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Topic 5.07 · SL and HL

Kinematics: notes and practice questions

Summary

Kinematics involves the motion of objects described using displacement (ss), velocity (vv), acceleration (aa), and time (tt):

  • Velocity: v=dsdtv = \frac{ds}{dt}
  • Acceleration: a=dvdt=d2sdt2a = \frac{dv}{dt} = \frac{d^2s}{dt^2}
  • Displacement from velocity: s=∫v dts = \int v \, dt
  • Velocity from acceleration: v=∫a dtv = \int a \, dt

How it is examined

Displacement versus total distance is the whole point of the subtopic, and the modulus sign is the marking point. A question that sets v(t)v(t) changing sign inside the interval is testing exactly that. Paper 2 mostly, because the integrals are GDC work. 6 to 8 marks across parts.

Given in the booklet

a=dvdt=d2sdt2a = \dfrac{\mathrm{d}v}{\mathrm{d}t} = \dfrac{\mathrm{d}^2 s}{\mathrm{d}t^2}, distance=∫t1t2∣v(t)∣ dt\text{distance} = \int_{t_1}^{t_2}|v(t)|\,\mathrm{d}t and displacement=∫t1t2v(t) dt\text{displacement} = \int_{t_1}^{t_2} v(t)\,\mathrm{d}t are given. v=dsdtv = \frac{\mathrm{d}s}{\mathrm{d}t} is not, though it is hard to imagine a student losing a mark for it.

Key ideas

Kinematic problems involving displacement ss, velocity vv, acceleration aa and total distance travelled.

Linking questions

  • Links to other subjects: kinematics (physics). Note that the SUVAT equations from physics are not on this syllabus and must not be used or expected.

Practice questions

23 questions · 15 medium · 8 hard
Showing 20 of 20

Question 1

MediumPaper 2 · calculator10 marks
(a)

If the velocity, v ms−1v\ ms^{- 1}, of a particle which is moving in a straight line after time, tt seconds, is v(t)=2cos⁡(t)−sin⁡(3t)v(t) = 2\cos(t) - \sin(3t) for 0≤t≤40 \leq t \leq 4.

aa Find the maximum speed.

[2]
(b)

bb At what time there would be a change in direction?

[2]
(c)

cc Find acceleration after 3 seconds

[4]
(d)

dd Find the total travelled distance.

[2]

Question 2

HardPaper 1 · no calculator20 marks
(a)

The acceleration, a ms−2a \text{ ms}^{-2}, of a particle moving in a straight line at time tt seconds, t≥0t \ge 0, is given by a=−2v−8a = -2v - 8, where v ms−1v \text{ ms}^{-1} is the particle's velocity. At t=0t=0, the particle is at the origin O and has an initial velocity v0 ms−1v_0 \text{ ms}^{-1}, where v0>0v_0 > 0.

By solving an appropriate differential equation, show that the particle's velocity at time tt is given by v(t)=(v0+4)e−2t−4v(t) = (v_0 + 4)e^{-2t} - 4.

[6]
(b)(i)

The particle moves in the positive direction until it reaches its maximum displacement from O at time TT. Show that e2T=v0+44e^{2T} = \frac{v_0+4}{4}.

[2]
(b)(ii)

Find an expression for the maximum displacement, smaxs_{\text{max}}, in terms of v0v_0.

[5]
(c)

Let v(T−k)v(T-k) represent the particle's velocity kk seconds before it reaches smaxs_{\text{max}}, where 0<k<T0 < k < T. By using the result from part (b)(i), show that v(T−k)=4(e2k−1)v(T-k) = 4(e^{2k} - 1).

[2]
(d)

Similarly, let v(T+k)v(T+k) represent the particle's velocity kk seconds after it reaches smaxs_{\text{max}}. Deduce a similar expression for v(T+k)v(T+k) in terms of kk.

[2]
(e)

Hence, show that the speed of the particle kk seconds before it reaches smaxs_{\text{max}} is greater than or equal to its speed kk seconds after it reaches smaxs_{\text{max}}.

[3]

Question 3

MediumPaper 2 · calculator7 marks
(a)

A small reconnaissance drone is performing a vertical ascent and descent. Its vertical velocity, v ms−1v \text{ ms}^{-1}, at time tt seconds, for 0≤t≤100 \le t \le 10, is modelled by the function v(t)=tsin⁡t−2.5v(t) = t \sin t - 2.5.

The following diagram shows the graph of vv.

Graph of vertical velocity v(t) of a drone

(a) Find the smallest value of tt for which the drone is momentarily stationary.

[2]
(b)

(b) Find the total vertical distance travelled by the drone during the first 10 seconds.

[3]
(c)

(c) Find the vertical acceleration of the drone when t=8t=8 seconds.

