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Topic 4.06 · SL and HL

Venn diagrams, tree diagrams, probability tables (+ notation & combined & mutually exclusive events): notes and practice questions

Summary
  • Venn diagrams represent sets and probabilities visually, showing intersections (A∩BA \cap B), unions (A∪BA \cup B), and complements (A′A').
  • Tree diagrams display sequential events and their probabilities.
  • Probability tables organize probabilities for joint events.
  • Key notations:
  • P(A)P(A): Probability of event AA.
  • P(A∩B)P(A \cap B): Probability of AA and BB.
  • P(A∪B)=P(A)+P(B)−P(A∩B)P(A \cup B) = P(A) + P(B) - P(A \cap B).
  • Events are mutually exclusive if P(A∩B)=0P(A \cap B) = 0 and independent if P(A∩B)=P(A)P(B)P(A \cap B) = P(A)P(B).

How it is examined

With or without replacement changes the second branch of a tree and is the standard discriminator. The guidance that problems can be solved without explicit formulae means a correct tree diagram plus a correct answer is worth full marks, so a mark scheme should not demand the formula. Paper 2, 5 to 8 marks.

Given in the booklet

All four formulas are given.

Key ideas
  • Use of Venn diagrams, tree diagrams, sample space diagrams and tables of outcomes to calculate probabilities.
  • Combined events: P(A∪B)=P(A)+P(B)−P(A∩B)\mathrm{P}(A \cup B) = \mathrm{P}(A) + \mathrm{P}(B) - \mathrm{P}(A \cap B).
  • Mutually exclusive events: P(A∩B)=0\mathrm{P}(A \cap B) = 0.
  • Conditional probability: P(A∣B)=P(A∩B)P(B)\mathrm{P}(A \mid B) = \dfrac{\mathrm{P}(A \cap B)}{\mathrm{P}(B)}.

Linking questions

  • Aim 8: use of probability in casinos.

Practice questions

31 questions · 4 easy · 24 medium · 3 hard
Showing 20 of 20

Question 1

EasyPaper 1 · no calculator4 marks
(a)

Let C be the event that a randomly chosen household in a town has a cat, and D be the event that the household has a dog. It is known that P(C)=0.4P(C) = 0.4, P(D)=0.5P(D) = 0.5 and P(C∩D)=0.15P(C \cap D) = 0.15.

(a) Find the probability that a randomly chosen household has a cat or a dog.

[2]
(b)

(b) Find the probability that a randomly chosen household has neither a cat nor a dog.

[2]

Question 2

MediumPaper 1 · no calculator5 marks
(a)

A student, Chloe, travels to school by bus. She can take one of two routes, Route X or Route Y. She is equally likely to choose either route on any given day.

The probability that she arrives on time when taking Route X is 34\frac{3}{4}.

The probability that she arrives on time when taking Route Y is 25\frac{2}{5}.

(a) Find the probability that Chloe arrives on time for school on a randomly chosen day.

[3]
(b)

Let XX be the event that Chloe chooses Route X and let TT be the event that she arrives on time.

(b) Determine whether events XX and TT are independent.

[2]

Question 3

HardPaper 2 · calculator16 marks
(a)

(a) An electronics factory produces two types of resistors: Type A and Type B.

The resistance, RAR_A (in Ohms), of Type A resistors is normally distributed with a mean of 120 Ohms and a standard deviation of 5 Ohms.

Find the probability that a randomly selected Type A resistor has a resistance less than 115 Ohms.

[2]
(b)

(b) In a random selection of 10 Type A resistors, find the probability that exactly 3 have a resistance less than 115 Ohms.

[2]
(c)(i)

(c) The resistance, RBR_B (in Ohms), of Type B resistors is normally distributed with a mean of 135 Ohms and a standard deviation of 7 Ohms.

Each day, 70% of the resistors produced are Type A, and 30% are Type B.

On a particular day, a resistor is randomly selected from all those produced at the factory.

Let AA represent 'Type A resistor' and BB represent 'Type B resistor'.

(i) Find the probability that the randomly selected resistor has a resistance less than 115 Ohms.

[4]
(c)(ii)

(ii) Given that a randomly selected resistor has a resistance less than 115 Ohms, find the probability that it is a Type A resistor.

