector minus triangle) is the standard composite question and it uses (1)/(2)r^2θ - (1)/(2)r^2sinθ, neither half of which is given as a single formula. Both papers. Then practise exam-style questions, easiest first, writing out every step of your working before you check it.

How does FourtyFive help me practise Circles (radians, arc length, sector area)?

FourtyFive has 10 Circles (radians, arc length, sector area) questions. Every answer you write is marked mark by mark, IB-style, and you see where each mark was won or lost. Every part has a hint, the AI tutor helps you through the step you are stuck on, and your Study Profile picks what to practise next.

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