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Topic 1.08 · SL and HL

Binomial theorem (+pascals triangle & nCr): notes and practice questions

Summary
  • The binomial theorem provides a way to expand (a+b)n(a+b)^n for positive integer nn:

(a+b)n=∑r=0n(nr)an−rbr (a+b)^n = \sum_{r=0}^n \binom{n}{r} a^{n-r} b^r
where (nr)=n!r!(n−r)!\binom{n}{r} = \frac{n!}{r!(n-r)!} (also written as nCrnCr) represents the binomial coefficient. - Pascal's Triangle can be used to determine the coefficients in the expansion.
Example: The row corresponding to n=3n=3 is 1,3,3,11, 3, 3, 1, representing (a+b)3=a3+3a2b+3ab2+b3(a+b)^3 = a^3 + 3a^2b + 3ab^2 + b^3.

How it is examined

Almost always "find the coefficient of xkx^k in the expansion of ...", where the work is picking the right rr, not expanding everything. Paper 1 wants the nCr^n\mathrm{C}_r formula written out. `Find`, `Determine`, `Show that`. 4 to 6 marks.

Given in the booklet

(a+b)n=an+(n1)an−1b+⋯+(nr)an−rbr+⋯+bn(a+b)^n = a^n + \binom{n}{1}a^{n-1}b + \dots + \binom{n}{r}a^{n-r}b^r + \dots + b^n and (nr)=nCr=n!r!(n−r)!\binom{n}{r} = {}^n\mathrm{C}_r = \dfrac{n!}{r!(n-r)!}.

Key ideas
  • The binomial theorem: expansion of (a+b)n(a+b)^n, n∈Nn \in \mathbb{N}.
  • Use of Pascal's triangle and nCr^n\mathrm{C}_r.
Not assessed

Not required at SL: proof of the binomial theorem (stated at AHL 1.10, and it is not required there either).

At HL

Extended at AHL 1.10 to fractional and negative indices (n∈Qn \in \mathbb{Q}).

Linking questions

  • Aim 8: attributing the origin of a mathematical discovery to the wrong mathematician (Pascal's triangle).
  • International-mindedness: Pascal's triangle was known in several cultures long before Pascal, for example to Yang Hui.

Practice questions

48 questions · 37 medium · 11 hard
Showing 20 of 20

Question 1

MediumPaper 2 · calculator6 marks

Consider the expansion of 6x3(kx+1)7,6x^{3}(kx + 1)^{7}, where k≠0k \neq 0 and the coefficient of the x8x^{8} term is 378k4378k^{4}.

Find the value of kk.

Question 2

HardPaper 1 · no calculator5 marks

Consider the expansion of (3x2−2x3)n\left(3x^2 - \frac{2}{x^3}\right)^n where n∈Z+n \in \mathbb{Z}^+. Determine all possible values of nn for which the expansion has a non-zero constant term.

Question 3

MediumPaper 2 · calculator5 marks

A scientist is analyzing the growth pattern of a bacterial colony, which can be modeled by a polynomial expansion. The size of the colony, P(x)P(x), after xx hours, is related to a binomial expression (2+x3)n+2(2 + x^3)^{n+2}, where n∈Z+n \in \mathbb{Z}^+ represents a specific growth factor.

Given that the coefficient of x6x^6 in the expansion of (2+x3)n+2(2 + x^3)^{n+2} is 1152011520, find the value of nn.

Question 4

HardPaper 1 · no calculator16 marks
(a)

(a) Find the binomial expansion of (cos⁡θ+isin⁡θ)4(\cos \theta + i \sin \theta)^4. Give your answer in the form a+bia + bi where aa and bb are expressed in terms of sin⁡θ\sin \theta and cos⁡θ\cos \theta.

[4]
(b)

(b) By using De Moivre's theorem and your answer to part (a), show that cos⁡4θ=8cos⁡4θ−8cos⁡2θ+1\cos 4\theta = 8 \cos^4\theta - 8 \cos^2\theta + 1.

[5]
(c)

(c) Hence, find the four distinct roots of the equation 8x4−8x2+1=08x^4 - 8x^2 + 1 = 0, expressing them in the form cos⁡(α)\cos(\alpha) where 0<α<π0 < \alpha < \pi.

[4]
(d)

(d) By considering the roots of the equation in part (c), or otherwise, find the exact value of cos⁡(π8)cos⁡(3π8)\cos(\frac{\pi}{8})\cos(\frac{3\pi}{8}).

[3]

Question 5

MediumPaper 1 · no calculator6 marks

The first three terms in the binomial expansion of (1+ax)n(1 + ax)^n in ascending powers of xx are 1−15x+45a2x21 - 15x + 45a^2x^2. Given that n∈Z+n \in \mathbb{Z}^+ and a∈Qa \in \mathbb{Q}.

Find the value of nn and the value of aa.

Question 6

HardPaper 1 · no calculator17 marks
(a)

Find the binomial expansion of (cos⁡θ+isin⁡θ)4(\cos \theta + i \sin \theta)^4. Give your answer in the form a+bia + bi where aa and bb are expressed in terms of sin⁡θ\sin \theta and cos⁡θ\cos \theta.