[3]
(d)

(d) The machine that makes the Type A resistors is adjusted so that the mean resistance of the Type A resistors remains the same, but their standard deviation changes to σ\sigma Ohms. The machine that makes the Type B resistors is not adjusted. The probability that the resistance of a randomly selected resistor from these machines is now less than 115 Ohms is 0.18.

Find the value of σ\sigma.

[5]

Question 4

EasyPaper 1 · no calculator4 marks
(a)

In a survey of a group of high school students, it was found that the probability that a student participates in the school's music program is 0.5, and the probability that a student plays on a school sports team is 0.6. The probability that a student participates in both is 0.2.

Let M be the event that a student participates in the music program and S be the event that a student plays on a sports team.

(a) Find the probability that a randomly selected student participates in the music program or plays on a sports team.

[2]
(b)

(b) Hence, find the probability that a randomly selected student participates in neither the music program nor a sports team.

[2]

Question 5

MediumPaper 1 · no calculator5 marks

At a high school, students can study Chemistry and Physics. Let C be the event that a randomly selected student studies Chemistry and P be the event that they study Physics.

It is known that P(C)=0.5P(C) = 0.5, P(C∣P)=0.6P(C|P) = 0.6 and P(C∪P)=0.8P(C \cup P) = 0.8.

Find the probability that a randomly selected student studies Physics, P(P)P(P).

Question 6

HardPaper 2 · calculator18 marks
(a)(i)

In a large university, 200 students were surveyed. Of those, 120 were undergraduates (U) and the rest postgraduates (P).

Each student in the survey was asked whether they preferred quiet zones (Q) or collaborative areas (C) for studying. It was found that 75 of the undergraduates preferred quiet zones. The total number of students who preferred collaborative areas was 100. This information is shown in the following table.

Quiet Zones (Q)Collaborative Areas (C)Total
Undergraduates (U)75p120
Postgraduates (P)x5580
Totalq100200

Find the value of

pp;

[1]
(a)(ii)

qq.

[2]
(b)

Three students are chosen at random from those surveyed. Find the probability that all three are postgraduates.

[4]
(c)(i)

Given that P(P∣Q)=14P(P|Q) = \frac{1}{4}, find the value of xx.

[3]
(c)(ii)

A student is chosen at random from those surveyed. Write down the probability that they are a postgraduate who prefers quiet zones.

[2]
(d)

Determine if the events P (Postgraduate) and Q (prefers Quiet Zones) are independent. Justify your answer.

[3]
(e)

It can be assumed that the survey results are representative of the university population. Ten students from the university are chosen at random. Find the probability that at least five of them prefer quiet zones.

[4]

Question 7

EasyPaper 1 · no calculator4 marks
(a)

In a survey, a group of students were asked if they play football (F) or basketball (B). The probability that a student plays football is 0.6, and the probability that a student plays basketball is 0.7. The probability that a student plays at least one of these sports is 0.9.

(a) Find the probability that a student plays both football and basketball.

[2]
(b)

(b) Find the probability that a student plays neither football nor basketball.

[2]

Question 8

MediumPaper 1 · no calculator5 marks
(a)

Two archers, Clara and David, are competing. To decide who shoots an arrow, a fair six-sided die is rolled. If the die shows a 1, Clara is chosen. If the die shows any other number, David is chosen.

The probability that Clara hits the target is 45\frac{4}{5}. The probability that David hits the target is 23\frac{2}{3}.

(a) Find the probability that the target is hit.

[3]
(b)

(b) Let CC be the event that Clara is chosen and let HH be the event that the target is hit. Determine, with a reason, whether events CC and HH are independent.

[2]

Question 9

HardPaper 2 · calculator17 marks
(a)(i)

(a) A batch of NN electronic components contains DD defective components and FF functional components. Components are selected randomly, one by one, without replacement.

(i) Find, in terms of NN, the probability that the first component selected is defective.

[2]
(a)(ii)

(ii) Given that N=25N = 25, D=10D = 10, and F=15F = 15, find the probability that the first two components selected are defective.

[3]
(b)

(b) Show that the probability that the first two components selected are functional is 0.35.

[2]
(c)

(c) Find the probability that the first three components selected are all functional.

[2]
(d)

(d) Find the probability that at least one of the first three components selected is defective.

