Venn diagrams, tree diagrams, probability tables (+ notation & combined & mutually exclusive events): notes and practice questions
- Venn diagrams represent sets and probabilities visually, showing intersections (), unions (), and complements ().
- Tree diagrams display sequential events and their probabilities.
- Probability tables organize probabilities for joint events.
- Key notations:
- : Probability of event .
- : Probability of and .
- .
- Events are mutually exclusive if and independent if .
How it is examined
With or without replacement changes the second branch of a tree and is the standard discriminator. The guidance that problems can be solved without explicit formulae means a correct tree diagram plus a correct answer is worth full marks, so a mark scheme should not demand the formula. Paper 2, 5 to 8 marks.
All four formulas are given.
- Use of Venn diagrams, tree diagrams, sample space diagrams and tables of outcomes to calculate probabilities.
- Combined events: .
- Mutually exclusive events: .
- Conditional probability: .
Linking questions
- Aim 8: use of probability in casinos.
Practice questions
31 questions · 4 easy · 24 medium · 3 hardQuestion 1
EasyPaper 1 · no calculator4 marksLet C be the event that a randomly chosen household in a town has a cat, and D be the event that the household has a dog. It is known that , and .
(a) Find the probability that a randomly chosen household has a cat or a dog.
(b) Find the probability that a randomly chosen household has neither a cat nor a dog.
Recall the addition rule for probability for two events: .
The event 'neither a cat nor a dog' is the complement of the event 'a cat or a dog'. This can be represented as . Consider using De Morgan's laws.
Question 2
MediumPaper 1 · no calculator5 marksA student, Chloe, travels to school by bus. She can take one of two routes, Route X or Route Y. She is equally likely to choose either route on any given day.
The probability that she arrives on time when taking Route X is .
The probability that she arrives on time when taking Route Y is .
(a) Find the probability that Chloe arrives on time for school on a randomly chosen day.
Let be the event that Chloe chooses Route X and let be the event that she arrives on time.
(b) Determine whether events and are independent.
Consider the two separate scenarios: choosing Route X and being on time, and choosing Route Y and being on time. The total probability is the sum of the probabilities of these two mutually exclusive events. Remember to account for the probability of choosing each route.
Two events A and B are independent if . Calculate both sides of this equation for the events X and T and compare them. Alternatively, you can check if .
Question 3
HardPaper 2 · calculator16 marks(a) An electronics factory produces two types of resistors: Type A and Type B.
The resistance, (in Ohms), of Type A resistors is normally distributed with a mean of 120 Ohms and a standard deviation of 5 Ohms.
Find the probability that a randomly selected Type A resistor has a resistance less than 115 Ohms.
(b) In a random selection of 10 Type A resistors, find the probability that exactly 3 have a resistance less than 115 Ohms.
(c) The resistance, (in Ohms), of Type B resistors is normally distributed with a mean of 135 Ohms and a standard deviation of 7 Ohms.
Each day, 70% of the resistors produced are Type A, and 30% are Type B.
On a particular day, a resistor is randomly selected from all those produced at the factory.
Let represent 'Type A resistor' and represent 'Type B resistor'.
(i) Find the probability that the randomly selected resistor has a resistance less than 115 Ohms.
(ii) Given that a randomly selected resistor has a resistance less than 115 Ohms, find the probability that it is a Type A resistor.
(d) The machine that makes the Type A resistors is adjusted so that the mean resistance of the Type A resistors remains the same, but their standard deviation changes to Ohms. The machine that makes the Type B resistors is not adjusted. The probability that the resistance of a randomly selected resistor from these machines is now less than 115 Ohms is 0.18.
Find the value of .
Use the normal cumulative distribution function (CDF) on your GDC. Remember to input the lower bound, upper bound, mean, and standard deviation.
This is a binomial probability problem. Identify the number of trials, the number of successes, and the probability of success from part (a).
You need to consider both types of resistors. Calculate the probability for Type B resistors first, then use the law of total probability, taking into account the proportions of each type.
This is a conditional probability problem, often solved using Bayes' theorem. You need the probability of a Type A resistor having low resistance and the overall probability of a low resistance resistor.
Set up an equation for the new total probability, similar to part (c.i). You'll need to solve for the new probability , then use the inverse normal function to find the z-score, and finally calculate the new standard deviation .
Question 4
EasyPaper 1 · no calculator4 marksIn a survey of a group of high school students, it was found that the probability that a student participates in the school's music program is 0.5, and the probability that a student plays on a school sports team is 0.6. The probability that a student participates in both is 0.2.