[4]
(b)

By using De Moivre's theorem and your answer to part (a), show that cos⁡4θ=8cos⁡4θ−8cos⁡2θ+1\cos 4\theta = 8\cos^4\theta - 8\cos^2\theta + 1.

[6]
(c)(i)

Hence, show that θ=π8\theta = \frac{\pi}{8} and θ=3π8\theta = \frac{3\pi}{8} are solutions of the equation 8cos⁡4θ−8cos⁡2θ+1=08\cos^4\theta - 8\cos^2\theta + 1 = 0.

[3]
(c)(ii)

Hence, find the exact value of cos⁡(π8)cos⁡(3π8)\cos(\frac{\pi}{8})\cos(\frac{3\pi}{8}).

[4]

Question 7

MediumPaper 1 · no calculator5 marks

In the expansion of (ax−2x)8(ax - \frac{2}{x})^8, where a∈Ra \in \mathbb{R}, the constant term is 70.

Find the possible values of aa.

Question 8

HardPaper 1 · no calculator18 marks
(a)

By considering De Moivre's theorem, show that cos⁡(4θ)=8cos⁡4θ−8cos⁡2θ+1\cos(4\theta) = 8\cos^4\theta - 8\cos^2\theta + 1.

[4]
(b)

Let w=1+iw = 1+i. Show that w4=−4w^4 = -4.

[2]
(c)

Hence, find the four roots of the equation z4=−4z^4 = -4 in Cartesian form.

[3]
(d)

The four roots are represented by points A, B, C, D on an Argand diagram, forming a square. Find the area of this square.

[2]
(e)

Each of the points A, B, C, D is rotated counter-clockwise about the origin by an angle of π6\frac{\pi}{6} to form new points A', B', C', D'. These points are the roots of an equation z4=Kz^4 = K. Find KK in Cartesian form.

[4]
(f)

It is given that the eight points represented by the roots of z4=−4z^4=-4 and z4=Kz^4=K are all solutions of zn=αz^n = \alpha for some α∈C\alpha \in \mathbb{C} and n∈Nn \in \mathbb{N}. Find the smallest positive value of nn.

[3]

Question 9

MediumPaper 1 · no calculator6 marks

The first three terms in the expansion of (a+x)n(a+x)^n are 81+108x+54x281 + 108x + 54x^2. Given that a∈Q+a \in \mathbb{Q}^+ and n∈Z+n \in \mathbb{Z}^+, find the value of aa and the value of nn.

Question 10

HardPaper 1 · no calculator7 marks

Use the principle of mathematical induction to prove that ∑r=2nrC2=n+1C3\sum_{r=2}^n {^rC_2} = {^{n+1}C_3} for all integers n≥2n \ge 2.

Question 11

MediumPaper 1 · no calculator5 marks

In the expansion of (2x+k)6(2x + k)^6, where k∈Rk \in \mathbb{R}, the coefficient of the term in x4x^4 is 960.

Find the possible values of k.

Question 12

HardPaper 1 · no calculator15 marks
(a)(i)

Expand and simplify (1+a)3(1+a)^3 in ascending powers of aa.

[2]
(a)(ii)

By using a suitable substitution for aa, show that 1+3cos⁡(2x)+3cos⁡2(2x)+cos⁡3(2x)=8cos⁡6(x)1+3\cos(2x)+3\cos^2(2x)+\cos^3(2x) = 8\cos^6(x).

[4]
(b)(i)

Consider the function g(x)=4sin⁡(x)(1+3cos⁡(2x)+3cos⁡2(2x)+cos⁡3(2x))g(x) = 4\sin(x)(1+3\cos(2x)+3\cos^2(2x)+\cos^3(2x) ).

Show that ∫0pg(x) dx=327(1−cos⁡7p)\int_0^p g(x) \, dx = \frac{32}{7}(1-\cos^7 p), where pp is a positive real constant.

[4]
(b)(ii)

It is given that ∫pπ2g(x) dx=128\int_p^{\frac{\pi}{2}} g(x) \, dx = \frac{1}{28}, where 0≤p≤π20 \le p \le \frac{\pi}{2}. Find the value of pp.

[5]

Question 13

MediumPaper 1 · no calculator7 marks
(a)

A new car is purchased for 10000 euros. The value of the car depreciates at a nominal annual rate of 10%, with the depreciation calculated semi-annually.

The value of the car after two years can be written as 10000(1−k)410000(1 - k)^4.

(a) Write down the value of kk.

[1]
(b)

(b) Expand and simplify (1−x)4(1 - x)^4.

[2]
(c)

(c) Hence or otherwise, find the value of the car after two years, giving your answer correct to the nearest euro.

[4]

Question 14

HardPaper 1 · no calculator22 marks
(a)(i)

Consider the complex number z1=1−i3z_1 = 1 - i\sqrt{3}.

(a) (i) Express z1z_1 in modulus-argument form.

[2]
(a)(ii)

(a) (ii) Find the smallest positive integer nn for which z1nz_1^n is a real number.