[2]
(e)

(e) A technician earns 10 points if the first defective component is found on the third test, and 50 points if the first defective component is found on the fourth test. The technician tests kk such batches. Find the least value of kk such that the technician's expected total score is greater than 100.

[6]

Question 10

EasyPaper 1 · no calculator4 marks

A letter is chosen at random from the word 'CONSTITUTION'. Find the probability that it is a vowel or a letter that appears more than once.

Question 11

MediumPaper 1 · no calculator5 marks

Events XX and YY are such that P(X)=0.3P(X) = 0.3, P(X∣Y)=0.2P(X|Y) = 0.2 and P(X∪Y)=0.9P(X \cup Y) = 0.9.

Find P(Y)P(Y).

Question 12

MediumPaper 1 · no calculator6 marks
(a)

Consider events CC and DD such that P(C′)=23P(C') = \frac{2}{3}, P(C∪D)=23P(C \cup D) = \frac{2}{3} and P(D∣C)=12P(D|C) = \frac{1}{2}.

(a) Find P(C∩D)P(C \cap D).

[3]
(b)

(b) Determine if events CC and DD are independent. Justify your answer.

[3]

Question 13

MediumPaper 2 · calculator8 marks
(a)

At a tech company, employees can participate in various initiatives. 70% of employees attend a professional development workshop (WW), and 20% of employees work on a special innovation project (PP). 20% of employees do neither activity.

An employee is selected at random.

Find the probability that the employee attends a professional development workshop and works on a special innovation project.

[2]
(b)

Find the probability that the employee works on a special innovation project, but does not attend a professional development workshop.

[2]
(c)

At the company, 40% of the employees are in the Marketing department. Of those in the Marketing department, 30% work on a special innovation project.

An employee is selected at random. Let MM be the event "the employee is in the Marketing department" and let PP be the event "the employee works on a special innovation project".

Find P(M∩P)P(M \cap P).

[2]
(d)

Determine if the events MM and PP are independent. Justify your answer.

[2]

Question 14

MediumPaper 2 · calculator8 marks
(a)

At a tech company, 60% of the employees use Python for their projects and 30% use Java. 20% of the employees use neither Python nor Java.

An employee is selected at random.

Find the probability that the employee uses both Python and Java.

[2]
(b)

Find the probability that the employee uses Java, but does not use Python.

[2]
(c)

At the company, 40% of the employees work remotely, and 35% of the remote employees use Java.

An employee is selected at random. Let R be the event "the employee works remotely" and let J be the event "the employee uses Java".

Find P(R∩J)P(R \cap J).

[2]
(d)

Determine if the events R and J are independent. Justify your answer.

[2]

Question 15

MediumPaper 2 · calculator6 marks

(a) In a manufacturing process, the event that component A passes its final inspection is denoted by AA, and the event that component B passes its final inspection is denoted by BB. The events AA and BB are independent.

It is known that the probability of component AA passing its inspection is twice the probability of component BB passing its inspection, i.e., P(A)=2P(B)\text{P}(A) = 2\text{P}(B).

Given that the probability that at least one of the components passes its inspection is 0.880.88, find P(B)\text{P}(B).

Question 16

MediumPaper 2 · calculator20 marks
(a)

(a) A fruit vendor has a basket containing gg green apples and rr red apples. Two apples are selected at random from the basket without replacement.

Let P(GG) represent the probability of selecting two green apples from the basket without replacement.

Given that P(GG) = 13\frac{1}{3}, show that 2g2−2(r+1)g+r−r2=02g^2 - 2(r+1)g + r - r^2 = 0.

[4]
(b)

(b) By solving the equation in part (a) for gg, show that g=(r+1)+3r2+12g = \frac{(r+1)+\sqrt{3r^2 +1}}{2}.

[4]
(c)

(c) Find two pairs of values for rr and gg that satisfy the condition P(GG) = 13\frac{1}{3}.

[4]
(d)

(d) Now consider a different basket that initially contains 1010 red apples and gg green apples. Three apples are selected at random from the basket without replacement.

Let P(GGG) represent the probability of selecting three green apples from the basket without replacement.

Find an expression for P(GGG) in terms of gg.

[3]
(e)

(e) A green apple is added to the basket so that it now contains 1010 red apples and (g+1)(g+1) green apples.

The probability of selecting three green apples from this modified basket is now twice the probability expressed in part (d).

Find the initial number of green apples in the basket.