[2]

Question 4

HardPaper 1 · no calculator15 marks
(a)

A drone takes off from a platform. Its height, hh metres, above the platform after tt seconds is given by h(t)=6t−t2h(t) = 6t - t^2, for 0≤t≤80 \le t \le 8. This is shown in the following diagram.

Graph of height h versus time t for the drone, showing a parabola opening downwards with vertex in the first quadrant and passing through the origin

The drone lands back on the platform when t=pt=p.

Find the value of pp.

[2]
(b)(i)

The drone reaches its maximum height when t=qt=q.

Find the value of qq.

[3]
(b)(ii)

Find the drone's maximum height above the platform.

[2]
(c)

Find the drone's vertical distance from the platform when t=8t=8.

[2]
(d)

The total vertical distance travelled by the drone in the first 8 seconds is given by dd.

Find the value of dd.

[2]
(e)

A second drone, Drone B, takes off from the same platform. Its velocity is given by vB(t)=8−2tv_B(t) = 8 - 2t, for t≥0t \ge 0.

When t=kt = k, the total vertical distance travelled by Drone B is equal to dd.

Find the value of kk.

[4]

Question 5

MediumPaper 2 · calculator7 marks
(a)

A mini-submarine is performing a test dive. Its velocity, vv in m/s, at time tt seconds is given by v(t)=5sin⁡(t)−t+2v(t) = 5\sin(t) - t + 2, for 0≤t≤80 \le t \le 8.

(a) Calculate the time(s) when the submarine is momentarily at rest.

[2]
(b)

(b) Find the acceleration of the submarine when it first changes direction.

[3]
(c)

(c) Determine the total distance travelled by the submarine during the first 8 seconds of its dive.

[2]

Question 6

HardPaper 1 · no calculator16 marks
(a)

A particle moves in a straight line. Its velocity, v ms−1v \,\text{ms}^{-1}, at time tt seconds is given by v(t)=−t3+6t2−9tv(t) = -t^3 + 6t^2 - 9t, for 0≤t≤50 \le t \le 5. The particle is at the origin at t=0t=0.

The graph of vv is shown in the following diagram.

Graph of velocity v against time t, showing a cubic function starting at (0,0), going down to a minimum between t=0 and t=3, then up to touch the t-axis at t=3, and then continuing downwards.

(a) Find the displacement of the particle from the origin at t=3t=3.

[4]
(b)

(b) Find an expression for the acceleration of the particle.

[2]
(c)

(c) The particle is momentarily at rest at t=0t=0 and again at t=kt=k. Find the greatest speed of the particle in the interval 0≤t≤k0 \le t \le k.

[5]
(d)

(d) Find the greatest speed of the particle for 0≤t≤50 \le t \le 5.

[2]
(e)

(e) Write down an expression that represents the distance travelled by the particle while its speed is increasing. Do not evaluate the expression.

[3]

Question 7

MediumPaper 2 · calculator6 marks
(a)

A drone is flying vertically. Its vertical velocity, vms−1v\text{ms}^{-1}, at time tt seconds is given by v(t)=(t−4)sin⁡(t2)+1v(t) = (t-4)\sin\left(\frac{t}{2}\right) + 1, for 0≤t≤120 \leq t \leq 12.

The following diagram shows the graph of vv.

Graph of vertical velocity v against time t for a drone

Find the smallest value of tt for which the drone is momentarily stationary.

[2]
(b)

Find the total vertical distance travelled by the drone during the first 12 seconds.

[2]
(c)

Find the acceleration of the drone when t=7t=7 seconds.

[2]

Question 8

HardPaper 2 · calculator15 marks
(a)(i)

A team of engineers is testing two autonomous robots, Alpha and Beta, on a straight track. Their positions are measured as the distance from a fixed starting point. The experiment runs for 10 minutes.

The position of Robot Alpha, PAP_A metres, at time tt minutes can be modelled by the function PA(t)=3sin⁡(2t+5)+14t+20P_A(t) = 3\sin(2t + 5) + 14t + 20, where 0≤t≤100 \le t \le 10.

The position of Robot Beta, PBP_B metres, at time tt minutes can be modelled by the function PB(t)=12t+25P_B(t) = 12t + 25, where 0≤t≤100 \le t \le 10.

Use the engineers' models to find the initial position of

(i) Robot Beta;

[1]
(a)(ii)

(ii) Robot Alpha correct to three significant figures.

[2]
(b)

Find the values of tt when Robot Alpha and Robot Beta are at the same position. Give your answers correct to three significant figures.

[3]
(c)

For t>5t > 5, prove that Robot Alpha was always ahead of Robot Beta.