[3]
(b)

Consider the equation (z+i)5−(z−i)5=0(z+i)^5 - (z-i)^5 = 0, where z∈Cz \in \mathbb{C}.

(b) Show that the roots of the equation are given by z=cot⁡(kπ5)z = \cot\left(\frac{k\pi}{5}\right) for k=1,2,3,4k=1, 2, 3, 4.

[6]
(c)(i)

(c) (i) By using the binomial expansion, show that the equation in part (b) can be written as 5z4−10z2+1=05z^4 - 10z^2 + 1 = 0.

[4]
(c)(ii)

(c) (ii) Let the roots of the equation in (c)(i) be z1,z2,z3,z4z_1, z_2, z_3, z_4. Without finding the roots, show that ∑j=14zj2=4\sum_{j=1}^4 z_j^2 = 4.

[3]
(d)

(d) Hence, find the exact value of cot⁡2(π5)\cot^2\left(\frac{\pi}{5}\right).

[4]

Question 15

MediumPaper 1 · no calculator6 marks

The first three terms in the binomial expansion of (1+xk)n(1 + \frac{x}{k})^n are given by 1+2x+74x2+…1 + 2x + \frac{7}{4}x^2 + \dots where n∈Z+n \in \mathbb{Z}^+ and k∈Qk \in \mathbb{Q}.

Find the value of nn and the value of kk.

Question 16

HardPaper 1 · no calculator7 marks
(a)

Find the term in x4x^4 in the expansion of (2x−1)8(2x-1)^8.

[3]
(b)

Hence, find the term in x5x^5 in the expansion of (x+3)(2x−1)8(x+3)(2x-1)^8.

[4]

Question 17

MediumPaper 2 · calculator5 marks

Consider the expansion of (2+2x3)n(2 + 2x^3)^n, where n∈Z+n \in \mathbb{Z}^+.

Given that the coefficient of x6x^6 is 18432, find the value of nn.

Question 18

HardPaper 1 · no calculator8 marks
(a)

A discrete random variable XX follows a binomial distribution, X∼B(n,13)X \sim B(n, \frac{1}{3}).

It is given that the probabilities P(X=r−1)P(X=r-1), P(X=r)P(X=r) and P(X=r+1)P(X=r+1) for some integer rr form an arithmetic sequence, where 1≤r≤n−11 \le r \le n-1.

(a) Show that n2−3n(2r+1)+9r2+3r−4=0n^2 - 3n(2r+1) + 9r^2 + 3r - 4 = 0.

[5]
(b)

(b) For a particular experiment, it is known that n=8n=8. Find the possible value(s) of rr.

[3]

Question 19

MediumPaper 2 · calculator7 marks

A scientist is investigating the properties of a newly synthesized compound. Its molecular structure's stability is modeled by polynomial expansions. The terms involving x4x^4 are critical for predicting its reactivity.

In the binomial expansion of (px2+q)7(px^2 + q)^7, the coefficient of the x4x^4 term is 6048.

In the binomial expansion of (px2+q)9(px^2 + q)^9, the coefficient of the x4x^4 term is 41472.

Given that p,q>0p, q > 0, find the value of pp and the value of qq.

Question 20

HardPaper 1 · no calculator15 marks
(a)

Let z=cos⁡θ+isin⁡θz = \cos\theta + i\sin\theta. Use De Moivre's theorem to show that zn−1zn=2isin⁡nθz^n - \frac{1}{z^n} = 2i\sin n\theta, for n∈Z+n \in \mathbb{Z}^+.

[3]
(b)

Expand (z−1z)5\left(z - \frac{1}{z}\right)^5.

[3]
(c)

Hence, find an expression for sin⁡5θ\sin^5 \theta in the form Asin⁡5θ+Bsin⁡3θ+Csin⁡θA\sin 5\theta + B\sin 3\theta + C\sin \theta, where A,B,CA, B, C are constants to be determined.

[5]
(d)

Hence, evaluate ∫0π4sin⁡5(2x) dx\int_0^{\frac{\pi}{4}} \sin^5(2x) \, dx.

[4]

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What does Binomial theorem (+pascals triangle & nCr) cover in IB Maths AA?

The binomial theorem provides a way to expand (a+b)^n for positive integer n:. $$. (a+b)^n = \sum_{r=0}^n \binom{n}{r} a^{n-r} b^r.

Is Binomial theorem (+pascals triangle & nCr) SL or HL?

Both. SL and HL students study Binomial theorem (+pascals triangle & nCr), and HL goes further: Extended at AHL 1.10 to fractional and negative indices (n ∈ mathbbQ).

How do I revise Binomial theorem (+pascals triangle & nCr) for IB Maths AA?

Start from the core idea: the binomial theorem provides a way to expand (a+b)^n for positive integer n:. In the exam: almost always "find the coefficient of x^k in the expansion of ...", where the work is picking the right r, not expanding everything. Paper 1 wants the ^nC_r formula written out. Then practise exam-style questions, easiest first, writing out every step of your working before you check it.

How does FourtyFive help me practise Binomial theorem (+pascals triangle & nCr)?

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