[5]

Question 17

MediumPaper 1 · no calculator8 marks
(a)

At a local café, the probability that a randomly chosen customer buys a coffee is 35\frac{3}{5}. The probability that they buy a pastry is 12\frac{1}{2}. The probability that they buy both a coffee and a pastry is 14\frac{1}{4}.

(a) State, with a reason, whether the events “buys a coffee” and “buys a pastry” are independent.

[2]
(b)

(b) Find the probability that a randomly chosen customer buys a coffee or a pastry or both.

[2]
(c)

(c) Find the probability that a randomly chosen customer buys exactly one of these items.

[2]
(d)

(d) Find the probability that a randomly chosen customer buys a pastry, given that they have bought a coffee.

[2]

Question 18

MediumPaper 1 · no calculator9 marks
(a)

Two fair spinners are spun. Spinner A has four equal sectors numbered 1, 2, 3, 4. Spinner B has five equal sectors numbered 1, 2, 3, 4, 5. The number on which each spinner lands is recorded.

(a) Find the probability that both spinners land on the same number.

[2]
(b)

(b) Find the probability that the sum of the two numbers is 6.

[2]
(c)

(c) Find the probability that at least one of the spinners lands on a 3.

[2]
(d)

(d) Find the probability that at least one of the spinners lands on a 4, given that the sum of the numbers is 6.

[3]

Question 19

MediumPaper 2 · calculator12 marks
(a)(i)

A bag contains 66 blue marbles and 44 yellow marbles. A marble is drawn at random from the bag and not replaced. A second marble is then drawn at random.

(a) (i) Find the probability that both marbles drawn are blue.

[2]
(a)(ii)

(ii) Find the probability that the two marbles drawn are of different colours.

[4]
(b)(i)

A marble is now drawn at random from the bag, its colour is noted, and it is then replaced in the bag. A second marble is then drawn at random.

(b) (i) Find the probability that both marbles drawn are blue.

[2]
(b)(ii)

(ii) Find the probability that the two marbles drawn are of different colours.

[4]

Question 20

MediumPaper 1 · no calculator4 marks

In a sports club with 8080 members, 4545 play tennis, 3535 play squash and 1010 play neither. If a member is selected at random, find the probability that this member plays both tennis and squash.

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What does Venn diagrams, tree diagrams, probability tables (+ notation & combined & mutually exclusive events) cover in IB Maths AA?

Venn diagrams represent sets and probabilities visually, showing intersections (A cap B), unions (A cup B), and complements (A'). Tree diagrams display sequential events and their probabilities. Probability tables organize probabilities for joint events.

Is Venn diagrams, tree diagrams, probability tables (+ notation & combined & mutually exclusive events) SL or HL?

Both. SL and HL students study Venn diagrams, tree diagrams, probability tables (+ notation & combined & mutually exclusive events) to the same depth.

How do I revise Venn diagrams, tree diagrams, probability tables (+ notation & combined & mutually exclusive events) for IB Maths AA?

Start from the core idea: venn diagrams represent sets and probabilities visually, showing intersections (A cap B), unions (A cup B), and complements (A'). In the exam: with or without replacement changes the second branch of a tree and is the standard discriminator. The guidance that problems can be solved without explicit formulae means a correct tree diagram plus a correct answer is worth full marks, so a mark scheme should not demand the formula. Then practise exam-style questions, easiest first, writing out every step of your working before you check it.

How does FourtyFive help me practise Venn diagrams, tree diagrams, probability tables (+ notation & combined & mutually exclusive events)?

FourtyFive has 31 Venn diagrams, tree diagrams, probability tables (+ notation & combined & mutually exclusive events) questions. Every answer you write is marked mark by mark, IB-style, and you see where each mark was won or lost. Every part has a hint, the AI tutor helps you through the step you are stuck on, and your Study Profile picks what to practise next.

Is FourtyFive free for Venn diagrams, tree diagrams, probability tables (+ notation & combined & mutually exclusive events) practice?

Yes. A free account gives you 50 marked answers a month, and you do not need a card to sign up.

Can I handwrite Venn diagrams, tree diagrams, probability tables (+ notation & combined & mutually exclusive events) answers on an iPad?

Yes. In the FourtyFive iPad app you write your working by hand with Apple Pencil, the way you would on paper, and it is marked the same way.

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