[3]
(d)

For 0≤t≤100 \le t \le 10, find the total amount of time when the speed of Robot Beta was greater than the speed of Robot Alpha. Give your answer correct to three significant figures.

[6]

Question 9

MediumPaper 2 · calculator5 marks
(a)

A buoy floats on the surface of a lake. Its vertical displacement, ss metres, from its equilibrium position at time tt seconds is modelled by the function s(t)=5cos⁡(2t+1)s(t) = 5 \cos(2t+1), for 0≤t≤50 \leq t \leq 5.

(a) Find the first time, qq seconds, when the buoy momentarily comes to rest.

[2]
(b)

(b) Find the total distance that the buoy travels in the first qq seconds.

[3]

Question 10

HardPaper 2 · calculator20 marks
(a)

A designer is creating a decorative glass container shaped like a dome. The outer profile of the container can be modelled by the function f(x)=9−x2f(x) = \sqrt{9-x^2}, where 0≤x≤30 \le x \le 3 and xx and yy are measured in metres.

Sketch the curve y=f(x)y = f(x), clearly indicating the coordinates of the endpoints.

[2]
(b)(i)

Show that the inverse function of ff is given by f−1(x)=9−x2f^{-1}(x) = \sqrt{9-x^2}.

[3]
(b)(ii)

State the domain and range of f−1f^{-1}.

[2]
(c)(i)

The container is formed by rotating the curve y=f(x)y = f(x) by 2π2\pi about the y-axis. Show that the volume, V m3V \text{ m}^3, of liquid in the container when it is filled to a height of hh metres is given by V=π(9h−13h3)V = \pi \left( 9h - \frac{1}{3}h^3 \right).

[3]
(c)(ii)

Hence, determine the maximum volume of the container.

[2]
(d)

At t=0t = 0, the container is empty. Liquid is then added to the container at a constant rate of 0.5 m3s−10.5 \text{ m}^3\text{s}^{-1}.

Find the time it takes to fill the container to its maximum volume.

[2]
(e)

Find the rate of change of the height of the liquid when the container is filled to half its maximum volume.

[6]

Question 11

MediumPaper 2 · calculator5 marks
(a)

A drone's altitude, hh metres, above the ground at time tt seconds is modelled by the function h(t)=8cos⁡(0.5t+1)+12h(t) = 8 \cos(0.5t + 1) + 12, for 0≤t≤150 \leq t \leq 15.

(a) Find the first time, qq seconds, when the drone's vertical velocity is zero.

[2]
(b)

(b) Find the total vertical distance that the drone travels in the first qq seconds.

[3]

Question 12

HardPaper 2 · calculator15 marks
(a)

A remote-controlled drone is launched from a platform and moves horizontally in a straight line. Its velocity, vv m s−1^{-1}, at time tt seconds after launch, is given by v(t)=t+1−4t+16v(t) = t + 1 - \sqrt{4t + 16}, for t≥0t \ge 0.

(a) Find the drone's initial velocity.

[2]
(b)

(b) Find the time when the drone is at rest.

[4]
(c)

(c) Find the drone's acceleration at the instant it comes to rest.

[4]
(d)(i)

(d) Determine the time interval(s) when the drone is:

(i) slowing down

[3]
(d)(ii)

(ii) speeding up.

[2]

Question 13

MediumPaper 2 · calculator6 marks
(a)

A drone is programmed to ascend vertically from the ground. Its height, hh metres, tt seconds after launch, is modelled by the function h(t)=60t−3t2h(t) = 60t - 3t^2.

(a) Find an expression for the vertical velocity, vv, of the drone at time tt.

[2]
(b)

(b) Calculate the maximum height reached by the drone.

[4]

Question 14

HardPaper 1 · no calculator12 marks
(a)

The vertical displacement, yy metres, of a buoy from its equilibrium position in the water is modelled by the equation y(t)=8sin⁡3(t)y(t) = 8\sin^3(t), where tt is the time in seconds, t≥0t \ge 0.

(a) Find an expression for the acceleration of the buoy at time tt.

[4]
(b)

(b) Find the values of yy at which the buoy is momentarily at rest.

[3]
(c)

(c) Find the values of yy for which the velocity of the buoy is at a maximum.

[5]

Question 15

MediumPaper 2 · calculator17 marks
(a)

A hot air balloon takes off from a launch platform. Its height above the ground, hh metres, tt minutes after takeoff, is modelled by the function h(t)=24t−0.8t2h(t) = 24t - 0.8t^2.

Determine the height of the hot air balloon after 5 minutes and after 10 minutes.

[2]
(b)

Find an expression for the vertical velocity of the hot air balloon, v(t)v(t), in terms of tt.

[2]
(c)

Calculate the time at which the hot air balloon reaches its maximum height.