Let M be the event that a student participates in the music program and S be the event that a student plays on a sports team.
(a) Find the probability that a randomly selected student participates in the music program or plays on a sports team.
(b) Hence, find the probability that a randomly selected student participates in neither the music program nor a sports team.
Recall the addition rule for probability: . You are looking for .
The event 'neither M nor S' is the complement of the event 'M or S'. Use your answer from part (a).
Question 5
MediumPaper 1 · no calculator5 marksAt a high school, students can study Chemistry and Physics. Let C be the event that a randomly selected student studies Chemistry and P be the event that they study Physics.
It is known that , and .
Find the probability that a randomly selected student studies Physics, .
You are given three pieces of information and need to find one unknown probability. Write down the standard probability formulas that connect these terms: the formula for the union of two events and the formula for conditional probability. You will end up with a system of two equations that you can solve.
Question 6
HardPaper 2 · calculator18 marksIn a large university, 200 students were surveyed. Of those, 120 were undergraduates (U) and the rest postgraduates (P).
Each student in the survey was asked whether they preferred quiet zones (Q) or collaborative areas (C) for studying. It was found that 75 of the undergraduates preferred quiet zones. The total number of students who preferred collaborative areas was 100. This information is shown in the following table.
| Quiet Zones (Q) | Collaborative Areas (C) | Total | |
|---|---|---|---|
| Undergraduates (U) | 75 | p | 120 |
| Postgraduates (P) | x | 55 | 80 |
| Total | q | 100 | 200 |
Find the value of
;
.
Three students are chosen at random from those surveyed. Find the probability that all three are postgraduates.
Given that , find the value of .
A student is chosen at random from those surveyed. Write down the probability that they are a postgraduate who prefers quiet zones.
Determine if the events P (Postgraduate) and Q (prefers Quiet Zones) are independent. Justify your answer.
It can be assumed that the survey results are representative of the university population. Ten students from the university are chosen at random. Find the probability that at least five of them prefer quiet zones.
Use the row total for undergraduates and the number of undergraduates preferring quiet zones to find .
Use the grand total and the total number of students preferring collaborative areas to find .
Remember that once a student is chosen, they are not replaced. This affects the total number of students and postgraduates for subsequent selections.
Recall the formula for conditional probability: . In this case, .
This is a direct probability from the completed table. Look for the cell representing postgraduates who prefer quiet zones and divide by the total number of students.
Two events A and B are independent if or if . Calculate these probabilities using your table values.
This scenario involves a fixed number of trials (10 students) and a probability of success (preferring quiet zones) for each trial. Consider which probability distribution is appropriate.
Question 7
EasyPaper 1 · no calculator4 marksIn a survey, a group of students were asked if they play football (F) or basketball (B). The probability that a student plays football is 0.6, and the probability that a student plays basketball is 0.7. The probability that a student plays at least one of these sports is 0.9.
(a) Find the probability that a student plays both football and basketball.
(b) Find the probability that a student plays neither football nor basketball.
Recall the addition rule for probabilities: . You are given three of these values and need to find the fourth.
The event 'plays neither sport' is the complement of the event 'plays at least one sport'. How do you calculate the probability of a complementary event?
Question 8
MediumPaper 1 · no calculator5 marksTwo archers, Clara and David, are competing. To decide who shoots an arrow, a fair six-sided die is rolled. If the die shows a 1, Clara is chosen. If the die shows any other number, David is chosen.
The probability that Clara hits the target is . The probability that David hits the target is .
(a) Find the probability that the target is hit.
(b) Let be the event that Clara is chosen and let be the event that the target is hit. Determine, with a reason, whether events and are independent.
First, determine the probability of choosing each archer based on the die roll. Then, use a tree diagram or the law of total probability to find the overall probability of hitting the target.
To check for independence between two events A and B, you can verify if or if .
Question 9
HardPaper 2 · calculator17 marks(a) A batch of electronic components contains defective components and functional components. Components are selected randomly, one by one, without replacement.
(i) Find, in terms of , the probability that the first component selected is defective.
(ii) Given that , , and , find the probability that the first two components selected are defective.
(b) Show that the probability that the first two components selected are functional is 0.35.
(c) Find the probability that the first three components selected are all functional.
(d) Find the probability that at least one of the first three components selected is defective.
(e) A technician earns 10 points if the first defective component is found on the third test, and 50 points if the first defective component is found on the fourth test. The technician tests such batches. Find the least value of such that the technician's expected total score is greater than 100.
The probability of an event is the number of favorable outcomes divided by the total number of possible outcomes.
Consider the probability of the first event, then the probability of the second event given the first, and multiply them.
Similar to part (a.ii), but for functional components. Simplify the fraction to show the decimal.
Extend the logic from part (b) for three consecutive functional components.
Consider the complementary event: what is the opposite of 'at least one defective'?
First, calculate the probability of finding the first defective component on the third test. Then, calculate the probability of finding the first defective component on the fourth test. Use these probabilities to find the expected points per batch, and then set up an inequality for the total expected score.
Question 10
EasyPaper 1 · no calculator4 marksA letter is chosen at random from the word 'CONSTITUTION'. Find the probability that it is a vowel or a letter that appears more than once.
First, count the total number of letters in the word. This will be the denominator of your probability. Then, identify the letters that are either vowels or appear more than once. Be careful not to double-count any letters when finding the total number of favourable outcomes. The formula for the union of two events, , might be helpful.
Question 11
MediumPaper 1 · no calculator5 marksEvents and are such that , and .
Find .
You need to use two key probability formulas. One relates to the union of two events, , and the other relates to conditional probability, . Write down these two formulas using the given information. You will end up with a system of two equations with two unknowns, which you can then solve.
Question 12
MediumPaper 1 · no calculator6 marksConsider events and such that , and .
(a) Find .
(b) Determine if events and are independent. Justify your answer.
First, find the probability of event C occurring using the given probability of its complement, C'. Then, use the formula for conditional probability, , to find the probability of the intersection.
To determine if two events are independent, you need to check if or if . You will first need to find using the formula for the union of two events: .
Question 13
MediumPaper 2 · calculator8 marksAt a tech company, employees can participate in various initiatives. 70% of employees attend a professional development workshop (), and 20% of employees work on a special innovation project (). 20% of employees do neither activity.
An employee is selected at random.
Find the probability that the employee attends a professional development workshop and works on a special innovation project.
Find the probability that the employee works on a special innovation project, but does not attend a professional development workshop.
At the company, 40% of the employees are in the Marketing department. Of those in the Marketing department, 30% work on a special innovation project.
An employee is selected at random. Let be the event "the employee is in the Marketing department" and let be the event "the employee works on a special innovation project".
Find .
Determine if the events and are independent. Justify your answer.
Consider using the formula for the union of two events or a Venn diagram. Remember that .
Think about how to express 'event B but not event A' in terms of probabilities you already know or can calculate.
Recall the definition of conditional probability: . Rearrange this to find .
For two events and to be independent, . Alternatively, check if or .
Question 14
MediumPaper 2 · calculator8 marksAt a tech company, 60% of the employees use Python for their projects and 30% use Java. 20% of the employees use neither Python nor Java.
An employee is selected at random.
Find the probability that the employee uses both Python and Java.
Find the probability that the employee uses Java, but does not use Python.
At the company, 40% of the employees work remotely, and 35% of the remote employees use Java.
An employee is selected at random. Let R be the event "the employee works remotely" and let J be the event "the employee uses Java".
Find .
Determine if the events R and J are independent. Justify your answer.
Consider using a Venn diagram or the formula for the union of two events: . Remember that .
Think about the region in a Venn diagram that represents 'Java only' or use the formula .
Recall the definition of conditional probability: . This can be rearranged to find the probability of the intersection.
Two events A and B are independent if or if (and ). Use the probabilities calculated or given in previous parts.
Question 15
MediumPaper 2 · calculator6 marks(a) In a manufacturing process, the event that component A passes its final inspection is denoted by , and the event that component B passes its final inspection is denoted by . The events and are independent.
It is known that the probability of component passing its inspection is twice the probability of component passing its inspection, i.e., .
Given that the probability that at least one of the components passes its inspection is , find .
Recall the formula for the probability of the union of two independent events. Let and express all probabilities in terms of . This will lead to a quadratic equation.
Question 16
MediumPaper 2 · calculator20 marks(a) A fruit vendor has a basket containing green apples and red apples. Two apples are selected at random from the basket without replacement.
Let P(GG) represent the probability of selecting two green apples from the basket without replacement.
Given that P(GG) = , show that .
(b) By solving the equation in part (a) for , show that .
(c) Find two pairs of values for and that satisfy the condition P(GG) = .
(d) Now consider a different basket that initially contains red apples and green apples. Three apples are selected at random from the basket without replacement.
Let P(GGG) represent the probability of selecting three green apples from the basket without replacement.
Find an expression for P(GGG) in terms of .