[3]
(d)

Determine the total duration of the balloon's flight before it lands.

[2]
(e)

Sketch the graph of h=h(t)h = h(t) for the duration of the flight, clearly indicating the intercepts with the tt-axis and the coordinates of the maximum point. State the domain of the model.

[4]
(f)

Find the vertical velocity of the hot air balloon at the instant it lands.

[2]
(g)

Show that the vertical acceleration of the hot air balloon is constant, stating its value.

[2]

Question 16

HardPaper 2 · calculator19 marks
(a)

(a) A deep-sea submersible's vertical displacement, in metres, from a reference depth is given by s(t)=5sin⁡(2t)−3cos⁡(t)s(t) = 5 \sin(2t) - 3 \cos(t) for time tt minutes. Positive s(t)s(t) indicates the submersible is above the reference depth, and negative s(t)s(t) indicates it is below.

Find the submersible's vertical velocity and acceleration at any time tt.

[3]
(b)

(b) Find the time intervals during 0≤t≤2π0 \le t \le 2\pi when the submersible is moving upwards.

[5]
(c)

(c) Determine the time intervals during 0≤t≤2π0 \le t \le 2\pi when the submersible's vertical velocity is decreasing.

[5]
(d)

(d) Calculate the total vertical distance travelled by the submersible during the time 0≤t≤2π0 \le t \le 2\pi. Give your answer to three significant figures.

[6]

Question 17

MediumPaper 2 · calculator18 marks
(a)

A drone takes off vertically from the ground. Its altitude, hh metres, above the ground at time tt seconds after takeoff is modelled by the function h(t)=50t−2.5t2h(t) = 50t - 2.5t^2.

(a) Determine the altitude of the drone at t=4t=4 seconds and t=5t=5 seconds.

[2]
(b)

(b) Find an expression for the vertical velocity of the drone, v(t)v(t), in terms of tt.

[2]
(c)

(c) Find the instant in time, tt, for which the drone reaches its maximum altitude.

[3]
(d)

(d) Determine how long it takes for the drone to return to the ground.

[3]
(e)

(e) Sketch the graph of h=h(t)h = h(t), stating clearly the domain of validity of the model and its maximum point.

[4]
(f)

(f) Find the velocity of the drone at the instant it returns to the ground.

[2]
(g)

(g) Show that the acceleration of the drone is constant, stating its value.

[2]

Question 18

MediumPaper 2 · calculator4 marks

(a) A scientist is analyzing the trajectory of a small probe in a controlled environment. The vertical displacement of the probe, hh metres, at time tt seconds, is modelled by the function h(t)=4t2+5sin⁡th(t) = 4t^2 + 5\sin t.

Find the instantaneous vertical velocity of the probe when t=π3t = \frac{\pi}{3} seconds.

Question 19

MediumPaper 1 · no calculator6 marks
(a)

A drone takes off vertically from the ground. Its velocity, vv in metres per second, is given by v(t)=3t2−0.2t3v(t) = 3t^2 - 0.2t^3 for 0≤t≤100 \le t \le 10.

(a) Find an expression for the acceleration, aa, of the drone at time tt.

[2]
(b)

(b) Let hh be the height of the drone above the ground. Find an expression for hh in terms of tt.

[4]

Question 20

MediumPaper 1 · no calculator4 marks

A particle moves along a straight line. Its velocity, vv m s⁻¹, at time tt seconds is given by v(t)=6t2−4t+1v(t) = 6t^2 - 4t + 1. Given that the displacement of the particle is 5 metres when t=1t=1, find an expression for the displacement, s(t)s(t).

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What does Kinematics cover in IB Maths AA?

Kinematics involves the motion of objects described using displacement (s), velocity (v), acceleration (a), and time (t):. Velocity: v = (ds)/(dt). Acceleration: a = (dv)/(dt) = (d^2s)/(dt^2).

Is Kinematics SL or HL?

Both. SL and HL students study Kinematics to the same depth.

How do I revise Kinematics for IB Maths AA?

Start from the core idea: kinematics involves the motion of objects described using displacement (s), velocity (v), acceleration (a), and time (t):. In the exam: displacement versus total distance is the whole point of the subtopic, and the modulus sign is the marking point. A question that sets v(t) changing sign inside the interval is testing exactly that. Then practise exam-style questions, easiest first, writing out every step of your working before you check it.

How does FourtyFive help me practise Kinematics?

FourtyFive has 23 Kinematics questions. Every answer you write is marked mark by mark, IB-style, and you see where each mark was won or lost. Every part has a hint, the AI tutor helps you through the step you are stuck on, and your Study Profile picks what to practise next.

Is FourtyFive free for Kinematics practice?

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