(e) A green apple is added to the basket so that it now contains red apples and green apples.
The probability of selecting three green apples from this modified basket is now twice the probability expressed in part (d).
Find the initial number of green apples in the basket.
Start by writing down the probability of selecting two green apples in terms of and . Remember that the selections are without replacement, so the total number of apples and the number of green apples decrease after the first pick.
Treat the equation from part (a) as a quadratic equation in terms of . Use the quadratic formula, , where is and the coefficients involve . Remember that the number of apples must be positive.
For to be an integer, the expression under the square root, , must be a perfect square. Test small integer values for to find when is a perfect square.
Similar to part (a), but now you are selecting three apples. The number of green apples and the total number of apples decrease with each successive pick.
First, write down the new probability of selecting three green apples with green apples. Then, set up an equation where this new probability is twice the expression from part (d). Simplify the equation by cancelling common terms before solving for .
Question 17
MediumPaper 1 · no calculator8 marksAt a local café, the probability that a randomly chosen customer buys a coffee is . The probability that they buy a pastry is . The probability that they buy both a coffee and a pastry is .
(a) State, with a reason, whether the events “buys a coffee” and “buys a pastry” are independent.
(b) Find the probability that a randomly chosen customer buys a coffee or a pastry or both.
(c) Find the probability that a randomly chosen customer buys exactly one of these items.
(d) Find the probability that a randomly chosen customer buys a pastry, given that they have bought a coffee.
Recall the definition of independent events. Two events A and B are independent if . Check if this condition holds for the given probabilities.
You are looking for the probability of the union of two events. Use the addition rule for probability: .
The event 'exactly one' means 'coffee but not pastry' OR 'pastry but not coffee'. You can calculate this by finding .
This is a conditional probability problem. Use the formula .
Question 18
MediumPaper 1 · no calculator9 marksTwo fair spinners are spun. Spinner A has four equal sectors numbered 1, 2, 3, 4. Spinner B has five equal sectors numbered 1, 2, 3, 4, 5. The number on which each spinner lands is recorded.
(a) Find the probability that both spinners land on the same number.
(b) Find the probability that the sum of the two numbers is 6.
(c) Find the probability that at least one of the spinners lands on a 3.
(d) Find the probability that at least one of the spinners lands on a 4, given that the sum of the numbers is 6.
What are the possible numbers that can be the same on both spinners? Calculate the probability for each case and add them up, or count the number of successful outcomes and divide by the total number of possible outcomes.
List all the pairs of numbers, one from each spinner, that add up to 6. Then calculate the probability.
It's often easier to calculate the probability of the complementary event, which is that NEITHER spinner lands on a 3. Then subtract this probability from 1.
Use the conditional probability formula . Let X be 'at least one spinner is 4' and Y be 'the sum is 6'. Alternatively, consider the reduced sample space of outcomes where the sum is 6.
Question 19
MediumPaper 2 · calculator12 marksA bag contains blue marbles and yellow marbles. A marble is drawn at random from the bag and not replaced. A second marble is then drawn at random.
(a) (i) Find the probability that both marbles drawn are blue.
(ii) Find the probability that the two marbles drawn are of different colours.
A marble is now drawn at random from the bag, its colour is noted, and it is then replaced in the bag. A second marble is then drawn at random.
(b) (i) Find the probability that both marbles drawn are blue.
(ii) Find the probability that the two marbles drawn are of different colours.
Consider the probability of drawing the first blue marble, and then the probability of drawing a second blue marble given the first was blue and not replaced.
There are two possible scenarios for drawing marbles of different colours: blue then yellow, or yellow then blue. Calculate the probability for each scenario and add them together.
Since the first marble is replaced, the probability of drawing a blue marble remains the same for both draws.
Similar to part (a.ii), consider the two scenarios (blue then yellow, or yellow then blue) but remember that the probabilities for the second draw are not affected by the first draw due to replacement.
Question 20
MediumPaper 1 · no calculator4 marksIn a sports club with members, play tennis, play squash and play neither. If a member is selected at random, find the probability that this member plays both tennis and squash.
Start by finding the number of members who play at least one of the two sports. You can use a Venn diagram or the formula to find the number of members who play both sports.
No question on this page matches those filters. Try another difficulty or paper.
11 more Venn diagrams, tree diagrams, probability tables (+ notation & combined & mutually exclusive events) questions in the app
Every answer is marked mark by mark, IB-style, and the AI tutor helps when you are stuck.
Where marks are lost
- Using your own wrong value after failing a "show that".